Chapter 7
Algebra 1 · 320 exercises
Problem 1
Describe the graph of a linear system that has the given number of solutions. Sketch an example. no solution
2 step solution
Problem 1
Determine whether the following statement is true or false. A solution of \(a\) system of linear inequalities is an ordered pair that is a solution of any one of the inequalities in the system. Explain.
3 step solution
Problem 1
When you use the linear combinations method to solve a linear system, what is the purpose of using multiplication as the first step?
3 step solution
Problem 1
Use the linear system below. $$-x+y=5 \quad \text { Equation } 1$$ $$\frac{1}{2} x+y=8 \quad \text { Equation } 2$$ Which equation would you choose to solve for y? Why?
3 step solution
Problem 1
Explain what it means to solve a system of linear equations.
3 step solution
Problem 2
Describe the graph of a linear system that has the given number of solutions. Sketch an example. infinitely many solutions
2 step solution
Problem 2
How is graphing a system of linear inequalities the same as graphing a system of linear equations? How is it different?
5 step solution
Problem 2
Use the linear system below. $$-x+y=5 \quad \text { Equation } 1$$ $$\frac{1}{2} x+y=8 \quad \text { Equation } 2$$ Solve for \(y\) in the equation that you chose.
5 step solution
Problem 3
Describe the graph of a linear system that has the given number of solutions. Sketch an example. exactly one solution
2 step solution
Problem 3
Graph the linear system below. Then decide if the ordered pair is a solution of the system. $$ \begin{array}{l} -x+y=-2 \\ 2 x+y=10 \end{array} $$ $$ (-4,-2) $$
3 step solution
Problem 3
After you graph a system of linear inequalities, how can you use algebra to check whether the correct region is shaded?
4 step solution
Problem 3
Choose a method to solve the linear system. Explain your choice. $$ \begin{aligned} &x+y=300\\\ &x+3 y=18 \end{aligned} $$
4 step solution
Problem 3
Use the linear system below. $$-x+y=5 \quad \text { Equation } 1$$ $$\frac{1}{2} x+y=8 \quad \text { Equation } 2$$ Substitute the expression into the other equation and solve for \(x .\)
4 step solution
Problem 4
Graph the linear system below. Then decide if the ordered pair is a solution of the system. $$ \begin{array}{l} -x+y=-2 \\ 2 x+y=10 \end{array} $$ $$ (4,-2) $$
4 step solution
Problem 4
Choose a method to solve the linear system. Explain your choice. $$ \begin{aligned} &3 x+5 y=25\\\ &2 x-6 y=12 \end{aligned} $$
5 step solution
Problem 4
Explain the steps you would use to solve the system of equations using linear combinations. Then solve the system. $$\begin{aligned} &x+3 y=6\\\ &x-3 y=12 \end{aligned}$$
5 step solution
Problem 4
Use the linear system below. $$-x+y=5 \quad \text { Equation } 1$$ $$\frac{1}{2} x+y=8 \quad \text { Equation } 2$$ Substitute the value of \(x\) into your equation from Exercise 2 . What is the solution of the linear system?
4 step solution
Problem 5
Explain how you can tell if the system of linear equations has a solution. Then solve the system. $$ \begin{aligned}&x-y=2\\\&4 x-4 y=8\end{aligned} $$
3 step solution
Problem 5
Graph the linear system below. Then decide if the ordered pair is a solution of the system. $$ \begin{array}{l} -x+y=-2 \\ 2 x+y=10 \end{array} $$ $$ (-4,2) $$
4 step solution
Problem 5
Choose a method to solve the linear system. Explain your choice.. $$ \begin{aligned} &2 x+y=0\\\ &x+y=5 \end{aligned} $$
3 step solution
Problem 5
Explain the steps you would use to solve the system of equations using linear combinations. Then solve the system. $$\begin{aligned} &x-3 y=0\\\ &x+10 y=13 \end{aligned}$$
4 step solution
Problem 5
Use the linear system below. $$-x+y=5 \quad \text { Equation } 1$$ $$\frac{1}{2} x+y=8 \quad \text { Equation } 2$$ Explain how you can check the solution algebraically and graphically.
3 step solution
Problem 6
Graph the system of linear equations. Does the system have exactly one solution, no solution, or infinitely many solutions? $$ \begin{aligned}&2 x+y=5\\\&-6 x-3 y=-15\end{aligned} $$
3 step solution
Problem 6
Graph the linear system below. Then decide if the ordered pair is a solution of the system. $$ \begin{array}{l} -x+y=-2 \\ 2 x+y=10 \end{array} $$ $$ (4,2) $$
3 step solution
Problem 6
Graph the system of linear inequalities. $$y>-2 x+2\( \)y \leq-1$$
3 step solution
Problem 6
Use the following problem. The total cost of 10 gallons of regular gasoline and 15 gallons of premium gasoline is \(\$ 32.75 .\) Premium costs \(\$ .20\) more per gallon than regular. What is the cost per gallon of each type of gasoline? Write a verbal model for the problem.
3 step solution
Problem 6
Explain the steps you would use to solve the system of equations using linear combinations. Then solve the system. $$\begin{aligned} &3 x-4 y=7\\\ &2 x-y=3 \end{aligned}$$
5 step solution
Problem 6
Use substitution to solve the linear system. $$\begin{aligned} &3 x+y=3\\\ &7 x+2 y=1 \end{aligned}$$
6 step solution
Problem 7
Graph the system of linear equations. Does the system have exactly one solution, no solution, or infinitely many solutions? $$ \begin{array}{l}-6 x+2 y=4 \\\\-9 x+3 y=12\end{array} $$
3 step solution
Problem 7
Graph the system of linear inequalities. \(y>x\) \(x \leq 1\)
3 step solution
Problem 7
Use the following problem. The total cost of 10 gallons of regular gasoline and 15 gallons of premium gasoline is \(\$ 32.75 .\) Premium costs \(\$ .20\) more per gallon than regular. What is the cost per gallon of each type of gasoline? Assign labels to the verbal model.
3 step solution
Problem 7
Explain the steps you would use to solve the system of equations using linear combinations. Then solve the system. $$\begin{aligned} &2 y=-2+2 x\\\ &2 x+3 y=12 \end{aligned}$$
3 step solution
Problem 7
Use substitution to solve the linear system. $$\begin{aligned} &2 x-y=-1\\\ &2 x+y=-7 \end{aligned}$$
4 step solution
Problem 8
Graph the system of linear equations. Does the system have exactly one solution, no solution, or infinitely many solutions? $$ \begin{aligned}&2 x+y=7\\\&3 x-y=-2\end{aligned} $$
4 step solution
Problem 8
Use the graph-and-check method to solve the system of linear equations. $$ \begin{aligned} &y=2 x-1\\\ &y=x+1 \end{aligned} $$
3 step solution
Problem 8
Graph the system of linear inequalities. \(x+1>y\) \(y \geq 0\)
3 step solution
Problem 8
Use the following problem. The total cost of 10 gallons of regular gasoline and 15 gallons of premium gasoline is \(\$ 32.75 .\) Premium costs \(\$ .20\) more per gallon than regular. What is the cost per gallon of each type of gasoline? Write a linear system as an algebraic model.
4 step solution
Problem 8
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &2 x+y=4\\\ &x-y=2 \end{aligned}$$
4 step solution
Problem 8
Use substitution to solve the linear system. $$\begin{aligned} &3 x-y=0\\\ &5 y=15 \end{aligned}$$
4 step solution
Problem 9
Use the substitution method or linear combinations to solve the linear system and tell how many solutions the system has. $$ \begin{aligned}&-x+y=7\\\&2 x-2 y=-18\end{aligned} $$
4 step solution
Problem 9
Use the graph-and-check method to solve the system of linear equations. $$ \begin{aligned} &y=-2 x+3\\\ &y=x-3 \end{aligned} $$
3 step solution
Problem 9
Use the following problem. The total cost of 10 gallons of regular gasoline and 15 gallons of premium gasoline is \(\$ 32.75 .\) Premium costs \(\$ .20\) more per gallon than regular. What is the cost per gallon of each type of gasoline? Solve the system and answer the question.
4 step solution
Problem 9
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &a-b=8\\\ &a+b=20 \end{aligned}$$
5 step solution
Problem 9
Use substitution to solve the linear system. $$\begin{aligned} &2 x+y=4\\\ &-x+y=1 \end{aligned}$$
4 step solution
Problem 10
Use the substitution method or linear combinations to solve the linear system and tell how many solutions the system has. $$ \begin{aligned}&-4 x+y=-8\\\&-12 x+3 y=-24\end{aligned} $$
3 step solution
Problem 10
Use the graph-and-check method to solve the system of linear equations. $$ \begin{aligned} &y=\frac{1}{2} x+2\\\ &y=-x+5 \end{aligned} $$
3 step solution
Problem 10
Solve the linear system using all three methods. $$ \begin{aligned} &x+y=2\\\ &6 x+y=2 \end{aligned} $$
8 step solution
Problem 10
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &y-2 x=0\\\ &6 y+2 x=0 \end{aligned}$$
5 step solution
Problem 10
Use substitution to solve the linear system. $$\begin{aligned} &x-y=0\\\ &x+y=2 \end{aligned}$$
4 step solution
Problem 11
Use the substitution method or linear combinations to solve the linear system and tell how many solutions the system has. $$ \begin{aligned}&-4 x+y=-8\\\&2 x-2 y=-14\end{aligned} $$
5 step solution