Chapter 5

A Graphical Approach to College Algebra · 468 exercises

Problem 31

Simplify each expression. (a) \(3^{\log _{3} 7}\) (b) \(4^{\log _{4} 9}\) (c) \(12^{\log _{13} 4}\) (d) \(a^{\log _{c} k}(k > 0, a > 0, a \neq 1)\)

6 step solution

Problem 32

If \(f(x)=x,\) then for any function \(g,(f \circ g)(x)=\) \((g \circ f)(x)=\)______.

3 step solution

Problem 32

Solve each exponential equation. Express the solution set so that (a) solutions are in exact form and, if irrational, (b) solutions are approximated to the nearest thousandth. Support your solutions by using a calculator. $$30-3(0.75)^{x-1}=29$$

6 step solution

Problem 32

Simplify each expression. (a) \(\log _{3} 3^{19}\) (b) \(\log _{4} 4^{17}\) (c) \(\log _{12} 12^{1 / 3}\) (d) \(\log _{a} \sqrt{a}(a>0, a \neq 1)\)

5 step solution

Problem 33

The interest rate stated by a financial institution is sometimes called the nominal rate. If interest is compounded, the actual rate is, in general, higher than the nominal rate, and is called the effective rate. If \(r\) is the nominal rate and \(n\) is the number of times interest is compounded annually, then $$R=\left(1+\frac{r}{n}\right)^{n}-1$$ is the effective rate. Here, \(R\) represents the annual rate that the investment would earn if simple interest were paid. Find the effective rate to the nearest hundredth of a percent if the nominal rate is \(3 \%\) and interest is compounded quarterly.

8 step solution

Problem 33

If a function \(f\) has an inverse, then the graph of \(f^{-1}\) may be obtained by reflecting the graph of \(f\) across the line with equation ____.

3 step solution

Problem 33

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$5 \ln x=10$$

5 step solution

Problem 33

Simplify each expression. (a) \(\log _{3} 1\) (b) \(\log _{4} 4^{17}\) (c) \(\log _{12} 1\) (d) \(\log _{a} 1(a>0, a \neq 1)\)

4 step solution

Problem 34

The interest rate stated by a financial institution is sometimes called the nominal rate. If interest is compounded, the actual rate is, in general, higher than the nominal rate, and is called the effective rate. If \(r\) is the nominal rate and \(n\) is the number of times interest is compounded annually, then $$R=\left(1+\frac{r}{n}\right)^{n}-1$$ is the effective rate. Here, \(R\) represents the annual rate that the investment would earn if simple interest were paid. Estimate the effective rate if the nominal rate is \(4.5 \%\) and interest is compounded daily \((n=365)\)

5 step solution

Problem 34

If a function \(f\) has an inverse and \(f(-3)=6,\) then \(f^{-1}(6)=\)____.

4 step solution

Problem 34

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$3 \log x=2$$

3 step solution

Problem 34

Simplify each expression. (a) Explain in your own words the meaning of \(\log _{a} x\) (b) In the expression \(\log _{a} x,\) why must \(x\) be nonnegative?

3 step solution

Problem 34

Sketch the graph of \(f(x)=2^{x}\). Then refer to it and use the techniques of Chapter 2 to graph each function. $$f(x)=2^{x}-4$$

4 step solution

Problem 35

In the formula \(A=P\left(1+\frac{r}{n}\right)^{n t},\) we can interpret \(P\) as the present value of A dollars t years from now, earning annual interest \(r\) compounded \(n\) times per year. In this context, \(A\) is called the future value. If we solve the formula for \(P,\) we obtain $$P=A\left(1+\frac{r}{n}\right)^{-n t}$$ Use the future value formula. Find the present value of an account that will be worth \(\$ 10,000\) in 5 years, if interest is compounded semiannually at \(3 \%\).

6 step solution

Problem 35

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\ln (4 x)=1.5$$

5 step solution

Problem 35

Evaluate each expression. Do not use a calculator. $$\log 10^{1.5}$$

3 step solution

Problem 36

In the formula \(A=P\left(1+\frac{r}{n}\right)^{n t},\) we can interpret \(P\) as the present value of A dollars t years from now, earning annual interest \(r\) compounded \(n\) times per year. In this context, \(A\) is called the future value. If we solve the formula for \(P,\) we obtain $$P=A\left(1+\frac{r}{n}\right)^{-n t}$$ Use the future value formula. Find the present value of an account that will be worth \(\$ 25,000\) in 2.75 years, if interest is compounded quarterly at \(6 \%\).

5 step solution

Problem 36

If \(f\) is a function that has an inverse and the graph of \(f\) lies completely within the second quadrant, then the graph of \(f^{-1}\) lies completely within the ____ quadrant.

3 step solution

Problem 36

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\ln (2 x)=5$$

5 step solution

Problem 36

Evaluate each expression. Do not use a calculator. $$\log 10^{4.3}$$

4 step solution

Problem 37

In the formula \(A=P\left(1+\frac{r}{n}\right)^{n t},\) we can interpret \(P\) as the present value of A dollars t years from now, earning annual interest \(r\) compounded \(n\) times per year. In this context, \(A\) is called the future value. If we solve the formula for \(P,\) we obtain $$P=A\left(1+\frac{r}{n}\right)^{-n t}$$ Use the future value formula. Estimate the interest rate necessary for a present value of \(\$ 25,000\) to grow to a future value of \(\$ 30,416\) if interest is compounded annually for 5 years.

6 step solution

Problem 37

Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=3 x-7, \quad g(x)=\frac{x+7}{3}$$

4 step solution

Problem 37

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log (2-x)=0.5$$

5 step solution

Problem 37

Evaluate each expression. Do not use a calculator. $$\log 10^{\sqrt{5}}$$

5 step solution

Problem 38

In the formula \(A=P\left(1+\frac{r}{n}\right)^{n t},\) we can interpret \(P\) as the present value of A dollars t years from now, earning annual interest \(r\) compounded \(n\) times per year. In this context, \(A\) is called the future value. If we solve the formula for \(P,\) we obtain $$P=A\left(1+\frac{r}{n}\right)^{-n t}$$ Use the future value formula. Estimate the interest rate necessary for a present value of \(\$ 1200\) to grow to a future value of \(\$ 1408\) if interest is compounded quarterly for 8 years.

7 step solution

Problem 38

Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=4 x+3, \quad g(x)=\frac{x-3}{4}$$

4 step solution

Problem 38

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\ln (1-x)=\frac{1}{2}$$

4 step solution

Problem 38

Evaluate each expression. Do not use a calculator. $$\log 10^{\sqrt{3}}$$

4 step solution

Problem 39

Graph each function. $$f(x)=\log _{5} x$$

5 step solution

Problem 39

Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=x^{3}+4, \quad g(x)=\sqrt[3]{x-4}$$

4 step solution

Problem 39

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log _{6}(2 x+4)=2$$

4 step solution

Problem 39

Evaluate each expression. Do not use a calculator. $$\ln e^{2 / 3}$$

2 step solution

Problem 39

Use the amortization formulas given in this section to find (a) the monthly payment on a loan with the given conditions and (b) the total interest that will be paid during the term of the loan. \(\$ 8500\) is amortized over 4 years with an interest rate of \(7.5 \%\).

6 step solution

Problem 40

Use the amortization formulas given in this section to find (a) the monthly payment on a loan with the given conditions and (b) the total interest that will be paid during the term of the loan. \(\$ 9600\) is amortized over 5 years with an interest rate of \(5.2 \%\)

7 step solution

Problem 40

Graph each function. $$f(x)=\log _{10} x$$

5 step solution

Problem 40

Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=x^{3}-7, \quad g(x)=\sqrt[3]{x+7}$$

4 step solution

Problem 40

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log _{5}(8-3 x)=3$$

5 step solution

Problem 40

Evaluate each expression. Do not use a calculator. $$\ln e^{0.5}$$

4 step solution

Problem 41

Graph each function. $$f(x)=\log _{1 / 2}(1-x)$$

5 step solution

Problem 41

Solve each equation. $$2^{3-x}=8$$

4 step solution

Problem 41

Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=-x^{5}, \quad g(x)=-\sqrt[5]{x}$$

4 step solution

Problem 41

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log _{4}\left(x^{3}+37\right)=3$$

4 step solution

Problem 41

Evaluate each expression. Do not use a calculator. $$\ln e^{\pi}$$

4 step solution

Problem 41

Use the amortization formulas given in this section to find (a) the monthly payment on a loan with the given conditions and (b) the total interest that will be paid during the term of the loan. \(\$ 125,000\) is amortized over 30 years with an interest rate of \(7.25 \%\)

7 step solution

Problem 42

Graph each function. $$f(x)=\log _{1 / 3}(3-x)$$

6 step solution

Problem 42

Solve each equation. $$5^{2 x+1}=25$$

4 step solution

Problem 42

Solve each logarithmic equation. Express all solutions in exact form. Support your solutions by using a calculator. $$\log _{7}\left(x^{3}+65\right)=0$$

5 step solution

Problem 42

Evaluate each expression. Do not use a calculator. $$\ln e^{\sqrt{6}}$$

2 step solution

Problem 43

Use the table feature of your graphing calculator to work parts (a) and (b). (a) Find how long it will take \(\$ 1500\) invested at \(5.75 \%\) compounded daily, to triple in value. Locate the solution by systematically decreasing \(\Delta\) Tbl. Find the answer to the nearest day. (Find your answer to the nearest day by eventually letting \(\Delta \mathrm{Tbl}=\frac{1}{365} .\) The decimal part of the solution can be multiplied by 365 to determine the number of days greater than the nearest year. For example, if the solution is determined to be 16.2027 years, then multiply 0.2027 by 365 to get \(73.9855 .\) The solution is then, to the nearest day, 16 years and 74 days.) Confirm your answer analytically. (b) Find how long it will take \(\$ 2000\) invested at \(8 \%,\) compounded daily, to be worth \(\$ 5000\).

7 step solution

Problem 43

Graph each function. $$f(x)=\log _{3}(x-1)$$

6 step solution

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