Federal regulations set an upper limit of 50 parts per million (ppm) of
\(\mathrm{NH}_{3}\) in the air in a work environment [that is, 50 molecules of
\(\mathrm{NH}_{3}(g)\) for every million molecules in the air]. Air from a
manufacturing operation was drawn through a solution containing \(1.00 \times
10^{2} \mathrm{~mL}\) of \(0.0105 \mathrm{M} \mathrm{HCl}\). The
\(\mathrm{NH}_{3}\)
reacts with \(\mathrm{HCl}\) as follows:
$$\mathrm{NH}_{3}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4}
\mathrm{Cl}(a q)$$
After drawing air through the acid solution for \(10.0 \mathrm{~min}\) at a rate
of \(10.0 \mathrm{~L} / \mathrm{min},\) the acid was titrated. The remaining
acid needed \(13.1 \mathrm{~mL}\) of \(0.0588 \mathrm{M} \mathrm{NaOH}\) to reach
the equivalence point. (a) How many grams of \(\mathrm{NH}_{3}\) were drawn into
the acid solution? (b) How many ppm of \(\mathrm{NH}_{3}\) were in the air? (Air
has a density of \(1.20 \mathrm{~g} / \mathrm{L}\) and an average molar mass of
\(29.0 \mathrm{~g} / \mathrm{mol}\) under the conditions of the experiment.) (c)
Is this manufacturer in compliance with regulations?
