Chapter 23
Chemistry: An Atoms-Focused Approach · 62 exercises
Problem 78
Many transition metal complexes are brightly colored. Why is the titanium(IV) compound budotitane be colorless?
4 step solution
Problem 79
Is the glucose tolerance factor that contains chromium(III) paramagnetic or diamagnetic?
5 step solution
Problem 80
Coordination complexes containing paramagnetic transition metal ions make the best MRI contrast agents. a. Which of the first-row transition metal cations with a 2+ cations have the most unpaired valence electrons in the gas phase? b. Which of the first-row transition metal cations with a 2+ cations have the most unpaired valence electrons in octahedral coordination complexes?
6 step solution
Problem 81
The complexation of mercury(II) ion with methionine $$\mathrm{Hg}^{2+}+\text { methionine } \rightleftharpoons \mathrm{Hg}(\text { methionine })^{2+}$$ has a formation constant of \(\log K_{\mathrm{f}}=14.2,\) whereas the formation constant for the \(\mathrm{Hg}^{2+}\) complex with penicillamine $$\mathrm{Hg}^{2+}+\text { penicillamine } \rightleftharpoons \mathrm{Hg} \text { (penicillamine) }^{2+}$$ is \(\log K_{\mathrm{f}}=16.3 .\) Calculate the equilibrium constant for the reaction Hg(methionine) \(^{2+}+\) penicillamine \(\rightleftharpoons\) Hg(penicillamine) \(^{2+}+\) methionine
4 step solution
Problem 82
The complexation of mercury(II) ion with cysteine in aqueous solution $$\mathrm{Hg}^{2+}+\text { cysteine } \rightleftharpoons \mathrm{Hg}(\text { cysteine })^{2+}$$ has a formation constant of \(\log K_{f}=14.2,\) whereas the formation constant for the \(\mathrm{Hg}^{2+}\) complex with glycine $$\mathrm{Hg}^{2+}+\text { glycine } \rightleftharpoons \mathrm{Hg}(\text { glycine })^{2+}$$ is \(\log K_{\mathrm{f}}=10.3 .\) Calculate the equilibrium constant for the reaction Hg(cysteine) \(^{2+}+\) glycine \(\rightleftharpoons\) Hg(glycine) \(^{2+}+\) cysteine
4 step solution
Problem 89
Dissolving cobalt(II) nitrate in water gives a beautiful purple solution. There are three unpaired electrons in this cobalt(II) complex. When cobalt(II) nitrate is dissolved in aqueous ammonia and oxidized with air, the resulting yellow complex has no unpaired electrons. Which cobalt complex has the larger crystal field splitting energy \(\Delta_{o} ?\)
4 step solution
Problem 91
A solid compound containing \(\mathrm{Fe}(\mathrm{II})\) in an octahedral crystal field has four unpaired electrons at \(298 \mathrm{K} .\) When the compound is cooled to \(80 \mathrm{K},\) the same sample appears to have no unpaired electrons. How do you explain this change in the compound's properties?
4 step solution
Problem 92
When \(\mathrm{Ag}_{2} \mathrm{O}\) reacts with peroxodisulfate \(\left(\mathrm{S}_{2} \mathrm{O}_{8}^{2-}\right)\) ion (a powerful oxidizing agent), \(\mathrm{AgO}\) is produced. Crystallographic and magnetic analyses of AgO suggest that it is not simply \(\mathrm{Ag}(\mathrm{II})\) oxide, but rather a blend of \(\mathrm{Ag}(\mathrm{I})\) and \(\mathrm{Ag}(\mathrm{III})\) in a square planar environment. The \(\mathrm{Ag}^{2+}\) ion is paramagnetic but, like \(\mathrm{AgO}, \mathrm{Ag}^{+}\) and \(\mathrm{Ag}^{3+}\) are diamagnetic. Explain why.
5 step solution
Problem 93
The iron(II) compound Fe(bipy) \(_{2}(\mathrm{SCN})_{2}\) is paramagnetic, but the corresponding cyanide compound \(\mathrm{Fe}(\text { bipy })_{2}(\mathrm{CN})_{2}\) is diamagnetic. Why do these two compounds have different magnetic properties?
5 step solution
Problem 94
Aqueous solutions of copper(II)-ammonia complexes are dark blue. Will the color of the series of complexes \(\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{(6-x)}\left(\mathrm{NH}_{3}\right)_{x}^{+}\) shift toward shorter or longer wavelengths as the value of \(x\) increases from 0 to \(6 ?\)
3 step solution
Problem 95
Manganese(II) chloride was one of the first compounds to be investigated as MRI contrast agents. How many unpaired electrons does the complex have when \(\mathrm{MnCl}_{2}\) dissolves in water to form the coordination compound \(\mathrm{MnCl}_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4} ?\)
5 step solution
Problem 96
Gadolinium(III) ions are used in contrast agents for MRI because they have unpaired electrons. What is the electron configuration for Gd \(^{3+}\) and how many unpaired electrons does it have?
3 step solution