Chapter 11
Algebra for College Students · 235 exercises
Problem 22
Find the partial fraction decomposition for each rational expression. See answers below. \(\frac{4 x^{2}+3 x+14}{x^{3}-8}\)
7 step solution
Problem 22
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}-5 x+6 y+4 z & =-4 \\ -7 x-8 y+2 z & =-2 \\ 2 x+9 y-z & =1\end{array}\right)\)
3 step solution
Problem 22
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}-5 & 1 & -1 \\ 3 & 4 & 2 \\ 0 & 2 & -3\end{array}\right|\)
6 step solution
Problem 22
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}-3 x+2 y+z & =17 \\ x-y+5 z & =-2 \\ 4 x-5 y-3 z & =-36\end{array}\right)\)
6 step solution
Problem 22
Solve each system by using the substitution method. \(\left(\begin{array}{l}y=5 x-9 \\ 5 x-y=9\end{array}\right)\)
3 step solution
Problem 23
Give a general description of partial fraction decomposition for someone who missed class the day it was discussed.
8 step solution
Problem 23
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}2 x-y+3 z=-17 \\ 3 y+z=5 \\ x-2 y-z=-3\end{array}\right)\)
6 step solution
Problem 23
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}3 & -4 & -2 \\ 5 & -2 & 1 \\ 1 & 0 & 0\end{array}\right|\)
5 step solution
Problem 23
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}x-3 y-z & =2 \\ 3 x+y-4 z & =-18 \\ -2 x+5 y+3 z & =2\end{array}\right)\)
6 step solution
Problem 23
Solve each system by using the substitution method. \(\left(\begin{array}{l}4 x+3 y=-7 \\ 3 x-2 y=16\end{array}\right)\)
5 step solution
Problem 24
Give a step-by-step explanation of how to find the partial fraction decomposition of \(\frac{11 x+5}{2 x^{2}+5 x-3}\).
7 step solution
Problem 24
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}2 x-y+3 z=-5 \\ 3 x+4 y-2 z=-25 \\\ -x+z=6\end{array}\right)\)
6 step solution
Problem 24
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}-6 & 5 & 3 \\ 2 & 0 & -1 \\ 4 & 0 & 7\end{array}\right|\)
6 step solution
Problem 24
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}x-4 y+3 z & =16 \\ 2 x+3 y-4 z & =-22 \\ -3 x+11 y-z & =-36\end{array}\right)\)
4 step solution
Problem 24
Solve each system by using the substitution method. \(\left(\begin{array}{l}5 x-3 y=-34 \\ 2 x+7 y=-30\end{array}\right)\)
7 step solution
Problem 25
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}x+3 y-4 z=-1 \\ 2 x-y+z=2 \\ 4 x+5 y-7 z=0\end{array}\right)\)
6 step solution
Problem 25
Use a matrix approach to solve each system. \(\left(\begin{array}{r}x-y+2 z=1 \\ -3 x+4 y-z=4 \\ -x+2 y+3 z=6\end{array}\right)\)
4 step solution
Problem 26
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}x-2 y+z=1 \\ 3 x+y-z=2 \\ 2 x-4 y+2 z=-1\end{array}\right)\)
5 step solution
Problem 26
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}2 & -1 & 3 \\ 0 & 3 & 1 \\ 4 & -8 & -4\end{array}\right|\)
5 step solution
Problem 26
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}x+2 y-5 z & =-1 \\ 2 x+3 y-2 z & =2 \\ 3 x+5 y-7 z & =4\end{array}\right)\)
5 step solution
Problem 26
Solve each system by using the substitution method. \(\left(\begin{array}{l}2 x+3 y=3 \\ 4 x-9 y=-4\end{array}\right)\)
5 step solution
Problem 27
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}3 x-2 y-3 z & =-5 \\ x+2 y+3 z & =-3 \\ -x+4 y-6 z & =8\end{array}\right)\)
7 step solution
Problem 27
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}2 & 3 & -4 \\ 4 & 6 & -1 \\ -6 & 1 & -2\end{array}\right|\)
4 step solution
Problem 27
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}-2 x+y+5 z & =-5 \\ 3 x+8 y-z & =-34 \\ x+2 y+z & =-12\end{array}\right)\)
5 step solution
Problem 27
Solve each system by using the substitution method. \(\left(\begin{array}{l}4 x-5 y=3 \\ 8 x+15 y=-24\end{array}\right)\)
5 step solution
Problem 28
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}3 x-2 y+z & =11 \\ 5 x+3 y & =17 \\ x+y-2 z & =6\end{array}\right)\)
7 step solution
Problem 28
Evaluate each \(3 \times 3\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrr}1 & 2 & -3 \\ -3 & -1 & 1 \\ 4 & 5 & 4\end{array}\right|\)
5 step solution
Problem 28
Use a matrix approach to solve each system. \(\left.\begin{array}{rl}4 x-10 y+3 z & =-19 \\ 2 x+5 y-z & =-7 \\ x-3 y-2 z & =-2\end{array}\right)\)
4 step solution
Problem 28
Solve each system by using the substitution method. \(\left(\begin{array}{c}4 x+y=9 \\ y=15-4 x\end{array}\right)\)
4 step solution
Problem 29
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}x-2 y+3 z & =1 \\ -2 x+4 y-3 z & =-3 \\ 5 x-6 y+6 z & =10\end{array}\right)\)
10 step solution
Problem 29
For Problems \(29-32\), evaluate each \(4 \times 4\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrrr}1 & -2 & 3 & 2 \\ 2 & -1 & 0 & 4 \\ -3 & 4 & 0 & -2 \\ -1 & 1 & 1 & 5\end{array}\right|\)
5 step solution
Problem 29
Use a matrix approach to solve each system. \(\left(\begin{array}{rl}2 x+3 y-z & =7 \\ 3 x+4 y+5 z & =-2 \\ 5 x+y+3 z & =13\end{array}\right)\)
4 step solution
Problem 29
Solve each system by using the substitution method. \(\left(\begin{array}{l}3 x+2 y=1 \\ 5 x-2 y=23\end{array}\right)\)
5 step solution
Problem 30
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}2 x-y+2 z=-1 \\ 4 x+3 y-4 z=2 \\ x+5 y-z=9\end{array}\right)\)
8 step solution
Problem 30
Evaluate each \(4 \times 4\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrrr}1 & 2 & 5 & 7 \\ -6 & 3 & 0 & 9 \\ -3 & 5 & 2 & 7 \\\ 2 & 1 & 4 & 3\end{array}\right|\)
7 step solution
Problem 30
Use a matrix approach to solve each system. \(\left(\begin{array}{r}4 x+3 y-z=0 \\ 3 x+2 y+5 z=6 \\ 5 x-y-3 z=3\end{array}\right)\)
4 step solution
Problem 30
Solve each system by using the substitution method. \(\left(\begin{array}{l}4 x+3 y=-22 \\ 4 x-5 y=26\end{array}\right)\)
5 step solution
Problem 31
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}-x-y+3 z & =-2 \\ -2 x+y+7 z & =14 \\ 3 x+4 y-5 z & =12\end{array}\right)\)
6 step solution
Problem 31
Evaluate each \(4 \times 4\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrrr}3 & -1 & 2 & 3 \\ 1 & 0 & 2 & 1 \\ 2 & 3 & 0 & 1 \\\ 5 & 2 & 4 & -5\end{array}\right|\)
4 step solution
Problem 31
Subscript notation is frequently used for working with larger systems of equations. For Problems 31-34, use a matrix approach to solve each system. Express the solutions as 4-tuples of the form \(\left(x_{1}, x_{2}, x_{3}, x_{4}\right)\).\(\left(\begin{array}{rl}x_{1}-3 x_{2}-2 x_{3}+x_{4} & =-3 \\ -2 x_{1}+7 x_{2}+x_{3}-2 x_{4} & =-1 \\ 3 x_{1}-7 x_{2}-3 x_{3}+3 x_{4} & =-5 \\\ 5 x_{1}+x_{2}+4 x_{3}-2 x_{4} & =18\end{array}\right)\)
5 step solution
Problem 31
Solve each system by using the substitution method. \(\left(\begin{array}{rl}x-3 y & =-22 \\ 2 x+7 y & =60\end{array}\right)\)
5 step solution
Problem 32
Use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{c}-2 x+y-3 z=-4 \\ x+5 y-4 z=13 \\ 7 x-2 y-z=37\end{array}\right)\)
6 step solution
Problem 32
Evaluate each \(4 \times 4\) determinant. Use the properties of determinants to your advantage. \(\left|\begin{array}{rrrr}1 & 2 & 0 & 0 \\ 3 & -1 & 4 & 5 \\ -2 & 4 & 1 & 6 \\\ 2 & -1 & -2 & -3\end{array}\right|\)
7 step solution
Problem 32
Subscript notation is frequently used for working with larger systems of equations. For Problems 31-34, use a matrix approach to solve each system. Express the solutions as 4-tuples of the form \(\left(x_{1}, x_{2}, x_{3}, x_{4}\right)\).\(\left(\begin{array}{rl}x_{1}-2 x_{2}+2 x_{3}-x_{4} & =-2 \\ -3 x_{1}+5 x_{2}-x_{3}-3 x_{4} & =2 \\ 2 x_{1}+3 x_{2}+3 x_{3}+5 x_{4} & =-9 \\\ 4 x_{1}-x_{2}-x_{3}-2 x_{4} & =8\end{array}\right)\)
5 step solution
Problem 32
Solve each system by using the substitution method. \(\left(\begin{array}{rl}6 x-y & =3 \\ 5 x+3 y & =-9\end{array}\right)\)
5 step solution
Problem 33
Give a step-by-step description of how you would solve the system $$ \left(\begin{array}{rl} 2 x-y+3 z & =31 \\ x-2 y-z & =8 \\ 3 x+5 y+8 z & =35 \end{array}\right) $$
6 step solution
Problem 33
Subscript notation is frequently used for working with larger systems of equations. For Problems 31-34, use a matrix approach to solve each system. Express the solutions as 4-tuples of the form \(\left(x_{1}, x_{2}, x_{3}, x_{4}\right)\).\(\left(\begin{array}{rl}x_{1}+3 x_{2}-x_{3}+2 x_{4} & =-2 \\ 2 x_{1}+7 x_{2}+2 x_{3}-x_{4} & =19 \\ -3 x_{1}-8 x_{2}+3 x_{3}+x_{4} & =-7 \\\ 4 x_{1}+11 x_{2}-2 x_{3}-3 x_{4} & =19\end{array}\right)\)
4 step solution
Problem 33
Solve each system by using the substitution method. \(\left(\begin{array}{l}4 x-5 y=21 \\ 3 x+7 y=-38\end{array}\right)\)
7 step solution
Problem 34
Give a step-by-step description of how you would finc the value of \(x\) in the solution for the system $$ \left(\begin{array}{rl} x+5 y-z & =-9 \\ 2 x-y+z & =11 \\ -3 x-2 y+4 z & =20 \end{array}\right) $$
8 step solution
Problem 34
Use the appropriate property of determinants from this section to justify each true statement. Do not evaluate the determinants. \(\left|\begin{array}{rrr}1 & -2 & 3 \\ 4 & -6 & -8 \\ 0 & 2 & 7\end{array}\right|=(-2)\left|\begin{array}{rrr}1 & -2 & 3 \\ -2 & 3 & 4 \\\ 0 & 2 & 7\end{array}\right|\)
3 step solution