Chapter 16
Chemistry Matter and Change · 70 exercises
Problem 69
Distinguish between a complex reaction, a reaction mechanism, and an elementary step.
3 step solution
Problem 70
Suppose that a chemical reaction takes place in a two-step mechanism. Step 1 (fast) \(\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}\) Step \(2(\text { slow }) \mathrm{C}+\mathrm{D} \rightarrow \mathrm{E}\) Which step in the reaction mechanism is the ratedetermining step? Explain.
3 step solution
Problem 73
Dinitrogen pentoxide decomposes in chloroform at a rate of \(2.48 \times 10^{-4} \mathrm{mol} /(\mathrm{L} \cdot \mathrm{min})\) at a particular temperature according to the equation \(2 \mathrm{N}_{2} \mathrm{O}_{5} \rightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2}\) The reaction is first order in \(\mathrm{N}_{2} \mathrm{O}_{5}\) . Given an initial concentration 0.400 \(\mathrm{mol} / \mathrm{L}\) , what is the rate constant for the reaction? What is the approximate \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]\) after the reaction proceeds for 1.30 \(\mathrm{h}\) ?
3 step solution
Problem 74
Radioactive decay is first order in the decaying isotope. For example, strontium-90 contained in fallout from nuclear explosions decays to yttrium-90 and a beta particle. Write the rate law for the decay of strontium-90.
3 step solution
Problem 75
Evaluate the validity of this statement: You can determine the rate law for a chemical reaction by examining the mole ratio of reactants in the balanced equation. Explain your answer.
3 step solution
Problem 76
The concentration of Reactant A decreases from 0.400 \(\mathrm{mol} / \mathrm{L}\) at 0.00 \(\mathrm{min}\) to 0.384 \(\mathrm{mol} / \mathrm{L}\) at 4.00 \(\mathrm{min}\) . Calculate the average reaction rate during this time period. Express the rate in mol/(L. min).
3 step solution
Problem 78
If the concentration of a reaction product increases from 0.0882 \(\mathrm{mol} / \mathrm{L}\) to 0.1446 \(\mathrm{mol} / \mathrm{L}\) in 12.0 minutes, what is the average reaction rate during the time interval?
5 step solution
Problem 79
A two-step mechanism has been proposed for the decomposition of nitryl chloride \(\left(\mathrm{NO}_{2} \mathrm{CL}\right)\) Step \(1 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})\) Step \(2 : \mathrm{NO}_{2} \mathrm{Cl}(\mathrm{g})+\mathrm{Cl}(\mathrm{g}) \rightarrow \mathrm{NO}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})\) What is the overall reaction? Identify any intermediates in the reaction sequence, and explain why they are called intermediates
4 step solution
Problem 81
Automobile Engine The following reaction takes place in an automobile’s engine and exhaust system. $$\mathrm{NO}_{2}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \rightarrow \mathrm{NO}(\mathrm{g})+\mathrm{CO}_{2}(\mathrm{g})$$ The reaction's rate law at a particular temperature is Rate \(=0.50 \mathrm{L} /(\mathrm{mol} \cdot \mathrm{s})\left[\mathrm{NO}_{2}\right]^{2}\) . What is the reaction's initial, instantaneous rate when \(\left[\mathrm{NO}_{2}\right]=0.0048 \mathrm{mol} / \mathrm{L} ?\)
3 step solution
Problem 82
The concentrations in a chemical reaction are expressed in moles per liter and time is expressed in seconds. If the overall rate law is third-order, what are the units for the rate and the rate constant?
4 step solution
Problem 85
Apply the method of initial rates to determine the order of a chemical reaction with respect to Reactant \(X\) . Create a set of hypothetical experimental data that would lead you to conclude that the reaction is second order in \(X .\)
4 step solution
Problem 86
Formulate a rationale to explain how a complex chemical reaction might have more than one rate-determining elementary step.
3 step solution
Problem 88
Apply collision theory to explain two reasons why increasing the temperature of a reaction by 10 \(\mathrm{K}\) often doubles the reaction rate.
4 step solution
Problem 90
Hydrocarbons Heating cyclopropane \(\left(\mathrm{C}_{3} \mathrm{H}_{6}\right)\) converts it to propene \(\left(\mathrm{CH}_{2}=\mathrm{CHCH}_{3}\right) .\) The rate law is first order in cyclopropane. If the rate constant at a particular temperature is \(6.22 \times 10^{-4} \mathrm{s}^{1}\) and the concentration of cyclopropane is held at 0.0300 \(\mathrm{mol} / \mathrm{L}\) , what mass of propene is produced in 10.0 \(\mathrm{min}\) in a volume of 2.50 \(\mathrm{L} ?\)
4 step solution
Problem 91
For the following categories of elements, state the possible number(s) of electrons in their outermost orbitals in the ground state? (Chapter 5) a. \(\mathrm{p}\) -block elements b. nitrogen-group elements c. d-block elements d. noble-gas elements e. s-block elements
5 step solution
Problem 92
Classify each of the following elements as a metal, nonmetal, or metalloid. (Chapter 6) a. molybdenum b. bromine c. arsenic d. neon e. cerium
2 step solution
Problem 94
Balance the following equations. (Chapter 9) a. \(\operatorname{Sn}(s)+\mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{Na}_{2} \mathrm{SnO}_{2}+\mathrm{H}_{2}\) b. \(\mathrm{C}_{8} \mathrm{H}_{18}(1)+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(1)\) c. \(\mathrm{Al}(\mathrm{s})+\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})\)
9 step solution
Problem 95
What mass of iron(III) chloride is needed to prepare 1.00 \(\mathrm{L}\) of a 0.255 \(\mathrm{M}\) solution? (Chapter 14\()\)
3 step solution
Problem 97
\(\Delta H\) for a reaction is negative. Compare the energy of the products and the reactants. Is the reaction endothermic or exothermic? (Chapter 15\()\)
3 step solution
Problem 102
The rate law is rate \(=k[\text { phenolphthalein }] .\) If the rate constant for the reaction is \(1.0 \times 10^{-2} \mathrm{s}^{-1}\) , what is the instantaneous rate of reaction when the concentration of phenolphthalein is 0.0025\(M\) ?
3 step solution