Chapter 29

Basic Engineering Mathematics · 24 exercises

Problem 1

Determine the next two terms in the series: \(3,6,9,12, \ldots\)

4 step solution

Problem 3

Determine the next two terms in the series: \(2,6,18,54, \ldots\)

3 step solution

Problem 4

The \(n^{\prime}\) th term of a sequence is given by \(3 n+1\). Write down the first four terms.

5 step solution

Problem 5

The \(n^{\prime}\) th term of a series is given by \(4 n-1\). Write down the first four terms.

5 step solution

Problem 6

Find the \(n^{\prime}\) th term of the series: \(1,4,7, \ldots\)

4 step solution

Problem 7

Find the \(n\) 'th term of the sequence: \(3,9,15\), \(21, \ldots\). Hence determine the 15 th term of the series.

6 step solution

Problem 8

Find the \(n^{\prime}\) th term of the series: \(1,4,9\), \(16,25, \ldots\)

3 step solution

Problem 9

Determine (a) the ninth, and (b) the sixteenth term of the series \(2,7,12,17, \ldots .\)

5 step solution

Problem 10

The 6th term of an \(A P\) is 17 and the 13 th term is 38 . Determine the 19 th term.

5 step solution

Problem 11

Determine the number of the term whose value is 22 in the series \(2 \frac{1}{2}, 4,5 \frac{1}{2}, 7, \ldots\).

5 step solution

Problem 12

Find the sum of the first 12 terms of the series \(5,9,13,17, \ldots\)

6 step solution

Problem 13

Find the sum of the first 21 terms of the series \(3.5,4.1,4.7,5.3, \ldots\)

5 step solution

Problem 14

The sum of 7 terms of an \(A P\) is 35 and the common difference is \(1.2\). Determine the first term of the series.

4 step solution

Problem 15

Three numbers are in arithmetic progression. Their sum is 15 and their product is 80 . Determine the three numbers.

6 step solution

Problem 16

Find the sum of all the numbers between 0 and 207 which are exactly divisible by 3 .

4 step solution

Problem 17

The first, twelfth and last term of an arithmetic progression are \(4,31 \frac{1}{2}\), and \(376 \frac{1}{2}\) respectively. Determine (a) the number of terms in the series, (b) the sum of all the terms and (c) the 80 'th term.

5 step solution

Problem 18

Determine the tenth term of the series 3,6, \(12,24, \ldots\)

4 step solution

Problem 19

Find the sum of the first 7 terms of the series, \(\frac{1}{2}, 1 \frac{1}{2}, 4 \frac{1}{2}, 13 \frac{1}{2}, \ldots\)

4 step solution

Problem 21

Which term of the series \(2187,729,243, \ldots\) is \(\frac{1}{4} ?\)

4 step solution

Problem 22

Find the sum of the first 9 terms of the series \(72.0,57.6,46.08, \ldots\)

5 step solution

Problem 24

In a geometric progression the sixth term is 8 times the third term and the sum of the seventh and eighth terms is 192 . Determine (a) the common ratio, (b) the first term, and (c) the sum of the fifth to eleventh terms, inclusive.

6 step solution

Problem 25

A hire tool firm finds that their net return from hiring tools is decreasing by \(10 \%\) per annum. If their net gain on a certain tool this year is \(£ 400\), find the possible total of all future profits from this tool (assuming the tool. lasts for ever).

5 step solution

Problem 26

Problem 26. If \(£ 100\) is invested at compound interest of \(8 \%\) per annum, determine (a) the value after 10 years,(b) the time, correct to the nearest year, it takes to reach more than \(£ 300\).

4 step solution

Problem 27

A drilling machine is to have 6 speeds ranging from \(50 \mathrm{rev} / \mathrm{min}\) to \(750 \mathrm{rev} / \mathrm{min}\). If the speeds form a geometric progression determine their values, each correct to the nearest whole number.

7 step solution

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Chapter 29 - Basic Engineering Mathematics Solutions | StudyQuestionHub