Alkyl Halides and Elimination Reactions

Organic Chemistry ยท 68 exercises

Q.51

Draw the structure of a dihalide that could be used to prepare each alkyne. There may be more than one possible dihalide.



a.




b.



c.

2 step solution

Q.52

Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new  bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What are the structures of A, B, and C?

3 step solution

Q.53

For which reaction mechanisms—SN1, SN2, E1, or E2—are each of the following statements true? A statement may be true for one or more mechanisms.

a. The mechanism involves carbocation intermediates.

b. The mechanism has two steps.

c. The reaction rate increases with better leaving groups.

d. The reaction rate increases when the solvent is changed from CH3OH to (CH3)2SO.

e. The reaction rate depends on the concentration of the alkyl halide only.

f. The mechanism is concerted.

g. The reaction of CH3CH2Br with NaOH occurs by this mechanism.

h. Racemization at a stereogenic center occurs.

i. Tertiary (3°) alkyl halides react faster than 2° or 1° alkyl halides.

j. The reaction follows a second-order rate equation.

5 step solution

Q.54

Draw the organic products formed in each reaction.



a.




b.



c.



d.



e.



f.



g.



h.

3 step solution

Q.55

What is the major product formed when each alkyl halide is treated with each of the following reagents: [1] NaOCOCH3 ; [2] NaOCH3;  [3]KOC(CH3)3 ? If it is not possible to predict the major product, identify the products in the mixture and the mechanism by which each is formed.



a.



b.



c.

3 step solution

Q.56

Draw all products, including stereoisomers, in each reaction.



a.



b.



c.



d.

3 step solution

Q.57

Draw all of the substitution and elimination products formed from the given alkyl halide with each reagent: (a) CH3OH; (b) KOH. Indicatethe stereochemistry around the stereogenic centers present in theproducts, as well as the mechanism by which each product is formed.



5 step solution

Q.58

The following reactions do not afford the major product that is given. Explain why this is so, and draw the structure of the major product actually formed.



a.



b.



c.



d.

3 step solution

Q.59

Draw a stepwise, detailed mechanism for each reaction.



a.



b.

3 step solution

Q.60

Draw the major product formed when (R)-1-chloro-3-methylpentane is treated with each reagent: (a) NaOCH2CH3 ; (b) KCN; (c) DBU.

3 step solution

Q.61

Draw a stepwise, detailed mechanism for the following reaction.


3 step solution

Q.62

Explain why the reaction of 2-bromopropane with NaOCOCH3 gives (CH3)2CHOCOCH3 exclusively as product, but the reaction of 2-bromopropane with  NaOCH2CH3 gives a mixture of  (CH3)2CHOCH2CH3 (20%) and  CH3CH=CH2 (80%).

2 step solution

Q.63

Draw a stepwise detailed mechanism that illustrates how four organic products are formed in the following reaction.


3 step solution

Q.64

Although there are nine stereoisomers of 1,2,3,4,5,6-hexachlorocyclohexane, one stereoisomer reacts 7000 times more slowly than any of the others in an E2 elimination. Draw the structure of this isomer and explain why this is so.

2 step solution

Q.65

Explain the selectivity observed in the following reactions.


2 step solution

Q.66

Draw a stepwise mechanism for the following reaction. The four-membered ring in the starting material and product is called a β-lactam. This functional group confers biological activity on penicillin and many related antibiotics, as is discussed in Chapter 22. (Hint: The mechanism begins with β elimination and involves only two steps.)


3 step solution

Q.67

Although dehydrohalogenation occurs with anti periplanar geometry, some eliminations have syn periplanar geometry. Examine the starting material and product of each elimination, and state whether the elimination occurs with syn or anti periplanar geometry.



a.



b.

3 step solution

Q.68

(a) Draw all products formed by treatment of each dibromide (A and B) with one equivalent of NaNH2 . (b) Label pairs of diastereomers and constitutional isomers.


4 step solution

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