Chapter 12

A Complete Resource Book in Mathematics for JEE Main · 111 exercises

Problem 116

In the following questions an Assertion \((A)\) is given followed by a Reason \((R) .\) Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason(R) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion: If \(f(x)=\operatorname{sgn}(x)\) and \(g(x)=x\left(1-x^{2}\right)\), then \(f o g(x)\) and \(g o f(x)\) are continuous everywhere Reason: \(f o g(x)=\left\\{\begin{aligned}-1, & x \in(-1,0) \cup(1, \infty) \\\ 0, & x \in\\{-1,0,1\\} \\ 1, & x \in(-\infty,-1) \cup(0,1) \end{aligned}\right.\) and, \(g o f(x)=0, \forall x \in R\)

6 step solution

Problem 117

In the following questions an Assertion \((A)\) is given followed by a Reason \((R) .\) Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason(R) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion: Let \(f\) be a function such that \(f(x y)=f(x)\). \(f(y), \forall y \in R\) and \(f(1+x)=1+x(1+g(x))\), where \(\lim _{x \rightarrow 0} g(x)=0\), then $$ \begin{aligned} &\int_{1}^{2} \frac{f(x)}{f^{\prime}(x)} \cdot \frac{1}{1+x^{2}} d x=\frac{1}{2} \log \left(\frac{5}{2}\right) \\ &\text { Reason: } f^{\prime}(x)=\frac{f(x)}{x} \end{aligned} $$

4 step solution

Problem 118

In the following questions an Assertion \((A)\) is given followed by a Reason \((R) .\) Mark your responses from the following options: (A) Assertion(A) is True and Reason(R) is True; Reason(R) is a correct explanation for Assertion(A) (B) Assertion(A) is True, Reason(R) is True; Reason(R) is not a correct explanation for Assertion(A) (C) Assertion(A) is True, Reason(R) is False (D) Assertion(A) is False, Reason(R) is True Assertion: The function \(y=f(x)\), defined parametrically as \(y=t^{2}+t|t|, x=2 t-|t|, t \in R\), is continuous \mathrm{\\{} f o r ~ a l l ~ r e a l ~ \(x\) Reason: \(f(x)=\left\\{\begin{array}{r}2 x^{2}, x \geq 0 \\ 0, x<0\end{array}\right.\)

5 step solution

Problem 119

Let \(f(x)=\frac{1-\tan x}{4 x-\pi}, x \neq \frac{\pi}{4}, x \in\left[0, \frac{\pi}{2}\right] .\) If \(f(x)\) is continuous in \(\left[0, \frac{\pi}{2}\right]\), then \(f\left[\frac{\pi}{4}\right]\) is \(\quad\) [2004] (A) 1 (B) \(\frac{1}{2}\) (C) \(-\frac{1}{2}\) (D) \(-1\)

8 step solution

Problem 120

Let \(f: R \rightarrow R\) be a function defined by \(f(x)=\min\) \(\\{x+1,|x|+1\\} .\) Then which of the following is true? [2007] (A) \(f(x) \geq 1\) for all \(x \in \mathrm{R}\) (B) \(f(x)\) is not differentiable at \(x=1\) (C) \(f(x)\) is differentiable everywhere (D) \(f(x)\) is not differentiable at \(x=0\)

8 step solution

Problem 123

Consider the following relations: \(R=\\{(x, y) \mid x, y\) are real numbers and \(x=w y\) for some rational number \(w\\} ;\) \(S=\left\\{\begin{array}{l}\left(\frac{m}{p}, \frac{p}{q}\right) m, n, p \text { and } q \in \mathbf{Z} \\ \text { such that } n, q \neq 0 \text { and } q m=p n\end{array}\right\\}\) Then [2010] (A) neither \(R\) nor \(S\) is an equivalence relation (B) \(S\) is an equivalence relation but \(R\) is not an equivalence relation (C) \(R\) and \(S\) both are equivalence relations (D) \(R\) is an equivalence relation but \(S\) is not an equivalence relation

10 step solution

Problem 124

The real values of \(p\) and \(q\) for which the function \(f(x)=\left\\{\begin{array}{l}\frac{\sin (p+1) x+\sin x}{x}, x<0 \\ q, x=0 \quad \frac{\sqrt{x+x^{2}}-\sqrt{x}}{x^{3 / 2}}, x>0\end{array} \quad\right.\) is continuous for all \(x\) in \(R\), is (A) \(p=\frac{5}{2}, q=\frac{1}{2}\) (B) \(p=-\frac{3}{2}, q=\frac{1}{2}\) (C) \(p=\frac{1}{2}, q=\frac{3}{2}\) (D) \(p=\frac{1}{2}, q=-\frac{3}{2}\)

7 step solution

Problem 125

If \(f: R \rightarrow R\) is a function defined by \(f(x)=[x] \cos \left(\frac{2 x-1}{2}\right) \pi\), where \([x]\) denotes the greatest integer function, then \(f\) is (A) continuous for every real \(x\) (B) discontinuous only at \(x=0\) (C) discontinuous only at non-zero integral values of \(x\) (D) continuous only at \(x=0\)

5 step solution

Problem 126

Consider the function \(f(x)=|x-2|+|x-5|, x \in R\). [2012] Statement 1: \(f^{\prime}(4)=0\) Statement 2: \(f\) is continuous in \([2,5]\), differentiable in \((2,5)\) and \(f(2)=f(5)\). (A) Statement 1 is false, statement 2 is true (B) Statement 1 is true, statement 2 is true; statement 2 is a correct explanation for statement 1 (C) Statement 1 is true, statement 2 is true; statement 2 is not a correct explanation for statement 1 (D) Statement 1 is true, statement 2 is false

7 step solution

Problem 127

If the function \(g(x)=\left\\{\begin{array}{ll}k \sqrt{x+1}, & 0 \leq x \leq 3 \\\ m x+2, & 3

6 step solution

Problem 128

For \(x \in R, f(x)=|\log 2-\sin x|\) and \(g(x)=f(f(x))\), then: [2016] (A) \(g\) is differentiable at \(x=0\) and \(g^{\prime}(0)=-\sin (\log 2)\) (B) \(g\) is not differentiable at \(x=0\) (C) \(g^{\prime}(0)=\cos (\log 2)\) (D) \(g^{\prime}(0)=-\cos (\log 2)\)

6 step solution

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