Chapter 6

Book of Proof · 20 exercises

Problem 1

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(n \in \mathbb{Z} .\) If \(n\) is odd, then \(n^{2}\) is odd.

4 step solution

Problem 2

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(n \in \mathbb{Z}\). If \(n^{2}\) is odd, then \(n\) is odd.

3 step solution

Problem 3

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt[3]{2}\) is irrational.

5 step solution

Problem 4

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt{6}\) is irrational.

3 step solution

Problem 5

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt{3}\) is irrational.

3 step solution

Problem 8

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(a, b, c \in \mathbb{Z} .\) If \(a^{2}+b^{2}=c^{2},\) then \(a\) or \(b\) is even.

4 step solution

Problem 9

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(a, b \in \mathbb{R} .\) If \(a\) is rational and \(a b\) is irrational, then \(b\) is irrational.

4 step solution

Problem 10

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) There exist no integers \(a\) and \(b\) for which \(21 a+30 b=1\).

4 step solution

Problem 11

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) There exist no integers \(a\) and \(b\) for which \(18 a+6 b=1\).

3 step solution

Problem 12

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) For every positive \(x \in \mathbb{Q},\) there is a positive \(y \in \mathbb{Q}\) for which \(y

3 step solution

Problem 13

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) For every \(x \in[\pi / 2, \pi], \sin x-\cos x \geq 1\)

5 step solution

Problem 14

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(A\) and \(B\) are sets, then \(A \cap(B-A)=\varnothing\).

4 step solution

Problem 15

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(b \in \mathbb{Z}\) and \(b \nmid k\) for every \(k \in \mathbb{N},\) then \(b=0\).

3 step solution

Problem 16

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(a\) and \(b\) are positive real numbers, then \(a+b \geq 2 \sqrt{a b}\).

5 step solution

Problem 17

Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) For every \(n \in \mathbb{Z}, 4 \nmid\left(n^{2}+2\right)\)

4 step solution

Problem 18

For every \(n \in \mathbb{Z}, 4 \nmid\left(n^{2}+2\right)\). Suppose \(a, b \in \mathbb{Z}\). If \(4 \mid\left(a^{2}+b^{2}\right),\) then \(a\) and \(b\) are not both odd.

2 step solution

Problem 19

Prove the following statements using any method from Chapters 4,5 or 6 . The product of any five consecutive integers is divisible by 120 . (For example, the product of 3,4,5,6 and 7 is 2520 , and \(2520=120 \cdot 21\).

4 step solution

Problem 22

Prove the following statements using any method from Chapters 4,5 or 6 . Explain why \(x^{2}+y^{2}-3=0\) not having any rational solutions (Exercise 20 ) implies \(x^{2}+y^{2}-3^{k}=0\) has no rational solutions for \(k\) an odd, positive integer.

4 step solution

Problem 23

Prove the following statements using any method from Chapters 4,5 or 6 . Use the above result to prove that \(\sqrt{3^{k}}\) is irrational for all odd, positive \(k\).

5 step solution

Problem 24

Prove the following statements using any method from Chapters 4,5 or 6 . The number \(\log _{2} 3\) is irrational.

3 step solution

Show/ page
Chapter 6 - Book of Proof Solutions | StudyQuestionHub