Chapter 6
College Algebra and Calculus: An Applied Approach · 314 exercises
Problem 12
Evaluate the expression. $$ \left[\begin{array}{rr} 6 & 8 \\ -1 & 0 \end{array}\right]+\left[\begin{array}{rr} 0 & 5 \\ -3 & -1 \end{array}\right]+\left[\begin{array}{rr} -11 & -7 \\ 2 & -1 \end{array}\right] $$
3 step solution
Problem 13
Find the determinant of the matrix. $$ \left[\begin{array}{ll} -\frac{1}{2} & \frac{1}{3} \\ -6 & \frac{1}{3} \end{array}\right] $$
4 step solution
Problem 13
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rr} 11 & 1 \\ -1 & 0 \end{array}\right] $$
3 step solution
Problem 13
Evaluate the expression. $$ 4\left(\left[\begin{array}{rrr} -4 & 0 & 1 \\ 0 & 2 & 3 \end{array}\right]-\left[\begin{array}{rrr} 2 & 1 & -2 \\ 3 & -6 & 0 \end{array}\right]\right) $$
2 step solution
Problem 13
Identify the elementary row operation(s) being performed to obtain the new row-equivalent matrix. \(\begin{array}{ll}\text { Original Matrix } & \text { New Row-Equivalent Matrix }\end{array}\) $$ \left[\begin{array}{rrr} -2 & 5 & 1 \\ 3 & -1 & -8 \end{array}\right] \quad\left[\begin{array}{rrr} 13 & 0 & -39 \\ 3 & -1 & -8 \end{array}\right] $$
3 step solution
Problem 14
Find the determinant of the matrix. $$ \left[\begin{array}{rr} \frac{2}{3} & \frac{4}{3} \\ -1 & -\frac{1}{3} \end{array}\right] $$
3 step solution
Problem 14
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rr} -7 & 33 \\ 4 & -19 \end{array}\right] $$
4 step solution
Problem 14
Identify the elementary row operation(s) being performed to obtain the new row-equivalent matrix. \(\begin{array}{ll}\text { Original Matrix } & \text { New Row-Equivalent Matrix }\end{array}\) $$ \left[\begin{array}{rrr} 3 & -1 & -4 \\ -4 & 3 & 7 \end{array}\right] \quad\left[\begin{array}{rrr} 3 & -1 & -4 \\ 5 & 0 & -5 \end{array}\right] $$
2 step solution
Problem 15
A large region of forest has been infested with gypsy moths. The region is roughly triangular, as shown in the figure. From the northernmost vertex \(A\) of the region, the distances to the other vertices are 30 miles south and 15 miles east (for vertex \(B\) ), and 25 miles south and 33 miles east (for vertex \(C\) ). Use a graphing utility to approximate the number of square miles in this region.
3 step solution
Problem 15
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{rrr} 0.1 & 0.3 & 0.2 \\ -0.3 & -0.2 & 0.1 \\ 1 & 2 & 3 \end{array}\right] $$
3 step solution
Problem 15
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rr} 8 & 4 \\ -2 & -2 \end{array}\right] $$
3 step solution
Problem 15
Evaluate the expression. $$ -3\left(\left[\begin{array}{rr} 0 & -3 \\ 7 & 2 \end{array}\right]+\left[\begin{array}{rr} -6 & 3 \\ 8 & 1 \end{array}\right]\right)-2\left[\begin{array}{ll} 4 & -4 \\ 7 & -9 \end{array}\right] $$
3 step solution
Problem 15
Identify the elementary row operation(s) being performed to obtain the new row-equivalent matrix. \(\begin{array}{ll}\text { Original Matrix } & \text { New Row-Equivalent Matrix }\end{array}\) $$ \left[\begin{array}{rrrr} 0 & -1 & -5 & 5 \\ -1 & 3 & -7 & 6 \\ 4 & -5 & 1 & 3 \end{array}\right] \quad\left[\begin{array}{rrrr} -1 & 3 & -7 & 6 \\ 0 & -1 & -5 & 5 \\ 0 & 7 & -27 & 27 \end{array}\right] $$
3 step solution
Problem 16
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{rrr} 0.2 & -0.1 & -0.3 \\ 0.1 & -0.1 & 0.4 \\ -0.5 & -0.2 & -0.1 \end{array}\right] $$
3 step solution
Problem 16
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{ll} 2 & 3 \\ 1 & 4 \end{array}\right] $$
4 step solution
Problem 16
Evaluate the expression. $$ -1\left[\begin{array}{rr} 4 & 11 \\ -2 & -1 \\ 9 & 3 \end{array}\right]+\frac{1}{6}\left(\left[\begin{array}{rr} -5 & -1 \\ 3 & 4 \\ 0 & 13 \end{array}\right]+\left[\begin{array}{rr} 7 & 5 \\ -9 & -1 \\ 6 & -1 \end{array}\right]\right) $$
2 step solution
Problem 16
Identify the elementary row operation(s) being performed to obtain the new row-equivalent matrix. \(\begin{array}{ll}\text { Original Matrix } & \text { New Row-Equivalent Matrix }\end{array}\) $$ \left[\begin{array}{rrrr} -1 & -2 & 3 & -2 \\ 2 & -5 & 1 & -7 \\ 5 & 4 & -7 & 6 \end{array}\right] \quad\left[\begin{array}{rrrr} -1 & -2 & 3 & -2 \\ 0 & -9 & 7 & -11 \\ 0 & -6 & 8 & -4 \end{array}\right] $$
3 step solution
Problem 17
Use a determinant to determine whether the points are collinear. $$ (-4,-7),(0,-4),(4,-1) $$
3 step solution
Problem 17
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{rrr} 0.9 & 0.7 & 0 \\ -0.1 & 0.3 & 1.3 \\ 2.2 & 4.2 & 6.1 \end{array}\right] $$
4 step solution
Problem 17
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rr} 0 & 4 \\ -3 & 6 \end{array}\right] $$
3 step solution
Problem 17
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{llll} 1 & 0 & 0 & 0 \\ 0 & 1 & 1 & 5 \\ 0 & 0 & 0 & 0 \end{array}\right] $$
2 step solution
Problem 18
Use a determinant to determine whether the points are collinear. $$ (2,4),(4,5),(-2,2) $$
4 step solution
Problem 18
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{rrr} 0.1 & 0.1 & -4.3 \\ 7.5 & 6.2 & 0.7 \\ 0.3 & 0.6 & -1.2 \end{array}\right] $$
3 step solution
Problem 18
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{ll} 2 & 3 \\ 6 & 9 \end{array}\right] $$
2 step solution
Problem 18
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{rrrr} 1 & 0 & 2 & 1 \\ 0 & 1 & -3 & 10 \\ 0 & 0 & 1 & 0 \end{array}\right] $$
2 step solution
Problem 19
Use a determinant to determine whether the points are collinear. $$ (-1,-7),(0,-3),(1,2) $$
3 step solution
Problem 19
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{rrr} 5 & -3 & 2 \\ 7 & 5 & -7 \\ 0 & 6 & -1 \end{array}\right] $$
4 step solution
Problem 19
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{rrrr} 2 & 0 & 4 & 0 \\ 0 & -1 & 3 & 6 \\ 0 & 0 & 1 & 5 \end{array}\right] $$
2 step solution
Problem 20
Use a determinant to determine whether the points are collinear. $$ (1,7),(0,4),(-1,2) $$
3 step solution
Problem 20
Use the matrix capabilities of a graphing utility to find the determinant of the matrix. $$ \left[\begin{array}{llr} 2 & 3 & 1 \\ 0 & 5 & -2 \\ 0 & 0 & -2 \end{array}\right] $$
3 step solution
Problem 20
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{llll} 0 & 0 & 0 & 0 \\ 0 & 1 & 0 & 5 \\ 0 & 0 & 1 & 3 \end{array}\right] $$
3 step solution
Problem 21
Use a determinant to determine whether the points are collinear. $$ (-2,-11),(4,13),(2,5) $$
3 step solution
Problem 21
Find all (a) minors and (b) cofactors of the matrix. $$ \left[\begin{array}{rr} 3 & 4 \\ 2 & -5 \end{array}\right] $$
2 step solution
Problem 21
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{lll} 1 & 1 & 1 \\ 3 & 5 & 4 \\ 3 & 6 & 5 \end{array}\right] $$
4 step solution
Problem 21
Solve for \(X\) when $$A=\left[\begin{array}{rr} -2 & -1 \\ 1 & 0 \\ 3 & -4 \end{array}\right] \text { and } B=\left[\begin{array}{rr} 0 & 3 \\ 2 & 0 \\ -4 & -1 \end{array}\right].$$ $$ X=3 \dot{A}-2 \bar{B} $$
2 step solution
Problem 21
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{llllll} \mathbf{1} & \underline{3} & 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 8 & 1 & 0 \\ 0 & 0 & 0 & 0 & 1 & 1 \\ 0 & 0 & 0 & 0 & 1 & 1 \end{array}\right] $$
3 step solution
Problem 22
Use a determinant to determine whether the points are collinear. $$ (4,3),(3,1),(2,-1) $$
3 step solution
Problem 22
Find all (a) minors and (b) cofactors of the matrix. $$ \left[\begin{array}{rr} 11 & 0 \\ -3 & 2 \end{array}\right] $$
2 step solution
Problem 22
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rrr} 1 & 2 & 2 \\ 3 & 7 & 9 \\ -1 & -4 & -7 \end{array}\right] $$
3 step solution
Problem 22
Solve for \(X\) when $$A=\left[\begin{array}{rr} -2 & -1 \\ 1 & 0 \\ 3 & -4 \end{array}\right] \text { and } B=\left[\begin{array}{rr} 0 & 3 \\ 2 & 0 \\ -4 & -1 \end{array}\right].$$ $$ 2 X=2 A-B $$
3 step solution
Problem 22
Determine whether the matrix is in row-echelon form. If it is, determine if it is also in reduced row-echelon form. $$ \left[\begin{array}{llll} 1 & 0 & 0 & 10 \\ 0 & 1 & 3 & 9 \\ 0 & 0 & 0 & 1 \\ 0 & 0 & 0 & 0 \end{array}\right] $$
2 step solution
Problem 23
Use a determinant to determine whether the points are collinear. $$ (-2,3),(2,-1),(7,-4) $$
3 step solution
Problem 23
Find all (a) minors and (b) cofactors of the matrix. $$ \left[\begin{array}{rr} 3 & 1 \\ -2 & -4 \end{array}\right] $$
3 step solution
Problem 23
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rrr} 1 & 1 & 2 \\ 3 & 1 & 0 \\ -2 & 0 & 3 \end{array}\right] $$
5 step solution
Problem 23
Solve for \(X\) when $$A=\left[\begin{array}{rr} -2 & -1 \\ 1 & 0 \\ 3 & -4 \end{array}\right] \text { and } B=\left[\begin{array}{rr} 0 & 3 \\ 2 & 0 \\ -4 & -1 \end{array}\right].$$ $$ 2 X+3 A=B $$
3 step solution
Problem 23
Use a graphing utility to perform the sequence of row operations in parts (a) through (d) to reduce the matrix to row-echelon form. \(\left[\begin{array}{rrr}1 & 1 & 2 \\ 3 & 4 & -3 \\ 2 & -1 & 1\end{array}\right]\) (a) Add \(-3\) times \(R_{1}\) to \(R_{2}\). (b) Add \(-2\) times \(R_{1}\) to \(R_{3}\). (c) Add 3 times \(R_{2}\) to \(R_{3}\). (d) Multiply \(R_{3}\) by \(-\frac{1}{30}\).
4 step solution
Problem 24
Use a determinant to determine whether the points are collinear. $$ (-3,-4),(-1,-1),(5,5) $$
3 step solution
Problem 24
Find all (a) minors and (b) cofactors of the matrix. $$ \left[\begin{array}{rr} -6 & 5 \\ 7 & -2 \end{array}\right] $$
2 step solution
Problem 24
Find the inverse of the matrix (if it exists). $$ \left[\begin{array}{rrr} 3 & 2 & 2 \\ 2 & 2 & 2 \\ -4 & 4 & 3 \end{array}\right] $$
6 step solution
Problem 24
Solve for \(X\) when $$A=\left[\begin{array}{rr} -2 & -1 \\ 1 & 0 \\ 3 & -4 \end{array}\right] \text { and } B=\left[\begin{array}{rr} 0 & 3 \\ 2 & 0 \\ -4 & -1 \end{array}\right].$$ $$ 2 A+4 B=-2 X $$
3 step solution