Chapter 6

A Graphical Approach to College Algebra · 524 exercises

Problem 36

\(\begin{aligned} \frac{5}{x}-\frac{1}{y}-\frac{2}{z} &=-6 \\ -\frac{1}{x}+\frac{3}{y}-\frac{3}{z} &=-12 \\ \frac{2}{x}-\frac{1}{y}-\frac{1}{z} &=6 \end{aligned}\)

7 step solution

Problem 36

Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}4 & 5 & -1 & -1 \\\2 & -3 & 1 & 0 \\\\-5 & 1 & 3 & 9 \\\0 & -2 & 1 & 5\end{array}\right]$$

14 step solution

Problem 37

Solve each system by elimination. $$\begin{array}{r}9 x-5 y=1 \\\\-18 x+10 y=1\end{array}$$

4 step solution

Problem 37

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}2 x+y>2 \\\x-3 y<6\end{array}$$

6 step solution

Problem 37

Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x+3 y=-10\\\ &3 x+4 y=-12 \end{aligned}$$

3 step solution

Problem 37

\(\begin{aligned} &x-4 y+2 z=-2\\\ &x+2 y-2 z=-3\\\ &x-y \quad=4 \end{aligned}\)

6 step solution

Problem 37

Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}4 & 0 & 0 & 2 \\\\-1 & 0 & 3 & 0 \\\2 & 4 & 0 & 1 \\\0 & 0 & 1 & 2\end{array}\right]$$

10 step solution

Problem 37

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} &2 x-3 y=2\\\ &4 x-6 y=1 \end{aligned}$$

3 step solution

Problem 38

Solve each system by elimination. $$\begin{aligned}&3 x+2 y=5\\\&6 x+4 y=8\end{aligned}$$

3 step solution

Problem 38

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}4 x+3 y<12 \\\y+4 x>-4\end{array}$$

4 step solution

Problem 38

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{array}{r} x+2 y=1 \\ 2 x+4 y=3 \end{array}$$

4 step solution

Problem 38

Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x-3 y=10\\\ &2 x+2 y=5 \end{aligned}$$

5 step solution

Problem 38

\(\begin{aligned} 2 x+y+3 z &=4 \\ -3 x-y-4 z &=5 \\ x+y+2 z &=0 \end{aligned}\)

4 step solution

Problem 38

Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}-2 & 0 & 4 & 2 \\\3 & 6 & 0 & 4 \\\0 & 0 & 0 & 3 \\\9 & 0 & 2 & -1\end{array}\right]$$

6 step solution

Problem 39

Solve each system by elimination. $$\begin{aligned}&3 x+y=6\\\&6 x+2 y=1\end{aligned}$$

4 step solution

Problem 39

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}3 x+5 y \leq 15 \\\x-3 y \geq 9\end{array}$$

5 step solution

Problem 39

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} 6 x-3 y &=1 \\ -12 x+6 y &=-2 \end{aligned}$$

5 step solution

Problem 39

Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x-5 y=10\\\ &2 x-5 y=15 \end{aligned}$$

3 step solution

Problem 39

\(\begin{array}{l} x+y+z=0 \\ x-y-z=3 \\ x+3 y+3 z=5 \end{array}\)

4 step solution

Problem 39

Find matrix \(A\) if $$B=\left[\begin{array}{rrr} 4 & 6 & -5 \\ -6 & 3 & 2 \end{array}\right] \text { and } A+B=\left[\begin{array}{rrr} 6 & 12 & 0 \\ -10 & -4 & 11 \end{array}\right].$$

5 step solution

Problem 39

A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(0,0), Q(0,2), R(1,4)$$

4 step solution

Problem 40

Solve each system by elimination. $$\begin{aligned}&3 x+5 y=-2\\\&9 x+15 y=-6\end{aligned}$$

4 step solution

Problem 40

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}y \leq x \\\x^{2}+y^{2}<1\end{array}$$

4 step solution

Problem 40

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} x-y &=1 \\ -x+y &=-1 \end{aligned}$$

5 step solution

Problem 40

\(\begin{array}{r} x+3 y+z=6 \\ 3 x+y-z=6 \\ x-y-z=0 \end{array}\)

6 step solution

Problem 40

Find matrix \(B\) if $$A=\left[\begin{array}{rrr} 3 & 6 & 5 \\ -2 & 1 & 4 \end{array}\right] \text { and } A-B=\left[\begin{array}{rrr} 9 & 0 & -5 \\ -4 & 6 & -3 \end{array}\right].$$

5 step solution

Problem 40

A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(0,1), Q(2,0), R(1,5)$$

4 step solution

Problem 41

Solve each system by elimination. $$\begin{array}{l}\frac{x}{2}+\frac{y}{3}=8 \\\\\frac{2 x}{3}+\frac{3 y}{2}=17\end{array}$$

6 step solution

Problem 41

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{aligned}4 x-3 y & \leq 12 \\\y & \leq x^{2}\end{aligned}$$

5 step solution

Problem 41

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{array}{l} x+y=-1 \\ y+z=4 \\ x+z=1 \end{array}$$

6 step solution

Problem 41

Solve each system by using the matrix inverse method. $$\begin{aligned} 2 x+4 z &=14 \\ 3 x+y+5 z &=19 \\ -x+y-2 z &=-7 \end{aligned}$$

5 step solution

Problem 41

\(\begin{aligned} 2 x-y+2 z &=6 \\ -x+y+z &=0 \\ -x-3 z &=-6 \end{aligned}\)

5 step solution

Problem 41

The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 4 \times 2 ; B \text { is } 2 \times 4.$$

5 step solution

Problem 41

A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(2,5), Q(-1,3), R(4,0)$$

7 step solution

Problem 42

Solve each system by elimination. $$\begin{aligned}&\frac{x}{5}+3 y=31\\\&2 x-\frac{y}{5}=8\end{aligned}$$

6 step solution

Problem 42

Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{aligned}&y \leq-x^{2}\\\&y \geq x^{2}-6\end{aligned}$$

6 step solution

Problem 42

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} &x-z=-3\\\ &y+z=9\\\ &x+z=7 \end{aligned}$$

7 step solution

Problem 42

Solve each system by using the matrix inverse method. $$\begin{aligned} 3 x+6 y+3 z &=12 \\ 6 x+4 y-2 z &=-4 \\ y-z &=-3 \end{aligned}$$

5 step solution

Problem 42

\(\begin{aligned} x+2 y+z &=0 \\ 3 x+2 y-z &=4 \\ -x+2 y+3 z &=-4 \end{aligned}\)

8 step solution

Problem 42

The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 3 \times 1 ; B \text { is } 1 \times 3.$$

5 step solution

Problem 42

A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(2,-2), Q(0,0), R(-3,-4)$$

4 step solution

Problem 43

Graph the solution set of each system of inequalities by hand. $$\begin{aligned} x+y & \leq 9 \\ x & \leq-y^{2} \end{aligned}$$

4 step solution

Problem 43

Solve each system by elimination. $$\begin{array}{l}\frac{2 x-1}{3}+\frac{y+2}{4}=4 \\\\\frac{x+3}{2}-\frac{x-y}{3}=3\end{array}$$

6 step solution

Problem 43

Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} x+y-z &=6 \\ 2 x-y+z &=-9 \\ x-2 y+3 z &=1 \end{aligned}$$

8 step solution

Problem 43

Solve each system by using the matrix inverse method. $$\begin{aligned} x+3 y+z &=2 \\ x-2 y+3 z &=-3 \\ 2 x-3 y-z &=34 \end{aligned}$$

5 step solution

Problem 43

Feed Requirements Solve the system from Example 4 . $$ \begin{aligned} 25 x+40 y+20 z &=2200 \\ 4 x+2 y+3 z &=280 \\ 3 x+2 y+z &=180 \end{aligned} $$

5 step solution

Problem 43

The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 3 \times 5 ; B \text { is } 5 \times 2.$$

4 step solution

Problem 43

A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(1,2), Q(4,3), R(3,5)$$

5 step solution

Problem 44

Graph the solution set of each system of inequalities by hand. $$\begin{aligned} &x+2 y \leq 4\\\ &y \geq x^{2}-1 \end{aligned}$$

5 step solution

Problem 44

Solve each system by elimination. $$\begin{aligned}&\frac{x+6}{5}+\frac{2 y-x}{10}=1\\\&\frac{x+2}{4}+\frac{3 y+2}{5}=-3\end{aligned}$$

5 step solution

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