Chapter 6
Calculus Early Transcendentals · 484 exercises
Problem 73
Consider the functions \(f(x)=x^{n}\) and \(g(x)=x^{1 / n},\) where \(n \geq 2\) is a positive integer. a. Graph \(f\) and \(g\) for \(n=2,3,\) and \(4,\) for \(x \geq 0\) b. Give a geometric interpretation of the area function \(A_{n}(x)=\int_{0}^{x}(f(s)-g(s)) d s,\) for \(n=2,3,4, \ldots\) and \(x>0\) c. Find the positive root of \(A_{n}(x)=0\) in terms of \(n\). Does the root increase or decrease with \(n\) ?
3 step solution
Problem 73
Determine whether the following statements are true and give an explanation or counterexample. a. \(\frac{d}{d x}(\sinh \ln 3)=\frac{\cosh \ln 3}{3}.\) b. \(\frac{d}{d x}(\sinh x)=\cosh x\) and \(\frac{d}{d x}(\cosh x)=-\sinh x.\) c. Differentiating the velocity equation for an ocean wave \(v=\sqrt{\frac{g \lambda}{2 \pi} \tanh \left(\frac{2 \pi d}{\lambda}\right)}\) results in the acceleration of the wave. d. \(\ln (1+\sqrt{2})=-\ln (-1+\sqrt{2}).\) e. \(\int_{0}^{1} \frac{d x}{4-x^{2}}=\frac{1}{2}\left(\operatorname{coth}^{-1} \frac{1}{2}-\cot ^{-1} 0\right).\)
5 step solution
Problem 73
Use a left Riemann sum with at least \(n=2\) sub-intervals of equal length to approximate \(\ln 2=\int_{1}^{2} \frac{d t}{t}\) and show that \(\ln 2<1 .\) Use a right Riemann sum with \(n=7\) sub-intervals of equal length to approximate \(\ln 3=\int_{1}^{3} \frac{d t}{t}\) and show that \(\ln 3>1\).
2 step solution
Problem 74
Use a calculator to evaluate each expression or state that the value does not exist. Report answers accurate to four decimal places. a. \(\coth 4\) b. \(\tanh ^{-1} 2\) c. \(\operatorname{csch}^{-1} 5\) d. \(\left.\operatorname{csch} x\right|_{1 / 2} ^{2}\) e. \(\left.\ln \left|\tanh \left(\frac{x}{2}\right)\right|\right|_{1} ^{10}\) f. \(\left.\tan ^{-1}(\sinh x)\right|_{-3} ^{3}\) g. \(\left.\frac{1}{4} \operatorname{coth}^{-1} \frac{x}{4}\right|_{20} ^{36}\)
7 step solution
Problem 74
Consider the functions \(f(x)=a \sin 2 x\) and \(g(x)=(\sin x) / a,\) where \(a>0\) is a real number. a. Graph the two functions on the interval \([0, \pi / 2],\) for \(a=\frac{1}{2}, 1\) and 2. b. Show that the curves have an intersection point \(x^{*}\) (other than \(x=0)\) on \([0, \pi / 2]\) that satisfies \(\cos x^{*}=1 /\left(2 a^{2}\right),\) provided \(a>1 / \sqrt{2}\) c. Find the area of the region between the two curves on \(\left[0, x^{*}\right]\) when \(a=1\) d. Show that as \(a \rightarrow 1 / \sqrt{2}^{+}\). the area of the region between the two curves on \(\left[0, x^{*}\right]\) approaches zero.
9 step solution
Problem 74
Assume that \(y>0\) is fixed and that \(x>0 .\) Show that \(\frac{d}{d x}(\ln x y)=\frac{d}{d x}(\ln x) .\) Recall that if two functions have the same derivative, then they differ by an additive constant. Set \(x=1\) to evaluate the constant and prove that \(\ln x y=\ln x+\ln y\).
5 step solution
Problem 74
Without evaluating integrals, explain the following equalities. (Hint: Draw pictures.) a. \(\pi \int_{0}^{4}(8-2 x)^{2} d x=2 \pi \int_{0}^{8} y\left(4-\frac{y}{2}\right) d y\) b. \(\int_{0}^{2}\left(25-\left(x^{2}+1\right)^{2}\right) d x=2 \int_{1}^{5} y \sqrt{y-1} d y\)
2 step solution
Problem 75
Evaluate each expression without using a calculator or state that the value does not exist. Simplify answers to the extent possible. a. \(\cosh 0\) b. \(\tanh 0\) c. \(\operatorname{csch} 0\) d. \(\operatorname{sech}(\sinh 0)\) e. \(\operatorname{coth}(\ln 5)\) f. \(\sinh (2 \ln 3)\) g. \(\cosh ^{2} 1\) h. \(\operatorname{sech}^{-1}(\ln 3)\) i. \(\cosh ^{-1}(17 / 8)\) j. \(\sinh ^{-1}\left(\frac{e^{2}-1}{2 e}\right)\)
9 step solution
Problem 75
In Chapter \(8,\) we will encounter the harmonic \(\operatorname{sum} 1+\frac{1}{2}+\frac{1}{3}+\cdots+\frac{1}{n} .\) Use a left Riemann sum to approximate \(\int_{1}^{n+1} \frac{d x}{x}(\) with unit spacing between the grid points) to show that \(1+\frac{1}{2}+\frac{1}{3}+\cdots+\frac{1}{n}>\ln (n+1) .\) Use this fact to conclude that \(\lim _{n \rightarrow \infty}\left(1+\frac{1}{2}+\frac{1}{3}+\cdots+\frac{1}{n}\right)\) does not exist.
6 step solution
Problem 75
Solve the following problems with and without calculus. A good picture helps. a. A cube with side length \(r\) is inscribed in a sphere, which is inscribed in a right circular cone, which is inscribed in a right circular cylinder. The side length (slant height) of the cone is equal to its diameter. What is the volume of the cylinder? b. A cube is inscribed in a right circular cone with a radius of 1 and a height of \(3 .\) What is the volume of the cube? c. A cylindrical hole 10 in long is drilled symmetrically through the center of a sphere. How much material is left in the sphere? (Enough information is given.)
9 step solution
Problem 77
Find the critical points of the function \(f(x)=\sinh ^{2} x \cosh x.\)
4 step solution
Problem 78
a. Show that the critical points of \(f(x)=\frac{\cosh x}{x}\) satisfy \(x=\operatorname{coth} x.\) b. Use a root finder to approximate the critical points of \(f.\)
4 step solution
Problem 80
Find the \(x\) -coordinate of the point(s) of inflection of \(f(x)=\operatorname{sech} x .\) Report exact answers in terms of logarithms (use Theorem 6.10 ).
7 step solution
Problem 81
Find the area of the region bounded by \(y=\operatorname{sech} x, x=1,\) and the unit circle.
4 step solution
Problem 83
Explain why l'Hôpital's Rule fails when applied to the limit \(\lim _{x \rightarrow \infty} \frac{\sinh x}{\cosh x}\) and then find the limit another way.
3 step solution
Problem 84
Use l'Hôpital's Rule to evaluate the following limits. $$\lim _{x \rightarrow \infty} \frac{1-\operatorname{coth} x}{1-\tanh x}$$
3 step solution
Problem 85
Use l'Hôpital's Rule to evaluate the following limits. $$\lim _{x \rightarrow 0} \frac{\tanh ^{-1} x}{\tan (\pi x / 2)}$$
5 step solution
Problem 86
Use l'Hôpital's Rule to evaluate the following limits. $$\lim _{x \rightarrow 1^{-}} \frac{\tanh ^{-1} x}{\tan (\pi x / 2)}$$
5 step solution
Problem 87
Use l'Hôpital's Rule to evaluate the following limits. $$\lim _{x \rightarrow 0^{+}}(\tanh x)^{x}$$
6 step solution
Problem 89
Evaluate the following integrals. $$\int \frac{\cosh z}{\sinh ^{2} z} d z$$
6 step solution
Problem 90
Evaluate the following integrals. $$\int \frac{\cos \theta}{9-\sin ^{2} \theta} d \theta$$
6 step solution
Problem 91
Evaluate the following integrals. $$\int_{5 / 12}^{3 / 4} \frac{\sinh ^{-1} x}{\sqrt{x^{2}+1}} d x$$
4 step solution
Problem 92
Evaluate the following integrals. $$\int_{25}^{225} \frac{d x}{\sqrt{x^{2}+25 x}}(\text { Hint: } \sqrt{x^{2}+25 x}=\sqrt{x} \sqrt{x+25} .)$$
5 step solution
Problem 95
When an object falling from rest encounters air resistance proportional to the square of its velocity, the distance it falls (in meters) after \(t\) seconds is given by \(d(t)=\frac{m}{k} \ln (\cosh (\sqrt{\frac{k g}{m}} t)),\) where \(m\) is the mass of the object in kilograms, \(g=9.8 \mathrm{m} / \mathrm{s}^{2}\) is the acceleration due to gravity, and \(k\) is a physical constant. a. A \(\mathrm{BASE}\) jumper \((m=75 \mathrm{kg})\) leaps from a tall cliff and performs a ten-second delay (she free-falls for \(10 \mathrm{s}\) and then opens her chute). How far does she fall in \(10 \mathrm{s} ?\) Assume \(k=0.2\) b. How long does it take her to fall the first \(100 \mathrm{m} ?\) The second \(100 \mathrm{m} ?\) What is her average velocity over each of these intervals?
3 step solution
Problem 101
Verify the following identities. $$\sinh \left(\cosh ^{-1} x\right)=\sqrt{x^{2}-1}, \text { for } x \geq 1$$
6 step solution
Problem 102
Verify the following identities. $$\cosh \left(\sinh ^{-1} x\right)=\sqrt{x^{2}+1}, \text { for all } x$$
5 step solution
Problem 103
Verify the following identities. $$\cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y$$
7 step solution
Problem 104
Verify the following identities. $$\sinh (x+y)=\sinh x \cosh y+\cosh x \sinh y$$
4 step solution
Problem 105
Show that \(\cosh ^{-1}(\cosh x)=|x|\) by using the formula \(\cosh ^{-1} t=\ln (t+\sqrt{t^{2}-1})\) and by considering the cases \(x \geq 0\) and \(x<0.\)
2 step solution
Problem 106
a. The definition of the inverse hyperbolic cosine is \(y=\cosh ^{-1} x \Leftrightarrow x=\cosh y,\) for \(x \geq 1,0 \leq y<\infty.\) Use implicit differentiation to show that \(\frac{d}{d x}\left(\cosh ^{-1} x\right)=\) \(1 / \sqrt{x^{2}-1}.\) b. Differentiate \(\sinh ^{-1} x=\ln (x+\sqrt{x^{2}+1})\) to show that \(\frac{d}{d x}\left(\sinh ^{-1} x\right)=1 / \sqrt{x^{2}+1}.\)
4 step solution
Problem 107
There are several ways to express the indefinite integral of \(\operatorname{sech} x\). a. Show that \(\left.\int \operatorname{sech} x d x=\tan ^{-1}(\sinh x)+C \text { (Theorem } 6.9\right)\) (Hint: Write sech \(x=\frac{1}{\cosh x}=\frac{\cosh x}{\cosh ^{2} x}=\frac{\cosh x}{1+\sinh ^{2} x}\) and then make a change of variables.) b. Show that \(\int \operatorname{sech} x d x=\sin ^{-1}(\tanh x)+C .\) (Hint: Show that \(\operatorname{sech} x=\frac{\operatorname{sech}^{2} x}{\sqrt{1-\tanh ^{2} x}}\) and then make a change of variables.) c. Verify that \(\int \operatorname{sech} x d x=2 \tan ^{-1} e^{x}+C\) by proving \(\frac{d}{d x}\left(2 \tan ^{-1} e^{x}\right)=\operatorname{sech} x.\)
6 step solution
Problem 108
Carry out the following steps to derive the formula \(\int \operatorname{csch} x d x=\ln |\tanh (x / 2)|+C(\text { Theorem } 6.9)\) a. Change variables with the substitution \(u=x / 2\) to show that $$\int \operatorname{csch} x d x=\int \frac{2 d u}{\sinh 2 u}.$$ b. Use the identity for sinh \(2 u\) to show that \(\frac{2}{\sinh 2 u}=\frac{\operatorname{sech}^{2} u}{\tanh u}.\) c. Change variables again to determine \(\int \frac{\operatorname{sech}^{2} u}{\tanh u} d u\) and then express your answer in terms of \(x.\)
3 step solution
Problem 110
Inverse hyperbolic tangent Recall that the inverse hyperbolic tangent is
defined as \(y=\tanh ^{-1} x \Leftrightarrow x=\tanh y,\) for \(-1
6 step solution
Problem 111
Use the substitution \(u=x^{r}\) to show that \(\int \frac{d x}{x \sqrt{1-x^{2
r}}}=-\frac{1}{r} \operatorname{sech}^{-1} x^{r}+C,\) for \(r>0\) and \(0
4 step solution