Chapter 1
Master Resource Book in JEE Main Physics · 142 exercises
Problem 61
The photograph of a house occupies an area of \(1.75 \mathrm{~cm}^{2}\) on a \(35 \mathrm{~mm}\) slide. The slide is projected on to a screen and the area of the house on the screen is \(1.55 \mathrm{~m}^{2}\). The linear magnification of the projector-screen arrangement, is (a) \(84.1\) (b) \(96.1\) (c) \(94.1\) (d) \(86.1\)
5 step solution
Problem 62
A highly rigid cubical block \(A\) of small mass \(M\) and side \(L\) is fixed rigidly on to another cubical block of same dimensions and of low modulus of rigidity \(\eta\) such that the lower face of \(A\) completely covers the upper face of \(B\). The lower face of \(B\) is rigidly held on a horizontal surface. \(A\) small force \(F\) is applied perpendicular to one of the side faces of \(A\). After the force is withdrawn, block \(A\) executes small oscillations, the time period of which is given by (a) \(2 \pi \sqrt{M \eta L}\) (b) \(2 \pi \sqrt{\frac{M \eta}{L}}\) (c) \(2 \pi \sqrt{\frac{M L}{\eta}}\) (d) \(2 \pi \sqrt{\frac{M}{\eta L}}\)
5 step solution
Problem 63
In an experiment to measure the height of a bridge by dropping stone into water underneath, if the error in measurement of time is \(0.1 \mathrm{~s}\) at the end of \(2 \mathrm{~s}\), then the error in estimation of height of bridge will be [Kerala CEE 2004] (a) \(0.49 \mathrm{~m}\) (b) \(0.98 \mathrm{~m}\) (c) \(1.96 \mathrm{~m}\) (d) \(2.12 \mathrm{~m}\)
4 step solution
Problem 63
If \(C\) is the restoring couple per unit radian twist and \(I\) is the moment of inertia, then the dimensional representation of \(2 \pi \sqrt{\frac{I}{C}}\) will be (a) \(\left[\mathrm{M}^{0} \mathbf{L}^{0} \mathrm{~T}^{-1}\right]\) (b) \(\left[\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}\right]\) (c) \(\left[\mathrm{M}^{0} \mathrm{LT}^{-1}\right]\) (d) \(\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]\)
6 step solution
Problem 64
A cube has a side of length \(1.2 \times 10^{-2} \mathrm{~m} .\) Calculate its volume (a) \(1.7 \times 10^{-6} \mathrm{~m}^{3}\) (b) \(1.73 \times 10^{-6} \mathrm{~m}^{3}\) (c) \(1.70 \times 10^{-6} \mathrm{~m}^{3}\) (d) \(1.732 \times 10^{-6} \mathrm{~m}^{3}\)
5 step solution
Problem 64
The velocity \(v\) of water waves may depend on their wavelength \((\lambda)\), the density of water \((\rho)\) and the acceleration due to gravity \((\mathrm{g})\). The method of dimensions gives the relation between these quantities as (a) \(v^{2} \propto \lambda^{-1} \rho^{-1}\) (b) \(v^{2} \propto g \lambda\) (c) \(v^{2} \propto g \lambda \rho\) (d) \(g^{-1} \propto \lambda\)
7 step solution
Problem 65
A spectrometer gives the following reading when used to measure the angle of a prism. Main scale reading \(=58.5^{\circ}\) Vernier scale reading \(=09\) division Given that 1 division on main scale corresponding to \(0.5^{\circ}\). Total division on the vernier scale is 30 and match with 29 divisions of the main scale. The angle of the prism from the above data \(\quad\) [AIEEE 2012] (a) \(58.59^{\circ}\) (b) \(58.77^{\circ}\) (c) \(58.65^{\circ}\) (d) \(59^{\circ}\)
5 step solution
Problem 65
If \(E, m, J\) and \(G\) represent energy, mass, angular momentum and gravitational constant respectively, then the dimensional formula of \(E J^{2} / m^{5} G^{2}\) is (a) \(\left[\mathrm{MLT}^{-2}\right]\) (b) \(\left[\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}\right]\) (c) \(\left[\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{0}\right]\) (d) dimensionless
6 step solution
Problem 66
Let \(\left[\varepsilon_{0}\right.\) ] denote the dimensional formula of the perimitivity of vacuum. If \(M=\) mass, \(L=\) length, \(T\) = Time and \(A=\) electric current, then [JEE Main 2013] (a) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{2} \mathrm{~A}\right]\) (b) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-1} \mathrm{~L}^{-3} \mathrm{~T}^{4} \mathrm{~A}^{2}\right]\) (c) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{2} \mathrm{l}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{-2}\right]\) (d) \(\left[\varepsilon_{0}\right]=\left[\mathrm{M}^{-} \mathrm{l}^{2} \mathrm{~T}^{-1} \mathrm{~A}^{2}\right]\)
7 step solution
Problem 66
Crane is British unit of volume (one crane \(=170.4742\) ). Convert crane into SI units. (a) \(0.170474 \mathrm{~m}^{3}\) (b) \(17.0474 \mathrm{~m}^{3}\) (c) \(0.00170474 \mathrm{~m}^{3}\) (d) \(1704.74 \mathrm{~m}^{3}\)
4 step solution
Problem 67
The wavelength associated with a moving particle depends upon power \(p\) of its mass \(m, q\) th power of its velocity \(v\) and \(r\) th power of Planck's constant \(h\). Then the correct set of values of \(p, q\) and \(r\) is (a) \(p=1, q=-1, r=1\) (b) \(p=1, q=1, r=1\) (c) \(p=-1, p=-1, r=-1\) (d) \(p=-1, q=-\mathbf{L} r=1\)
4 step solution
Problem 69
If \(x=a-b\), then the maximum percentage error in the measurement of \(x\) will be (a) \(\left(\frac{\Delta a+\Delta b}{a-b}\right) \times 100 \%\) (b) \(\left(\frac{\Delta a}{a}-\frac{\Delta b}{b}\right) \times 100 \%_{0}\) (c) \(\left(\frac{\Delta a}{a-a}+\frac{\Delta b}{a-b}\right) \times 100 \%\) (d) \(\left(\frac{\Delta a}{a-a}-\frac{\Delta b}{a-b}\right) \times 100 \%\)
4 step solution
Problem 70
If \(X=A \times B\) and \(\Delta X, \Delta A\) and \(\Delta B\) are maximum absolute errors in \(X, A\) and \(B\) respectively, then the maximum relative error in \(X\) is given by (a) \(\Delta X=\Delta A+\Delta B\) (b) \(\Delta X=\Delta A-\Delta B\) (c) \(\frac{\Delta X}{X}=\frac{\Delta A}{A}-\frac{\Delta B}{B}\) (d) \(\frac{\Delta X}{X}=\frac{\Delta A}{A}+\frac{\Delta B}{B}\)
4 step solution
Problem 71
The percentage errors in the measurement of mass and speed are \(2 \%\) and \(3 \%\) respectively. How much will be the maximum error in the estimate of kinetic energy obtained by measuring mass and speed? (a) 1196 (b) \(8 \%\) (c) \(59 \%\) (d) \(1 \%\)
5 step solution
Problem 72
Error in the measurement of radius of sphere is \(2 \%\). The error in the measurement of volume is (a) \(1 \%\) (b) 596 (c) \(3 \%\) (d) 690
5 step solution
Problem 73
There are atomic clocks capable of measuring time with an accuracy of 1 part in \(10^{11} .\) If two such clocks are operated with precision, then after running for \(5000 \mathrm{yr}\), these will record (a) a difference of nearly \(2 \mathrm{~s}\) (b) a difference of 1 day (c) a difference of \(10^{11} \mathrm{~s}\) (d) a difference of \(1 \mathrm{yr}\)
4 step solution
Problem 74
If there is a positive error of \(50 \%\) in the measurement of speed of a body, then the error in the measurement of kinetic energy is (a) \(25 \%\) (b) \(50 \%\) (c) \(100 \%\) (d) \(125 \%\)
4 step solution
Problem 75
The radius of the sphere is \((4.3 \pm 0.1) \mathrm{cm}\). The percentage error in its volume is (a) \(\frac{0.1}{4.3} \times 100\) (b) \(3 \times \frac{0.1 \times 100}{4.3}\) (c) \(\frac{1}{3} \times \frac{0.1 \times 100}{4.3}\) (d) \(3+\frac{0.1 \times 100}{4.3}\)
5 step solution
Problem 76
A public park, in the form of a square, has an area of \((100 \pm 0.2) \mathrm{m}^{2}\). The side of park is (a) \((10 \pm 0.01) \mathrm{m}\) (b) \((10 \pm 0.1) \mathrm{m}\) (c) \((10.0 \pm 0.1) \mathrm{m}\) (d) \((10.0 \pm 0.2) \mathrm{m}\)
4 step solution
Problem 77
The specific resistance \(\rho\) of a circular wire of radius \(r_{1}\) resistance \(R\) and length \(l\) is given by \(\rho=\frac{\pi r^{2} R}{l}\). Given, \(r=0:(24 \pm 0.02) \mathrm{cm}, R=(30 \pm 1) \Omega\) and \(l=(4.80 \pm 0.01) \mathrm{cm}\). The percentage error in \(\rho\) is nearly (a) \(7 \%\) (b) \(9 \%\) (c) 139 (d) \(20 \%\)
5 step solution
Problem 78
The initial temperature of a liquid is \((80.0 \pm 0.1)^{\circ} \mathrm{C}\). After it has been cooled, its temperature is \((10.0 \pm 0.1)^{\circ} \mathrm{C}\). The fall in temperature in degree centigrade is (a) \(70.0\) (b) \(70.0 \pm 0.3\) (c) \(70.0 \pm 0.2\) (d) \(70.0 \pm 0.1\)
4 step solution
Problem 79
A physical quantity is represented by \(X=\mathrm{M}^{a} \mathrm{~L}^{b} \mathrm{~T}^{-c}\). If percentage errors in the measurements of \(M, L\) and \(T\) are \(\alpha \%, \beta \%\) and \(\gamma \%\) respectively, then total percentage error is (a) \((\alpha a+\beta b-\gamma c) \%\) (b) \((\alpha a+\beta b+\gamma c) \%\) (c) \((\alpha a-\beta b-\gamma c) q\) (d) 096
3 step solution
Problem 80
The internal and external diameters of a hollow cylinder are measured with the help of a vernier callipers. Their values are \(4.23 \pm 0.01 \mathrm{~cm}\) and \(3.87 \pm 0.01 \mathrm{~cm}\) respectively. The thickness of the wall of the cylinder is (a) \(0.36 \pm 0.02 \mathrm{~cm}\) (b) \(0.18 \pm 0.02 \mathrm{~cm}\) (c) \(0.36 \pm 0.01 \mathrm{~cm}\) (d) \(0.18 \pm 0.01 \mathrm{~cm}\)
4 step solution
Problem 81
The density of the material of a cube is measured by measuring its mass and length of its side. If the maximum errors in the measurement of mass and the length are \(3 \%\) and \(2 \%\) respectively, the maximum error in the measurement of density is (a) \(1 \%\) (b) \(5 \%\) (c) \(7 \%\) (d) \(9 \%\)
5 step solution
Problem 82
When the planet Jupiter is at a distance of \(824.7\) million \(\mathrm{km}\) from the earth, its angular diameter is measured to be \(35.72^{\prime \prime}\) of arc. The diameter of Jupiter can be calculated as (a) \(1329 \times 10^{7} \mathrm{~km}\) (b) \(1429 \times 10^{5} \mathrm{~km}\) (c) \(929 \times 10^{5} \mathrm{~km}\) (d) \(1829 \times 10^{5} \mathrm{~km}\)
5 step solution
Problem 83
In an experiment, we measure quantities \(a, b\) and \(c\). Then \(x\) is calculated from the formula, \(x=\frac{a b^{2}}{c^{3}}\). The percentage errors in \(a, b, c\) are \(\pm 1 \%, \pm 3 \%\) and \(\pm 2 \%\) respectively. The percentage error in \(x\) can be (a) \(\pm 10\) (b) \(\pm 4 \%\) (c) \(7 \%\) (d) \(\pm 139\)
5 step solution
Problem 84
The time dependence of a physical quantity \(P\) is given by \(P=P_{0} e^{-a t^{2}}\), where \(\alpha\) is a constant and \(t\) is time. Then constant \(\alpha\) is (a) dimensionless (b) dimension of \(t^{-2}\) (c) dimensions of \(\boldsymbol{P}\) (d) dimension of \(t^{2}\)
4 step solution
Problem 85
The least count of a stop watch is \(0.2 \mathrm{~s}\). The time of 20 oscillations of a pendulum is measured to be \(25 \mathrm{~s}\). The percentage error in the measurement of time will be (a) \(8 \%\) (b) \(1.8 \%\) (c) \(0.8 \%\) (d) \(0.1 \%\)
5 step solution
Problem 86
The pressure on a square plate is measured by measuring the force on the plate and the length of the sides of the plate by using the formula \(p=\frac{F}{l^{2}}\).If the maximum errors in the measurement of force and length are \(4 \%\) and \(2 \%\) respectively, then the maximum error in the measurement of pressure is (a) \(1 \%\) (b) \(2 \%\) (c) \(8 \%\) (d) \(10 \%\)
6 step solution
Problem 87
Given, potential difference \(V=(8 \pm 0.5) \mathrm{V}\) and current \(I=(2 \pm 0.2) \mathrm{A}\). The value of resistance \(R\) is (a) \(4 \pm 16.259\) (b) \(4 \pm 6.25 \%\) (c) \(4 \pm 10 \%\) (d) \(4 \pm 896\)
4 step solution
Problem 88
The length, breadth and thickness of a block is measured to be \(50 \mathrm{~cm}, 2.0 \mathrm{~cm}\) and \(1.00 \mathrm{~cm}\). The percentage error in the measurement of volume is (a) \(0.89\) (b) \(8 \%\) (c) 1096 (d) \(12.5 \%\)
4 step solution
Problem 89
Given \(\pi=3.14\). The value of \(\pi^{2}\) with due regard for significant figures is (a) \(9.86\) (b) \(9.859\) (c) \(9.8596\) (d) \(9.85960\)
4 step solution
Problem 90
One side of a cubical block is measured with the help of a vernier callipers of vernier constant \(0.01 \mathrm{~cm}\). This side comes out to be \(1.23 \mathrm{~cm}\). What is the percentage error in the measurement of area? (a) \(\frac{1.23}{0.01} \times 100\) (b) \(\frac{0.01}{1.23} \times 100\) (c) \(2 \times \frac{0.01}{1.23} \times 100\) (d) \(3 \times \frac{0.01}{1.23} \times 100\)
4 step solution
Problem 91
A physical quantity \(P\) is related to four observables \(a, b, c\) and \(d\) are as follows \(P=a^{3} b^{2} / \sqrt{c} d\) The percentage errors of measurement in \(a, b, c\) and \(d\) are \(1 \%, 3 \%, 4 \%\) and \(2 \%\) respectively. What is the percentage error in the quantity \(P\), if the value of \(P\) calculated using the above relation turns out to be 3.763, to what value should you round-off the result? [NCERT] (a) \(13 \%\) and \(3.8\) (b) \(1.3 \%\) and \(0.38\) (c) \(1.3 \%\) and \(3.8\) (d) \(3.896\) and 13
5 step solution
Problem 92
Length is measured in metre and time in second as usual. But a new unit of mass is so chosen that \(G=1\). This new unit of mass is equal to (a) \(1.5 \times 10^{7} \mathrm{~kg}\) (b) \(1.5 \times 10^{10} \mathrm{~kg}\) (c) \(6.67 \times 10^{-11} \mathrm{~kg}\) (d) \(6.67 \times 10^{-8} \mathrm{~kg}\)
4 step solution
Problem 93
The length, breadth and thickness of a metal block is given by \(l=90 \mathrm{~cm}, b=8 \mathrm{~cm}, t=2.45 \mathrm{~cm}\). The volume of the block is (a) \(2 \times 10^{2} \mathrm{~cm}^{3}\) (b) \(1.8 \times 10^{2} \mathrm{~cm}^{3}\) (c) \(1.77 \times 10^{2} \mathrm{~cm}^{3}\) (d) \(1.764 \times 10^{2} \mathrm{~cm}^{2}\)
5 step solution
Problem 94
The focal length of a mirror is given by \(\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\) where \(u\) and \(v\) represent object and image distances respectively. The maximum relative error in \(f\) is (a) \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}\) (b) \(\frac{\Delta f}{f}=\frac{1}{\Delta u / u}+\frac{1}{\Delta v / v}\) (c) \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}+\frac{\Delta(u+v)}{u+v}\) (d) \(\frac{\Delta f}{f}=\frac{\Delta u}{u}+\frac{\Delta v}{v}+\frac{\Delta u}{u+v}+\frac{\Delta v}{u+v}\)
3 step solution
Problem 95
The measured mass and volume of a body are \(23.42 \mathrm{~g}\) and \(4.9 \mathrm{~cm}^{3}\) respectively with possible error \(0.01 \mathrm{~g}\) and \(0.1 \mathrm{~cm}^{3} .\) The maximum error in density is nearly (a) \(0.2 \%\) (b) \(2 \%\) (c) \(5 \%\) (d) \(10 \%\)
5 step solution
Problem 96
The velocity of transverse wave in a string is \(v=\sqrt{\frac{T}{M}}\) where \(T\) is the tension in the string and \(M\) is mass per unit length. If \(T=3.0 \mathrm{kgf}\), mass of string is \(2.5 \mathrm{~g}\) and length of string is \(1.00 \mathrm{~m}\), then the percentage error in the measurement of velocity is (a) \(0.5\) (b) \(0.7\) (c) \(2.3\) (d) \(3.6\)
5 step solution
Problem 97
The unit of length convenient on the atomic scale is known as an angstrom and is denoted by Á. \(1 \AA\) \(10^{-10} \mathrm{~m}\). The size of the hydrogen atom is about \(0.5 \mathrm{~A}\). The total atomic volume in \(\mathrm{m}^{3}\) of a mole of hydrogen atoms would be [NCERT] (a) \(3.15 \times 10^{-7} \mathrm{~m}^{3}\) (b) \(3.0 \times 10^{-8} \mathrm{~m}^{3}\) (c) \(3.85 \times 10^{-7} \mathrm{~m}^{3}\) (d) \(2.85 \times 10^{-7} \mathrm{~m}^{3}\)
4 step solution
Problem 98
The relative density of the material of a body is the ratio of its weight in air and the loss of its weight in water. By using a spring balance, the weight of the body in air is measured to be \(5.00 \pm 0.05 \mathrm{~N}\). The weight of the body in water is measured to be \(4.00 \pm 0.05 \mathrm{~N}\). Then, the maximum possible percentage error in relative density is (a) \(11 \%\) (b) 1096 (c) \(9 \%_{6}\) (d) \(7 \%\)
5 step solution
Problem 99
The length \(l\), breadth \(b\) and thickness \(t\) of a block are measured with the help of a metre scale. Given \(l=15.12 \pm 0.01 \mathrm{~cm}, \mathrm{~b}=10.15 \pm 0.01 \mathrm{~cm}, t=5.28 \pm 0.01 \mathrm{~cm}\) The percentage error in volume is (a) \(0.64 \%\) (b) \(0.28 \%\) (c) \(0.37 \%\) (d) \(0.489\)
8 step solution