Chapter 5

Applied Mathematics: For the Managerial, Life, and Social Sciences · 249 exercises

Problem 19

(a) write a matrix equation that is equivalent to the system of linear equations and (b) solve the system using the inverses found in Exercises 5-16. \(\begin{aligned} 2 x-3 y-4 z &=4 \\\\-z &=3 \\ x-2 y+z &=-8 \end{aligned}\) (See Exercise 9.)

5 step solution

Problem 19

Compute the indicated products. \(\left[\begin{array}{rrrr}3 & 0 & -2 & 1 \\ 1 & 2 & 0 & -1\end{array}\right]\left[\begin{array}{rrr}2 & 1 & -1 \\ -1 & 2 & 0 \\ 0 & 0 & 1 \\ -1 & -2 & 2\end{array}\right]\)

3 step solution

Problem 19

Perform the indicated operations. \(\frac{1}{2}\left[\begin{array}{rrrr}1 & 0 & 0 & -4 \\ 3 & 0 & -1 & 6 \\ -2 & 1 & -4 & 2\end{array}\right]+\frac{4}{3}\left[\begin{array}{rrrr}3 & 0 & -1 & 4 \\ -2 & 1 & -6 & 2 \\ 8 & 2 & 0 & -2\end{array}\right]\) \(-\frac{1}{3}\left[\begin{array}{rrrr}3 & -9 & -1 & 0 \\ 6 & 2 & 0 & -6 \\ 0 & 1 & -3 & 1\end{array}\right]\)

3 step solution

Problem 19

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{array}{rr}x-2 y= & 2 \\ 7 x-14 y= & 14 \\ 3 x-6 y= & 6\end{array}\)

4 step solution

Problem 19

Pivot the system about the circled element. \(\left[\begin{array}{cc|c}(2) & 4 & 8 \\ 3 & 1 & 2\end{array}\right]\)

2 step solution

Problem 19

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. The total number of passengers riding a certain city bus during the morning shift is 1000 . If the child's fare is $$\$ .50$$, the adult fare is $$\$ 1.50$$, and the total revenue from the fares in the morning shift is $$\$ 1300$$, how many children and how many adults rode the bus during the morning shift?

7 step solution

Problem 20

Compute the indicated products. \(\left[\begin{array}{rrrr}2 & 1 & -3 & 0 \\ 4 & -2 & -1 & 1 \\ -1 & 2 & 0 & 1\end{array}\right]\left[\begin{array}{rr}2 & -1 \\ 1 & 4 \\ 3 & -3 \\ 0 & -5\end{array}\right]\)

3 step solution

Problem 20

Perform the indicated operations. \(0.5\left[\begin{array}{rrr}1 & 3 & 5 \\ 5 & 2 & -1 \\ -2 & 0 & 1\end{array}\right]-0.2\left[\begin{array}{rrr}2 & 3 & 4 \\ -1 & 1 & -4 \\ 3 & 5 & -5\end{array}\right]\) \(+0.6\left[\begin{array}{rrr}3 & 4 & -1 \\ 4 & 5 & 1 \\ 1 & 0 & 0\end{array}\right]\)

3 step solution

Problem 20

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} x+2 y+z &=-2 \\\\-2 x-3 y-z &=1 \\ 2 x+4 y+2 z &=-4 \end{aligned}\)

4 step solution

Problem 20

Pivot the system about the circled element. \(\left[\begin{array}{ll|l}3 & 2 & 6 \\ (4) & 2 & 5\end{array}\right]\)

3 step solution

Problem 20

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. Cantwell Associates, a real estate developer, is planning to build a new apartment complex consisting of one-bedroom units and two- and three-bedroom townhouses. A total of 192 units is planned, and the number of family units (two- and three-bedroom townhouses) will equal the number of one-bedroom units. If the number of one-bedroom units will be 3 times the number of threebedroom units, find how many units of each type will be in the complex.

8 step solution

Problem 21

Compute the indicated products. \(4\left[\begin{array}{rrr}1 & -2 & 0 \\ 2 & -1 & 1 \\ 3 & 0 & -1\end{array}\right]\left[\begin{array}{rrr}1 & 3 & 1 \\ 1 & 4 & 0 \\ 0 & 1 & -2\end{array}\right]\)

4 step solution

Problem 21

Solve for \(u, x, y\), and \(z\) in the given matrix equation. \(\left[\begin{array}{crc}2 x-2 & 3 & 2 \\ 2 & 4 & y-2 \\ 2 z & -3 & 2\end{array}\right]=\left[\begin{array}{rrr}3 & u & 2 \\ 2 & 4 & 5 \\ 4 & -3 & 2\end{array}\right]\)

5 step solution

Problem 21

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} 3 x+2 y=& 4 \\\\-\frac{3}{2} x-y=&-2 \\ 6 x+4 y=& 8 \end{aligned}\)

6 step solution

Problem 21

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. he annual returns on Sid Carrington's three investments amounted to $$\$ 21,600: 6 \%$$ on a savings account, $$8 \%$$ on mutual funds, and $$12 \%$$ on bonds. The amount of Sid's investment in bonds was twice the amount of his investment in the savings account, and the interest earned from his investment in bonds was equal to the dividends he received from his investment in mutual funds. Find how much money he placed in each type of investment.

4 step solution

Problem 22

Compute the indicated products. \(3\left[\begin{array}{rrr}2 & -1 & 0 \\ 2 & 1 & 2 \\ 1 & 0 & -1\end{array}\right]\left[\begin{array}{rrr}2 & 3 & 1 \\ 3 & -3 & 0 \\ 0 & 1 & -1\end{array}\right]\)

2 step solution

Problem 22

Solve for \(u, x, y\), and \(z\) in the given matrix equation. \(\left[\begin{array}{rr}x & -2 \\ 3 & y\end{array}\right]+\left[\begin{array}{ll}-2 & z \\ -1 & 2\end{array}\right]=\left[\begin{array}{cr}4 & -2 \\ 2 u & 4\end{array}\right]\)

3 step solution

Problem 22

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} 3 y+2 z &=4 \\ 2 x-y-3 z &=3 \\ 2 x+2 y-z &=7 \end{aligned}\)

3 step solution

Problem 22

Pivot the system about the circled element. \(\left[\begin{array}{ll|l}(1) & 3 & 4 \\ 2 & 4 & 6\end{array}\right]\)

3 step solution

Problem 22

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. A private investment club has $$\$ 200,000$$ earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of $$15 \% / y e a r ;$$ medium-risk stocks, $$10 \% / y e a r ;$$ and low-risk stocks, $$6 \% /$$ year. The members have decided that the investment in low-risk stocks should be equal to the sum of the investments in the stocks of the other two categories. Determine how much the club should invest in each type of stock if the investment goal is to have a return of $$\$ 20,000 /$$ year on the total investment. (Assume that all the money available for investment is invested.)

2 step solution

Problem 23

Compute the indicated products. \(\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\left[\begin{array}{rrr}4 & -3 & 2 \\ 7 & 1 & -5\end{array}\right]\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\)

2 step solution

Problem 23

Solve for \(u, x, y\), and \(z\) in the given matrix equation. \(\left[\begin{array}{rr}1 & x \\ 2 y & -3\end{array}\right]-4\left[\begin{array}{rr}2 & -2 \\ 0 & 3\end{array}\right]=\left[\begin{array}{cc}3 z & 10 \\ 4 & -u\end{array}\right]\)

3 step solution

Problem 23

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} 2 x_{1}-x_{2}+x_{3} &=-4 \\ 3 x_{1}-\frac{3}{2} x_{2}+\frac{3}{2} x_{3} &=-6 \\\\-6 x_{1}+3 x_{2}-3 x_{3} &=12 \end{aligned}\)

7 step solution

Problem 23

Pivot the system about the circled element. \(\left[\begin{array}{rrr|r}(2) & 4 & 6 & 12 \\ 2 & 3 & 1 & 5 \\ 3 & -1 & 2 & 4\end{array}\right]\)

2 step solution

Problem 23

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. Lawnco produces three grades of commercial fertilizers. A 100 -lb bag of grade-A fertilizer contains 18 lb of nitrogen, 4 lb of phosphate, and 5 lb of potassium. A \(100-\mathrm{lb}\) bag of grade-B fertilizer contains \(20 \mathrm{lb}\) of nitrogen and \(4 \mathrm{lb}\) each of phosphate and potassium. A \(100-\mathrm{lb}\) bag of grade-C fertilizer contains 24 lb of nitrogen, 3 lb of phosphate, and 6 lb of potassium. How many \(100-\mathrm{lb}\) bags of each of the three grades of fertilizers should Lawnco produce if 26,400 lb of nitrogen, 4900 lb of phosphate, and \(6200 \mathrm{lb}\) of potassium are available and all the nutrients are used?

3 step solution

Problem 24

Compute the indicated products. \(2\left[\begin{array}{rrr}3 & 2 & -1 \\ 0 & 1 & 3 \\ 2 & 0 & 3\end{array}\right]\left[\begin{array}{rrr}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\left[\begin{array}{rrr}1 & 2 & 0 \\ 0 & -1 & -2 \\ 1 & 3 & 1\end{array}\right]\)

5 step solution

Problem 24

Solve for \(u, x, y\), and \(z\) in the given matrix equation. \(\left[\begin{array}{rr}1 & 2 \\ 3 & 4 \\ x & -1\end{array}\right]-3\left[\begin{array}{cc}y-1 & 2 \\ 1 & 2 \\ 4 & 2 z+1\end{array}\right]=2\left[\begin{array}{rr}-4 & -u \\ 0 & -1 \\ 4 & 4\end{array}\right]\)

3 step solution

Problem 24

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{array}{rr}x+y-2 z= & -3 \\ 2 x-y+3 z= & 7 \\ x-2 y+5 z= & 0\end{array}\)

6 step solution

Problem 24

Pivot the system about the circled element. \(\left[\begin{array}{rrr|r}1 & 3 & 2 & 4 \\ 2 & 4 & 8 & 6 \\ -1 & 2 & 3 & 4\end{array}\right]\)

4 step solution

Problem 25

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. \(\quad x+2 y=b_{1}$$2 x-y=b_{2}\) where (i) \(b_{1}=14, b_{2}=5\) and (ii) \(b_{1}=4, b_{2}=-1\)

4 step solution

Problem 25

Let $$\begin{array}{l}A=\left[\begin{array}{rrr}1 & 0 & -2 \\\1 & -3 & 2 \\\\-2 & 1 & 1 \end{array}\right] \quad B=\left[\begin{array}{rrr}3 & 1 & 0 \\\2 & 2 & 0 \\ 1 & -3 & -1\end{array}\right] \\\C=\left[\begin{array}{lll}2 & -1 & 0 \\\1 & -1 & 2 \\\3 & -2 & 1\end{array}\right]\end{array}$$ Verify the validity of the associative law for matrix multiplication.

5 step solution

Problem 25

Let $$\begin{array}{l}A=\left[\begin{array}{rrr}2 & -4 & 3 \\\4 & 2 & 1\end{array}\right] \quad B=\left[\begin{array}{rrr}4 & -3 & 2 \\\1 & 0 & 4\end{array}\right] \\ C=\left[\begin{array}{rrr}1 & 0 & 2 \\\3 & -2 & 1\end{array}\right]\end{array}$$ Verify by direct computation the validity of the commutative law for matrix addition.

4 step solution

Problem 25

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} x-2 y+3 z=& 4 \\ 2 x+3 y-z=& 2 \\ x+2 y-3 z=&-6 \end{aligned}\)

6 step solution

Problem 25

Pivot the system about the circled element. \(\left[\begin{array}{rrr|r}0 & 1 & 3 & 4 \\ 2 & 4 & 1 & 3 \\ 5 & 6 & 2 & -4\end{array}\right]\)

3 step solution

Problem 25

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. The management of Hartman Rent-A-Car has allocated $$\$ 1.5$$ million to buy a fleet of new automobiles consisting of compact, intermediate-size, and full- size cars. Compacts cost $$\ 12,000$$ each, intermediate size cars cost $$\ 18,000$$ each, and full-size cars cost $$\ 24,000$$ each. If Hartman purchases twice as many compacts as intermediate-size cars and the total number of cars to be purchased is 100, determine how many cars of each type will be purchased. (Assume that the entire budget will be used.)

4 step solution

Problem 26

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. \(3 x-2 y=b_{1}\) \(4 x+3 y=b_{2}\) where (i) \(b_{1}=-6, b_{2}=10\) and (ii) \(b_{1}=3, b_{2}=-2\)

4 step solution

Problem 26

Let $$\begin{array}{l}A=\left[\begin{array}{rrr}1 & 0 & -2 \\\1 & -3 & 2 \\\\-2 & 1 & 1 \end{array}\right] \quad B=\left[\begin{array}{rrr}3 & 1 & 0 \\\2 & 2 & 0 \\ 1 & -3 & -1\end{array}\right] \\\C=\left[\begin{array}{lll}2 & -1 & 0 \\\1 & -1 & 2 \\\3 & -2 & 1\end{array}\right]\end{array}$$ Verify the validity of the distributive law for matrix multiplication.

5 step solution

Problem 26

Let $$\begin{array}{l}A=\left[\begin{array}{rrr}2 & -4 & 3 \\\4 & 2 & 1\end{array}\right] \quad B=\left[\begin{array}{rrr}4 & -3 & 2 \\\1 & 0 & 4\end{array}\right] \\ C=\left[\begin{array}{rrr}1 & 0 & 2 \\\3 & -2 & 1\end{array}\right]\end{array}$$ Verify by direct computation the validity of the associative law for matrix addition.

3 step solution

Problem 26

Solve the system of linear equations, using the Gauss-Jordan elimination method. \(\begin{aligned} x_{1}-2 x_{2}+x_{3} &=-3 \\ 2 x_{1}+x_{2}-2 x_{3} &=2 \\\ x_{1}+3 x_{2}-3 x_{3} &=5 \end{aligned}\)

4 step solution

Problem 26

Pivot the system about the circled element. \(\left[\begin{array}{rrr|r}1 & 2 & 3 & 5 \\ 0 & -3 & 3 & 2 \\ 0 & 4 & -1 & 3\end{array}\right]\)

3 step solution

Problem 26

Formulate but do not solve the problem. You will be asked to solve these problems in the next section. The management of a private investment club has a fund of $$\$ 200,000$$ earmarked for investment in stocks. To arrive at an acceptable overall level of risk, the stocks that management is considering have been classified into three categories: high risk, medium risk, and low risk. Management estimates that high-risk stocks will have a rate of return of $$15 \% /$$ year; medium- risk stocks, $$10 \% /$$ year; and low-risk stocks, $$6 \% /$$ year. The investment in low-risk stocks is to be twice the sum of the investments in stocks of the other two categories. If the investment goal is to have an average rate of return of $$9 \% /$$ year on the total investment, determine how much the club should invest in each type of stock. (Assume that all the money available for investment is invested.)

3 step solution

Problem 27

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. \(\begin{aligned} x+2 y+z &=b_{1} \\ x+y+z &=b_{2} \\ 3 x+y+z &=b_{3} \\\ \text { where } & \text { (i) } b_{1}=7, b_{2}=4, b_{3}=2 \\ \text { and } & \text { (ii) } b_{1}=5, b_{2}=-3, b_{3}=-1 \end{aligned}\)

5 step solution

Problem 27

Let $$A=\left[\begin{array}{ll}1 & 2 \\\3 & 4 \end{array}\right] \text { and } B=\left[\begin{array}{ll}2 & 1 \\\4 & 3\end{array}\right]$$ Compute \(A B\) and \(B A\) and hence deduce that matrix multiplication is, in general, not commutative.

3 step solution

Problem 27

Let $$A=\left[\begin{array}{rr}3 & 1 \\\2 & 4 \\\\-4 & 0\end{array}\right] \text { and } B=\left[\begin{array}{rr}1 & 2 \\\\-1 & 0 \\\3 & 2\end{array}\right]$$ Verify each equation by direct computation\\. \((3+5) A=3 A+5 A\)

4 step solution

Problem 27

Fill in the missing entries by performing the indicated row operations to obtain the row-reduced matrices. \(\left[\begin{array}{ll|l}3 & 9 & 6 \\ 2 & 1 & 4\end{array}\right] \stackrel{\downarrow R_{1}}{\longrightarrow}\left[\begin{array}{ll|l}\cdot & \cdot & \cdot \\ 2 & 1 & 4\end{array}\right] \frac{R_{2}-2 R_{1}}{\longrightarrow}\) \(\left[\begin{array}{ll|l}1 & 3 & 2 \\ \cdot & \cdot & \cdot\end{array}\right]-\frac{1}{3} R_{2}\left[\begin{array}{ll|l}1 & 3 & 2 \\\ \cdot & \cdot & \cdot\end{array}\right] \frac{R_{1}-3 R_{2}}{\longrightarrow}\left[\begin{array}{ll|l}1 & 0 & 2 \\ 0 & 1 & 0\end{array}\right]\)

6 step solution

Problem 28

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. \(x_{1}+x_{2}+x_{3}=b_{1}\) \(x_{1}-x_{2}+x_{3}=b_{2}\) \(x_{1}-2 x_{2}-x_{3}=b_{3}\) where \(\quad\) (i) \(b_{1}=5, b_{2}=-3, b_{3}=-1\) and \(\quad\) (ii) \(b_{1}=1, b_{2}=4, b_{3}=-2\)

4 step solution

Problem 28

Let $$\begin{array}{l}A=\left[\begin{array}{lll}0 & 3 & 0 \\\1 & 0 & 1 \\\0 & 2 & 0\end{array}\right] \quad B=\left[\begin{array}{rrr}2 & 4 & 5 \\\3 & -1 & -6 \\\4 & 3 & 4\end{array}\right] \\\C=\left[\begin{array}{rrr} 4 & 5 & 6 \\\3 & -1 & -6 \\\2 & 2 & 3\end{array}\right]\end{array}$$ a. Compute \(\overline{A B}\). b. Compute \(A \bar{C}\). c. Using the results of parts (a) and (b), conclude that \(A B=A C\) does not imply that \(B=C\).

3 step solution

Problem 28

Let $$A=\left[\begin{array}{rr}3 & 1 \\\2 & 4 \\\\-4 & 0\end{array}\right] \text { and } B=\left[\begin{array}{rr}1 & 2 \\\\-1 & 0 \\\3 & 2\end{array}\right]$$ Verify each equation by direct computation\\. \(2(4 A)=(2 \cdot 4) A=8 A\)

3 step solution

Problem 28

Fill in the missing entries by performing the indicated row operations to obtain the row-reduced matrices. \(\left[\begin{array}{rr|r}1 & 2 & 1 \\ 2 & 3 & -1\end{array}\right] \stackrel{R_{2}-2 R_{1}}{\longrightarrow}\left[\begin{array}{ll|l}1 & 2 & 1 \\\ . & . & .\end{array}\right] \frac{-R_{2}}{\longrightarrow}\) \(\left[\begin{array}{ll|l}1 & 2 & 1 \\ . & . & .\end{array}\right] \frac{R_{1}-2 R_{2}}{\longrightarrow}\left[\begin{array}{ll|r}1 & 0 & -5 \\ 0 & 1 & 3\end{array}\right]\)

4 step solution

Problem 28

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. A system composed of two linear equations must have at least one solution if the straight lines represented by these equations are nonparallel.

3 step solution

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