Problem 75
Question
Which molecules are non-polar? (i) \(\mathrm{NH}_{3}\) (ii) \(\mathrm{CO}_{2}\) (iii) \(\mathrm{H}_{2} \mathrm{O}\) (iv) \(\mathrm{CF}_{4}\) (v) \(\mathrm{Br}_{2}\) (vi) \(\mathrm{BF}_{3}\) (vii) \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) (viii) \(\mathrm{H}_{2} \mathrm{O}_{2}\) (a) \(\mathrm{ii}, \mathrm{iv}, \mathrm{v}, \mathrm{vi}\) (b) \(\mathrm{i}, \mathrm{iv}, \mathrm{vi}\), viii (c) iii, \(\mathrm{iv}, \mathrm{v}, \mathrm{vi}\) (d) i, iii, vii, viii
Step-by-Step Solution
Verified Answer
The correct answer is (a) ii, iv, v, vi.
1Step 1: Identify Molecular Geometry
First, we need to determine the molecular geometry of each given molecule. For instance, \(\mathrm{NH}_{3}\) has a trigonal pyramidal structure, \(\mathrm{CO}_{2}\) is linear, \(\mathrm{H}_{2} \mathrm{O}\) is bent, \(\mathrm{CF}_{4}\) is tetrahedral, \(\mathrm{Br}_{2}\) is linear, \(\mathrm{BF}_{3}\) is trigonal planar, \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) is tetrahedral, and \(\mathrm{H}_{2} \mathrm{O}_{2}\) is bent.
2Step 2: Determine Polarity Based on Geometry and Electronegativities
Evaluate each molecule's polarity by considering its molecular geometry and the electronegativity difference between atoms. Non-polar molecules have a symmetrical distribution of electrical charges. For example, \(\mathrm{CO}_{2}\)'s linear shape results in dipoles that cancel out, making it non-polar. \(\mathrm{CF}_{4}\) has a symmetrical tetrahedral shape, \(\mathrm{Br}_{2}\) has no difference in electronegativity (being a diatomic molecule of the same element), and in \(\mathrm{BF}_{3}\), the trigonal planar shape ensures the dipoles cancel out, making all these molecules non-polar.
3Step 3: Select the Non-Polar Molecules Based on Analysis
Based on the above analysis, the non-polar molecules are \(\mathrm{CO}_{2}\), \(\mathrm{CF}_{4}\), \(\mathrm{Br}_{2}\), and \(\mathrm{BF}_{3}\). Thus, the correct answer is option (a).
Key Concepts
Molecular GeometryElectronegativityNon-Polar MoleculesSymmetrical Molecules
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. This structural configuration is determined by the number of bonds and the lone pairs of electrons associated with the central atom. Understanding the geometry is crucial, as it directly affects the physical and chemical properties of the molecule, including its polarity.
Some common geometries include:
Some common geometries include:
- Linear: This shape occurs when there are two bonding pairs and generally no lone pairs on the central atom, like in \(CO_{2}\), where it allows for the cancellation of dipoles, resulting in a non-polar molecule.
- Tetrahedral: Characteristic of molecules like \(CF_{4}\), where four bonded atoms around a central atom create a shape that often leads to non-polarity when all outer atoms are identical.
- Trigonal Planar: Involves three bonds in one plane, as seen in \(BF_{3}\), where the symmetry aids in dipole cancellation, leading to a non-polar outcome.
- Bent: Often contributes to molecular polarity, as in \(H_{2}O\), due to its unsymmetrical shape which prevents dipole cancellation.
Electronegativity
Electronegativity is a chemical property that describes an atom's ability to attract and hold onto electrons in a chemical bond. This concept is significant in determining the polarity of molecules. Varying electronegativity among atoms causes uneven sharing of electrons, or dipoles, within a molecule.
Key aspects to consider:
Key aspects to consider:
- High Electronegativity: Atoms with a high electronegativity, like fluorine, oxygen, and nitrogen, are more likely to pull electrons towards themselves, creating polar bonds.
- Difference in Electronegativity: The larger the difference between the electronegativities of bonded atoms, the more polar the bond. For instance, in \(NH_{3}\), nitrogen is more electronegative than hydrogen, resulting in a polar structure.
- Symmetrical Non-Polarity: When the dipoles within a molecule cancel each other out due to symmetry, the molecule can become non-polar even if it contains polar bonds, such as in \(CO_{2}\) where the linear shape leads to dipole cancellation.
Non-Polar Molecules
Non-polar molecules are characterized by an even or symmetrical distribution of electron charge, which results in a net dipole of zero. The polarity of these molecules is often determined by the molecular geometry and electronegativity of the atoms involved.
Key features include:
Key features include:
- Symmetrical Electron Distribution: When the electron distribution is even, as in \(CF_{4}\) and \(BF_{3}\), the symmetrical shape allows any dipoles to cancel out, resulting in non-polarity.
- Identical Atoms: Molecules like \(Br_{2}\) consist of identical atoms and zero electronegativity difference, making them intrinsically non-polar.
- Shape-Induced Non-Polarity: Even though a molecule may contain polar bonds, its symmetrical shape can lead to overall non-polarity, as seen in \(CO_{2}\).
Symmetrical Molecules
Symmetrical molecules have a balanced, uniform structure where the individual polarities of bonds or atoms cancel out the effects of each other. This symmetry is key in defining their lack of overall polarity, making the molecule non-polar.
Importance of symmetry includes:
Importance of symmetry includes:
- Balanced Shape: In symmetric molecules like \(CF_{4}\), the tetrahedral arrangement balances out any possible dipole moments, ensuring the molecule remains non-polar.
- Dipole Cancellation: Symmetrical geometry ensures that even with polar bonds, like in \(BF_{3}\), the dipole effects negate each other, resulting in no net dipole.
- Predictability in Reactions: These molecules are often less reactive due to their non-polar nature, impacting their behavior in chemical reactions and intermolecular interactions.
Other exercises in this chapter
Problem 73
What is the Lewis structure of \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CHO} ?\)
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Which is the electronic configuration that describes \(\mathrm{Na}^{+}\) ? (a) \(1 S^{2}, 2 S^{2}, 2 P^{6}\) (b) \(1 S^{2}, 2 S^{2}, 2 P^{6}, 3 S^{2}, 3 P^{6}\)
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Hyperconjugation is best described as: (a) delocalisation of \(\mathrm{p}\) electrons into a nearby empty orbital (b) delocalisation of \(\sigma\) electrons int
View solution Problem 80
Which of the following statements best explains why 1-propyne can be deprotonated by the ethyl anion \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}^{-}\right) ?\) (a)
View solution