Chapter 6
Book of Proof · 20 exercises
Problem 1
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(n \in \mathbb{Z} .\) If \(n\) is odd, then \(n^{2}\) is odd.
4 step solution
Problem 2
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(n \in \mathbb{Z}\). If \(n^{2}\) is odd, then \(n\) is odd.
3 step solution
Problem 3
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt[3]{2}\) is irrational.
5 step solution
Problem 4
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt{6}\) is irrational.
3 step solution
Problem 5
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Prove that \(\sqrt{3}\) is irrational.
3 step solution
Problem 8
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(a, b, c \in \mathbb{Z} .\) If \(a^{2}+b^{2}=c^{2},\) then \(a\) or \(b\) is even.
4 step solution
Problem 9
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) Suppose \(a, b \in \mathbb{R} .\) If \(a\) is rational and \(a b\) is irrational, then \(b\) is irrational.
4 step solution
Problem 10
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) There exist no integers \(a\) and \(b\) for which \(21 a+30 b=1\).
4 step solution
Problem 11
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) There exist no integers \(a\) and \(b\) for which \(18 a+6 b=1\).
3 step solution
Problem 12
Use the method of proof by contradiction to prove the following statements.
(In each case, you should also think about how a direct or contrapositive
proof would work. You will find in most cases that proof by contradiction is
easier.)
For every positive \(x \in \mathbb{Q},\) there is a positive \(y \in \mathbb{Q}\)
for which \(y
3 step solution
Problem 13
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) For every \(x \in[\pi / 2, \pi], \sin x-\cos x \geq 1\)
5 step solution
Problem 14
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(A\) and \(B\) are sets, then \(A \cap(B-A)=\varnothing\).
4 step solution
Problem 15
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(b \in \mathbb{Z}\) and \(b \nmid k\) for every \(k \in \mathbb{N},\) then \(b=0\).
3 step solution
Problem 16
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) If \(a\) and \(b\) are positive real numbers, then \(a+b \geq 2 \sqrt{a b}\).
5 step solution
Problem 17
Use the method of proof by contradiction to prove the following statements. (In each case, you should also think about how a direct or contrapositive proof would work. You will find in most cases that proof by contradiction is easier.) For every \(n \in \mathbb{Z}, 4 \nmid\left(n^{2}+2\right)\)
4 step solution
Problem 18
For every \(n \in \mathbb{Z}, 4 \nmid\left(n^{2}+2\right)\). Suppose \(a, b \in \mathbb{Z}\). If \(4 \mid\left(a^{2}+b^{2}\right),\) then \(a\) and \(b\) are not both odd.
2 step solution
Problem 19
Prove the following statements using any method from Chapters 4,5 or 6 . The product of any five consecutive integers is divisible by 120 . (For example, the product of 3,4,5,6 and 7 is 2520 , and \(2520=120 \cdot 21\).
4 step solution
Problem 22
Prove the following statements using any method from Chapters 4,5 or 6 . Explain why \(x^{2}+y^{2}-3=0\) not having any rational solutions (Exercise 20 ) implies \(x^{2}+y^{2}-3^{k}=0\) has no rational solutions for \(k\) an odd, positive integer.
4 step solution
Problem 23
Prove the following statements using any method from Chapters 4,5 or 6 . Use the above result to prove that \(\sqrt{3^{k}}\) is irrational for all odd, positive \(k\).
5 step solution
Problem 24
Prove the following statements using any method from Chapters 4,5 or 6 . The number \(\log _{2} 3\) is irrational.
3 step solution