Chapter 6
A Graphical Approach to College Algebra · 524 exercises
Problem 36
\(\begin{aligned} \frac{5}{x}-\frac{1}{y}-\frac{2}{z} &=-6 \\ -\frac{1}{x}+\frac{3}{y}-\frac{3}{z} &=-12 \\ \frac{2}{x}-\frac{1}{y}-\frac{1}{z} &=6 \end{aligned}\)
7 step solution
Problem 36
Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}4 & 5 & -1 & -1 \\\2 & -3 & 1 & 0 \\\\-5 & 1 & 3 & 9 \\\0 & -2 & 1 & 5\end{array}\right]$$
14 step solution
Problem 37
Solve each system by elimination. $$\begin{array}{r}9 x-5 y=1 \\\\-18 x+10 y=1\end{array}$$
4 step solution
Problem 37
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}2 x+y>2 \\\x-3 y<6\end{array}$$
6 step solution
Problem 37
Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x+3 y=-10\\\ &3 x+4 y=-12 \end{aligned}$$
3 step solution
Problem 37
\(\begin{aligned} &x-4 y+2 z=-2\\\ &x+2 y-2 z=-3\\\ &x-y \quad=4 \end{aligned}\)
6 step solution
Problem 37
Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}4 & 0 & 0 & 2 \\\\-1 & 0 & 3 & 0 \\\2 & 4 & 0 & 1 \\\0 & 0 & 1 & 2\end{array}\right]$$
10 step solution
Problem 37
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} &2 x-3 y=2\\\ &4 x-6 y=1 \end{aligned}$$
3 step solution
Problem 38
Solve each system by elimination. $$\begin{aligned}&3 x+2 y=5\\\&6 x+4 y=8\end{aligned}$$
3 step solution
Problem 38
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}4 x+3 y<12 \\\y+4 x>-4\end{array}$$
4 step solution
Problem 38
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{array}{r} x+2 y=1 \\ 2 x+4 y=3 \end{array}$$
4 step solution
Problem 38
Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x-3 y=10\\\ &2 x+2 y=5 \end{aligned}$$
5 step solution
Problem 38
\(\begin{aligned} 2 x+y+3 z &=4 \\ -3 x-y-4 z &=5 \\ x+y+2 z &=0 \end{aligned}\)
4 step solution
Problem 38
Evaluate each determinant. $$\operatorname{det}\left[\begin{array}{rrrr}-2 & 0 & 4 & 2 \\\3 & 6 & 0 & 4 \\\0 & 0 & 0 & 3 \\\9 & 0 & 2 & -1\end{array}\right]$$
6 step solution
Problem 39
Solve each system by elimination. $$\begin{aligned}&3 x+y=6\\\&6 x+2 y=1\end{aligned}$$
4 step solution
Problem 39
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}3 x+5 y \leq 15 \\\x-3 y \geq 9\end{array}$$
5 step solution
Problem 39
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} 6 x-3 y &=1 \\ -12 x+6 y &=-2 \end{aligned}$$
5 step solution
Problem 39
Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x-5 y=10\\\ &2 x-5 y=15 \end{aligned}$$
3 step solution
Problem 39
\(\begin{array}{l} x+y+z=0 \\ x-y-z=3 \\ x+3 y+3 z=5 \end{array}\)
4 step solution
Problem 39
Find matrix \(A\) if $$B=\left[\begin{array}{rrr} 4 & 6 & -5 \\ -6 & 3 & 2 \end{array}\right] \text { and } A+B=\left[\begin{array}{rrr} 6 & 12 & 0 \\ -10 & -4 & 11 \end{array}\right].$$
5 step solution
Problem 39
A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(0,0), Q(0,2), R(1,4)$$
4 step solution
Problem 40
Solve each system by elimination. $$\begin{aligned}&3 x+5 y=-2\\\&9 x+15 y=-6\end{aligned}$$
4 step solution
Problem 40
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}y \leq x \\\x^{2}+y^{2}<1\end{array}$$
4 step solution
Problem 40
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} x-y &=1 \\ -x+y &=-1 \end{aligned}$$
5 step solution
Problem 40
\(\begin{array}{r} x+3 y+z=6 \\ 3 x+y-z=6 \\ x-y-z=0 \end{array}\)
6 step solution
Problem 40
Find matrix \(B\) if $$A=\left[\begin{array}{rrr} 3 & 6 & 5 \\ -2 & 1 & 4 \end{array}\right] \text { and } A-B=\left[\begin{array}{rrr} 9 & 0 & -5 \\ -4 & 6 & -3 \end{array}\right].$$
5 step solution
Problem 40
A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(0,1), Q(2,0), R(1,5)$$
4 step solution
Problem 41
Solve each system by elimination. $$\begin{array}{l}\frac{x}{2}+\frac{y}{3}=8 \\\\\frac{2 x}{3}+\frac{3 y}{2}=17\end{array}$$
6 step solution
Problem 41
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{aligned}4 x-3 y & \leq 12 \\\y & \leq x^{2}\end{aligned}$$
5 step solution
Problem 41
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{array}{l} x+y=-1 \\ y+z=4 \\ x+z=1 \end{array}$$
6 step solution
Problem 41
Solve each system by using the matrix inverse method. $$\begin{aligned} 2 x+4 z &=14 \\ 3 x+y+5 z &=19 \\ -x+y-2 z &=-7 \end{aligned}$$
5 step solution
Problem 41
\(\begin{aligned} 2 x-y+2 z &=6 \\ -x+y+z &=0 \\ -x-3 z &=-6 \end{aligned}\)
5 step solution
Problem 41
The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 4 \times 2 ; B \text { is } 2 \times 4.$$
5 step solution
Problem 41
A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(2,5), Q(-1,3), R(4,0)$$
7 step solution
Problem 42
Solve each system by elimination. $$\begin{aligned}&\frac{x}{5}+3 y=31\\\&2 x-\frac{y}{5}=8\end{aligned}$$
6 step solution
Problem 42
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{aligned}&y \leq-x^{2}\\\&y \geq x^{2}-6\end{aligned}$$
6 step solution
Problem 42
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} &x-z=-3\\\ &y+z=9\\\ &x+z=7 \end{aligned}$$
7 step solution
Problem 42
Solve each system by using the matrix inverse method. $$\begin{aligned} 3 x+6 y+3 z &=12 \\ 6 x+4 y-2 z &=-4 \\ y-z &=-3 \end{aligned}$$
5 step solution
Problem 42
\(\begin{aligned} x+2 y+z &=0 \\ 3 x+2 y-z &=4 \\ -x+2 y+3 z &=-4 \end{aligned}\)
8 step solution
Problem 42
The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 3 \times 1 ; B \text { is } 1 \times 3.$$
5 step solution
Problem 42
A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(2,-2), Q(0,0), R(-3,-4)$$
4 step solution
Problem 43
Graph the solution set of each system of inequalities by hand. $$\begin{aligned} x+y & \leq 9 \\ x & \leq-y^{2} \end{aligned}$$
4 step solution
Problem 43
Solve each system by elimination. $$\begin{array}{l}\frac{2 x-1}{3}+\frac{y+2}{4}=4 \\\\\frac{x+3}{2}-\frac{x-y}{3}=3\end{array}$$
6 step solution
Problem 43
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} x+y-z &=6 \\ 2 x-y+z &=-9 \\ x-2 y+3 z &=1 \end{aligned}$$
8 step solution
Problem 43
Solve each system by using the matrix inverse method. $$\begin{aligned} x+3 y+z &=2 \\ x-2 y+3 z &=-3 \\ 2 x-3 y-z &=34 \end{aligned}$$
5 step solution
Problem 43
Feed Requirements Solve the system from Example 4 . $$ \begin{aligned} 25 x+40 y+20 z &=2200 \\ 4 x+2 y+3 z &=280 \\ 3 x+2 y+z &=180 \end{aligned} $$
5 step solution
Problem 43
The dimensions of matrices \(A\) and \(B\) are given. Find the dimensions of the product \(A B\) and of the product BA if the products are defined. If they are not defined, say so. $$A \text { is } 3 \times 5 ; B \text { is } 5 \times 2.$$
4 step solution
Problem 43
A triangle with vertices at \(\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right),\) as shown in the figure, has area equal to the absolute value of \(D,\) where $$D=\frac{1}{2} \operatorname{det}\left[\begin{array}{lll}x_{1} & y_{1} & 1 \\\x_{2} & y_{2} & 1 \\ x_{3} & y_{3} & 1\end{array}\right]$$ Use \(D\) to find the area of each triangle with coordinates as given. $$P(1,2), Q(4,3), R(3,5)$$
5 step solution
Problem 44
Graph the solution set of each system of inequalities by hand. $$\begin{aligned} &x+2 y \leq 4\\\ &y \geq x^{2}-1 \end{aligned}$$
5 step solution
Problem 44
Solve each system by elimination. $$\begin{aligned}&\frac{x+6}{5}+\frac{2 y-x}{10}=1\\\&\frac{x+2}{4}+\frac{3 y+2}{5}=-3\end{aligned}$$
5 step solution