Chapter 8

Algebra and Trigonometry Real Mathematics, Real People · 660 exercises

Problem 22

Find the determinant of the matrix. Expand by cofactors on each indicated row or column. \(\left[\begin{array}{rrr}-3 & 4 & 2 \\ 6 & 3 & 1 \\ 4 & -7 & -8\end{array}\right]\) (a) Row 2 (b) Column 3

6 step solution

Problem 22

Use Cramer's Rule to solve (if possible) the system of equations. \(\left\\{\begin{array}{rr}6 x-5 y= & 17 \\ -13 x+3 y= & -76\end{array}\right.\)

5 step solution

Problem 22

Write the system of linear equations represented by the augmented matrix. (Use the variables \(x, y, z,\) and \(w,\) if applicable.) $$\left[\begin{array}{rrrrrr} 6 & 2 & -1 & -5 & 5 & -25 \\ -1 & 0 & 7 & 3 & \vdots & 7 \\ 4 & -1 & -10 & 6 & \vdots & 23 \\ 0 & 8 & 1 & -11 & \vdots & -21 \end{array}\right]$$

4 step solution

Problem 22

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrr} 1 & 2 & -1 \\ 3 & 7 & -10 \\ -5 & -7 & -15 \end{array}\right]$$

4 step solution

Problem 22

Solve the system by the method of elimination and check any solutions algebraically. $$\left\\{\begin{array}{l} 9 x+3 y=18 \\ 2 x-7 y=-19 \end{array}\right.$$

5 step solution

Problem 22

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{array}{c} 6 x-3 y-4=0 \\ x+2 y-4=0 \end{array}\right.$$

5 step solution

Problem 22

Evaluating an Expression Evaluate the expression. $$\left[\begin{array}{rr} 6 & 9 \\ -1 & 0 \\ 7 & 1 \end{array}\right]+\left[\begin{array}{rr} 0 & 5 \\ -2 & -1 \\ 3 & -6 \end{array}\right]+\left[\begin{array}{rr} -13 & -7 \\ 4 & -1 \\ -6 & 0 \end{array}\right]$$

3 step solution

Problem 22

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{aligned} x+y+z &=5 \\ x-2 y+4 z &=-1 \\ 3 y+4 z &=-1 \end{aligned}\right.$$

7 step solution

Problem 23

Find the determinant of the matrix. Expand by cofactors on each indicated row or column. \(\left[\begin{array}{rrrr}6 & 0 & -3 & 5 \\ 4 & 13 & 6 & -8 \\ -1 & 0 & 7 & 4 \\ 8 & 6 & 0 & 2\end{array}\right]\) (a) Row 2 (b) Column 2

4 step solution

Problem 23

Identify the elementary row operation performed to obtain the new row- equivalent matrix. New Row-Equivalent Matrix \(\left[\begin{array}{rrr}1 & -2 & 5 \\ -2 & 6 & 7\end{array}\right]\) \(\left[\begin{array}{rrr}-18 & 0 & 6 \\ 5 & 2 & -2\end{array}\right]\) \(\left[\begin{array}{rrrr}-1 & -2 & 3 & -2 \\ 2 & -5 & 1 & -7 \\ 0 & -6 & 8 & -4\end{array}\right]\) \(\left[\begin{array}{rrrr}-1 & 3 & -7 & 6 \\ 0 & -1 & -5 & 5 \\ 4 & -5 & 1 & 3\end{array}\right]\) Original Matrix \(\left[\begin{array}{ccc}-4 & 8 & -20 \\ -2 & 6 & 7\end{array}\right]\)

2 step solution

Problem 23

Use Cramer's Rule to solve (if possible) the system of equations. \(\left\\{\begin{array}{l}4 x-y+z=-5 \\ 2 x+2 y+3 z=10 \\ 6 x+y+4 z=-5\end{array}\right.\)

3 step solution

Problem 23

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrr} -\frac{1}{2} & \frac{3}{4} & \frac{1}{4} \\ 1 & 0 & -\frac{3}{2} \\ 0 & -1 & \frac{1}{2} \end{array}\right]$$

4 step solution

Problem 23

Solve the system by the method of elimination and check any solutions algebraically. $$\left\\{\begin{array}{r} 1.8 x+1.2 y=4 \\ 9 x+6 y=3 \end{array}\right.$$

3 step solution

Problem 23

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{array}{l} 1.5 x+0.8 y=2.3 \\ 0.3 x-0.2 y=0.1 \end{array}\right.$$

5 step solution

Problem 23

Evaluating an Expression Evaluate the expression. $$\frac{1}{3}\left(\left[\begin{array}{rrr} -4 & 0 & 1 \\ 0 & 2 & -12 \end{array}\right]-\left[\begin{array}{rrr} 5 & 1 & -2 \\ 12 & -6 & 3 \end{array}\right]\right)$$

2 step solution

Problem 23

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{aligned} 2 x\quad &+2 z=2 \\ 5 x+3 y\quad &=4 \\ \quad3 y-4 z &=4 \end{aligned}\right.$$

5 step solution

Problem 24

Find the determinant of the matrix. Expand by cofactors on each indicated row or column. \(\left[\begin{array}{rrrr}10 & 8 & 3 & -7 \\ 4 & 0 & 5 & -6 \\ 0 & 3 & 2 & 7 \\\ 1 & 0 & -3 & 2\end{array}\right]\) (a) Row 3 (b) Column I

5 step solution

Problem 24

Use Cramer's Rule to solve (if possible) the system of equations. \(\left\\{\begin{array}{l}4 x-2 y+3 z=-2 \\ 2 x+2 y+5 z=16 \\ 8 x-5 y-2 z=4\end{array}\right.\)

5 step solution

Problem 24

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrr} -\frac{5}{6} & \frac{1}{3} & \frac{11}{6} \\ 0 & \frac{2}{3} & 2 \\ 1 & -\frac{1}{2} & -\frac{5}{2} \end{array}\right]$$

4 step solution

Problem 24

Solve the system by the method of elimination and check any solutions algebraically. $$\left\\{\begin{array}{l} 3.1 x-2.9 y=-10.2 \\ 31 x-12 y=34 \end{array}\right.$$

6 step solution

Problem 24

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{aligned} -0.5 x+4 y &=7.8 \\ 0.2 x-1.6 y &=-3.6 \end{aligned}\right.$$

4 step solution

Problem 24

Evaluating an Expression Evaluate the expression. $$\frac{1}{2}\left(\left[\begin{array}{ccc} 3 & -2 & 4 & 0 \end{array}\right]-\left[\begin{array}{cccc} 10 & -6 & -18 & 9 \end{array}\right]\right)$$

3 step solution

Problem 24

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{array}{r} 2 x+4 y+z=2 \\ -2 y-3 z=-8 \\ x-z=-1 \end{array}\right.$$

4 step solution

Problem 25

Solve the system of equations using (a) Gaussian elimination and (b) Cramer's Rule. Which method do you prefer, and why? \(\left\\{\begin{array}{l}3 x+3 y+5 z=1 \\ 3 x+5 y+9 z=2 \\ 5 x+9 y+17 z=4\end{array}\right.\)

3 step solution

Problem 25

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrr} 0.1 & 0.2 & 0.3 \\ -0.3 & 0.2 & 0.2 \\ 0.5 & 0.4 & 0.4 \end{array}\right]$$

3 step solution

Problem 25

Solve the system by the method of elimination and check any solutions algebraically. $$\left\\{\begin{array}{l} 3 x+\frac{1}{4} y=1 \\ 2 x-\frac{1}{3} y=0 \end{array}\right.$$

5 step solution

Problem 25

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{array}{c} \frac{1}{5} x+\frac{1}{2} y=8 \\ x+y=20 \end{array}\right.$$

5 step solution

Problem 25

Operations with Matrices Use the matrix capabilities of a graphing utility to evaluate the expression. Round your results to the nearest thousandths, if necessary. $$\frac{3}{7}\left[\begin{array}{rr} 2 & 5 \\ -1 & -4 \end{array}\right]+6\left[\begin{array}{rr} -3 & 0 \\ 2 & 2 \end{array}\right]$$

4 step solution

Problem 25

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{array}{cc} 4 x+y-3 z= & 11 \\ 2 x-3 y+2 z= & 9 \\ x+y+z= & -3 \end{array}\right.$$

4 step solution

Problem 26

Find the determinant of the matrix. Expand by cofactors on the row or column that appears to make the computations easiest. $$\left[\begin{array}{rrr}-3 & 1 & 0 \\\7 & 11 & 5 \\\1 & 2 & 2\end{array}\right]$$

4 step solution

Problem 26

Solve the system of equations using (a) Gaussian elimination and (b) Cramer's Rule. Which method do you prefer, and why? \(\left\\{\begin{array}{l}2 x+3 y-5 z=1 \\ 3 x+5 y+9 z=-16 \\ 5 x+9 y+17 z=-30\end{array}\right.\)

4 step solution

Problem 26

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrr} 0.6 & 0 & -0.3 \\ 0.7 & -1 & 0.2 \\ 1 & 0 & -0.9 \end{array}\right]$$

3 step solution

Problem 26

Solve the system by the method of elimination and check any solutions algebraically. $$\left\\{\begin{array}{c} \frac{1}{2} x-2 y=-\frac{5}{2} \\ -x+4 y=5 \end{array}\right.$$

4 step solution

Problem 26

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{array}{l} \frac{1}{2} x+\frac{3}{4} y=10 \\ \frac{3}{4} x-y=4 \end{array}\right.$$

4 step solution

Problem 26

Operations with Matrices Use the matrix capabilities of a graphing utility to evaluate the expression. Round your results to the nearest thousandths, if necessary. $$\frac{4}{5}\left[\begin{array}{rr} 14 & -11 \\ -22 & 19 \end{array}\right]+7\left[\begin{array}{rr} -22 & 20 \\ 13 & 6 \end{array}\right]$$

3 step solution

Problem 26

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{array}{c} 5 x-3 y+2 z=3 \\ 2 x+4 y-z=7 \\ x-11 y+4 z=3 \end{array}\right.$$

4 step solution

Problem 27

Fill in the blank(s) using elementary row operations to form a row-equivalent matrix. $$\begin{aligned} &\left[\begin{array}{ccc} 1 & 4 & 3 \\ 2 & 10 & 5 \end{array}\right]\\\ &\left[\begin{array}{rrr} 1 & 4 & 3 \\ 0 & & -1 \end{array}\right] \end{aligned}$$

3 step solution

Problem 27

Find the determinant of the matrix. Expand by cofactors on the row or column that appears to make the computations easiest. $$\left[\begin{array}{rrr} 6 & 3 & -7 \\ 0 & 0 & 0 \\ 4 & -6 & 3 \end{array}\right]$$

3 step solution

Problem 27

The retail sales of family clothing stores in the United States from 2009 through 2013 are shown in the table. The coefficients of the least squares regression parabola \(y=a t^{2}+b t+c,\) where \(y\) represents the retail sales (in billions of dollars) and \(t\) represents the year, with \(t=9\) corresponding to \(2009,\) can be found by solving the system \(\left\\{\begin{array}{rr}80,499 a+6985 b+615 c= & 56,453.6 \\\ 6985 a+615 b+55 c= & 5004.4 \\ 615 a+\quad 55 b+\quad 5 c= & 450.8\end{array}\right.\) (a) Use Cramer's Rule to solve the system and write the least squares regression parabola for the data. (b) Use a graphing utility to graph the parabola with the data. How well does the model fit the data? (c) Use the model to predict the retail sales of family clothing stores in the U.S. in the year 2015

4 step solution

Problem 27

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrrr} -1 & 0 & 1 & 0 \\ 0 & 2 & 0 & -2 \\ 2 & 0 & -1 & 0 \\ 0 & -1 & 0 & 1 \end{array}\right]$$

3 step solution

Problem 27

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{array}{l} -\frac{5}{3} x+y=5 \\ -5 x+3 y=6 \end{array}\right.$$

3 step solution

Problem 27

Operations with Matrices Use the matrix capabilities of a graphing utility to evaluate the expression. Round your results to the nearest thousandths, if necessary. $$-5\left[\begin{array}{rr} 3.211 & 6.829 \\ -1.004 & 4.914 \\ 0.055 & -3.889 \end{array}\right]-\frac{1}{4}\left[\begin{array}{rr} 1.630 & -3.090 \\ 5.256 & 8.335 \\ -9.768 & 4.251 \end{array}\right]$$

2 step solution

Problem 27

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{aligned} 3 x-2 y+4 z &=1 \\ x+y-2 z &=3 \\ 2 x-3 y+6 z &=8 \end{aligned}\right.$$

7 step solution

Problem 28

The retail sales \(y\) (in billions of dollars) of stores selling auto parts, accessories, and tires in the United States from 2009 through 2013 are given by the ordered pairs of the form \((t, y(t)),\) where \(t=9\) represents \(2009 .\) $$\begin{aligned} &(9,74.1) \quad(10,77.7) \quad(11,82.7)\\\ &(12,83.9) \quad(13,82.8) \end{aligned}$$ The coefficients of the least squares regression parabola \(y=a t^{2}+b t+c\) can be found by solving the system \(\left\\{\begin{array}{rr}80,499 a+6985 b+615 c= & 49,853.8 \\ 6985 a+615 b+55 c= & 4436.8 \\ 615 a+\quad 55 b+\quad 5 c= & 401.2\end{array}\right.\) (a) Use Cramer's Rule to solve the system and write the least squares regression parabola for the data. (b) Use a graphing utility to graph the parabola with the data. How well does the model fit the data? (c) Is this a good model for predicting retail sales in future years? Explain.

3 step solution

Problem 28

Find the determinant of the matrix. Expand by cofactors on the row or column that appears to make the computations easiest. $$\left[\begin{array}{rrr}1 & 1 & 2 \\\3 & -5 & 9 \\\0 & 0 & 0\end{array}\right]$$

3 step solution

Problem 28

Finding the Inverse of a Matrix, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). $$\left[\begin{array}{rrrr} 1 & -2 & -1 & -2 \\ 3 & -5 & -2 & -3 \\ 2 & -5 & -2 & -5 \\ -1 & 4 & 4 & 11 \end{array}\right]$$

3 step solution

Problem 28

Solve the system by the method of substitution. Use a graphing utility to verify your results. $$\left\\{\begin{aligned} -\frac{2}{3} x+y &=2 \\ 3 x-\frac{1}{2} y &=4 \end{aligned}\right.$$

5 step solution

Problem 28

Operations with Matrices Use the matrix capabilities of a graphing utility to evaluate the expression. Round your results to the nearest thousandths, if necessary. $$-3\left[\begin{array}{rr} 10 & 15 \\ -20 & 10 \\ 12 & 4 \end{array}\right]-\frac{1}{8}\left(\left[\begin{array}{rr} 12 & 11 \\ 7 & 0 \\ 6 & 9 \end{array}\right]+\left[\begin{array}{rr} -3 & 13 \\ -3 & 8 \\ -14 & 15 \end{array}\right]\right)$$

5 step solution

Problem 28

Solve the system of linear equations and check any solution algebraically. $$\left\\{\begin{array}{l} 2 x+4 y+z=-4 \\ 2 x-4 y+6 z=13 \\ 4 x-2 y+z=6 \end{array}\right.$$

6 step solution

Problem 29

Find the determinant of the matrix. Expand by cofactors on the row or column that appears to make the computations easiest. $$\left[\begin{array}{rrr}-1 & 2 & -5 \\\0 & 3 & -4 \\\0 & 0 & 3\end{array}\right]$$

3 step solution

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