Chapter 14

A Complete Resource Book in Physics for JEE Main · 68 exercises

Problem 6

A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be (Assuming potential difference is same in both cases). (A) One-fourth (B) Halved (C) Doubled (D) Four times

7 step solution

Problem 10

There are \(n\) similar resistors each of resistance \(R\). The equivalent resistance comes out to be \(x\) when connected in parallel. If they are connected in series, the resistance comes out to be (A) \(x / n^{2}\) (B) \(n^{2} x\) (C) \(x / n\) (D) \(n x\)

3 step solution

Problem 15

A cell of emf \(E\) is connected across a resistance \(R\). The potential difference between the terminals of the cell is found to be \(V\). The internal resistance of the cell must be (A) \(\frac{2(E-V) V}{R}\) (B) \(\frac{2(E-V) R}{E}\) (C) \(\frac{(E-V) R}{V}\) (D) \((E-V) R\)

3 step solution

Problem 20

The resistances \(500 \Omega\) and \(1000 \Omega\) are connected in series with a battery of \(1.5 \mathrm{~V}\). The voltage across the \(1000 \Omega\) resistance is measured by a voltmeter having a resistance of \(1000 \Omega\). The reading in the voltmeter would be (A) \(1.5 \mathrm{~V}\) (B) \(1.0 \mathrm{~V}\) (C) \(0.75 \mathrm{~V}\) (D) \(0.5 \mathrm{~V}\)

7 step solution

Problem 21

A set of \(n\) identical resistors, each of resistance \(R \Omega\), when connected in series, has an effective resistance of \(x\) ohm. When the resistors are connected in parallel, the effective resistance is \(y\) ohm. What is the relation between \(R, x\), and \(y ?\) (A) \(R=\frac{x y}{(x+y)}\) (B) \(R=(y-x)\) (C) \(R=\sqrt{x y}\) (D) \(R=(x+y)\)

6 step solution

Problem 25

Five cells, each of EMF \(E\) and internal resistance \(r\) are connected in series. If due to oversight, one cell is connected wrongly, then the equivalent EMF and internal resistance of the combination, is (A) \(5 E\) and \(5 r\) (B) \(3 E\) and \(3 r\) (C) \(3 E\) and \(5 r\) (D) \(5 E\) and \(3 r\)

4 step solution

Problem 27

A wire with resistance \(12 \Omega\) is bent in the form of a circle. The effective resistance between the two points on any diameter of the circle is (A) \(12 \Omega\) (B) \(24 \Omega\) (C) \(6 \Omega\) (D) \(3 \Omega\)

4 step solution

Problem 28

When cells are connected in series (A) the EMF increases. (B) the potential difference decreases. (C) the current capacity increases. (D) the current capacity decreases.

5 step solution

Problem 29

Which of the following has the maximum resistance? (A) Voltmeter (B) Millivoltmeter (C) Ammeter (D) Milliammeter

3 step solution

Problem 31

A wire \(l=8 \mathrm{~m}\) long of uniform cross-sectional area \(A=8 \mathrm{~mm}^{2}\) has a conductance of \(G=2.45 \Omega^{-1}\). The resistivity of material of the wire will be (A) \(2.1 \times 10^{-7} \Omega \mathrm{m}\) (B) \(3.1 \times 10^{-7} \Omega \mathrm{m}\) (C) \(4.1 \times 10^{-7} \Omega \mathrm{m}\) (D) \(5.1 \times 10^{-7} \Omega \mathrm{m}\)

2 step solution

Problem 32

A galvanometer of resistance \(400 \Omega\) can measure a current of \(1 \mathrm{~mA}\). To convert it into a voltmeter of range \(8 \mathrm{~V}\), the required resistance is (A) \(4600 \Omega\) (B) \(5600 \Omega\) (C) \(6600 \Omega\) (D) \(7600 \Omega\)

5 step solution

Problem 33

An ammeter reads up to \(1 \mathrm{~A}\). Its internal resistance is \(0.81 \Omega\). To increase the range to \(10 \mathrm{~A}\), the value of the required shunt is (A) \(0.03 \Omega\) (B) \(0.3 \Omega\) (C) \(0.9 \Omega\) (D) \(0.09 \Omega\)

4 step solution

Problem 34

The resistance of the series combination of two resistances is \(S\). When they are joined in parallel, the total resistance is \(P\). If \(S=n P\), then the minimum possible value of \(n\) is (A) 4 (B) 3 (C) 2 (D) 1

2 step solution

Problem 35

A wire of resistance \(4 \Omega\) is stretched to twice its original length. What is the resistance of the wire now? (A) \(1 \Omega\) (B) \(14 \Omega\) (C) \(8 \Omega\) (D) \(16 \Omega\)

7 step solution

Problem 43

Kirchhoff's second law is based on the law of conservation of (A) Momentum (B) Charge (C) Energy (D) Sum of mass and energy

3 step solution

Problem 46

What is the current through the resistor \(R\) in the circuit shown below? The EMF of each cell is \(E_{m}\) and internal resistance is \(r\) (A) \(\frac{E_{m}}{2 R+r}\) (B) \(\frac{E_{m}}{2 r+R}\) (C) \(\frac{2 E_{m}}{R+2 r}\) (D) \(\frac{2 E_{m}}{2 R+r}\)

4 step solution

Problem 49

The current at which a fuse wire melts does not depend on its (A) Cross-sectional area (B) Length (C) Resistivity (D) Density

6 step solution

Problem 50

In the circuit shown in Fig. \(14.27\), the heat produced in the \(5 \Omega\) resistor due to a current flowing in it is 10 calories per second. The heat produced in the \(4 \Omega\) resistor is (A) \(1 \mathrm{cal} \mathrm{s}^{-1}\) (B) \(2 \mathrm{cal} \mathrm{s}^{-1}\) (C) \(3 \mathrm{cal} \mathrm{s}^{-1}\) (D) \(4 \mathrm{cal} \mathrm{s}^{-1}\)

4 step solution

Problem 54

\(n\) identical cells, each of emf \(\varepsilon\) and internal resistance \(r\), are joined in series to form a closed circuit. The potential difference across any one cell is (A) Zero (B) \(\varepsilon\) (C) \(\frac{\varepsilon}{n}\) (D) \(\frac{n-1}{n} \varepsilon\)

4 step solution

Problem 62

If \(\mathrm{EMF}\) in a thermocouple is \(\varepsilon=\alpha T+\beta T^{2}\), then the neutral temperature of the thermocouple is (A) \(-\beta /(2 \alpha)\) (B) \(-2 \beta / \alpha\) (C) \(-\alpha /(2 \beta)\) (D) \(-2 \alpha / \beta\)

3 step solution

Problem 63

The charge flowing through a resistance \(R\) varies with time \(t\) as \(Q=a t-b t^{2} .\) The total heat produced in \(R\) from \(t=0\) to the time when value of \(Q\) becomes again zero is (A) \(\frac{a^{3} R}{6 b}\) (B) \(\frac{a^{3} R}{3 b}\) (C) \(\frac{a^{3} R}{2 b}\) (D) \(\frac{a^{3} R}{b}\)

6 step solution

Problem 65

The charge flowing through a resistance \(R\) varies with time \(t\) as \(Q=a t-b t^{2} .\) The total heat produced in \(R\) from \(t=0\) to the time when value of \(Q\) becomes again zero is (A) \(\frac{a^{3} R}{6 b}\) (B) \(\frac{a^{3} R}{3 b}\) (C) \(\frac{a^{3} R}{2 b}\) (D) \(\frac{a^{3} R}{b}\)

6 step solution

Problem 70

In the given circuit, find the equivalent resistance between points \(A\) and \(B\). (A) \(18 \Omega\) (B) \(12 \Omega\) (C) \(20 \Omega\) (D) \(27 \Omega\)

1 step solution

Problem 80

The resistance of a wire is \(10 \Omega\). Its length is increased by \(10 \%\) by stretching. The new resistance will now be nearly (A) \(12 \Omega\) (B) \(1.2 \Omega\) (C) \(13 \Omega\) (D) \(11 \Omega\)

3 step solution

Problem 81

The same mass of copper is drawn into two wires \(1 \mathrm{~mm}\) and \(2 \mathrm{~mm}\) thick. Two wires are connected in series and current is passed through them. Heat produced in the wire is in the ratio (A) \(2: 1\) (B) \(1: 16\) (C) \(4: 1\) (D) \(16: 1\)

3 step solution

Problem 87

\(A B\) is a wire of uniform resistance. The galvanometer \(G\) shows zero current when the length \(A C=20 \mathrm{~cm}\) and \(C B=80 \mathrm{~cm}\). The resistance \(R\) is equal to (A) \(2 \Omega\) (B) \(8 \Omega\) (C) \(20 \Omega\) (D) \(40 \Omega\)

6 step solution

Problem 89

Two cells with the same EMF \(E\) and different internal resistances \(r_{1}\) and \(r_{2}\) are connected in series to an external resistance \(R\). The value of \(R\) for the potential difference across the first cell to be zero is (A) \(\sqrt{r_{1} r_{2}}\) (B) \(r_{1}+r_{2}\) (C) \(r_{1}-r_{2}\) (D) \(\frac{r_{1}+r_{2}}{2}\)

8 step solution

Problem 92

\(A, B\), and \(C\) are voltmeters of resistances \(R, 1.5 R\), and \(3 R\), respectively. When some potential difference is applied between \(X\) and \(Y\), the voltmeter readings are \(V_{A}, V_{B}\), and \(V_{C}\), respectively. (A) \(V_{A}=V_{B}=V_{C}\) (B) \(V_{A} \neq V_{B}=V_{C}\) (C) \(V_{A}=V_{B} \neq V_{C}\) (D) \(V_{B} \neq V_{A}=V_{C}\)

3 step solution

Problem 93

A galvanometer of resistance \(19.5 \Omega\) gives full-scale deflection when a current of \(0.5 \mathrm{~A}\) is passed through it. It is desired to convert it into an ammeter of full-scale current \(20 \mathrm{~A}\). Value of shunt is (A) \(0.5 \Omega\) (B) \(1 \Omega\) (C) \(1.5 \Omega\) (D) \(2 \Omega\)

4 step solution

Problem 94

In the arrangement shown, the magnitude of each resistance is \(2 \Omega\). The equivalent resistance between \(O\) and \(A\) is given by (A) \(\frac{14}{15} \Omega\) (B) \(\frac{7}{15} \Omega\) (C) \(\frac{4}{3} \Omega\) (D) \(\frac{5}{6} \Omega\)

3 step solution

Problem 95

In the circuit shown, if point \(O\) is earthed, the potential of point \(X\) is equal to (A) \(10 \mathrm{~V}\) (B) \(15 \mathrm{~V}\) (C) \(25 \mathrm{~V}\) (D) \(12.5 \mathrm{~V}\)

5 step solution

Problem 99

An ammeter is obtained by shunting a \(30 \Omega\) galvanometer with a \(30 \Omega\) resistance. What additional shunt should be connected across it to double the range? (A) \(15 \Omega\) (B) \(10 \Omega\) (C) \(5 \Omega\) (D) None of these

5 step solution

Problem 105

A voltmeter and an ammeter are connected in series to an ideal cell of EMF \(E\). The voltmeter reading is \(V\), and the ammeter reading is \(I .\) (A) \(V

4 step solution

Problem 106

A dielectric slab of thickness \(d\) is inserted in a parallel plate capacitor whose negative plate is at \(x=0\) and positive plate is at \(x=3 d\). The slab is equidistant from the plates. The capacitor is given some charge. As \(x\) goes from 0 to \(3 d\), (A) the magnitude of the electric field remains the same. (B) the direction of the electric field remains the same. (C) the electric potential increases continuously. (D) the electric potential increases at first, then decreases and again increases.

3 step solution

Problem 107

Two heaters designed for the same voltage \(V\) have different power ratings. When connected individually across a source of voltage \(V\), they produce \(H\) amount of heat each in time \(t_{1}\) and \(t_{2}\), respectively. When used together across the same source, they produce \(H\) amount of heat in time \(t\), (A) if they are in series, \(t=t_{1}+t_{2}\). (B) if they are in series, \(t=2\left(t_{1}+t_{2}\right)\). (C) if they are in parallel, \(t=2\left(t_{1}-t_{2}\right)\). (D) if they are in parallel, \(t=\frac{t_{1} t_{2}}{2\left(t_{1}+t_{2}\right)}\).

5 step solution

Problem 109

A positively charged conducting ball \(B\) is placed inside a cavity of a positively charged conductor \(A \cdot A\) and \(B\) are isolated from each other. If the charges on \(A\) and \(B\) be \(Q\) and \(q(Q>q)\), respectively, then (A) the charge on the outer surface of conductor \(A\) is \(Q+q\) (B) potential of \(B\) is greater than potential of \(A\). (C) when \(B\) touches the surface of \(A\), then potential of \(A\) and \(B\) become same. (D) no charge is left on \(B\) when it touches the surface of \(A\)

4 step solution

Problem 114

The average bulk resistivity of the human body (apart from the surface resistance of the skin) is about \(5 \Omega m\). The conducting path between the hands can be represented approximately as a cylinder \(1.6 \mathrm{~m}\) long and \(0.1 \mathrm{~m}\) diameter. The skin resistance may be made negligible by soaking the hands in salt water. A lethal shock current needed is \(100 \mathrm{~mA}\). Note that a small amount of potential difference could be fatal if the skin is damp. What is the resistance between the hands? (A) \(10^{2} \Omega\) (B) \(10^{3} \Omega\) (C) \(10^{4} \Omega\) (D) None of these

3 step solution

Problem 115

The average bulk resistivity of the human body (apart from the surface resistance of the skin) is about \(5 \Omega m\). The conducting path between the hands can be represented approximately as a cylinder \(1.6 \mathrm{~m}\) long and \(0.1 \mathrm{~m}\) diameter. The skin resistance may be made negligible by soaking the hands in salt water. A lethal shock current needed is \(100 \mathrm{~mA}\). Note that a small amount of potential difference could be fatal if the skin is damp. What potential difference is needed between the hands for a lethal shock current? (A) \(100 \mathrm{~V}\) (B) \(10 \mathrm{~V}\) (C) \(120 \mathrm{~V}\) (D) \(150 \mathrm{~V}\)

4 step solution

Problem 116

The average bulk resistivity of the human body (apart from the surface resistance of the skin) is about \(5 \Omega m\). The conducting path between the hands can be represented approximately as a cylinder \(1.6 \mathrm{~m}\) long and \(0.1 \mathrm{~m}\) diameter. The skin resistance may be made negligible by soaking the hands in salt water. A lethal shock current needed is \(100 \mathrm{~mA}\). Note that a small amount of potential difference could be fatal if the skin is damp. The power dissipated in the body is (A) \(1 \mathrm{~W}\) (B) \(0.1 \mathrm{~W}\) (C) \(100 \mathrm{~W}\) (D) \(10 \mathrm{~W}\)

3 step solution

Problem 117

A potentiometer is a device used for measuring EMF and internal resistance of a cell. It consists of two circuits, one is main circuit in which there is a cell of given emf \(\varepsilon^{\prime}\) and given resistance \(R\) which is connected across a wire of length \(100 \mathrm{~cm}\) and having resistance \(r\) and another circuit having unknown EMF \(\varepsilon\) and galvanometer. For a given potentiometer, if \(\varepsilon^{\prime}=30 \mathrm{~V}, r=1 \Omega\), and resistance \(R\) varies with time \(t\) given by \(R=2 t\). The jockey can move on wire with constant velocity \(10 \mathrm{~cm} / \mathrm{s}\) and switch \(S\) is closed at \(t=0\)If jockey starts moving from \(A\) at \(t=0\) and balancing point found at \(t=1 \mathrm{~s}\) then the value of \(\varepsilon\) is (A) \(1 \mathrm{~V}\) (B) \(2 \mathrm{~V}\) (C) \(3 \mathrm{C}\) (D) \(4 \mathrm{~V}\)

4 step solution

Problem 119

A potentiometer is a device used for measuring EMF and internal resistance of a cell. It consists of two circuits, one is main circuit in which there is a cell of given emf \(\varepsilon^{\prime}\) and given resistance \(R\) which is connected across a wire of length \(100 \mathrm{~cm}\) and having resistance \(r\) and another circuit having unknown EMF \(\varepsilon\) and galvanometer. For a given potentiometer, if \(\varepsilon^{\prime}=30 \mathrm{~V}, r=1 \Omega\), and resistance \(R\) varies with time \(t\) given by \(R=2 t\). The jockey can move on wire with constant velocity \(10 \mathrm{~cm} / \mathrm{s}\) and switch \(S\) is closed at \(t=0\) If balancing length is found to be \(70 \mathrm{~cm}\), then the time after which jockey starts moving from \(A\) is (A) \(1 \mathrm{~s}\) (B) \(2 \mathrm{~s}\) (C) \(3 \mathrm{~s}\) (D) \(4 \mathrm{~s}\)

4 step solution

Problem 120

Figure \(14.47\) shows the circuit of a potentiometer. The length of the potentiometer wire \(A B\) is \(50 \mathrm{~cm}\). The EMF \(E_{1}\) of the battery is \(4 \mathrm{~V}\), having negligible internal resistance. Value of \(R_{1}\) and \(R_{2}\) are \(15 \Omega\) and \(5 \Omega\), respectively. When both the keys are open, the null point is obtained at a distance of \(31.25 \mathrm{~cm}\) from \(A\), but when both the keys are closed, the balance length reduces to \(5 \mathrm{~cm}\) only. Given \(R_{A B}=10 \Omega\)The EMF of the cell \(E_{2}\) is (A) \(1 \mathrm{~V}\) (B) \(2 \mathrm{~V}\) (C) \(3 \mathrm{~V}\) (D) \(4 \mathrm{~V}\)

4 step solution

Problem 121

Figure \(14.47\) shows the circuit of a potentiometer. The length of the potentiometer wire \(A B\) is \(50 \mathrm{~cm}\). The EMF \(E_{1}\) of the battery is \(4 \mathrm{~V}\), having negligible internal resistance. Value of \(R_{1}\) and \(R_{2}\) are \(15 \Omega\) and \(5 \Omega\), respectively. When both the keys are open, the null point is obtained at a distance of \(31.25 \mathrm{~cm}\) from \(A\), but when both the keys are closed, the balance length reduces to \(5 \mathrm{~cm}\) only. Given \(R_{A B}=10 \Omega\) The internal resistance of the cell \(E_{2}\) is (A) \(4.5 \Omega\) (B) \(5.5 \Omega\) (C) \(6.5 \Omega\) (D) \(7.5 \Omega\)

4 step solution

Problem 122

Figure \(14.47\) shows the circuit of a potentiometer. The length of the potentiometer wire \(A B\) is \(50 \mathrm{~cm}\). The EMF \(E_{1}\) of the battery is \(4 \mathrm{~V}\), having negligible internal resistance. Value of \(R_{1}\) and \(R_{2}\) are \(15 \Omega\) and \(5 \Omega\), respectively. When both the keys are open, the null point is obtained at a distance of \(31.25 \mathrm{~cm}\) from \(A\), but when both the keys are closed, the balance length reduces to \(5 \mathrm{~cm}\) only. Given \(R_{A B}=10 \Omega\) The balance length when key \(K_{2}\) is open and \(K_{1}\) is closed is given by (A) \(10.5 \mathrm{~cm}\) (B) \(11.5 \mathrm{~cm}\) (C) \(12.5 \mathrm{~cm}\) (D) \(13.5 \mathrm{~cm}\)

4 step solution

Problem 123

Figure \(14.47\) shows the circuit of a potentiometer. The length of the potentiometer wire \(A B\) is \(50 \mathrm{~cm}\). The EMF \(E_{1}\) of the battery is \(4 \mathrm{~V}\), having negligible internal resistance. Value of \(R_{1}\) and \(R_{2}\) are \(15 \Omega\) and \(5 \Omega\), respectively. When both the keys are open, the null point is obtained at a distance of \(31.25 \mathrm{~cm}\) from \(A\), but when both the keys are closed, the balance length reduces to \(5 \mathrm{~cm}\) only. Given \(R_{A B}=10 \Omega\) The balance length when key \(K_{1}\) is open and \(K_{2}\) is closed is given by (A) \(10.5 \mathrm{~cm}\) (B) \(11.5 \mathrm{~cm}\) (C) \(12.5 \mathrm{~cm}\) (D) \(25 \mathrm{~cm}\)

4 step solution

Problem 130

Consider two identical cells each of \(\mathrm{EMF} E\) and internal resistance \(r\) connected to a load resistance \(R\) Column-I Column-II (A) For maximum power 1\. \(\frac{E^{2}}{4 r}\) transferred to load if cells are connected in series (B) For maximum power transferred to load if 2\. \(\frac{E^{2}}{2 r}\) cells are connected in parallel (C) For series combina- 3\. \(E_{\mathrm{eq}}=E, r_{\mathrm{eq}}=\frac{r}{2}\) tion of cells (D) For parallel combina- 4\. \(E_{\mathrm{eq}}=2 E, r_{\mathrm{eq}}=2 r\) tion of cells

4 step solution

Problem 140

Assertion: Three identical very large metallic plates having charges \(Q,-Q\), and \(3 Q\), respectively are placed parallel. If middle is earthed through a switch, then charge flow through the switch is \(-Q\). Reason: In above assertion, final charge on middle plate is \(-4 Q\). (A) A (B) \(\mathrm{B}\) (C) \(\mathrm{C}\) (D) D

6 step solution

Problem 144

A resistance of \(4 \Omega\) and a wire of length \(5 \mathrm{~m}\) and resistance \(5 \Omega\) are joined in series and connected to a cell of EMF \(10 \mathrm{~V}\) and internal resistance \(1 \Omega\). A parallel combination of two identical cells is balanced across \(300 \mathrm{~cm}\) of the wire. The EMF of each cell is

4 step solution

Problem 155

Two conductors have the same resistance at \(0^{\circ} \mathrm{C}\) but their temperature coefficients of resistance are \(\alpha_{1}\) and \(\alpha_{2} .\) The respective temperature coefficients of their series and parallel combinations are nearly (A) \(\frac{\alpha_{1}+\alpha_{2}}{2}, \alpha_{1}+\alpha_{2}\) (B) \(\alpha_{1}+\alpha_{2}, \frac{\alpha_{1}+\alpha_{2}}{2}\) (C) \(\alpha_{1}+\alpha_{2}, \frac{\alpha_{1} \alpha_{2}}{\alpha_{1}+\alpha_{2}}\) (D) \(\frac{\alpha_{1}+\alpha_{2}}{2}, \frac{\alpha_{1}+\alpha_{2}}{2}\)

3 step solution

Problem 156

The resistance of a wire is \(5 \Omega\) at \(50^{\circ} \mathrm{C}\) and \(6 \Omega\) at \(100^{\circ} \mathrm{C}\). The resistance of the wire at \(0^{\circ} \mathrm{C}\) will be (A) \(2 \Omega\) (B) \(1 \Omega\) (C) \(4 \Omega\) (D) \(3 \Omega\)

6 step solution

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