Chapter 6

Thomas Calculus · 169 exercises

Problem 12

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region bounded by the parabola \(x=y^{2}-y\) and the line \(y=x\)

5 step solution

Problem 12

Find the volume of the given pyramid, which has a square base of area 9 and height 5.

5 step solution

Problem 12

Find the lengths of the curves in Exercises \(1-12 .\) If you have graphing software, you may want to graph these curves to see what they look like. $$y=\int_{-2}^{x} \sqrt{3 t^{4}-1} d t, \quad-2 \leq x \leq-1$$

5 step solution

Problem 12

Force of attraction When a particle of mass \(m\) is at \((x, 0),\) it is attracted toward the origin with a force whose magnitude is \(k / x^{2}\) . If the particle starts from rest at \(x=b\) and is acted on by no other forces, find the work done on it by the time it reaches \(x=a\) \(0 < a < b .\)

6 step solution

Problem 13

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region bounded by the \(x\) -axis and the curve \(y=\cos x,\) \(-\pi / 2 \leq x \leq \pi / 2\)

8 step solution

Problem 13

A twisted solid A square of side length \(s\) lies in a plane perpendicular to a line \(L .\) One vertex of the square lies on \(L .\) As this square moves a distance \(h\) along \(L,\) the square turns one revolution about \(L\) to generate a corkscrew-like column with square cross-sections. a. Find the volume of the column. b. What will the volume be if the square turns twice instead of once? Give reasons for your answer.

6 step solution

Problem 13

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$y=x^{2},-1 \leq x \leq 2$$

3 step solution

Problem 14

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$y = \sqrt { 2 x - x ^ { 2 } } , \quad 0.5 \leq x \leq 1.5 ; \quad x -axis$$

6 step solution

Problem 14

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region between the curve \(y=\sec ^{2} x,-\pi / 4 \leq x \leq \pi / 4\) and the \(x\) -axis

7 step solution

Problem 14

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$y=\tan x, \quad-\pi / 3 \leq x \leq 0$$

4 step solution

Problem 15

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$y = \sqrt { 2 x - x ^ { 2 } } , \quad 0.5 \leq x \leq 1.5 ; \quad x -axis$$

6 step solution

Problem 15

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. \begin{equation}\begin{array}{l}{\text { a. The region cut from the first quadrant by the circle } x^{2}+y^{2}=9} \\ {\text { b. The region bounded by the } x \text { -axis and the semicircle }} \\ {y=\sqrt{9-x^{2}}} \\ {\text { Compare your answer in part (b) with the answer in part (a). }}\end{array} \end{equation}

10 step solution

Problem 15

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$x=\sin y, \quad 0 \leq y \leq \pi$$

4 step solution

Problem 16

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$y = \sqrt { x + 1 } , \quad 1 \leq x \leq 5 ; \quad x -axis$$

6 step solution

Problem 16

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region bounded by the parabolas \(y=2 x^{2}-4 x\) and \(y=2 x-x^{2}\)

5 step solution

Problem 16

Gasoline in a tank A gasoline tank is in the shape of a right circular cylinder (lying on its side) of length 10 \(\mathrm{ft}\) and radius 4 ft. Set up an integral that represents the volume of the gas in the tank if it is filled to a depth of 6 ft. You will learn how to compute this integral in Chapter 8 (or you may use geometry to find its value).

7 step solution

Problem 16

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$x=\sqrt{1-y^{2}}, \quad-1 / 2 \leq y \leq 1 / 2$$

4 step solution

Problem 17

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$x = y ^ { 3 } / 3 , \quad 0 \leq y \leq 1 ; \quad y -axis$$

5 step solution

Problem 17

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region between the curve \(y=1 / \sqrt{x}\) and the \(x\) -axis from \(x=1\) to \(x=16\)

7 step solution

Problem 18

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. The region bounded above by the curve \(y=1 / x^{3}\) , below by the curve \(y=-1 / x^{3},\) and on the left and right by the lines \(x=1\) and \(x=a>1 .\) Also, find \(\lim _{a \rightarrow \infty} \overline{x}\)

7 step solution

Problem 18

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$y=\sin x-x \cos x, \quad 0 \leq x \leq \pi$$

5 step solution

Problem 19

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$x = 2 \sqrt { 4 - y } , \quad 0 \leq y \leq 15 / 4 ; \quad y -axis$$

7 step solution

Problem 19

Emptying a tank A vertical right-circular cylindrical tank measures 30 \(\mathrm{ft}\) high and 20 \(\mathrm{ft}\) in diameter. It is full of kerosene weighing 51.2 \(\mathrm{lb} / \mathrm{ft}^{3} .\) How much work does it take to pump the kerosene to the level of the top of the tank?

7 step solution

Problem 19

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$y=\int_{0}^{x} \tan t d t, \quad 0 \leq x \leq \pi / 6$$

5 step solution

Problem 20

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$x = \sqrt { 2 y - 1 } , \quad 5 / 8 \leq y \leq 1 ; \quad y -axis$$

9 step solution

Problem 20

In Exercises \(18,\) find the center of mass of a thin plate of constant density \(\delta\) covering the given region. Consider a thin plate of constant density \(\delta\) lies in the region bounded by the graphs of \(y=\sqrt{x}\) and \(x=2 y .\) Find the plate's \begin{equation}\begin{array}{l}{\text { a. moment about the } x \text { -axis. }} \\ {\text { b. moment about the } y \text { -axis. }} \\ {\text { c. moment about the line } x=5 \text { . }} \\ {\text { d. moment about the line } x=-1} \\ {\text { e. moment about the line } y=2 \text { . }} \\\ {\text { f. moment about the line } y=-3 \text { . }} \\ {\text { g. mass. }} \\\ {\text { h. center of mass. }}\end{array}\end{equation}

8 step solution

Problem 20

In Exercises \(13-20,\) do the following. \begin{equation}\begin{array}{l}{\text { a. Set up an integral for the length of the curve. }} \\ {\text { b. Graph the curve to see what it looks like. }} \\\ {\text { c. Use your grapher's or computer's integral evaluator to find }} \\\ {\text { the curve's length numerically. }}\end{array}\end{equation} $$x=\int_{0}^{y} \sqrt{\sec ^{2} t-1} d t, \quad-\pi / 3 \leq y \leq \pi / 4$$

6 step solution

Problem 21

Find the areas of the surfaces generated by revolving the curves in Exercises \(13 - 23\) about the indicated axes. If you have a grapher, you may want to graph these curves to see what they look like. $$y = ( 1 / 2 ) \left( x ^ { 2 } + 1 \right) , \quad 0 \leq x \leq 1 ; \quad y -axis$$

9 step solution

Problem 21

Find the center of mass of a thin plate covering the region between the \(x\) -axis and the curve \(y=2 / x^{2}, 1 \leq x \leq 2,\) if the plate's den- sity at the point \((x, y)\) is \(\delta(x)=x^{2}\)

6 step solution

Problem 21

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\)-axis. \(y=x^{2}, \quad y=0, \quad x=2\)

5 step solution

Problem 21

The graph of \(y=x^{2}\) on \(0 \leq x \leq 2\) is revolved about the \(y\)-axis to form a tank that is then filled with salt water from the Dead Sea (weighing approximately 73 lb/ \(\mathrm{ft}^{3}\) . How much work does it take to pump all of the water to the top of the tank?

8 step solution

Problem 22

Find the center of mass of a thin plate covering the region bounded below by the parabola \(y=x^{2}\) and above by the line \(y=x\) if the plate's density at the point \((x, y)\) is \(\delta(x)=12 x\) .

8 step solution

Problem 22

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\)-axis. \(y=x^{3}, \quad y=0, \quad x=2\)

6 step solution

Problem 22

A right-circular cylindrical tank of height 10 \(\mathrm{ft}\) and radius 5 \(\mathrm{ft}\) is lying horizontally and is full of diesel fuel weighing 53 \(\mathrm{lb} / \mathrm{ft}^{3}\). How much work is required to pump all of the fuel to a point 15 \(\mathrm{ft}\) above the top of the tank?

8 step solution

Problem 23

The region bounded by the curves \(y=\pm 4 / \sqrt{x}\) and the lines \(x=1\) and \(x=4\) is revolved about the \(y\) -axis to generate a solid. \begin{equation}\begin{array}{l}{\text { a. Find the volume of the solid. }} \\\ {\text { b. Find the center of mass of a thin plate covering the region if }} \\ {\text { the plate's density at the point }(x, y) \text { is } \delta(x)=1 / x \text { . }} \\ {\text { c. Sketch the plate and show the center of mass in your sketch. }}\end{array}\end{equation}

7 step solution

Problem 23

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\) -axis. $$ y=\sqrt{9-x^{2}}, \quad y=0 $$

5 step solution

Problem 23

In Exercises \(23-26,\) use the shell method to find the volumes of the solids generated by revolving the regions bounded by the given curves about the given lines. \(y=3 x, \quad y=0, \quad x=2\) a. The \(y\) -axis b. The line \(x=4\) c. The line \(x=-1\) d. The \(x\) -axis e. The line \(y=7\) f. The line \(y=-2\)

8 step solution

Problem 23

Emptying a water reservoir We model pumping from spherical containers the way we do from other containers, with the axis of integration along the vertical axis of the sphere. Use the figure here to find how much work it takes to empty a full hemispherical water reservoir of radius 5 \(\mathrm{m}\) by pumping the water to a height of 4 \(\mathrm{m}\) above the top of the reservoir. Water weighs 9800 \(\mathrm{N} / \mathrm{m}^{3} .\)

9 step solution

Problem 23

Find the length of the curve $$y=\int_{0}^{x} \sqrt{\cos 2 t} d t$$ from \(x=0\) to \(x=\pi / 4\)

6 step solution

Problem 24

Write an integral for the area of the surface generated by revolving the curve \(y = \cos x , - \pi / 2 \leq x \leq \pi / 2 ,\) about the \(x\) -axis. In Section 8.4 we will see how to evaluate such integrals.

4 step solution

Problem 24

The region between the curve \(y=2 / x\) and the \(x\) -axis from \(x=1\) to \(x=4\) is revolved about the \(x\) -axis to generate a solid. \begin{equation}\begin{array}{l}{\text { a. Find the volume of the solid. }} \\\ {\text { b. Find the center of mass of a thin plate covering the region if }} \\ {\text { the plate's density at the point }(x, y) \text { is } \delta(x)=\sqrt{x} \text { . }} \\ {\text { c. Sketch the plate and show the center of mass in your sketch. }}\end{array}\end{equation}

4 step solution

Problem 24

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\)-axis. \(y=x-x^{2}, \quad y=0\)

7 step solution

Problem 24

In Exercises \(23-26,\) use the shell method to find the volumes of the solids generated by revolving the regions bounded by the given curves about the given lines. \(y=x^{3}, \quad y=8, \quad x=0\) $$ \begin{array}{ll}{\text { a. The } y \text { -axis }} & {\text { b. The line } x=3} \\ {\text { c. The line } x=-2} & {\text { d. The } x \text { -axis }} \\\ {\text { e. The line } y=8} & {\text { f. The line } y=-1}\end{array} $$

8 step solution

Problem 24

The length of an astroid The graph of the equation \(x^{2 / 3}+\) \(y^{2 / 3}=1\) is one of a family of curves called astroids (not "asteroids") because of their starlike appearance (see the accompanying figure. Find the length of this particular astroid by finding the length of half the first-quadrant portion, \(y=\left(1-x^{2 / 3}\right)^{3 / 2}\) \(\sqrt{2} / 4 \leq x \leq 1,\) and multiplying by \(8 .\)

8 step solution

Problem 25

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\)-axis. \(y=\sqrt{\cos x}, \quad 0 \leq x \leq \pi / 2, \quad y=0, \quad x=0\)

5 step solution

Problem 25

In Exercises \(23-26,\) use the shell method to find the volumes of the solids generated by revolving the regions bounded by the given curves about the given lines. \(y=x+2, \quad y=x^{2}\) $$ \begin{array}{ll}{\text { a. The line } x=2} & {\text { b. The line } x=-1} \\\ {\text { c. The } x \text { -axis }} & {\text { d. The line } y=4}\end{array} $$

6 step solution

Problem 25

Kinetic energy If a variable force of magnitude \(F(x)\) moves an object of mass \(m\) along the \(x\) -axis from \(x_{1}\) to \(x_{2},\) the object's velocity \(v\) can be written as \(d x / d t\) (where \(t\) represents time). Use Newton's second law of motion \(F=m(d v / d t)\) and the Chain Rule \begin{equation}\frac{d v}{d t}=\frac{d v}{d x} \frac{d x}{d t}=v \frac{d v}{d x}\end{equation} to show that the net work done by the force in moving the object from \(x_{1}\) to \(x_{2}\) is \begin{equation}W=\int_{x_{1}}^{x_{2}} F(x) d x=\frac{1}{2} m v_{2}^{2}-\frac{1}{2} m v_{1}^{2},\end{equation} where \(v_{1}\) and \(v_{2}\) are the object's velocities at \(x_{1}\) and \(x_{2} .\) In physics, the expression \((1 / 2) m v^{2}\) is called the kinetic energy of an object of mass \(m\) moving with velocity \(v .\) Therefore, the work done by the force equals the change in the object's kinetic energy, and we can find the work by calculating this change.

8 step solution

Problem 26

Testing the new definition The lateral (side) surface area of a cone of height \(h\) and base radius \(r\) should be \(\pi r \sqrt { r ^ { 2 } + h ^ { 2 } }\) , the semiperimeter of the base times the slant height. Show that this is still the case by finding the area of the surface generated by revolving the line segment \(y = ( r / h ) x , 0 \leq x \leq h ,\) about the \(x\) -axis.

6 step solution

Problem 26

Find the volumes of the solids generated by revolving the regions bounded by the lines and curves about the \(x\)-axis. \(y=\sec x, \quad y=0, \quad x=-\pi / 4, \quad x=\pi / 4\)

6 step solution

Problem 26

In Exercises \(23-26,\) use the shell method to find the volumes of the solids generated by revolving the regions bounded by the given curves about the given lines. \(y=x^{4}, \quad y=4-3 x^{2}\) $$ \text { a. The }x=1 \quad \text { b. The x-axis} $$

7 step solution

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