Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Organic Chemistry (Mcmurry) ยท 71 exercises
Q 13-26P
Question: Sketch what you might expect the 1H and 13C NMR spectra of the following compound to look like (green =Cl):
3 step solution
51P
Assign as many resonances as you can to specific carbon atoms in the 13C
NMR spectrum of ethyl benzoate.
2 step solution
52P
Assume that you have a compound with the formula C3H6O .
(a) How many double bonds and/or rings does your compound
contain?
(b) Propose as many structures as you can that fit the molecular
formula.
(c) If your compound shows an infrared absorption peak at 1715cm-1,
what functional group does it have?
(d) If your compound shows a single 1H NMR absorption peak at 2.1,
what is its structure?
2 step solution
54P
The compound whose 1H NMR spectrum is shown has the molecular
formula C4H7O2CI and has an infrared absorption peak at 1740cm-1.
Propose a structure.
2 step solution
Q 55P
Propose structures for compounds that fit the following 1H NMR data:
a.
2.18(3H, singlet)
4.16(2H, doublet j=7Hz)
5.71(1H, triplet j=7Hz)
b.
1.30(9H, singlet)
7.30(5H, singlet)
c.
2.11(3H, singlet)
3.52(2H, triplet j=6Hz)
5.71(2H, triplet j=6Hz)
d.
2.15(2H, quintent j=7Hz)
2.75(2H, triplet j=7Hz)
3.38(2H, triplet j=7Hz)
7.22(5H, singlet)
5 step solution
Q 56P
Long-range coupling between protons more than two carbon atoms apart is sometimes observed when p bonds intervene. An example is found in 1-methoxy-1-buten-3-yne. Not only does the acetylenic proton, , couple with the vinylic proton , it also couples with the vinylic proton , four carbon atoms away. The data are:
Construct tree diagrams that account for the observed splitting patterns of , , and .
4 step solution
Q 57P
Question: The NMR spectra of compound A, , are shown. Propose a structure for A, and assign peaks in the spectra to your structure.
5 step solution
Q 58P
Question: Propose structures for the three compounds whose NMR spectra are shown.
6 step solution
Q 59P
Question: The mass spectrum and NMR spectrum of a hydrocarbon are shown. Propose a structure for this hydrocarbon, and explain the spectral data.
4 step solution
Q 60P
Compound A, a hydrocarbon with = 96 in its mass spectrum, has the spectral data given below. On reaction with , followed by treatment with basic , A is converted into B, whose spectral data are also given below. Propose structures for A and B.
Compound A Broadband-decoupled NMR: 26.8, 28.7, 35.7, 106.9, 149.7 d DEPT-90: no peaks DEPT-135: no positive peaks; negative peaks at 26.8, 28.7, 35.7, 106.9 d
Compound B Broadband-decoupled NMR: 26.1, 26.9, 29.9, 40.5, 68.2 d DEPT-90: 40.5 d DEPT-135: positive peak at 40.5 d; negative peaks at 26.1, 26.9, 29.9, 68.2 d
3 step solution
Q 61P
Propose a structure for compound C, which has = 86 in its mass spectrum, an IR absorption at 3400 , and the following NMR spectral data:
Compound C Broadband-decoupled NMR: 30.2, 31.9, 61.8, 114.7, 138.4 d DEPT-90: 138.4 d DEPT-135: positive peak at 138.4 d; negative peaks at 30.2, 31.9, 61.8, 114.7 d
3 step solution
Q 62P
Compound D is isomeric with compound C (Problem 13-61) and has the following NMR spectral data. Propose a structure.
Compound D Broadband-decoupled NMR: 9.7, 29.9, 74.4, 114.4, 141.4 d DEPT-90: 74.4, 141.4 d DEPT-135: positive peaks at 9.7, 74.4, 141.4 d; negative peaks at 29.9, 114.4 d
3 step solution
Q63E
Propose a structure for compound E, , which has the following NMR spectral data:
Compound E Broadband-decoupled NMR: 19.1, 28.0, 70.5, 129.0, 129.8, 165.8 DEPT-90: 28.0, 129.8 DEPT-135: positive peaks at 19.1, 28.0, 129.8 ; negative peaks at 70.5, 129.0
3 step solution
Q64E
Compound F, a hydrocarbon with = 96 in its mass spectrum, undergoes reaction with HBr to yield compound G. Propose structures for F and G, whose NMR spectral data are given below.
a. Compound F Broadband-decoupled NMR: 27.6, 29.3, 32.2, 132.4 d DEPT-90: 132.4 d DEPT-135: positive peak at 132.4 d; negative peaks at 27.6, 29.3, 32.2 d
b. Compound G Broadband-decoupled NMR: 25.1, 27.7, 39.9, 56.0 d DEPT-90: 56.0 d DEPT-135: positive peak at 56.0 d; negative peaks at 25.1, 27.7, 39.9 d
5 step solution
Q65E
3-Methyl-2-butanol has five signals in its NMR spectrum at 17.90, 18.15, 20.00, 35.05, and 72.75 d. Why are the two methyl groups attached to C3 non- equivalent? Making a molecular model should be helpful.
4 step solution
Q66E
A NMR spectrum of commercially available 2,4-pentanediol, shows five peaks at 23.3, 23.9, 46.5, 64.8, and 68.1 d. Explain.
3 step solution
Q67E
Carboxylic acids react with alcohols (R'OH) in the presence of an acid catalyst. The reaction product of propanoic acid with methanol has the following spectroscopic properties. Propose a structure.
MS: = 88
IR: 1735
NMR: 1.11 (3 H, triplet, J 5 7 Hz); 2.32 (2 H, quartet, J 5 7 Hz); 3.65 (3 H, singlet) NMR: 9.3, 27.6, 51.4, 174.6
4 step solution
Q68E
Nitriles (RC≡N) react with Grignard reagents (R'MgBr). The reaction product from 2-methylpropanenitrile with methyl magnesium bromide has the following spectroscopic properties. Propose a structure.
MS: =86
IR: 1715
NMR: 1.05 (6 H, doublet, J 5 7 Hz); 2.12 (3 H, singlet); 2.67 (1 H, septet, J 5 7 Hz) NMR: 18.2, 27.2, 41.6, 211.2
4 step solution
Q69E
The proton NMR spectrum is shown for a compound with the formula . The infrared spectrum displays strong bands at 1750 and 1562 and a medium-intensity band at 1320 . The normal carbon-13 and the DEPT experimental results are tabulated. Draw the structure of this compound.
5 step solution
Q70E
The proton NMR spectrum of a compound with the formula C5H10O isshown. The normal carbon-13 and the DEPT experimental results aretabulated. The infrared spectrum shows a broad peak at about3340 cm-1 and a medium-sized peak at about 1651 cm-1. Draw the structure of thiscompound.
5 step solution
Q71E
The proton NMR spectrum of a compound with the formula C7H12O2 is
shown. The infrared spectrum displays a strong band at 1738 cm-1 and
a weak band at 1689 cm-1 . The normal carbon-13 and the DEPT experimental
results are tabulated. Draw the structure of this compound.
5 step solution