Chapter 20

A Complete Resource Book in Mathematics for JEE Main 2017 ยท 90 exercises

Problem 54

A ray of light is coming along the line \(y=b\) from the positive direction of \(x\)-axis and strikes a concave mirror whose intersection with the \(x y\)-plane is a parabola \(y^{2}=4 a x .\) If \(a\) and \(b\) are positive, then the equation of the reflected ray is (A) \(y-2 a t=\frac{2 t}{t^{2}+1}\left(x-a t^{2}\right)\) (B) \(y-2 a t=\frac{2 t}{t^{2}-1}\left(x-a t^{2}\right)\) (C) \(y-2 a t=\frac{-2 t}{t^{2}-1}\left(x-a t^{2}\right)\) (D) none of these

7 step solution

Problem 56

Three normals are drawn from the point \((14,7)\) to the parabola \(y^{2}-16 x-8 y=0\). The coordinates of the feet of the normals are (A) \((0,0),(8,-16),(3,-4)\) (B) \((0,0),(8,16),(3,-4)\) (C) \((0,0),(-8,16),(3,-4)\) (D) none of these

5 step solution

Problem 57

Consider a curve \(a x^{2}+2 h x y+b y^{2}=1\) and a point \(P\) not on the curve. A line drawn from the point \(P\) intersects the curve at points \(Q\) and \(R\). If the product \(P Q . P R\) is independent of the slope of the line, then the curve is a (A) parabola (B) circle (C) ellipse (D) none of these

7 step solution

Problem 58

A tangent to the ellipse \(x^{2}+4 y^{2}=4\) meets the ellipse \(x^{2}\) \(+2 y^{2}=6\) at \(P\) and \(Q .\) The angle between the tangents at \(P\) and \(Q\) of the ellipse \(x^{2}+2 y^{2}=6\) is (A) \(\frac{\pi}{2}\) (B) \(\frac{\pi}{3}\) (C) \(\frac{\pi}{4}\) (D) \(\frac{\pi}{6}\)

5 step solution

Problem 59

The maximum area of an isosceles triangle inscribed in the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) with its vertex at one end of the major axis is (A) \(\sqrt{3} a b\) (B) \(\frac{3 \sqrt{3}}{4} a b\)(C) \(\frac{5 \sqrt{3}}{4} a b\) (D) none of these

9 step solution

Problem 60

The tangent at the point ' \(\alpha\) ' on the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) meets the auxiliary circle in two points which subtend a right angle at the centre. The eccentricity of the ellipse is (A) \(\frac{1}{\sqrt{1+\sin ^{2} \alpha}}\) (B) \(\frac{1}{\sqrt{1+\cos ^{2} \alpha}}\) (C) \(\sqrt{1+\sin ^{2} \alpha}\) (D) none of these

7 step solution

Problem 61

If a chord joining two points whose eccentric angles are \(\alpha, \beta\) cut the major axis of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\), at a distance \(d\) from the centre, then \(\tan \frac{\alpha}{2} \cdot \tan \frac{\beta}{2}=\) (A) \(\frac{d+a}{d-a}\) (B) \(\frac{d-a}{d+a}\) (C) \(\frac{a-d}{a+d}\) (D) none of these

5 step solution

Problem 63

\(\mathrm{PN}\) is the ordinate of any point \(P\) on the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) and \(A A^{\prime}\) is its transverse axis. If \(Q\) divides \(A P\) in the ratio \(a^{2}: b^{2}\), then \(N Q\) is (A) \(\perp\) to \(A^{\prime} P\) (B) parallel to \(A^{\prime} P\) (C) \(\perp\) to \(O P\) (D) none of these

6 step solution

Problem 65

A variable straight line of slope 4 intersects the hyperbola \(x y=1\) at two points. The locus of the point which divides the line segment between these two points in the ratio \(1: 2\) is (A) \(16 x^{2}+10 x y+y^{2}=2\) (B) \(16 x^{2}-10 x y+y^{2}=2\) (C) \(16 x^{2}+10 x y+y^{2}=4\) (D) none of these

7 step solution

Problem 66

If the parabola \(x^{2}=a y\) makes an intercept of length \(\sqrt{40}\) on the line \(y-2 x=1\), then \(a\) is equal to (A) 1 (B) \(-2\) (C) \(-1\) (D) 2

9 step solution

Problem 67

The asymptotes of the hyperbola \(x y-3 x+4 y+2=0\) are (A) \(x=-4\) (B) \(x=4\) (C) \(y=-3\) (D) \(y=3\)

8 step solution

Problem 70

\(P\) is a point which moves in the \(x y\) plane such that the point \(P\) is nearer to the centre of a square than any of the sides. The four vertices of the square are \((\pm a, \pm a)\). The region in which \(P\) will move is bounded by parts of parabola of which one has the equation (A) \(y^{2}=a^{2}-2 a x\) (B) \(y^{2}=a^{2}+2 a x\) (C) \(x^{2}=a^{2}-2 a y\) (D) \(x^{2}=a^{2}+2 a y\)

5 step solution

Problem 71

subtend a constant angle \(\alpha\) at the vertex is \(\left(y^{2}-2 a x+\right.\) \(\left.8 a^{2}\right)^{2} \tan ^{2} \alpha=k a^{2}\left(4 a x-y^{2}\right)\), where \(k=\) (A) 4 (B) 8 (C) 16 (D) none of these

7 step solution

Problem 77

Assertion: The combined equation of the asymptotes of the hyperbola \(2 x^{2}+5 x y+2 y^{2}+4 x+5 y+2=0\) Reason: The equation of a hyperbola and 1 ts asymptotes differ in constant terms only.

4 step solution

Problem 78

Assertion: The locus of the centre of the circle described on any focal chord of a parabola \(y^{2}=4 a x\) as diameter is \(y^{2}\) \(=2 a(x-a)\) Reason: If \(A\left(a t^{2}, 2 a t_{1}\right)\) and \(B\left(a t^{2}, 2 a t_{2}\right)\) be the extremities of a focal chord for the parabola \(y^{2}=4 a x\), then \(t_{1} t_{2}=-1\)

5 step solution

Problem 80

The radius of the circle passing through the foci of the ellipse \(\frac{x^{2}}{16}+\frac{y^{2}}{9}=1\) and having its centre at \((0,3)\), is: (A) 4 unit (B) 3 unit (C) \(\sqrt{12}\) unit (D) \(\frac{7}{2}\) unit

4 step solution

Problem 81

The equation of the ellipse whose foci are \((\pm 2,0)\) and eccentricity is \(\frac{1}{2}\) is: (A) \(\frac{x^{2}}{12}+\frac{y^{2}}{16}=1\) (B) \(\frac{x^{2}}{16}+\frac{y^{2}}{12}=1\) (C) \(\frac{x^{2}}{16}+\frac{y^{2}}{8}=1\) (D) none of these

5 step solution

Problem 82

The equation of the chord joining two points \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right)\) on the rectangular hyperbola \(x y=c^{2}\) is : (A) \(\frac{x}{x_{1}+x_{2}}+\frac{y}{y_{1}+y_{2}}=1\) (B) \(\frac{x}{x_{1}-x_{2}}+\frac{y}{y_{1}-y_{2}}=1\) (C) \(\frac{x}{y_{1}+y_{2}}+\frac{y}{x_{1}+x_{2}}=1\) (D) \(\frac{x}{y_{1}-y_{2}}+\frac{y}{x_{1}-x_{2}}=1\)

4 step solution

Problem 83

If \(x_{1}, x_{2}, x_{3}\) and \(y_{1}, y_{2}, y_{3}\) are both in G.P. with the same common ratio, then the points \(\left(x_{1}, y_{1}\right)\left(x_{2}, y_{2}\right)\) and \(\left(x_{3}, y_{3}\right)\) (A) lie on a straight line (B) lie on an ellipse (C) lie on a circle (D) are vertices of a triangle

4 step solution

Problem 85

A point on the parabola \(y^{2}=18 x\) at which the ordinate increases at twice the rate of the abscissa is (A) \((2,4)\) (B) \((2,-4)\) (C) \(\left(\frac{-9}{8}, \frac{9}{2}\right)\) (D) \(\left(\frac{9}{8}, \frac{9}{2}\right)\)

9 step solution

Problem 87

The eccentricity of an ellipse, with its centre at the origin, is \(\frac{1}{2} .\) If one of the directrices is \(x=4\), then the 2 equation of the ellipse is (A) \(3 x^{2}+4 y^{2}=1\) (B) \(3 x^{2}+4 y^{2}=12\) (C) \(4 x^{2}+3 y^{2}=12\) (D) \(4 x^{2}+3 y^{2}=1\)

7 step solution

Problem 88

Area of the greatest rectangle that can be inscribed in the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) is (A) \(2 a b\) (B) \(a b\) (C) \(\sqrt{a b}\) (D) \(\frac{a}{b}\)

8 step solution

Problem 89

The locus of a point \(P(\alpha, \beta)\) moving under the condition that the line \(y=\alpha x+\beta\) is a tangent to the hyperbola \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) is (A) an ellipse (B) a circle (C) a parabola (D) a hyperbola

4 step solution

Problem 90

An ellipse has \(O B\) as semi minor axis, \(F\) and \(F^{\prime}\) its focii and the angle \(F B F^{\prime}\) is a right angle. Then the eccentricity of the ellipse is (A) \(\frac{1}{\sqrt{2}}\) (B) \(\frac{1}{2}\) (C) \(\frac{1}{4}\) (D) \(\frac{1}{\sqrt{3}}\)

5 step solution

Problem 91

In an ellipse, the distance between its foci is 6 and minor axis is 8 . Then its eccentricity is (A) \(\frac{3}{5}\) (B) \(\frac{1}{2}\) (C) \(\frac{4}{5}\) (D) \(\frac{1}{\sqrt{5}}\)

8 step solution

Problem 92

For the hyperbola \(\frac{x^{2}}{\cos ^{2} \alpha}-\frac{y^{2}}{\sin ^{2} \alpha}=1\), which of thefollowing remains constant when \(\alpha\). varies? (A) eccentricity (B) directrix (C) abscissae of vertices (D) abscissae of foci

5 step solution

Problem 93

A focus of an ellipse is at the origin. The directrix is the line \(x=4\) and the eccentricity is \(\frac{1}{2} .\) Then the length of the semi-major axis is (A) \(\frac{8}{3}\) (B) \(\frac{2}{3}\) (C) \(\frac{4}{3}\) (D) \(\frac{5}{3}\)

4 step solution

Problem 94

A parabola has the origin as its focus and the line \(x=\) 2 as the directrix. Then the vertex of the parabola is at (A) \((0,2)\) (B) \((1,0)\) (C) \((0,1)\) (D) \((2,0)\)

4 step solution

Problem 95

The ellipse \(x^{2}+4 y^{2}=4\) is inscribed in a rectangle aligned with the coordinate axes, which in turn in inscribed in another ellipse that passes through the point \((4,0)\). Then the equation of the ellipse is (A) \(x^{2}+16 y^{2}=16\) (B) \(x^{2}+12 y^{2}=16\) (C) \(4 x^{2}+48 y^{2}=48\) (D) \(4 x^{2}+64 y^{2}=48\)

5 step solution

Problem 96

If two tangents drawn from a point \(P\) to the parabola \(y^{2}\) \(=4 x\) are at right angles, then the locus of the point \(P\) is (A) \(2 x+1=0\) (B) \(x=-1\) (C) \(2 x-1=0\) (D) \(x=1\)

7 step solution

Problem 98

An ellipse is drawn by considering a diameter of the circle \((x-1)^{2}+y^{2}=1\) as its semi-minor axis and a diameter of the circle \(x^{2}+(y-2)^{2}=4\) as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is (A) \(4 x^{2}+y^{2}=4\) (B) \(x^{2}+4 y^{2}=8\) (C) \(4 x^{2}+y^{2}=8\) (D) \(x^{2}+4 y^{2}=16\)

4 step solution

Problem 99

Given: A circle, \(2 x^{2}+2 y^{2}=5\) and a parabola, \(y^{2}=4 \sqrt{5 x}\) Statement-I: An equation of a common tangent to these curves is \(y=x+\sqrt{5}\). Statement - II: If the line, \(y=m x+\frac{\sqrt{5}}{m}(m \neq 0)\) is their common tangent, then \(m\) satisfies \(m^{4}-3 m^{2}+2=0\) (A) Statement - I is True; Statement -II is true; Statement-II is not a correct explanation for Statement-I (B) Statement -I is True; Statement -II is False. (C) Statement -I is False; Statement -II is True (D) Statement -I is True; Statement -II is True; Statement-II is a correct explanation for Statement-I

6 step solution

Problem 100

The circle passing through the foci of the ellipse \(\frac{x^{2}}{16}+\frac{y^{2}}{4}=1\) with center at \((0,3)\) has equation (A) \(x^{2}+y^{2}-6 y+7=0\) (B) \(x^{2}+y^{2}-6 y-5=0\) (C) \(x^{2}+y^{2}-6 y+5=0\) (D) \(x^{2}+y^{2}-6 y-7=0\)

5 step solution

Problem 101

The locus of the foot of the perpendicular drawn from the centre of the ellipse \(x^{2}+3 y^{2}=6\) on any tangent to it is (A) \(\left(x^{2}-y^{2}\right)^{2}=6 x^{2}+2 y^{2}\) (B) \(\left(x^{2}-y^{2}\right)^{2}=6 x^{2}-2 y^{2}\) (C) \(\left(x^{2}+y^{2}\right)^{2}=6 x^{2}+2 y^{2}\) (D) \(\left(x^{2}+y^{2}\right)^{2}=6 x^{2}-2 y^{2}\)

4 step solution

Problem 102

The slope of the line touching both the parabolas \(y^{2}=\) \(4 x\) and \(x^{2}=-32 y\) is (A) \(\frac{1}{2}\) (B) \(\frac{3}{2}\) (D) \(\frac{2}{3}\) (C) \(\frac{1}{8}\)

5 step solution

Problem 103

The slope of the line touching both the parabolas \(y^{2}=\) \(4 x\) and \(x^{2}=-32 y\) is (A) \(\frac{1}{2}\) (B) \(\frac{3}{2}\) (D) \(\frac{2}{3}\) (C) \(\frac{1}{8}\)

6 step solution

Problem 104

The area (in sq. units) of the quadrilateral formed by the tangents at the end points of the latus rectum to the ellipse \(\frac{x^{2}}{9}+\frac{y^{2}}{5}=1\), is: (A) 18 (B) \(\frac{27}{2}\) (C) 27 (D) \(\frac{27}{4}\)

6 step solution

Problem 105

The eccentricity of the hyperbola whose length of the latus rectum is equal to 8 and the length of its conjugate axis is equal to half of the distance between its foci, is (A) \(\sqrt{3}\) (B) \(\frac{4}{3}\) (C) \(\frac{4}{\sqrt{3}}\) (D) \(\frac{2}{\sqrt{3}}\)

8 step solution

Problem 106

Let \(P\) be the point on the parabola, \(y^{2}=8 x\) which is at a minimum distance from the cente \(C\) of the circle, \(x^{2}\) \(+(y+6)^{2}=1 .\) Then the equation of the circle, passing through \(C\) and having its centre at \(P\) is (A) \(x^{2}+y^{2}-4 x+9 y+18=0\) (B) \(x^{2}+y^{2}-4 x+8 y+12=0\) (C) \(x^{2}+y^{2}-x+4 y+12=0\) (D) \(x^{2}+y^{2}-\frac{x}{4}+2 y-24=0\)

8 step solution

Problem 107

The centres of those circles which touch the circle, \(x^{2}\) \(+y^{2}-8 x-8 y-4=0\), externally and also touch the \(x\)-axis, lie on (A) A parabola (B) A circle (C) An ellipse which is not a circle (D) A hyperbola

5 step solution

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