Problem 8
Question
Find the \(n^{\prime}\) th term of the series: \(1,4,9\), \(16,25, \ldots\)
Step-by-Step Solution
Verified Answer
The nth term of the series is \(n^2\).
1Step 1: Identify the pattern
The given series is: 1, 4, 9, 16, 25, .... Let's determine the pattern by looking at the terms. Notice that each term is a perfect square: \(1 = 1^2\), \(4 = 2^2\), \(9 = 3^2\), \(16 = 4^2\), \(25 = 5^2\). This indicates a pattern where each term is the square of a natural number.
2Step 2: Express the general term using the identified pattern
Since the terms are perfect squares of consecutive natural numbers, the \(n^{th}\) term of the series can be represented as \(a_n = n^2\), where \(n\) is 1, 2, 3, and so on.
3Step 3: Write the formula for the nth term
Based on the identified pattern and the way we have expressed the general term, the formula for the \(n^{th}\) term in the series is given by \(a_n = n^2\).
Key Concepts
Perfect Squaresnth Term FormulaNatural Numbers
Perfect Squares
In mathematics, a perfect square is a number that can be expressed as the square of an integer. For example:
They have a special significance in mathematics, particularly in number theory and algebra. Recognizing perfect squares helps us find patterns in sequences and solve equations more efficiently.
- The number 1 is a perfect square because it can be written as \(1^2\)
- The number 4 is a perfect square because it is \(2^2\)
- The number 9 is \(3^2\)
- Continuing on, 16 is \(4^2\) and 25 is \(5^2\).
They have a special significance in mathematics, particularly in number theory and algebra. Recognizing perfect squares helps us find patterns in sequences and solve equations more efficiently.
nth Term Formula
The nth term formula of a sequence provides a way to find any term in the sequence without listing all previous terms. It is particularly useful for long sequences.
For the exercise series: 1, 4, 9, 16, 25, ..., each term is a square of its position in the sequence.
To represent this pattern algebraically, we use the nth term formula \( a_n = n^2 \).
This formula tells us that:
For the exercise series: 1, 4, 9, 16, 25, ..., each term is a square of its position in the sequence.
To represent this pattern algebraically, we use the nth term formula \( a_n = n^2 \).
This formula tells us that:
- To find the first term (\( n = 1 \)), calculate \( a_1 = 1^2 = 1 \)
- For the second term (\( n = 2 \)), it's \( a_2 = 2^2 = 4 \)
- The third term (\( n = 3 \)) is \( a_3 = 3^2 = 9 \)
- This pattern continues indefinitely, following the rule \( a_n = n^2 \)
Natural Numbers
Natural numbers are the set of positive integers beginning from 1, extending indefinitely upwards. They include:
In our sequence, each perfect square corresponds to a natural number squared:
- 1, 2, 3, 4, 5, ...
In our sequence, each perfect square corresponds to a natural number squared:
- 1 is the first natural number and its square is 1 (\(1^2 = 1\))
- 2 is the second natural number and its square is 4 (\(2^2 = 4\))
- 3 is the third natural number and its square is 9 (\(3^2 = 9\))
- And so on.
Other exercises in this chapter
Problem 6
Find the \(n^{\prime}\) th term of the series: \(1,4,7, \ldots\)
View solution Problem 7
Find the \(n\) 'th term of the sequence: \(3,9,15\), \(21, \ldots\). Hence determine the 15 th term of the series.
View solution Problem 9
Determine (a) the ninth, and (b) the sixteenth term of the series \(2,7,12,17, \ldots .\)
View solution Problem 10
The 6th term of an \(A P\) is 17 and the 13 th term is 38 . Determine the 19 th term.
View solution