Chapter 1

Advanced Problems in Organic Chemistry for Competitive Examinations · 25 exercises

Problem 4

Compare the hybridisation of the central carbon atoms in carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) and allene \(\left(\mathrm{H}_{2} \mathrm{C}=\mathrm{C}=\mathrm{CH}_{2}\right) .\) Which statement is correct? (a) The hybridisation types of these two carbons cannot be compared because of large electronegativity difference between carbon and oxygen in \(\mathrm{CO}_{2}\), that does not exist in allene. (b) The hybridisation of carbon in \(\mathrm{CO}_{2}\) cannot be determined, because the lone electron pairs on oxygen do not allow for angle measurements that are necessary to determine the hybridisation involved. (c) \(\operatorname{In} \mathrm{CO}_{2}\) the carbon is sp \(^{2}\) hybridised, but in allene the central carbon is sp hybridised. (d) In \(\mathrm{CO}_{2}\) the carbon is sp hybridised but in allene the central carbon is sp hybridised.

3 step solution

Problem 9

Choose the correct formula for epinephrine.

3 step solution

Problem 12

In allene \(\left(\mathrm{H}_{2} \mathrm{C}=\mathrm{C}=\mathrm{CH}_{2}\right)\), the terminal carbons are sp \(^{2}\) hybridised. Each of the two terminal \(\mathrm{H}_{2} \mathrm{C}\) groups are situated in such a manner that the two "terminal" planes are \(90^{\circ}\) from each other. Other compounds with double bonds on successive carbons may also exist. They are called cumulenes. What is the relationship between the two terminal \(\mathrm{H}_{2} \mathrm{C}\) groups in a cumulene containing three consecutive double bonds \(\left(\mathrm{H}_{2} \mathrm{C}=\mathrm{C}=\mathrm{C}=\mathrm{CH}_{2}\right)\) ? (a) They are in perpendicular planes. (b) They are in two planes \(60^{\circ}\) from each other. (c) They are in the same plane. (d) They are in two planes \(120^{\circ}\) from each other.

3 step solution

Problem 14

Alkyne hydrogens are more acidic than alkene or alkane hydrogens because (a) The alkyne carbon has higher 's' character. (b) The anion formed is more stable. (c) The electrons in the sp orbital are closer to the nucleus. (d) All of the above.

4 step solution

Problem 30

The relative yield of the following alkenes produced by the reaction of trans-1-chloro-2methylcyclohexane with KOH/heat is (i) 1-methylcyclohexene (ii) methylenecyclohexane (iii) 3-methylcyclohexene (a) \(\mathrm{i}>\mathrm{ii}>\mathrm{iii}\) (b) \(\mathrm{ii}>\mathrm{iii}>\mathrm{i}\) (c) \(\mathrm{i}>\mathrm{iii}>\mathrm{ii}\) (d) \(\mathrm{iii}>\mathrm{i}>\mathrm{ii}\)

5 step solution

Problem 38

Imidazole has a \(\mathrm{pKa}=7\) with respect to its conjugate acid. Which \(\mathrm{N}\) is protonated in this conjugate acid and why? (a) N1 because imidazole is an aromatic heterocycle where \(n=1\) as per Huckel's rule. (b) N1 is protonated because it is \(\mathrm{sp}^{3}\) hybridised. (c) \(\mathrm{N} 3\) is protonated because it is \(\mathrm{sp}^{2}\) hybridised. (d) N1 is protonated because the lone pair is part of the aromatic pi system.

5 step solution

Problem 39

Cyclopentadiene has a \(\mathrm{pKa}=15\), whereas cyclopentane has a \(\mathrm{pKa}>50 .\) This is because (a) Cyclopentadiene is particularly unstable. (b) Cyclopentane contains no lone pairs. (c) Cyclopentadiene is a \(4 \pi\) anti-aromatic compound. (d) Cyclopentadiene is a \(4 \pi\) non-aromatic compound and after deprotonation it is aromatic.

5 step solution

Problem 40

The \(\alpha\) -hydrogens of esters typically have a \(\mathrm{pKa}=25\), whereas for ketones \(\mathrm{pKa}=20 .\) This is because: (a) There is no resonance stabilisation of the enolates of esters. (b) The inductive effect of the oxygen in the ester destabilises the ester enolate. (c) The electron donating alkoxy group in esters destabilises the enolate. (d) The electron donating alkoxy group in esters stabilises the enolate.

5 step solution

Problem 58

Rank, from the most stabilised to the least stabilised, the following free radicals according to their stabilisation energies. (i) \(\mathrm{CH}_{3} \mathrm{CH}_{2}\) (ii) \(\dot{\mathrm{C}} \mathrm{H}_{2} \mathrm{CH}_{3}\) (iii) \(\left(\mathrm{CH}_{3}\right)_{2} \dot{\mathrm{C}} \mathrm{H}\) (iv) \(\left(\mathrm{CH}_{2}=\mathrm{CH}-\dot{\mathrm{C}} \mathrm{H}_{2}\right)\) (a) \(\mathrm{iv}>\mathrm{iii}>\mathrm{ii}>\mathrm{i}\) (b) \(\mathrm{i}>\mathrm{iv}>\mathrm{iii}>\mathrm{ii}\) (c) \(\mathrm{iii}>\mathrm{iv}>\mathrm{i}>\mathrm{ii}\) (d) iii \(>\mathrm{iv}>\mathrm{ii}>\mathrm{i}\)

4 step solution

Problem 66

Arrange the following compounds in order of their acidity. (most to least) (i) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (ii) \(\mathrm{CFH}_{2} \mathrm{CO}_{2} \mathrm{H}\) (iii) \(\mathrm{CF}_{2} \mathrm{HCO}_{2} \mathrm{H}\) (iv) \(\mathrm{CF}_{3}^{3} \mathrm{COOH}\) (v) \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\) (a) \(\mathrm{iv}>\mathrm{iii}>\mathrm{ii}>\mathrm{v}>\mathrm{i}\) (b) \(\mathrm{iv}>\mathrm{iii}>\mathrm{ii}>\mathrm{i}>\mathrm{v}\) (c) \(v>\mathrm{ii}>\mathrm{iii}>\mathrm{iv}>\mathrm{i}\) (d) \(\mathrm{v}>\mathrm{iii}>\mathrm{iv}>\mathrm{ii}>\mathrm{i}\)

5 step solution

Problem 70

Which of the following compound has the highest boiling point? (a) \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\) (b) \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) (d) \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}\)

3 step solution

Problem 73

What is the Lewis structure of \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CHO} ?\)

5 step solution

Problem 73

Which is the electronic configuration that describes \(\mathrm{Na}^{+}\) ? (a) \(1 S^{2}, 2 S^{2}, 2 P^{6}\) (b) \(1 S^{2}, 2 S^{2}, 2 P^{6}, 3 S^{2}, 3 P^{6}\) (c) \(1 S^{2}, 2 S^{2}\) (d) \(1 S^{2}, 2 S^{2}, 2 P^{6}, 3 S^{2}\)

3 step solution

Problem 75

Which molecules are non-polar? (i) \(\mathrm{NH}_{3}\) (ii) \(\mathrm{CO}_{2}\) (iii) \(\mathrm{H}_{2} \mathrm{O}\) (iv) \(\mathrm{CF}_{4}\) (v) \(\mathrm{Br}_{2}\) (vi) \(\mathrm{BF}_{3}\) (vii) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (viii) \(\mathrm{H}_{2} \mathrm{O}_{2}\) (a) \(\mathrm{ii}, \mathrm{iv}, \mathrm{v}, \mathrm{vi}\) (b) \(\mathrm{i}, \mathrm{iv}, \mathrm{vi}\), viii (c) iii, \(\mathrm{iv}, \mathrm{v}, \mathrm{vi}\) (d) i, iii, vii, viii

3 step solution

Problem 78

Hyperconjugation is best described as: (a) delocalisation of \(\mathrm{p}\) electrons into a nearby empty orbital (b) delocalisation of \(\sigma\) electrons into a nearby empty orbital (c) the effect of alkyl groups donating a small amount of electron density inductively into a carbocation (d) the migration of a carbon or hydrogen from one carbocation to another

3 step solution

Problem 80

Which of the following statements best explains why 1-propyne can be deprotonated by the ethyl anion \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}^{-}\right) ?\) (a) The acetylide anion is a stronger base than the ethyl anion. (b) Ethane has a lower \(\mathrm{pK}\), than acetylene. (c) The lone-pair orbitals in acetylide anions have more s character than those in alkyl anions. (d) The acetylide anion is a weaker base than an alkyl anion.

5 step solution

Problem 81

Which of the following statements is NOT true for ethylene \(\left(\mathrm{CH}_{2}=\mathrm{CH}_{2}\right)\) molecule? (a) Both carbons are sp \(^{2}\) hybridised. (b) \(\mathrm{C}=\mathrm{C}\) bond length is shorter than the \(\mathrm{C}-\mathrm{C}\) bond length in ethane. (c) The two \(C=C\) bonds are equally strong. (one is pi and the other is sigma.) (d) The entire molecule has a planar geometry.

4 step solution

Problem 87

The nitrogen in trimethylamine is (a) \(\mathrm{sp}^{2}\) hybridised (b) \(\mathrm{sp}^{3}\) hybridised (c) sp hybridised (d) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) hybridised

4 step solution

Problem 94

Which of the following statements about resonance structures is false? (a) Individual resonance structures are imaginary, not real. (b) Resonance forms differ only in the placement of their \(\pi\) - or non- bonding electrons or unpaired electron. (c) Different resonance structures of a substance do not have to be equivalent. (d) In valid resonance structures, all atoms from the second row of the periodic table must have an octet of electrons.

6 step solution

Problem 96

\(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2} \frac{\mathrm{NaNO}_{2}}{\mathrm{HCl}} \rightarrow[\mathrm{P}] ;\) Products of the reaction are: (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH}\) (b) Et-Cl (c) \(\mathrm{Et}-\mathrm{C}-\mathrm{H}\) (d) \(\mathrm{Et}-\mathrm{ONO}\)

4 step solution

Problem 102

Which of the following alkane can not be synthesised by Wurtz reaction in good yield? (a) \(\left(\mathrm{CH}_{3}\right)_{2}-\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}-\left(\mathrm{CH}_{3}\right)_{2}\) (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}-\left(\mathrm{CH}_{3}\right)_{2}\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C}\left(\mathrm{CH}_{3}\right)_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\) (d) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\)

6 step solution

Problem 108

Test for identification of But-2-ene and benzene is (a) Tollen's Reagent test (b) \(1 \%\) Alkaline \(\mathrm{KMnO}_{2}\) (c) Iodoform test (d) \(\mathrm{Br}_{2}+\mathrm{H}_{2} \mathrm{O}\) test

5 step solution

Problem 135

Which of the following is most acidic in character? (a) o-nitrobenzoic acid (b) \(\mathrm{p}\) -nitrobenzoic acid (c) m-nitrobenzoic acid (d) Benzoic acid

5 step solution

Problem 137

Arrange acidity of the given compounds increasing order (i) p-nitrophenol (ii) \(\mathrm{p}\) -fluorophenol (iii) \(\mathrm{p}\) -chlorophenol (a) (i), (ii), (iii) (b) (ii), (i), (iii) (c) (ii), (iii), (i) (d) (iii), (ii), (i)

4 step solution

Problem 138

Which of the following statements are correct for \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CCl}_{3} ?\) (a) \(\mathrm{CCl}_{3}\) group is electron withdrawing due to the -I effect and reverse hyperconjugation. (b) \(\mathrm{CCl}_{3}\) group is meta directing due to the \(-\mathrm{M}\) effect. (c) \(\mathrm{CCl}_{3}\) group is o, p-directing because it is \(+\mathrm{R}\) group. (d) \(\mathrm{CCl}_{3}\) group can exert \(+\mathrm{M}\) effect.

4 step solution

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