Chapter 41

Physics for Scientists and Engineers with Modern Physics · 63 exercises

Problem 73

Using the uncertainty principle and the radius of a nucleus, estimate the minimum possible kinetic energy of a nucleon in, say, iron. Ignore relativistic corrections. [Hint: A particle can have a momentum at least as large as its momentum uncertainty.

5 step solution

Problem 75

The nuclide \({ }_{76}^{191}\) Os decays with \(\beta^{-}\) energy of 0.14 MeV accompanied by \(\gamma\) rays of energy \(0.042 \mathrm{MeV}\) and \(0.129 \mathrm{MeV}\) (a) What is the daughter nucleus? (b) Draw an energy-level diagram showing the ground states of the parent and daughter and excited states of the daughter. (c) To which of the daughter states does \(\beta^{-}\) decay of \({ }_{76}^{191}\) Os occur?

4 step solution

Problem 75

The nuclide \(\frac{191}{76} \mathrm{Os}\) decays with \(\beta^{-}\) energy of 0.14 MeV accompanied by \(\gamma\) rays of energy 0.042 MeV and 0.129 MeV. \((a)\) What is the daughter nucleus? \((b)\) Draw an energy-level diagram showing the ground states of the parent and daughter and excited states of the daughter. (c) To which of the daughter states does \(\beta^{-}\) decay of \(\frac{191}{76} \mathrm{Os}\) occur?

4 step solution

Problem 76

Determine the activities of \((a) 1.0 \mathrm{~g}\) of \({ }_{53}^{131} \mathrm{I}\left(T_{\frac{1}{2}}=8.02\right.\) days \()\) and \((b) 1.0 \mathrm{~g}\) of \({ }_{92}^{238} \mathrm{U}\left(T_{\frac{1}{2}}=4.47 \times 10^{9} \mathrm{yr}\right)\)

4 step solution

Problem 76

\(\begin{array}{l}{\text { Determine the activities of }(a) 1.0 \mathrm{g} \text { of } \frac{131}{53} \mathrm{I}\left(T_{\frac{1}{2}}=8.02 \text { days) }\right.} \\ {\text { and }(b) 1.0 \mathrm{g} \text { of }_{92}^{238} \mathrm{U}\left(T_{1}=4.47 \times 10^{9} \mathrm{yr}\right)}\end{array} \)

5 step solution

Problem 80

(a) Show that the mean life of a radioactive nuclide, defined as $$\tau=\frac{\int_{0}^{\infty} t N(t) d t}{\int_{0}^{\infty} N(t) d t}$$ is \(\tau=1 / \lambda .\) (b) What fraction of the original number of nuclei remains after one mean life?

7 step solution

Problem 82

If the mass of the proton were just a little closer to the mass of the neutron, the following reaction would be possible even at low collision energies: $$\mathrm{e}^{-}+\mathrm{p} \rightarrow \mathrm{n}+\nu$$ (a) Why would this situation be catastrophic? \((b)\) By what percentage would the proton's mass have to be increased to make this reaction possible?

5 step solution

Problem 83

What is the ratio of the kinetic energies for an alpha particle and a beta particle if both make tracks with the same radius of curvature in a magnetic field, oriented perpendicular to the paths of the particles?

5 step solution

Problem 84

A 1.00-g sample of natural samarium emits \(\alpha\) particles at a rate of \(120 \mathrm{~s}^{-1}\) due to the presence of \({ }_{62}^{147} \mathrm{Sm} .\) The natural abundance of \({ }_{62}^{14} \mathrm{Sm}\) is \(15 \% .\) Calculate the half-life for this decay process.

5 step solution

Problem 85

Almost all of naturally occurring uranium is \({ }_{92}^{238} \mathrm{U}\) with a half-life of \(4.468 \times 10^{9}\) yr. Most of the rest of natural uranium is \({ }_{92}^{235} \mathrm{U}\) with a half-life of \(7.04 \times 10^{8} \mathrm{yr} .\) Today a sample contains \(0.720 \%{ }_{92}^{235} \mathrm{U} .\) ( \(a\) ) What was this percentage 1.0 billion years ago? (b) What percentage of \({ }_{92}^{235} \mathrm{U}\) will remain 100 million years from now?

4 step solution

Problem 85

Almost all of naturally occurring uranium is \(\frac{238}{92} \mathrm{U}\) with a half-life of \(4.468 \times 10^{9}\) yr. Most of the rest of natural uranium is \(\frac{235}{92} \mathrm{U}\) with a half-life of \(7.04 \times 10^{8} \mathrm{yr.}\) Today a sample contains0.720\(\%_{0} \frac{235}{92} U\) (a) What was this percentage 1.0 billion years ago? (b) What percentage of\(\frac{235}{92} \mathrm{U}\) will remain 100 million years from now?

4 step solution

Problem 87

Some radioactive isotopes have half-lives that are larger than the age of the universe (like gadolinium or samarium). The only way to determine these half- lives is to monitor the decay rate of a sample that contains these isotopes. For example, suppose we find an asteroid that currently contains about \(15,000 \mathrm{~kg}\) of \({ }_{64}^{152}\) Gd (gadolinium) and we detect an activity of 1 decay/s. What is the half-life of gadolinium (in years)?

4 step solution

Problem 89

(I) A laboratory has a \(1.80-\mu \mathrm{g}\) sample of radioactive \(\frac{13}{7} \mathrm{N}\) whose decay constant \(\lambda=1.16 \times 10^{-3} \mathrm{s }^{-1} .\) Calculate the initial number of nuclei, \(N_{0},\) present in the sample. Use the radioactive decay law, \(N=N_{0} e^{-\lambda t},\) to determine th number of nuclei \(N\) present at time \(t\) for \(t=0\) th 30 minutes \((1800\) s) in steps of 0.5 \(\min (30\) s). Make a grap of \(N\) versus \(t\) and from the graph determine the half-life the sample.

4 step solution

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