Chapter 9
Mathematics for IIT JEE Main and Advanced Differential Calculus Algebra Trigonometry · 307 exercises
Problem 54
Find an A.P. in which sum of any number of terms is always three times the squared number of these terms.
4 step solution
Problem 56
Sum of certain consecutive odd positive integers is \(57^{2}-13^{2}\). Find them.
4 step solution
Problem 57
150 workers were engaged to finish a piece of work in a certain number of days. Four workers dropped the second day, four more workers dropped the third day and so on. It takes 8 more days to finish the work now. Find the number of days in which the work was completed. \
4 step solution
Problem 58
Along a road lie an odd number of stones placed at intervals of 10 meters. These stones have to be assembled around the middle stone. A person can carry only one stone at a time. A man carried the job with one of the end stones by carrying them in succession. In carrying all the stones he covered a distance of \(3 \mathrm{~km}\). Find the number of stones.
3 step solution
Problem 59
Balls are arranged in rows to from an equilateral triangle. The first row consists of one ball, the second row of two balls and so on. If 669 more balls are added then all the ball can be arranged in the shape of a square and each of the sides then contains 8 balls less then each side of the triangle did. Determine the initial numbers of balls.
4 step solution
Problem 60
Certain numbers appear in both arithmetic progressions \(17,21,25, \ldots\) and \(16,21,26, \ldots\) Find the sum of first hundred numbers appearing in both progressions.
4 step solution
Problem 61
Let \(S_{n}\) denote the sum of first \(n\) terms of an A.P. If \(S_{2 n}=3 S_{n}\), then find the ratio \(\frac{S_{3 n}}{S_{n}}\)
8 step solution
Problem 62
If \(S_{n}=Q n^{2}+P n\), where \(S_{n}\) denotes the sum of the first \(n\) terms of an A.P., then show that the third term is \(P+5 Q\).
5 step solution
Problem 63
The first and last term of an A.P. are \(a\) and \(l\) respectively. If \(S\) be the sum of all the term of the A.P., show that the common difference is \(\frac{l^{2}-a^{2}}{2 S-(l+a)}\).
9 step solution
Problem 64
Show that the sum of an A.P. whose first term is \(a\), second term is \(b\) and the last term is \(c\) is equal to \(\frac{(a+c)(b+c-2 a)}{2(b-a)}\)
4 step solution
Problem 65
If the ratio of the sum of \(m\) term and \(n\) terms of an A.P. be \(m^{2}: n^{2}\), prove that the ratio of its \(m\) th and \(n\) th terms will be \(2 m-1: 2 n-1\).
5 step solution
Problem 66
The ratio between the sum of \(n\) term of two A.P.'s is \(3 n+8: 7 n+15\). Find the ratio between their 12 th terms. Also find the ratio of their common difference.
3 step solution
Problem 67
The ratio between the sum of \(n\) term of two A.P.'s is \(7 n+1: 4 n+27\). Find the ratio between their \(n\) th terms.
3 step solution
Problem 68
The sum of the first \(n\) term of two A.P.'s are as \(3 n+5: 5 n-9\). Prove that their 4 th terms are equal.
4 step solution
Problem 69
The \(p\) th term of an A.P. is \(a\) and \(q\) th term is \(b\). Prove that sum of its \((p+q)\) terms is \(\frac{p+q}{2}\left[a+b+\frac{a-b}{p-q}\right.\).
6 step solution
Problem 70
If the sums of \(p, q\) and \(r\) terms of an A.P. be \(a, b\) and \(c\) respectively then prove that \(\frac{a}{p}(q-r)+\frac{b}{q}(r-p)+\frac{c}{r}(p-q)=0\)
3 step solution
Problem 71
If in an A.P the sum of \(p\) terms is equal to sum of \(q\) terms, then prove that the sum of \(p+q\) terms is zero.
3 step solution
Problem 72
In an A.P., of which \(a\) is the first term, if the sum of the first \(p\) terms is zero, show that the sum of the next \(q\) terms is \(-\frac{a(p+q) q}{p-1}\).
4 step solution
Problem 73
The sum of first \(p\) terms of an A.P. is \(q\) and the sum of the first \(q\) terms is \(p\). Find the sum of the first \(p+q\) terms.
4 step solution
Problem 74
Prove that the sum of the latter half of \(2 n\) terms of any A.P. is one-third the sum of \(3 n\) terms of the same A.P.
5 step solution
Problem 75
The sums of \(n\) terms of three arithmetical progressions are \(S_{1}, S_{2}\) and \(S_{3}\). The first term of each is unity and the common differences are 1,2 and 3 respectively. Prove that \(S_{1}+S_{3}=2 S_{2}\).
3 step solution
Problem 76
The sums of \(n, 2 n, 3 n\) terms of an A.P. are \(S_{1}, S_{2}, S_{3}\) respectively. Prove that \(S_{3}=3\left(S_{2}-S_{1}\right)\).
5 step solution
Problem 78
There are \(n\) A.P.'s whose common difference are \(1,2,3, \ldots n\) respectively, the first term of each being unity. Prove that sum of their \(n\) th terms is \(\frac{1}{2} n\left(n^{2}+1\right)\).
4 step solution
Problem 79
If there be \(m\) A.P.'s beginning with unity whose common differences are \(1,2,3, \ldots m\) respectively, show that the sum of their \(n\) th terms is \(\frac{1}{2} m[m n-m+n+1]\).
4 step solution
Problem 80
The sum of \(n\) terms of \(m\) arithmetical progressions are \(S_{1}, S_{2}, S_{3}, \ldots . S_{m}\). The first term and common differences are \(1,2,3, \ldots, m\) respectively. Prove that \(S_{1}+S_{2}+S_{3}+\ldots+S_{m}=\frac{1}{4} m n(m+1)(n+1)\).
5 step solution
Problem 81
If \(S_{1}, S_{2}, S_{3}, \ldots, S_{m}\) are the sums of \(n\) term of \(m\) A.P.'s whose first terms are \(1,2,3, \ldots, m\) and common differences are \(1,3,5, \ldots ., 2 m-1\) respectively. Show that \(S_{1}+S_{2}+S_{3}+\ldots+S_{m}=\frac{1}{2} m n(m n+1)\).
4 step solution
Problem 82
If the sum of \(m\) terms of an A.P. is equal to sum of either the next \(n\) terms or the next \(p\) terms, prove that \((m+n)\left(\frac{1}{m}-\frac{1}{p}\right)=(m+p)\left(\frac{1}{m}-\frac{1}{n}\right) .\)
4 step solution
Problem 83
Show that in arithmetical progression \(a_{1}, a_{2}, a_{3}, \ldots ., a_{1}^{2}-a_{2}^{2}+a_{3}^{2}-a_{4}^{2}+\ldots-a_{2 k}^{2}=\frac{k}{2 k-1}\left(a_{1}^{2}-a_{2 k}{\underline{\phantom{xx}}}^{2}\right)\)
5 step solution
Problem 84
If \(a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) be an A.P. of non-zero terms prove that i. \(\frac{1}{a_{1} a_{n}}+\frac{1}{a_{2} a_{n-1}}+\frac{1}{a_{3} a_{n-2}}+\ldots+\frac{1}{a_{n} a_{1}}=\frac{2}{a_{1}+a_{n}}\left(\frac{1}{a_{1}}+\frac{1}{a_{2}}+\ldots+\frac{1}{a_{n}}\right)\) ii. \(\frac{1}{a_{1} a_{2}}+\frac{1}{a_{2} a_{3}}+\ldots+\frac{1}{a_{n-1} a_{n}}=\frac{n-1}{a_{1} a_{n}}\).
6 step solution
Problem 85
If \(a_{1}, a_{2}, a_{3}, \ldots, a_{n}\) are in A.P. where \(a_{i}>0\) for all \(i\), show that \(\frac{1}{\sqrt{a_{1}}+\sqrt{a_{2}}}+\frac{1}{\sqrt{a_{2}}+\sqrt{a_{3}}}+\cdots \cdots+\frac{1}{\sqrt{a_{n-1}}+\sqrt{a_{n}}}=\frac{n-1}{\sqrt{a_{1}}+\sqrt{a_{n}}}\)
3 step solution
Problem 86
Let the sequence \(a_{1}, a_{2}, a_{3}, \ldots ., a_{n}\) from an A.P. and let \(a_{1}=0\), prove that \(\frac{a_{3}}{a_{2}}+\frac{a_{4}}{a_{3}}+\frac{a_{5}}{a_{4}}+\ldots+\frac{a_{n}}{a_{n-1}}-a_{2}\left(\frac{1}{a_{2}}+\frac{1}{a_{3}}+\ldots+\frac{1}{a_{n-2}}\right)=\frac{a_{n-1}}{a_{2}}+\frac{a_{2}}{a_{n-1}}\)
3 step solution
Problem 87
Find fifth of the ten arithmetic means inserted between 1 and 100 .
2 step solution
Problem 88
If \(a, b, c, d, e, f\) are AM's between 2 and 12, then find the value of \(a+b+c+d+e+f\).
4 step solution
Problem 89
The sum of two numbers is \(2 \frac{1}{6}\). An even number of arithmetic means are being inserted between them and their sum exceeds their number by 1. Find the number of means inserted.
4 step solution
Problem 90
Between 1 and 31 are inserted \(m\) arithmetic means so that the ratio of the 7 th and \((m-1)\) th means is \(5: 9\). Find the value of \(m\)
4 step solution
Problem 91
Prove that the sum of the \(n\) arithmetic means inserted between two quantities is \(n\) times the single arithmetic mean between them.
6 step solution
Problem 92
For what value of \(n, \frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}}\) is the arithmetic mean of \(a\) and \(b ?\)
9 step solution
Problem 93
If \(x, 2 x+2,3 x+3\) are in GP, then find the fourth term.
4 step solution
Problem 94
Find three numbers in G.P. whose sum is 65 and whose product is 3375 .
3 step solution
Problem 95
The product of three numbers in G.P. is 125 and sum of their products taken in pairs is \(87 \frac{1}{2}\). Find them.
6 step solution
Problem 96
If the product of three numbers in G.P. is 216 and sum of the products taken in pairs is 156 , find the numbers.
10 step solution
Problem 97
Three numbers are in G.P. whose sum is 70 . If the extremes be each multiplied by 4 and the mean by 5 , they will be in A.P. Find the numbers.
9 step solution
Problem 98
The sum of three numbers in G.P. is 14 . If the first two terms are each increased by 1 and the third term decreased by 1 , the resulting numbers are in A.P. Find the numbers.
9 step solution
Problem 99
Three numbers whose sum is 15 are in A.P. If \(1,4,19\) be added to them respectively, then they are in G.P. Find the numbers.
5 step solution
Problem 100
In a set of four numbers the first three are in G.P. and the last three in A.P. with common difference \(6 .\) If the first number is the same as the fourth, find the four numbers.
5 step solution
Problem 101
Find four numbers in G.P. whose sum is 85 and product is 4096 .
6 step solution
Problem 102
Does there exist a geometric progression containing 27,8 and 12 as three of its terms? If it exists, how many such progressions are possible?
4 step solution
Problem 103
Show that the numbers \(10,11,12\) cannot be the terms of a single G.P. with common ratio not equal to \(1 .\)
3 step solution
Problem 105
In a G.P. the first, third and fifth terms may be considered as the first, fourth and sixteenth terms of an A.P. Determine the fourth term of the A.P., knowing that its first term is 5 and determine \(T_{1}, T_{3}, T_{5}\) of G.P.
6 step solution
Problem 106
The sum of first ten terms of an A.P. is equal to 155 , and sum of the first two terms of a G.P. is 9 , find these progressions if the first term of A.P. is equal to common ratio of G.P. and the first term of G.P. is equal to common difference of A.P.
4 step solution