Chapter 11
Thomas Calculus · 313 exercises
Problem 71
The width of a parabola at the focus Show that the number 4\(p\) is the width of the parabola \(x^{2}=4 p y(p>0)\) at the focus by showing that the line \(y=p\) cuts the parabola at points that are 4\(p\) units apart.
4 step solution
Problem 72
Graph the lines and conic sections in Exercises \(65-74.\) $$r=1 /(1+\cos \theta)$$
5 step solution
Problem 72
The asymptotes of \(\left(x^{2} / a^{2}\right)-\left(y^{2} / b^{2}\right)=1\) Show that the vertical distance between the line \(y=(b / a) x\) and the upper half of the right-hand branch \(y=(b / a) \sqrt{x^{2}-a^{2}}\) of the hyperbola \(\left(x^{2} / a^{2}\right)-\left(y^{2} / b^{2}\right)=1\) approaches 0 by showing that $$ \lim _{x \rightarrow \infty}\left(\frac{b}{a} x-\frac{b}{a} \sqrt{x^{2}-a^{2}}\right)=\frac{b}{a} \lim _{x \rightarrow \infty}\left(x-\sqrt{x^{2}-a^{2}}\right)=0 $$ Similar results hold for the remaining portions of the hyperbola and the lines \(y=\pm(b / a) x .\)
5 step solution
Problem 73
Area Find the dimensions of the rectangle of largest area that can be inscribed in the ellipse \(x^{2}+4 y^{2}=4\) with its sides parallel to the coordinate axes. What is the area of the rectangle?
9 step solution
Problem 74
Volume Find the volume of the solid generated by revolving the region enclosed by the ellipse \(9 x^{2}+4 y^{2}=36\) about the (a) \(x\) -axis, (b) \(y\) -axis.
6 step solution
Problem 74
Graph the lines and conic sections in Exercises \(65-74.\) $$r=1 /(1+2 \cos \theta)$$
3 step solution
Problem 75
Volume The "triangular" region in the first quadrant bounded by the \(x\) -axis, the line \(x=4,\) and the hyperbola \(9 x^{2}-4 y^{2}=36\) is revolved about the \(x\) -axis to generate a solid. Find the volume of the solid.
6 step solution
Problem 76
Tangents Show that the tangents to the curve \(y^{2}=4 p x\) from any point on the line \(x=-p\) are perpendicular.
6 step solution
Problem 77
Tangents Find equations for the tangents to the circle \((x-2)^{2}+(y-1)^{2}=5\) at the points where the circle crosses the coordinate axes.
3 step solution
Problem 78
Volume The region bounded on the left by the \(y\) -axis, on the right by the hyperbola \(x^{2}-y^{2}=1,\) and above and below by the lines \(y=\pm 3\) is revolved about the \(y\) -axis to generate a solid. Find the volume of the solid.
6 step solution
Problem 79
Centroid Find the centroid of the region that is bounded below by the \(x\) -axis and above by the ellipse \(\left(x^{2} / 9\right)+\left(y^{2} / 16\right)=1\)
6 step solution
Problem 80
Surface area The curve \(y=\sqrt{x^{2}+1}, 0 \leq x \leq \sqrt{2},\) which is part of the upper branch of the hyperbola \(y^{2}-x^{2}=1,\) is revolved about the \(x\) -axis to generate a surface. Find the area of the surface.
8 step solution
Problem 81
The reflective property of parabolas The accompanying figure shows a typical point \(P\left(x_{0}, y_{0}\right)\) on the parabola \(y^{2}=4 p x\) . The line \(L\) is tangent to the parabola at \(P .\) The parabola's focus lies at \(F(p, 0) .\) The ray \(L^{\prime}\) extending from \(P\) to the right is parallel to the \(x\) -axis. We show that light from \(F\) to \(P\) will be reflected out along \(L^{\prime}\) by showing that \(\beta\) equals \(\alpha .\) Establish this equality by taking the following steps. $$ \begin{array}{l}{\text { a. Show that } \tan \beta=2 p / y_{0}} \\ {\text { b. Show that } \tan \phi=y_{0} /\left(x_{0}-p\right)} \\ {\text { c. Use the identity }}\end{array} $$ $$ \tan \alpha=\frac{\tan \phi-\tan \beta}{1+\tan \phi \tan \beta} $$ \(\begin{aligned} & \text { to show that } \tan \alpha=2 p / y_{0} \\ \text { since } \alpha \text { and } \beta & \text { are both acute, tan } \beta=\tan \alpha \text { implies } \beta=\alpha \end{aligned}\) $$ \begin{array}{l}{\text { This reflective property of parabolas is used in applications like }} \\ {\text { car headlights, radio telescopes, and satellite TV dishes. }}\end{array} $$
3 step solution