Chapter 8
College Algebra with Corequisite Support · 264 exercises
Problem 47
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center at the origin, symmetric with respect to the \(x\) - and \(y\) -axes, focus at \((0,-2),\) and point on graph (5,0) .
6 step solution
Problem 48
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-1 ; \quad e=1\)
5 step solution
Problem 48
For the following exercises, find the equation of the parabola given information about its graph. Vertex is (-2,3) ; directrix is \(x=-\frac{7}{2},\) focus is \(\left(-\frac{1}{2}, 3\right) .\)
5 step solution
Problem 48
For the following exercises, given information about the graph of the hyperbola, find its equation. Center: (0,0)\(;\) vertex: (0,-13)\(;\) one focus: \((0, \sqrt{313})\)
6 step solution
Problem 48
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center at the origin, symmetric with respect to the \(x\) - and \(y\) -axes, focus at \((3,0),\) and major axis is twice as long as minor axis.
5 step solution
Problem 49
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-\frac{1}{4} ; \quad e=\frac{7}{2}\)
4 step solution
Problem 49
For the following exercises, find the equation of the parabola given information about its graph. Vertex is \((\sqrt{2},-\sqrt{3}) ;\) directrix is \(x=2 \sqrt{2},\) focus is \((0,-\sqrt{3})\).
4 step solution
Problem 49
For the following exercises, given information about the graph of the hyperbola, find its equation. Center: (4,2)\(;\) vertex: (9,2)\(;\) one focus: \((4+\sqrt{26}, 2)\).
5 step solution
Problem 49
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center (4,2)\(;\) vertex (9,2)\(;\) one focus: \((4+2 \sqrt{6}, 2)\).
5 step solution
Problem 50
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(y=\frac{2}{5} ; \quad e=\frac{7}{2}\)
4 step solution
Problem 50
For the following exercises, determine the angle of rotation in order to eliminate the xy term. Then graph the new set of axes. \(6 x^{2}-5 \sqrt{3} x y+y^{2}+10 x-12 y=0\)
5 step solution
Problem 50
For the following exercises, find the equation of the parabola given information about its graph. Vertex is (1,2)\(; \quad\) directrix is \(y=\frac{11}{3},\) focus is \(\left(1, \frac{1}{3}\right)\).
5 step solution
Problem 50
For the following exercises, given information about the graph of the hyperbola, find its equation. Center: (4,2)\(;\) vertex: (9,2)\(;\) one focus: \((4+\sqrt{26}, 2)\).
5 step solution
Problem 50
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center (3,5)\(;\) vertex (3,11)\(;\) one focus: \((3, \quad 5+4 \sqrt{2})\)
5 step solution
Problem 51
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(y=4 ; \quad e=\frac{3}{2}\)
6 step solution
Problem 51
For the following exercises, determine the angle of rotation in order to eliminate the xy term. Then graph the new set of axes. \(6 x^{2}-5 x y+6 y^{2}+20 x-y=0\)
3 step solution
Problem 51
For the following exercises, use the given information about the graph of each ellipse to determine its equation. Center (-3,4)\(;\) vertex (1,4)\(;\) one focus: \((-3+2 \sqrt{3}, 4)\)
5 step solution
Problem 52
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-2 ; \quad e=\frac{8}{3}\)
4 step solution
Problem 52
For the following exercises, determine the angle of rotation in order to eliminate the xy term. Then graph the new set of axes. \(6 x^{2}-8 \sqrt{3} x y+14 y^{2}+10 x-3 y=0\)
4 step solution
Problem 53
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-5 ; \quad e=\frac{3}{4}\)
5 step solution
Problem 54
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(y=2 ; \quad e=2.5\)
4 step solution
Problem 55
For the following exercises, find the polar equation of the conic with focus at the origin and the given eccentricity and directrix. Directrix: \(x=-3 ; \quad e=\frac{1}{3}\)
5 step solution
Problem 55
For the following exercises, determine the angle of rotation in order to eliminate the xy term. Then graph the new set of axes. \(16 x^{2}+24 x y+9 y^{2}+20 x-44 y=0\)
5 step solution
Problem 56
Recall from Rotation of Axes that equations of conics with an \(x y\) term have rotated graphs. For the following exercises, express each equation in polar form with \(r\) as a function of \(\theta\). \(x y=2\)
5 step solution
Problem 56
Given \(4 x^{2}+k x y+16 y^{2}+8 x+24 y-48=0\) find \(k\) for the graph to be a parabola.
5 step solution
Problem 56
For the following exercises, the vertex and endpoints of the latus rectum of a parabola are given. Find the equation. \(V(0,0)\), Endpoints (2,1),(-2,1)
5 step solution
Problem 57
Recall from Rotation of Axes that equations of conics with an \(x y\) term have rotated graphs. For the following exercises, express each equation in polar form with \(r\) as a function of \(\theta\). \(x^{2}+x y+y^{2}=4\)
6 step solution
Problem 57
Given \(2 x^{2}+k x y+12 y^{2}+10 x-16 y+28=0\) find \(k\) for the graph to be an ellipse.
4 step solution
Problem 57
For the following exercises, the vertex and endpoints of the latus rectum of a parabola are given. Find the equation. \(V(0,0)\), Endpoints (-2,4) , $$ (-2,-4) $$
5 step solution
Problem 57
For the following exercises, express the equation for the hyperbola as two functions, with \(y\) as a function of \(x\). Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\)
4 step solution
Problem 57
For the following exercises, find the area of the ellipse. The area of an ellipse is given by the formula Area \(=a \cdot b \cdot \pi\). \(\frac{(x-3)^{2}}{9}+\frac{(y-3)^{2}}{16}=1\)
2 step solution
Problem 58
Recall from Rotation of Axes that equations of conics with an \(x y\) term have rotated graphs. For the following exercises, express each equation in polar form with \(r\) as a function of \(\theta\). \(2 x^{2}+4 x y+2 y^{2}=9\)
6 step solution
Problem 58
Given \(3 x^{2}+k x y+4 y^{2}-6 x+20 y+128=0\) find \(k\) for the graph to be a hyperbola.
5 step solution
Problem 58
For the following exercises, the vertex and endpoints of the latus rectum of a parabola are given. Find the equation. \(V(1,2),\) Endpoints (-5,5),(7,5)
4 step solution
Problem 58
For the following exercises, express the equation for the hyperbola as two functions, with \(y\) as a function of \(x\). Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. \(\frac{(x-2)^{2}}{16}-\frac{(y+3)^{2}}{25}=1\)
6 step solution
Problem 58
For the following exercises, find the area of the ellipse. The area of an ellipse is given by the formula Area \(=a \cdot b \cdot \pi\). \(\frac{(x+6)^{2}}{16}+\frac{(y-6)^{2}}{36}=1\)
3 step solution
Problem 59
Recall from Rotation of Axes that equations of conics with an \(x y\) term have rotated graphs. For the following exercises, express each equation in polar form with \(r\) as a function of \(\theta\). \(16 x^{2}+24 x y+9 y^{2}=4\)
5 step solution
Problem 59
Given \(3 x^{2}+k x y+4 y^{2}-6 x+20 y+128=0\) find \(k\) for the graph to be a hyperbola.
5 step solution
Problem 59
For the following exercises, the vertex and endpoints of the latus rectum of a parabola are given. Find the equation. \(V(-3,-1),\) Endpoints (0,5) , (0,-7)
4 step solution
Problem 59
For the following exercises, express the equation for the hyperbola as two functions, with \(y\) as a function of \(x\). Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. \(-4 x^{2}-16 x+y^{2}-2 y-19=0\)
9 step solution
Problem 59
For the following exercises, find the area of the ellipse. The area of an ellipse is given by the formula Area \(=a \cdot b \cdot \pi\). \(\frac{(x+1)^{2}}{4}+\frac{(y-2)^{2}}{5}=1\)
3 step solution
Problem 60
Given \(6 x^{2}+12 x y+k y^{2}+16 x+10 y+4=0\) find \(k\) for the graph to be an ellipse.
6 step solution
Problem 60
For the following exercises, the vertex and endpoints of the latus rectum of a parabola are given. Find the equation. \(V(4,-3)\), Endpoints \(\left(5,-\frac{7}{2}\right)\), \(\left(3,-\frac{7}{2}\right)\)
5 step solution
Problem 60
For the following exercises, express the equation for the hyperbola as two functions, with \(y\) as a function of \(x\). Express as simply as possible. Use a graphing calculator to sketch the graph of the two functions on the same axes. \(4 x^{2}-24 x-y^{2}-4 y+16=0\)
6 step solution
Problem 60
For the following exercises, find the area of the ellipse. The area of an ellipse is given by the formula Area \(=a \cdot b \cdot \pi\). \(4 x^{2}-8 x+9 y^{2}-72 y+112=0\)
7 step solution
Problem 61
The mirror in an automobile headlight has a parabolic crosssection with the light bulb at the focus. On a schematic, the equation of the parabola is given as \(x^{2}=4 y\). At what coordinates should you place the light bulb?
4 step solution
Problem 61
For the following exercises, a hedge is to be constructed in the shape of a hyperbola near a fountain at the center of the yard. Find the equation of the hyperbola and sketch the graph. The hedge will follow the asymptotes \(y=x \quad\) and \(y=-x,\) and its closest distance to the center fountain is 5 yards.
5 step solution
Problem 62
For the following exercises, a hedge is to be constructed in the shape of a hyperbola near a fountain at the center of the yard. Find the equation of the hyperbola and sketch the graph. The hedge will follow the asymptotes \(y=2 x\) and \(y=-2 x,\) and its closest distance to the center fountain is 6 yards.
6 step solution
Problem 62
Find the equation of the ellipse that will just fit inside a box that is 8 units wide and 4 units high.
3 step solution
Problem 63
A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its axis of symmetry. The receiver is to be located at the focus. If the dish is 12 feet across at its opening and 4 feet deep at its center, where should the receiver be placed?
5 step solution