Chapter 14

Calculus Early Transcendentals: Pearson New International Edition · 124 exercises

Problem 9

Evaluate each line integral. \(\int_{C} y^{3} d x+x^{3} d y ; C\) is the right-angle curve from \((-4,1)\) to \((-4,-2)\) to \((2,-2)\).

5 step solution

Problem 10

In Problems 7-12, find \(\nabla f\). $$ f(x, y, z)=\frac{1}{2}\left(x^{2}+y^{2}+z^{2}\right) $$

5 step solution

Problem 10

In Problems 1-14, use Gauss's Divergence Theorem to calculate \(\iint_{\partial S} \mathbf{F} \cdot \mathbf{n} d S .\) \(\mathbf{F}(x, y, z)=x^{2} \mathbf{i}+y^{2} \mathbf{j}+z^{2} \mathbf{k} ; S\) is the solid enclosed by \(x+y+z=4, x=0, y=0, z=0\).

6 step solution

Problem 10

\(\int_{C} y^{3} d x+x^{3} d y ; C\) is the curve \(x=2 t, \quad y=t^{2}-3\), \(-2 \leq t \leq 1 .\)

6 step solution

Problem 10

Evaluate each line integral. \(\int_{C} y^{3} d x+x^{3} d y ; C\) is the curve \(x=2 t, y=t^{2}-3\), \(-2 \leq t \leq 1 .\)

6 step solution

Problem 11

In Problems \(7-12\), use Stokes's Theorem to calculate \(\oint_{C} \mathbf{F} \cdot \mathbf{T} d s\). \(\mathbf{F}=(z-y) \mathbf{i}+y \mathbf{j}+x \mathbf{k} ; C\) is the intersection of the cylinder \(x^{2}+y^{2}=x\) with the sphere \(x^{2}+y^{2}+z^{2}=1\), oriented counterclockwise as viewed from above.

5 step solution

Problem 11

In Problems 7-12, find \(\nabla f\). $$ f(x, y, z)=x e^{y} \cos z $$

5 step solution

Problem 11

In Problems 1-14, use Gauss's Divergence Theorem to calculate \(\iint_{\partial S} \mathbf{F} \cdot \mathbf{n} d S .\) \(\mathbf{F}(x, y, z)=2 x \mathbf{i}+3 y \mathbf{j}+4 z \mathbf{k} ; S\) is the solid spherical shell \(9 \leq x^{2}+y^{2}+z^{2} \leq 25\).

6 step solution

Problem 11

Use the vector forms of Green's Theorem to calculate (a) \(\oint_{C} \mathbf{F} \cdot \mathbf{n} d s\) and (b) \(\oint_{C} \mathbf{F} \cdot \mathbf{T} d s\). \(\mathbf{F}=y^{3} \mathbf{i}+x^{3} \mathbf{j} ; C\) is the unit circle.

6 step solution

Problem 11

\(\int_{C}(x+2 y) d x+(x-2 y) d y ; C\) is the line segment from \((1,1)\) to \((3,-1)\).

6 step solution

Problem 11

Evaluate each line integral. \(\int_{C}(x+2 y) d x+(x-2 y) d y ; C\) is the line segment from \((1,1)\) to \((3,-1)\).

6 step solution

Problem 12

In Problems \(7-12\), use Stokes's Theorem to calculate \(\oint_{C} \mathbf{F} \cdot \mathbf{T} d s\). \(\mathbf{F}=(y-z) \mathbf{i}+(z-x) \mathbf{j}+(x-y) \mathbf{k} ; C\) is the ellipse which is the intersection of the plane \(x+z=1\) and the cylinder \(x^{2}+y^{2}=1\), oriented clockwise as viewed from above.

6 step solution

Problem 12

In Problems 7-12, find \(\nabla f\). $$ f(x, y, z)=y^{2} e^{-2 z} $$

5 step solution

Problem 12

In Problems 1-14, use Gauss's Divergence Theorem to calculate \(\iint_{\partial S} \mathbf{F} \cdot \mathbf{n} d S .\) \(\mathbf{F}(x, y, z)=2 z \mathbf{i}+x \mathbf{j}+z^{2} \mathbf{k} ; S\) is the solid cylindrical shell \(1 \leq x^{2}+y^{2} \leq 4,0 \leq z \leq 2\)

5 step solution

Problem 12

Use the vector forms of Green's Theorem to calculate (a) \(\oint_{C} \mathbf{F} \cdot \mathbf{n} d s\) and (b) \(\oint_{C} \mathbf{F} \cdot \mathbf{T} d s\). \(\mathbf{F}=x \mathbf{i}+y \mathbf{j} ; C\) is the unit circle.

6 step solution

Problem 12

$$ \int_{C} y d x+x d y ; C \text { is the curve } y=x^{2}, 0 \leq x \leq 1 $$

5 step solution

Problem 12

Evaluate each line integral. \(\int_{C} y d x+x d y ; C\) is the curve \(y=x^{2}, 0 \leq x \leq 1\).

5 step solution

Problem 13

Suppose that the surface \(S\) is determined by the formula \(z=g(x, y)\). Show that the surface integral in Stokes's Theorem can be written as a double integral in the following way: $$ \iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} d S=\iint_{S_{x y}}(\operatorname{curl} \mathbf{F}) \cdot\left(-g_{x} \mathbf{i}-g_{y} \mathbf{j}+\mathbf{k}\right) d A $$ where \(\mathbf{n}\) is the upward normal to \(S\) and \(S_{x y}\) is the projection of \(S\) in the \(x y\)-plane.

6 step solution

Problem 13

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=x^{2} \mathbf{i}-2 x y \mathbf{j}+y z^{2} \mathbf{k} $$

7 step solution

Problem 13

Suppose that the integrals \(\oint \mathbf{F} \cdot \mathbf{T} d s\) taken counterclockwise around the circles \(x^{2}+y^{2}=36\) and \(x^{2}+y^{2}=1\) are 30 and \(-20\), respectively. Calculate \(\iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{k} d A\), where \(S\) is the region between the circles.

6 step solution

Problem 13

\(\int_{C}(x+y+z) d x+x d y-y z d z ; C\) is the line segment from \((1,2,1)\) to \((2,1,0)\).

6 step solution

Problem 13

Evaluate each line integral. \(\int_{C}(x+y+z) d x+x d y-y z d z ; C\) is the line segment from \((1,2,1)\) to \((2,1,0)\).

6 step solution

Problem 14

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=x^{2} \mathbf{i}+y^{2} \mathbf{j}+z^{2} \mathbf{k} $$

8 step solution

Problem 14

\(\int_{C} x z d x+(y+z) d y+x d z ; C\) is the curve \(x=e^{t}\), \(y=e^{-t}, z=e^{2 t}, 0 \leq t \leq 1 .\)

5 step solution

Problem 14

Find the mass of the surface \(z=1-\left(x^{2}+y^{2}\right) / 2\) over \(0 \leq x \leq 1,0 \leq y \leq 1\), if \(\delta(x, y, z)=k x y\).

8 step solution

Problem 14

Evaluate each line integral. \(\int_{C} x z d x+(y+z) d y+x d z ; C\) is the curve \(x=e^{t}\), \(y=e^{-t}, z=e^{2 t}, 0 \leq t \leq 1 .\)

6 step solution

Problem 15

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=y z \mathbf{i}+x z \mathbf{j}+x y \mathbf{k} $$

4 step solution

Problem 15

Let \(\mathbf{F}(x, y, z)=x \mathbf{i}+y \mathbf{j}+z \mathbf{k}\), and let \(S\) be a solid for which Gauss's Divergence Theorem applies. Show that the volume of \(S\) is given by $$ V(S)=\frac{1}{3} \iint_{\partial S} \mathbf{F} \cdot \mathbf{n} d S $$

4 step solution

Problem 15

\(\int_{C}(x+y+z) d x+(x-2 y+3 z) d y+\) \((2 x+y-z) d z ; C\) is the line-segment path from \((0,0,0)\) to \((2,0,0)\) to \((2,3,0)\) to \((2,3,4)\).

5 step solution

Problem 15

Find the center of mass of the homogeneous triangle with vertices \((a, 0,0),(0, a, 0)\), and \((0,0, a)\).

3 step solution

Problem 15

Evaluate each line integral. \(\int_{C}(x+y+z) d x+(x-2 y+3 z) d y+\) \((2 x+y-z) d z ; C\) is the line-segment path from \((0,0,0)\) to \((2,0,0)\) to \((2,3,0)\) to \((2,3,4)\).

5 step solution

Problem 16

Let \(\mathbf{F}=2 \mathbf{i}+x z \mathbf{j}+z^{3} \mathbf{k}\) and \(\partial S\) be the boundary of the surface \(z=x^{2} y^{2}, x^{2}+y^{2} \leq a^{2}\), oriented counterclockwise as viewed from above. Evaluate \(\oint_{\partial S} \mathbf{F} \cdot \mathbf{T} d s\).

7 step solution

Problem 16

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=\cos x \mathbf{i}+\sin y \mathbf{j}+3 \mathbf{k} $$

4 step solution

Problem 16

Find the center of mass of the homogeneous triangle with vertices \((a, 0,0),(0, b, 0)\), and \((0,0, c)\), where \(a, b\), and \(c\) are all positive.

5 step solution

Problem 17

Let \(\mathbf{F}=2 z \mathbf{i}+2 y \mathbf{k}\), and let \(\partial S\) be the intersection of the cylinder \(x^{2}+y^{2}=a y\) with the hemisphere \(z=\sqrt{a^{2}-x^{2}-y^{2}}\), \(a>0\). Assuming distances in meters and force in newtons, find the work done by the force \(\mathbf{F}\) in moving an object around \(\partial S\) in the counterclockwise direction as viewed from above.

7 step solution

Problem 17

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=e^{x} \cos y \mathbf{i}+e^{x} \sin y \mathbf{j}+z \mathbf{k} $$

7 step solution

Problem 17

Show that the work done by a constant force \(\mathbf{F}\) in moving a body around a simple closed curve is 0 .

5 step solution

Problem 17

Find the mass of a wire with the shape of the curve \(y=x^{2}\) between \((-2,4)\) and \((2,4)\) if the density is given by \(\delta(x, y)=\) \(k|x|\).

5 step solution

Problem 17

Plot the parametric surface over the indicated domain. \(\mathbf{r}(u, v)=u \mathbf{i}+3 v \mathbf{j}+\left(4-u^{2}-v^{2}\right) \mathbf{k} ; 0 \leq u \leq 2\), \(0 \leq v \leq 1\)

4 step solution

Problem 18

A central force is one of the form \(\mathbf{F}=f(\|\mathbf{r}\|) \mathbf{r}\), where \(f\) has a continuous derivative (except possibly at \(\|\mathbf{r}\|=0\) ). Show that the work done by such a force in moving an object around a closed path that misses the origin is 0 .

2 step solution

Problem 18

In Problems 13-18, find div \(\mathbf{F}\) and curl \(\mathbf{F}\). $$ \mathbf{F}(x, y, z)=(y+z) \mathbf{i}+(x+z) \mathbf{j}+(x+y) \mathbf{k} $$

3 step solution

Problem 18

Plot the parametric surface over the indicated domain. \(\mathbf{r}(u, v)=2 u \mathbf{i}+3 v \mathbf{j}+\left(u^{2}+v^{2}\right) \mathbf{k} ;-1 \leq u \leq 1\), \(-2 \leq v \leq 2\)

4 step solution

Problem 18

A wire of constant density has the shape of the helix \(x=a \cos t, y=a \sin t, z=b t, 0 \leq t \leq 3 \pi\). Find its mass and center of mass.

7 step solution

Problem 19

Let \(S\) be a solid sphere (or any solid enclosed by a "nice" surface \(\partial S)\). Show that $$ \iint_{\partial S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} d S=0 $$ (a) By using Stokes's Theorem. (b) By using Gauss's Theorem. Hint: Show \(\operatorname{div}(\operatorname{curl} \mathbf{F})=0\).

5 step solution

Problem 19

Let \(f\) be a scalar field and \(\mathbf{F}\) a vector field. Indicate which of the following are scalar fields, vector fields, or meaningless. (a) \(\operatorname{div} f\) (b) grad \(f\) (c) curl \(\mathbf{F}\) (d) \(\operatorname{div}(\operatorname{grad} f)\) (e) curl \((\operatorname{grad} f)\) (f) \(\operatorname{grad}(\operatorname{div} \mathbf{F})\) (g) curl (curl F) (h) \(\operatorname{div}(\operatorname{div} \mathbf{F})\) (i) \(\operatorname{grad}(\operatorname{grad} f)\) (j) \(\operatorname{div}(\operatorname{curl}(\operatorname{grad} f))\) (k) \(\operatorname{curl}(\operatorname{div}(\operatorname{grad} f))\)

12 step solution

Problem 19

Calculate \(\iint_{2 S} \mathbf{F} \cdot \mathbf{n} d S\) for each of the following. Looked at the right way, all are quite easy and some are even trivial. (a) \(\mathbf{F}=(2 x+y z) \mathbf{i}+3 y \mathbf{j}+z^{2} \mathbf{k}\); \(S\) is the solid sphere \(x^{2}+y^{2}+z^{2} \leq 1\). (b) \(\mathbf{F}=\left(x^{2}+y^{2}+z^{2}\right)^{5 / 3}(x \mathbf{i}+y \mathbf{j}+z \mathbf{k}) ; S\) as in part (a). (c) \(\mathbf{F}=x^{2} \mathbf{i}+y^{2} \mathbf{j}+z^{2} \mathbf{k}\) \(S\) is the solid sphere \((x-2)^{2}+y^{2}+z^{2} \leq 1\). (d) \(\mathbf{F}=x^{2} \mathbf{i} ; S\) is the cube \(0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1\). (e) \(\mathbf{F}=(x+z) \mathbf{i}+(y+x) \mathbf{j}+(z+y) \mathbf{k} ; S\) is the tetrahedron cut from the first octant by the plane \(3 x+4 y+2 z=12\). (f) \(\mathbf{F}=x^{3} \mathbf{i}+y^{3} \mathbf{j}+z^{3} \mathbf{k} ; S\) as in part (a). (g) \(\mathbf{F}=(x \mathbf{i}+y \mathbf{j}) \ln \left(x^{2}+y^{2}\right)\); \(S\) is the solid cylinder \(x^{2}+y^{2} \leq 4,0 \leq z \leq 2\).

8 step solution

Problem 19

Let $$ \mathbf{F}=\frac{y}{x^{2}+y^{2}} \mathbf{i}-\frac{x}{x^{2}+y^{2}} \mathbf{j}=M \mathbf{i}+N \mathbf{j} $$ (a) Show that \(\partial N / \partial x=\partial M / \partial y\). (b) Show, by using the parametrization \(x=\cos t, y=\sin t\), that \(\oint_{C} M d x+N d y=-2 \pi\), where \(C\) is the unit circle. (c) Why doesn't this contradict Green's Theorem?

5 step solution

Problem 19

Plot the parametric surface over the indicated domain. \(\mathbf{r}(u, v)=2 \cos v \mathbf{i}+3 \sin v \mathbf{j}+u \mathbf{k} ;-6 \leq u \leq 6\), \(0 \leq v \leq 2 \pi\)

4 step solution

Problem 19

Find the work done by the force field \(\mathbf{F}\) in moving a particle along the curve \(C\). \(\mathbf{F}(x, y)=\left(x^{3}-y^{3}\right) \mathbf{i}+x y^{2} \mathbf{j} ; \quad C\) is the curve \(x=t^{2}\), \(y=t^{3},-1 \leq t \leq 0 .\)

6 step solution

Problem 20

Assuming that the required partial derivatives exist and are continuous, show that (a) \(\operatorname{div}(\operatorname{curl} \mathbf{F})=0\); (b) \(\operatorname{curl}(\operatorname{grad} f)=\mathbf{0}\); (c) \(\operatorname{div}(f \mathbf{F})=(f)(\operatorname{div} \mathbf{F})+(\operatorname{grad} f) \cdot \mathbf{F}\); (d) \(\operatorname{curl}(f \mathbf{F})=(f)(\operatorname{curl} \mathbf{F})+(\operatorname{grad} f) \times \mathbf{F}\).

5 step solution

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