Chapter 5

Applied Calculus · 409 exercises

Problem 104

Suppose that you have a positive function and you approximate the area under it using Riemann sums with midpoint rectangles. Explain why, if the function is linear, you will always get the exact area, no matter how many (or few) rectangles you use. [Hint: Make a sketch.]

5 step solution

Problem 105

Evaluate \(\int_{1}^{1} \frac{x^{43} e^{-17 x}+219 \sqrt[3]{x^{2}}}{\ln \sqrt[29]{6 x^{3}-x^{-11}}-\pi^{3}} d x .\) [Hint: No work necessary.

2 step solution

Problem 106

Find a formula for \(\int_{a} c d x .\) [Hint: No calculation necessary-just think of a graph.]

4 step solution

Problem 107

Finding \(\int_{-1}^{1} \frac{1}{x^{2}} d x\) by the Fundamental Theorem of Integral Calculus gives an answer of -2 , as you should check. However, shouldn't the area under a positive function be positive? Explain.

6 step solution

Problem 108

How will \(\int_{a}^{b} f(x) d x\) and \(\int_{b}^{a} f(x) d x\) differ? [Hint: Assume that they can be evaluated by the Fundamental Theorem of Integral Calculus, and think how they will differ at the "evaluate and subtract" step.

4 step solution

Problem 109

ECONOMICS: Pareto's Law The economist Vilfredo Pareto \((1848-1923)\) estimated that the number of people who have an income between \(A\) and \(B\) dollars \((A

5 step solution

Problem 110

BIOMEDICAL: Poiseuille's Law According to Poiseuille's law, the speed of blood in a blood vessel is given by \(V=\frac{p}{4 L v}\left(R^{2}-r^{2}\right)\) where \(R\) is the radius of the blood vessel, \(r\) is the distance of the blood from the center of the blood vessel, and \(p, L,\) and \(v\) are constants determined by the pressure and viscosity of the blood and the length of the vessel. The total blood flow is then given by $$ \left(\begin{array}{c} \text { Total } \\ \text { blood flow } \end{array}\right)=\int_{0}^{R} 2 \pi \frac{p}{4 L v}\left(R^{2}-r^{2}\right) r d r $$ Find the total blood flow by finding this integral \((p, L, v,\) and \(R\) are constants)

7 step solution

Problem 111

BUSINESS: Capital Value of an Asset The capital value of an asset (such as an oil well) that produces a continuous stream of income is the sum of the present value of all future earnings from the asset. Therefore, the capital value of an asset that produces income at the rate of \(r(t)\) dollars per year (at a continuous interest rate \(i\) ) is $$ \left(\begin{array}{c} \text { Capital } \\ \text { value } \end{array}\right)=\int_{0}^{T} r(t) e^{-i t} d t $$ where \(T\) is the expected life (in years) of the asset. Use the formula in the preceding instructions to find the capital value (at interest rate \(i=0.06\) ) of an oil well that produces income at the constant rate of \(r(t)=240,000\) dollars per year for 10 years.

7 step solution

Problem 112

BUSINESS: Capital Value of an Asset The capital value of an asset (such as an oil well) that produces a continuous stream of income is the sum of the present value of all future earnings from the asset. Therefore, the capital value of an asset that produces income at the rate of \(r(t)\) dollars per year (at a continuous interest rate \(i\) ) is $$ \left(\begin{array}{c} \text { Capital } \\ \text { value } \end{array}\right)=\int_{0}^{T} r(t) e^{-i t} d t $$ where \(T\) is the expected life (in years) of the asset. Use the formula in the preceding instructions to find the capital value (at interest rate \(i=0.05)\) of a uranium mine that produces income at the rate of \(r(t)=560,000 t^{1 / 2}\) dollars per year for 20 years.

5 step solution

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