Chapter 21
A Complete Resource Book in Mathematics for JEE Main ยท 83 exercises
Problem 1
\(a\) and \(b\) are mutually perpendicular unit vectors. If \(r\) is a vector satisfying \(r \cdot a=0, r \cdot b=1\) and \([r a b]=1\), then \(r\) is (A) \(a \times b+b\) (B) \(a+(a \times b)\) (C) \(b+(a \times b)\) (D) \(a \times \vec{b}+a\)
5 step solution
Problem 2
\(a, b, c\) are three vectors of magnitude, \(\sqrt{3}, 1,2\) such that \(a \times(a \times c)+3 b=O .\) If \(\theta\) is the angle between \(a\) and \(c\), then \(\cos ^{2} \theta\) is equal to (A) \(\frac{1}{4}\) (B) \(\frac{3}{4}\) (C) \(\underline{1}=\) (D) none of these
6 step solution
Problem 5
Let \(A B C D E F\) be a regular hexagon. If \(A D=x B C\) and \(C F=y A B\), then \(x y=\) (A) 4 (B) \(-4\) (C) 2 (D) \(-2\)
6 step solution
Problem 6
Given a cube \(A B C D A_{1} B_{1} C_{1} D_{1}\) with lower base \(A B C D\), upper base \(A_{1} B_{1} C_{1} D_{1}\) and the lateral edges \(A A_{1}, B B_{1}\), \(C C_{1}\) and \(D D_{1} ; M\) and \(M_{1}\) are the centres of the faces \(A B C D\) and \(A_{1} B_{1} C_{1} D_{1}\) respectively. \(O\) is a point on line \(M M_{1}\), such that \(O A+O B+O C+O D=O M_{1}\), then \(O M=\lambda O M_{1}\) if \(\lambda=\) (A) \(\frac{1}{4}\) (B) \(\frac{1}{2}\) (C) \(\frac{1}{6}\) (D) \(\frac{1}{8}\)
7 step solution
Problem 7
The triangle \(A B C\) is defined by the vertices \(A(1,-2,2)\), \(B(1,4,0)\) and \(C(-4,1,1) .\) Let \(M\) be the foot of the altitude drawn from the vertex \(B\) to side \(A C\). Then, \(B M=\) (A) \((-20 / 7,-30 / 7,10 / 7)\) (B) \((-20,-30,10)\) (C) \((2,3,-1)\) (D) none of these
5 step solution
Problem 8
If \(A B=3 i+j-k\) and \(A C=i-j+3 k .\) If the point \(P\) on the line segment \(B C\) is equidistant from \(A B\) and \(A C\), then \(A P\) is (A) \(2 i-k\) (B) \(i-2 \mathrm{k}\) (C) \(2 i+k\) (D) none of these
7 step solution
Problem 9
\(A, B, C, D\) are four points on a plane with position vectors \(a, b, c, d\), respectively, such that \((a-d)\). \((b-c)=(b-d) \cdot(c-a)=0 .\) For \(\Delta A B C, D\) is the (A) incentre (B) orthocentre (C) centroid (D) none of these
6 step solution
Problem 10
If \(a\) and \(b\) are two unit vectors, then the vector \((a+b)\) \(\times(a \times b)\) is parallel to the vector (A) \(a-b\) (B) \(a+b\) (C) \(2 a-b\) (D) \(2 a+b\)
5 step solution
Problem 12
In a parallelogram \(A B C D,|A B|=a,|A D|=b\) and \(\mid A C\) \(\mid=c\). Then, \(D B \cdot A B\) has the value (A) \(\frac{3 a^{2}+b^{2}-c^{2}}{2}\) (B) \(\frac{a^{2}+3 b^{2}-c^{2}}{2}\) (C) \(\frac{a^{2}-b^{2}+3 c^{2}}{2}\) (D) \(\frac{a^{2}+3 b^{2}+c^{2}}{2}\)
4 step solution
Problem 14
If \(a, b, c\) are non-coplanar unit vectors such that \(a \times(b \times c)=\frac{b+c}{\sqrt{2}}\), then the angle between \(a\) and \(b\) is (A) \(\frac{3 \pi}{4}\) (B) \(\frac{\pi}{4}\) (C) \(\frac{\pi}{2}\) (D) \(\pi\)
5 step solution
Problem 15
If the vectors \(a\) and \(b\) are perpendicular to each other, then a vector \(v\) in terms of \(a\) and \(b\) satisfying the equations \(v \cdot a=0, v \cdot b=1\) and \([v a b]=1\) is (A) \(\frac{1}{|b|^{2}} b+\frac{1}{|a \times b|^{2}} a \times b\) (B) \(\frac{b}{|b|}+\frac{a \times b}{|a \times b|^{2}}\) (C) \(\frac{b}{|b|^{2}}+\frac{a \times b}{|a \times b|}\) (D) none of these
6 step solution
Problem 16
Let the unit vectors \(a\) and \(b\) be perpendicular to each other and the unit vector \(c\) be inclined at an angle \(\theta\) to both \(a\) and \(b\). If \(c=x a+y b+z(a \times b)\), then (A) \(x=\cos \theta, y=\sin \theta, z=\cos 2 \theta\) (B) \(x=\sin \theta, y=\cos \theta, z=-\cos 2 \theta\) (C) \(x=y=\cos \theta, z^{2}=\cos 2 \theta\) (D) \(x=y=\cos \theta, z^{2}=-\cos 2 \theta\)
5 step solution
Problem 20
If \(\sum_{i=1}^{n} a_{i}=0\) where \(\left|a_{i}\right|=1+i\), then the value of
is \(\sum_{1 \leq i
7 step solution
Problem 21
Forces \(P, Q\) act at \(O\) and have a resultant \(R\). If any transversal cuts their lines of action at \(A, B, C\), respectively, then (A) \(\frac{P}{O A}+\frac{Q}{O B}+\frac{R}{O C}=0\) (B) \(\frac{\mathrm{P}}{O A}+\frac{\mathrm{Q}}{O B}+\frac{\mathrm{R}}{O C}=1\) (C) \(\frac{\mathrm{P}}{O A}+\frac{\mathrm{Q}}{O B}-\frac{\mathrm{R}}{O C}=0\) (D) \(\frac{\mathrm{P}}{O A}+\frac{\mathrm{Q}}{O B}-\frac{\mathrm{R}}{O C}=1\).
4 step solution
Problem 22
A vector \(A\) has components \(A_{1}, A_{2}, A_{3}\) in a right-handed rectangular cartesian coordinate system \(O x, O y, O z\). The coordinate system is rotated about the z-axis through an angle \(\frac{\pi}{2} .\) The components of \(A\) in the new coordinate system are (A) \(A_{1},-A_{2}, A_{3}\) (B) \(A_{2}, A_{1}, A_{3}\) (C) \(A_{1}, A_{2},-A_{3}\) (D) \(A_{2},-A_{1}, A_{3}\).
4 step solution
Problem 23
In a \(\Delta O A B, \mathrm{E}\) is the mid-point of \(O B\) and \(D\) is a poir on \(A B\) such that \(A D: D B=2: 1 .\) If \(O D\) and \(A E\) intes sect at \(P\), then the ratio \(O P: P D\) is (A) \(1: 2\) (B) \(2: 1\) (C) \(3: 2\) (D) \(2: 3\).
6 step solution
Problem 24
If \(a, b, c\) are three non-parallel unit vectors such that \(a \times(b \times c)=\frac{1}{2} b\), then the angles which a makes with \(b\) and \(c\) are (A) \(90^{\circ}, 60^{\circ}\) (B) \(45^{\circ}, 60^{\circ}\) (C) \(30^{\circ}, 60^{\circ}\) (D) none of these
5 step solution
Problem 26
If the \(p\) th, \(q\) th and \(r\) th terms of a G. P. are positive numbers \(a, b\) and \(c\), respectively, then the angle between the vectors \(i l_{n} a+j l_{n} b+k l_{n} c\) and \(i(q-r)+j(r-p)+k\) \((p-q)\) is (A) \(\frac{\pi}{3}\) (B) \(\frac{\pi}{6}\) (C) \(\frac{\pi}{2}\) (D) none of these
6 step solution
Problem 27
A vector \(a\) is collinear with vector \(b=\left(6,-8,-7 \frac{1}{2}\right)\) and make an acute angle with the positive direction of \(z\)-axis. If \(|a|=50\), then \(a=\) (A) \((24,32,30)\) (B) \((24,-32,30)\) (C) \((-24,32,30)\) (D) none of these
5 step solution
Problem 28
The perpendicular distance of a corner of a unit cube form a diagonal not passing through it is (A) \(\sqrt{6}\) (B) \(\frac{\sqrt{6}}{3}\) (C) \(\frac{3}{\sqrt{6}}\) (D) none of these
6 step solution
Problem 29
The vectors \(a, b\) and \(c\) are equal in length and taken pairwise, they make equal angles. If \(a=i+j, b=j+\) \(k\), and \(c\) makes an obtuse angle with the base vector \(i\), then \(c\) is equal to (A) \(i+k\) (B) \(-i+4 j-k\) (C) \(\frac{-1}{3} i+\frac{4}{3} j-\frac{1}{3} k\) (D) \(\frac{1}{3} i+\frac{-4}{3} j+\frac{1}{3} k\).
3 step solution
Problem 30
If the four points \(a, b, c, d\) are coplanar, then \(\left[\begin{array}{ll}b c d\end{array}\right]+\left[\begin{array}{ll}c & a & d\end{array}\right]+\left[\begin{array}{ll}a & b & d\end{array}\right]=\) (A) 0 (B) 1 (C) \(-1\) (D) \(\left[\begin{array}{lll}a & b & c\end{array}\right]\)
5 step solution
Problem 31
A tetrahedron has vertices at \(O(0,0,0), A(1,2,1)\), \(B(2,1,3)\) and \(C(-1,1,2)\). Then, the angle between the faces \(O A B\) and \(A B C\) will be (A) \(\cos ^{-1}\left(\frac{19}{35}\right)\) (B) \(\cos ^{-1}\left(\frac{71}{31}\right)\) (C) \(30^{\circ}\) (D) \(90^{\circ}\)
9 step solution
Problem 32
If a quadrilateral \(A B C D\) is such that \(A B=b, A D=d\) and \(A C=m b+p d(m+p \geq 1)\), then the area of the quadrilateral is \(k(p+m)|b \times d|\), where \(k\) is equal to (A) \(\frac{1}{4}\) (B) \(\frac{1}{8}\) (C) \(\frac{1}{2}\) (D) none of these
6 step solution
Problem 33
Let \(a\) be a unit vector and \(b\) be a non-zero vector not parallel to \(a\). If two sides of the triangle are represented by the vectors \(\sqrt{3}(a \times b)\) and \(b-(a \cdot b) a\), then the angles of the triangle are (A) \(30^{\circ}, 90^{\circ}, 60^{\circ}\) (B) \(45^{\circ}, 45^{\circ}, 90^{\circ}\) (C) \(60^{\circ}, 60^{\circ}, 60^{\circ}\) (D) none of these
5 step solution
Problem 34
Let \(u\) and \(v\) be unit vectors. If \(w\) is a vector such that \(w\) \(+(w \times u)=v\), then \(|(u \times v) \cdot w|\) \((\mathrm{A}) \leq \frac{1}{3}\) \((\mathrm{B}) \leq \frac{1}{2}\) (C) \(>\frac{1}{3}\) \((\mathrm{D}) \geq \frac{1}{2}\)
7 step solution
Problem 35
If \(b\) and \(c\) are any two non-collinear unit vectors and \(a\) is any vector, then \((a \cdot b) b+(a \cdot c) c+\frac{a \cdot(b+c)}{|b+c|^{2}}(b \times c)=\) (A) \(a\) (B) \(b\) (C) \(c\) (D) none of these
5 step solution
Problem 36
If the vector \(-i+j-k\) bisects the angle between \(3 i+4 j\) and vector \(c\), then the unit vector along \(c\) is (A) \(\frac{-11 i-10 j-2 k}{15}\) (B) \(\frac{-11 i+10 j+2 k}{15}\) (C) \(\frac{-11 i+10 j-2 k}{15}\) (D) none of these
6 step solution
Problem 37
If \(a, b\) and \(c\) are three unit vectors such that \(a+b+c\) is also a unit vector and \(\theta_{1}, \theta_{2}\) and \(\theta_{3}\) are angles between the vectors \(a, b ; b, c\) and \(c, a\), respectively, then among \(\theta_{1}, \theta_{2}\) and \(\theta_{3}\) (A) all are acute angles (B) all are right angles (C) at least one is obtuse angle (D) none of these
4 step solution
Problem 38
If \(x\) and \(y\) are two non-collinear vectors and \(A B C\) is a triangle with side lengths \(a, b, c\) satisfying \((20 a-15 b) x+(15 b-12 c) y+(12 c-20 a)(x \times y)=\overrightarrow{0}\) then \(\triangle A B C\) is (A) an acute-angled triangle (B) an obtuse-angled triangle (C) a right-angled triangle (D) an isosceles triangle
6 step solution
Problem 41
Let \(a=i+j\) and \(b=2 i-k\). The point of intersection of the lines \(r \times a=b \times a\) and \(r \times b=a \times b\) is (A) \(-i+j+k\) (B) \(3 i-j+k\) (C) \(3 i+j-k\) (D) \(i-j-k\)
8 step solution
Problem 42
The sides of a parallelogram are \(2 i+4 j-5 k\) and \(i+2 j\) \(+3 k\). The unit vector parallel to one of the diagonals size is (A) \(\frac{1}{7}(3 i+6 j-2 k)\) (B) \(\frac{1}{7}(3 i-6 j-2 k)\) (C) \(\frac{1}{7}(-3 i+6 j-2 k)\) (D) \(\frac{1}{7}(3 i+6 j+2 k)\)
5 step solution
Problem 44
If \(a \times(b \times c)+(a \cdot b) b=(4-2 \beta-\sin \alpha) b+\left(\beta^{2}-1\right) c\) and \((c \cdot c) a=c\), while \(b\) and \(c\) are non-collinear, then (A) \(\alpha=\frac{\pi}{2}\) (B) \(\alpha=\frac{\pi}{3}\) (C) \(\beta=1\) (D) \(\beta=-1\)
9 step solution
Problem 46
Let \(b=4 i+3 j\) and \(c\) be two vectors perpendicular to each other in \(x y\)-plane, then the vector in the same plane having projections 1 and 2 along \(b\) and \(c\) respectively is (A) \(2 i-j\) (B) \(-2 i+j\) (C) \(2 i+j\) (D) none of these
8 step solution
Problem 47
A vector of magnitude 2 along a bisector of the angle between the two vectors \(2 i-2 j+k\) and \(i+2 j-2 k\) is (A) \(\frac{2}{\sqrt{10}}(3 i-k)\) (B) \(\frac{1}{\sqrt{26}}(i-4 j+3 k)\) (C) \(\frac{2}{\sqrt{26}}(i-4 j+3 k)\) (D) none of these
6 step solution
Problem 48
The value of \(\lambda\) such that \((x, y, z) \neq(0,0,0)\) and \((i+j+3 k) x+(3 i-3 j+k) y+(-4 i+5 j) z\) \(=\lambda(x i+y j+z k)\) is (A) 0 (B) 1 (C) \(-1\) (D) none of these
5 step solution
Problem 50
If the three vectors \(a=(12,4,3), b=(8,-12,-9)\) and \(c=(33,-4,-24)\) define a parallelopiped, then (A) the lengths of the edges are \(13,17,41\) (B) areas of the faces are \(220,435,455\) (C) volume of parallelopiped is 3696 (D) all of these
4 step solution
Problem 51
A vector of magnitude \(\sqrt{51}\) which makes equal angles with the vectors \(a=\frac{1}{3}(i-2 j+2 k)\), \(b=\frac{1}{5}(-4 i-3 k)\) and \(c=j\) is given by (A) \(5 i-j-5 k\) (B) \(-5 i+j+5 k\) (C) \(5 i+j+5 k\) (D) none of these
5 step solution
Problem 54
If \(D A=a, A B=b\) and \(C B=k a\), where \(k>0\) and \(X, Y\) are the mid-points of \(D B\) and \(A C\) respectively such that \(|a|=17\) and \(|X Y|=4\), then \(k\) is equal to (A) \(\frac{8}{17}\) (B) \(\frac{9}{17}\) (C) \(\frac{25}{17}\) (D) 1
6 step solution
Problem 55
Let \(a\) and \(b\) be two non-collinear unit vectors. If \(u=a-(a \cdot b) b\) and \(v=a \times b\), then \(|v|\) is (A) \(|u|\) (B) \(|u|+|u \cdot a|\) (C) \(|u|+|u \cdot b|\) (D) \(|u|+u \cdot(a+b)\)
4 step solution
Problem 56
A non-zero vector \(a\) is parallel to the line of intersection of the plane determined by the vectors \(i, i+j\) and the plane determined by the vectors \(i-j, i+k\). The angle between \(a\) and the vector \(i-2 j+2 k\) is (A) \(\frac{\pi}{3}\) (B) \(\frac{\pi}{4}\) (C) \(\frac{3 \pi}{4}\) (D) none of these
6 step solution
Problem 57
A unit vector coplanar with \(i+j+2 k\) and \(i+2 j+k\) and perpendicular to \(i+j+k\) is (A) \(\frac{j-k}{\sqrt{2}}\) (B) \(\frac{-j+k}{\sqrt{2}}\) (C) \(\frac{j+k}{\sqrt{2}}\) (D) \(\frac{-(j+k)}{\sqrt{2}}\)
5 step solution
Problem 58
The vectors \(a, b, c\) are of same length and taken pairwise, they form equal angles. If \(a=i+j\) and \(b=j+k\), then \(c=\) (A) \(i+k\) (B) \(j+k\) (C) \(i+k\) (D) \(-\frac{i}{3}+\frac{4}{3} j-\frac{k}{3}\)
9 step solution
Problem 60
\(a\) and \(c\) are unit vectors and \(|b|=4\) with \(a \times b=2 a \times c\). The angle between \(a\) and \(c\) is \(\cos ^{-1}\left(\frac{1}{4}\right)\). Then, \(b-2 c\) \(=\mathrm{la}\), if \(\lambda\) is (A) 3 (B) \(-3\) (C) 4 (D) \(-4\)
6 step solution
Problem 61
The vector c directed along the bisectors of the angle between the vectors \(a=7 i-4 j-4 k\) and \(\hat{b}=-2 i-j+2 k\) if \(|c|=3 \sqrt{6}\), is given by (A) \(i-7 j+2 k\) (B) \(2 i+7 j-3 k\) (C) \(-i+7 j-2 k\) (D) \(4 i+7 j-4 k\)
4 step solution
Problem 62
The vector differential operator DEL, written \(\nabla\), is defined by \(\nabla=\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k=i \frac{\partial}{\partial x}+j \frac{\partial}{\partial y}+k \frac{\partial}{\partial z}\), where \(\frac{\partial}{\partial x}\) rep- resents the derivative w.r.t. \(x\) regarding \(y\) and \(z\) as constant. Similarly, \(\frac{\partial}{\partial y}\) represents the derivative w.r.t. \(y\) regarding \(x\) and \(z\) as constant and \(\frac{\partial}{\partial z}\) represents the derivative w.r.t. \(z\) regarding \(x\) and \(y\) as constant. The operator \(\nabla\) is also known as nabla. Let \(\phi(x, y, z)\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the gradient of \(\phi\), written \(\nabla \phi\) or grad \(\phi\), is defined by $$ \nabla \phi=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \phi=\frac{\partial \phi}{\partial x} i+\frac{\partial \phi}{\partial y} j+\frac{\partial \phi}{\partial z} k $$ Let \(r\) be any vector such that \(r=x i+y j+z k\) If \(\phi=\ln |r|\) then \(\nabla \phi=\) (A) \(\frac{r}{r^{2}}\) (B) \(\frac{r}{r^{3}}\) (C) \(\frac{r}{r^{4}}\) (D) \(\frac{r}{r}\)
7 step solution
Problem 64
The vector differential operator DEL, written \(\nabla\), is defined by \(\nabla=\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k=i \frac{\partial}{\partial x}+j \frac{\partial}{\partial y}+k \frac{\partial}{\partial z}\), where \(\frac{\partial}{\partial x}\) rep- resents the derivative w.r.t. \(x\) regarding \(y\) and \(z\) as constant. Similarly, \(\frac{\partial}{\partial y}\) represents the derivative w.r.t. \(y\) regarding \(x\) and \(z\) as constant and \(\frac{\partial}{\partial z}\) represents the derivative w.r.t. \(z\) regarding \(x\) and \(y\) as constant. The operator \(\nabla\) is also known as nabla. Let \(\phi(x, y, z)\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the gradient of \(\phi\), written \(\nabla \phi\) or grad \(\phi\), is defined by $$ \nabla \phi=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \phi=\frac{\partial \phi}{\partial x} i+\frac{\partial \phi}{\partial y} j+\frac{\partial \phi}{\partial z} k $$ Let \(r\) be any vector such that \(r=x i+y j+z k\) \(\nabla r^{n}=\) (A) \(n r n-{ }^{1} r\) (B) \(n m-{ }^{2} r\) (C) \(\bar{n} \overline{r n} r\) (D) none of these
5 step solution
Problem 65
Let \(\nabla(x, y, z)=V_{1} i+V_{2} j+V_{3} k\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the divergence of \(V\), written \(\nabla \cdot V\) or div \(V\) is defined by $$ \begin{aligned} \nabla \cdot V &=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \cdot\left(V_{1} i+V_{2} j+V_{3} k\right) \\ &=\frac{\partial V_{1}}{\partial x}+\frac{\partial V_{2}}{\partial y}+\frac{\partial V_{3}}{\partial z} \end{aligned} $$ Here, \(\nabla=\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\) is the del operator. Note the analogy with \(A \cdot B=A_{1} B_{1}+A_{2} B_{2}+A_{3} B_{3} .\) Also, note that \(\vec{\nabla} \cdot V \neq V \cdot \nabla\). If \(\phi=2 x^{3} y^{2} z^{4}\), then \(\nabla . \nabla \phi=k\left(3 x y^{2} z^{4}+x^{3} z^{4}+6 x^{3} y^{2} z^{2}\right)\), where \(k=\) (A) 2 (B) 3 (C) 4 (D) 6
3 step solution
Problem 67
Let \(\nabla(x, y, z)=V_{1} i+V_{2} j+V_{3} k\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the divergence of \(V\), written \(\nabla \cdot V\) or div \(V\) is defined by $$ \begin{aligned} \nabla \cdot V &=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \cdot\left(V_{1} i+V_{2} j+V_{3} k\right) \\ &=\frac{\partial V_{1}}{\partial x}+\frac{\partial V_{2}}{\partial y}+\frac{\partial V_{3}}{\partial z} \end{aligned} $$ Here, \(\nabla=\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\) is the del operator. Note the analogy with \(A \cdot B=A_{1} B_{1}+A_{2} B_{2}+A_{3} B_{3} .\) Also, note that \(\vec{\nabla} \cdot V \neq V \cdot \nabla\). If \(r=x i+y j+z k\), then \(\nabla \cdot\left(\frac{r}{r^{3}}\right)=\) (A) 0 (B) 1 (C) \(-1\) (D) none of these
7 step solution
Problem 68
Let \(V(x, y, z)=V_{1} i+V_{2} j+V_{3} k\) be defined and differentiable at each point \((x, y, z)\) in a certain region of space. Then, the curl or roation of \(\vec{V}\), written \(\nabla \times \vec{V}\), curl \(\vec{V}\) or rot \(\vec{V}\), is defined by \(\begin{aligned} \nabla \times V &=\left(\frac{\partial}{\partial x} i+\frac{\partial}{\partial y} j+\frac{\partial}{\partial z} k\right) \times\left(V_{1} i+V_{2} j+V_{3} k\right) \\ &=\left|\begin{array}{lll}i & j & k \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ V_{1} & V_{2} & V_{3}\end{array}\right| \\\ &=\left(\frac{\partial V_{3}}{\partial y}-\frac{\partial V_{2}}{\partial z_{2}}\right) i+\left(\frac{\partial V_{2}}{\partial z}-\frac{\partial V_{3}}{\partial x}\right) j+\left(\frac{\partial V_{2}}{\partial x}-\frac{\partial V_{1}}{\partial y}\right) k \end{aligned}\) Note that in the expansion of the determinant the operators \(\frac{\partial}{\partial x}, \frac{\partial}{\partial y}, \frac{\partial}{\partial z}\) must precede \(V_{1}, V_{2}, V_{3}\). For a scalar function \(\phi\), possessing continuous secot order partial derivatives \(\nabla \times(\nabla \phi)=\) (A) \(\phi\) (B) 0 (C) \(\nabla \phi\) (D) none of these
3 step solution