Chapter 1
A Complete Resource Book in Chemistry for JEE Main · 139 exercises
Problem 69
A gaseous mixture contains \(\mathrm{O}_{2}\) and \(\mathrm{N}_{2}\) in the ratio \(1: 4\) by weight. Then the ratio of their number of molecules in the mixture is (a) \(3: 32\) (b) \(7: 32\) (c) \(1: 4\) (d) \(3: 16\)
5 step solution
Problem 70
\(1 \mathrm{cc} \mathrm{N}_{2} \mathrm{O}\) at NTP contains (a) \(\frac{1.32}{224} \times 10^{23}\) electrons (b) \(\frac{6.02}{22400} \times 10^{23}\) molecules (c) \(\frac{1.8}{224} \times 10^{22}\) atoms (d) all of these
4 step solution
Problem 71
\(0.30 \mathrm{~g}\) of a volatile liquid displaces \(90.0 \mathrm{~cm}^{3}\) of air at STP in the Victor Meyer's method. The molecular mass of the liquid is (a) \(54.44 \mathrm{~g}\) (b) \(34.64 \mathrm{~g}\) (c) \(64.76 \mathrm{~g}\) (d) \(74.66 \mathrm{~g}\)
5 step solution
Problem 72
A 5 molar solution of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is diluted from 1 litre to a volume of 10 litres, the normality of the solution will be (a) \(0.5 \mathrm{~N}\) (b) \(1 \mathrm{~N}\) (c) \(2.5 \mathrm{~N}\) (d) \(5 \mathrm{~N}\)
4 step solution
Problem 73
If \(0.50\) mole of \(\mathrm{BaCl}_{2}\) is mixed with \(0.20\) mole of \(\mathrm{Na}_{3} \mathrm{PO}_{4}\), the maximum number of moles of \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) that can be formed is (a) \(0.10\) (b) \(0.20\) (c) \(0.30\) (d) \(0.40\)
3 step solution
Problem 74
The equivalent weight of \(\mathrm{MnSO}_{4}\) is half its molecular weight when it is converted to (a) \(\mathrm{MnO}\) (b) \(\mathrm{MnO}_{4}^{2-}\) (c) \(\mathrm{MnO}_{2}\) (d) \(\mathrm{MnO}_{4}^{-}\)
5 step solution
Problem 75
An aqueous solution of \(6.3 \mathrm{~g}\) oxalic acid dehydrate is made up to \(250 \mathrm{ml}\). The volume of \(0.1 \mathrm{~N} \mathrm{NaOH}\) required to completely neutralize \(10 \mathrm{~mL}\) of this solution is (a) \(4 \mathrm{~mL}\) (b) \(20 \mathrm{~mL}\) (c) \(40 \mathrm{~mL}\) (d) \(60 \mathrm{~mL}\)
6 step solution
Problem 79
The weight of a single atom of oxygen is (a) \(5.057 \times 10^{23} \mathrm{~g}\) (b) \(1.556 \times 10^{23} \mathrm{~g}\) (c) \(2.656 \times 10^{-23} \mathrm{~g}\) (d) \(4.538 \times 10^{-23} \mathrm{~g}\)
5 step solution
Problem 80
From the complete decomposition of \(20 \mathrm{~g} \mathrm{CaCO}_{3}\) at STP the volume of \(\mathrm{CO}_{2}\) obtained is (a) \(2.24 \mathrm{~L}\) (b) \(4.48 \mathrm{~L}\) (c) \(44.8 \mathrm{~L}\) (d) \(48.4 \mathrm{~L}\)
6 step solution
Problem 81
\(5 \mathrm{~g}\) of \(\mathrm{CH}_{3} \mathrm{COOH}\) is dissolved in one litre of ethanol. Suppose there is no reaction between them. If the density of ethanol is \(0.789 \mathrm{~g} / \mathrm{mL}\) then the molality of resulting solution is (a) \(0.0256\) (b) \(0.1056\) (c) \(1.1288\) (d) \(0.2076\)
3 step solution
Problem 82
\(800 \mathrm{~g}\) of a \(40 \%\) solution by weight was cooled. \(100 \mathrm{~g}\) of solute precipitated. The percentage composition of remaining solution is (a) \(31.4 \%\) (b) \(57.6 \%\) (c) \(45.8 \%\) (d) \(41.4 \%\)
5 step solution
Problem 83
\(0.25 \mathrm{~mol}\) of \(\mathrm{P}_{4}\) molecules contains ______ atoms. (a) \(1.764 \times 10^{23}\) (b) \(6.02 \times 10^{19}\) (c) \(6.023 \times 10^{23}\) (d) \(8.086 \times 10^{23}\)
4 step solution
Problem 84
How many grams of \(\mathrm{CH}_{3} \mathrm{OH}\) would have to be added to water to prepare \(150 \mathrm{~mL}\) of a solution that is \(2.0 \mathrm{M}\) \(\mathrm{CH}_{3} \mathrm{OH} ?\) (a) \(9.6 \mathrm{~g}\) (b) \(906 \mathrm{~g}\) (c) \(4.3 \times 10^{2} \mathrm{~g}\) (d) \(9.6 \times 10^{3} \mathrm{~g}\)
6 step solution
Problem 86
The molar concentration of \(20 \mathrm{~g}\) of \(\mathrm{NaOH}\) present in 5 litre of solution is (a) \(0.1 \mathrm{~mol} / \mathrm{L}\) (b) \(0.2 \mathrm{~mol} / \mathrm{L}\) (c) \(\mathrm{v} 1.0 \mathrm{~mol} / \mathrm{L}\) (d) \(2.0 \mathrm{~mol} / \mathrm{L}\)
4 step solution
Problem 87
Volume of a gas at NTP is \(1.12 \times 10^{-7} \mathrm{cc}\). The number of molecules in it is (a) \(3.01 \times 10^{12}\) (b) \(3.01 \times 10^{18}\) (c) \(3.01 \times 10^{24}\) (d) \(3.01 \times 10^{30}\)
5 step solution
Problem 88
Maximum number of molecules will be in (a) \(1 \mathrm{~g}\) of \(\mathrm{H}_{2}\) (b) \(10 \mathrm{~g}\) of \(\mathrm{H}_{2}\) (c) \(22 \mathrm{~g}\) of \(\mathrm{O}_{2}\) (d) \(44 \mathrm{~g}\) of \(\mathrm{CO}_{2}\)
4 step solution
Problem 89
Haemoglobin contains \(0.33 \%\) of iron by weight. The molecular weight of haemoglobin is approximately 67200\. The number of iron atom (at. wt of \(\mathrm{Fe}\) is 56 ) present in one molecule of haemoglobin are (a) 1 (b) 6 (c) 4 (d) 2
2 step solution
Problem 92
4 g caustic soda is dissolved in \(100 \mathrm{cc}\) of solution. The normality of solution is (a) 1 (b) \(0.8\) (c) \(0.6\) (d) \(0.10\)
6 step solution
Problem 94
The mass of \(\mathrm{BaCO}_{3}\) formed where excess of \(\mathrm{CO}_{2}\) is passed through a solution having \(0.205\) mole of Ba \((\mathrm{OH})_{2}\) is? (a) \(40.5 \mathrm{gm}\) (b) \(20.25 \mathrm{gm}\) (c) \(81 \mathrm{gm}\) (d) \(4.05 \mathrm{gm}\)
4 step solution
Problem 95
120 gram of urea is present in 5 litre of solution. The active mass of urea is (a) \(0.06\) (b) \(0.2\) (c) \(0.4\) (d) \(1.4\)
4 step solution
Problem 96
The normality of orthophosphoric acid having purity of \(70 \%\) be weight and specific gravity \(1.54\) is (a) \(11 \mathrm{~N}\) (b) \(22 \mathrm{~N}\) (c) \(33 \mathrm{~N}\) (d) \(44 \mathrm{~N}\)
6 step solution
Problem 97
\(10^{21}\) molecules are removed from \(200 \mathrm{mg}\) of \(\mathrm{CO}_{2} .\) The moles of \(\mathrm{CO}_{2}\) left are (a) \(2.88 \times 10^{-3}\) (b) \(28.8 \times 10^{-3}\) (c) \(288 \times 10^{-3}\) (d) \(28.8 \times 10^{3}\)
5 step solution
Problem 98
What is the volume (in litres) of oxygen at STP required for complete combustion of \(32 \mathrm{~g}\) of \(\mathrm{CH}_{4}\) ? (mol. wt of \(\mathrm{CH}_{4}=16\) ) (a) \(89.6\) (b) \(189.6\) (c) \(98.4\) (d) \(169.5\)
4 step solution
Problem 100
How many water molecules are there in one drop of water (volume \(=0.0018 \mathrm{~mL}\) ) at room temperature? (a) \(4.86 \times 10^{17}\) (b) \(6.023 \times 10^{24}\) (c) \(2.584 \times 10^{19}\) (d) \(6.023 \times 10^{19}\)
5 step solution
Problem 101
'X' litres of carbon monoxide is present at STP. It is completely oxidized to \(\mathrm{CO}_{2}\). The volume of \(\mathrm{CO}_{2}\) formed is \(11.207\) litres at STP. What is the value of ' \(\mathrm{X}\) ' in litres? (a) \(32.2\) (b) \(21.2\) (c) \(10.2\) (d) \(11.2\)
4 step solution
Problem 102
Which has maximum number of molecules? (a) \(7 \mathrm{~g} \mathrm{~N}_{2}\) (b) \(2 \mathrm{~g} \mathrm{H}_{2}\) (c) \(18 \mathrm{~g} \mathrm{NO}_{2}\) (d) \(16 \mathrm{~g} \mathrm{O}_{2}\)
4 step solution
Problem 103
One mole of fluorine is reacted with two mole of hot and concentrated KOH. The products formed are \(\mathrm{KF}, \mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{O}_{2} .\) The molar ratio of \(\mathrm{KF}, \mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{O}_{2}\) respectively is (a) \(1: 2: 1\) (b) \(1: 2: 2\) (c) \(0.5: 1: 2\) (d) \(2: 1: 0.5\)
3 step solution
Problem 104
The total number of protons in \(10 \mathrm{~g}\) of calcium carbonate is \(\left(\mathrm{N}_{0}=6.023 \times 10^{25}\right)\) (a) \(3.01 \times 10^{24}\) (b) \(4.06 \times 10^{24}\) (c) \(30.1 \times 10^{24}\) (d) \(3.01 \times 10^{23}\)
5 step solution
Problem 105
What is the volume (in litre) of oxygen required at STP to completely convert \(1.5\) moles of sulphur to sulphur dioxide? (a) \(33.6\) (b) \(43.6\) (c) \(11.2\) (d) \(23.6\)
3 step solution
Problem 106
In acidic medium, dichromate ion oxidize ferrous ion to ferric ion. If the gram molecular weight of potassium dichromate is \(294 \mathrm{~g}\), its equivalent weight is (a) 19 (b) 49 (c) 99 (d) 294
3 step solution
Problem 107
\(10 \mathrm{~g}\) of \(\mathrm{CaCO}_{3}\) is completely decomposed to \(\mathrm{X}\) and \(\mathrm{CaO} . \mathrm{X}\) is passed into an aqueous solution containing one mole of sodium carbonate. What is the number of moles of sodium bicarbonate formed? (Mol. wt of \(\mathrm{CaCO}_{3}=100, \mathrm{Na}_{2} \mathrm{CO}_{3}=106\) \(\mathrm{NaHCO}_{3}=84\) ) (a) \(0.010\) (b) \(0.2\) (c) \(0.4\) (d) 10
4 step solution
Problem 108
The mass of carbon anode consumed (giving only \(\mathrm{CO}_{2}\) ) in the production of \(270 \mathrm{~kg}\) of aluminium metal from bauxite by the Hall process is (atomic mass of \(\mathrm{Al}=27\) ) (a) \(180 \mathrm{~kg}\) (b) \(270 \mathrm{~kg}\) (c) \(145 \mathrm{~kg}\) (d) \(90 \mathrm{~kg}\)
5 step solution
Problem 109
The number of moles of \(\mathrm{KMnO}_{4}\) reduced by one mole of KI in alkaline medium is (a) 2 (b) 1 (c) 5 (d) 6
3 step solution
Problem 110
How many grams of dibasic acid (mol. wt 200 ) should be present in \(100 \mathrm{~mL}\) of the aqueous solution to give \(0.1\) normality? (a) \(1 \mathrm{~g}\) (b) \(1.5 \mathrm{~g}\) (c) \(0.5 \mathrm{~g}\) (d) \(20 \mathrm{~g}\)
5 step solution
Problem 111
' \(X\) ' gram of calcium carbonate was completely burnt in air. The weight of solid residue formed is \(28 \mathrm{~g}\). What is the value of ' \(\mathrm{X}\) ' (in grams)? (a) 50 (b) 100 (c) 150 (d) 200
4 step solution
Problem 112
One mole of acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) on reaction with excess KI will liberate ..... moles (s) of \(\mathrm{I}_{2}\). (a) 2 (b) 3 (c) 6 (d) 7
3 step solution
Problem 113
\(0.59 \mathrm{~g}\) of the silver salt of an organic acid (molar mass 210) on ignition gave \(0.36 \mathrm{~g}\) of pure silver. The basicity of the acid is (a) 2 (b) 3 (c) 4 (d) 5
5 step solution
Problem 114
\(\mathrm{KMnO}_{4}\) (mol. wt = 158 ) oxidizes oxalic acid in acidic medium to \(\mathrm{CO}_{2}\) and water as follows. \(5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-}+2 \mathrm{MnO}_{4}^{-}+16 \mathrm{H}^{+} \longrightarrow 10 \mathrm{CO}_{2}+\) \(2 \mathrm{Mn}^{2+}+8 \mathrm{H}_{2} \mathrm{O}\) What is the equivalent weight of \(\mathrm{KMnO}_{4} ?\) (a) 158 (b) \(31.6\) (c) \(39.5\) (d) 79
3 step solution
Problem 115
Sodium bicarbonate on heating decomposes to form sodium carbonate, \(\mathrm{CO}_{2}\) and water. If \(0.2\) moles of sodium bicarbonate is completely decomposed, how many moles of sodium carbonate is formed? (a) \(0.1\) (b) \(0.2\) (c) \(0.05\) (d) \(0.025\)
4 step solution
Problem 116
A purified pepsin was subjected to amino acid analysis. The amino acid present in the smallest amount was lysine, \(\mathrm{C}_{6} \mathrm{H}_{14} \mathrm{~N}_{2} \mathrm{O}_{2}\) and the amount of lysine was found to be \(0.431 \mathrm{~g}\) per \(100 \mathrm{~g}\) of protein. The minimum molecular mass of protein is (a) \(34 \mathrm{u}\) (b) \(3400 \mathrm{u}\) (c) \(34,000 \mathrm{u}\) (d) \(3400,000 \mathrm{u}\)
4 step solution
Problem 117
Find the number of valence electrons present in \(0.53\) gram of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\). (a) \(3.01 \times 10^{23}\) (b) \(1.2046 \times 10^{23}\) (c) \(12.046 \times 10^{23}\) (d) \(6.023 \times 10^{23}\)
6 step solution
Problem 119
If \(3.02 \times 10^{19}\) molecules are removed from \(98 \mathrm{mg}\) of \(\mathrm{H}_{2} \mathrm{SO}_{4}\), then the number of moles of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) left are (a) \(0.1 \times 10^{-3}\) (b) \(5 \times 10^{-4}\) (c) \(1.2 \times 10^{-4}\) (d) \(1.5 \times 10^{-3}\)
4 step solution
Problem 120
A metal oxide has the formula \(\mathrm{M}_{2} \mathrm{O}_{3} .\) It can be reduced by hydrogen to give free metal and water. \(0.1595 \mathrm{~g}\) of the metal oxide requires \(6 \mathrm{mg}\) of hydrogen for complete reduction. What is the atomic weight of metal? (a) \(54.4\) (b) \(46.56\) (c) \(55.8\) (d) \(58.5\)
6 step solution
Problem 121
1\. A chloride of a metal (M) has \(65.5 \%\) of chlorine. 100 \(\mathrm{ml}\) of vapour of the chloride of metal at STP weighs \(0.72 \mathrm{~g}\). The molecular formula of this metal chloride is (a) \(\mathrm{MCl}_{3}\) (b) \(\mathrm{MCl}_{4}\) (c) \(\mathrm{M}_{2} \mathrm{Cl}_{3}\) (d) \(\mathrm{MCl}_{4}\)
5 step solution
Problem 122
The strength of \(0.01 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}\) solution in terms of molality is nearly ______ when the density of the solution is \(1.1 \mathrm{~g} / \mathrm{mL}\) (a) \(9 \times 10^{-3}\) (b) \(1.8 \times 10^{-3}\) (c) \(4.5 \times 10^{-3}\) (d) \(1.1 \times 10^{-3}\)
6 step solution
Problem 123
One mole of magnesium in the vapour state absorbed \(1200 \mathrm{~kJ} \mathrm{~mol}^{-1}\) of energy. If the first and second ionization energies of \(\mathrm{Mg}\) are 750 and \(1450 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively, the final composition of the mixture is (a) \(86 \% \mathrm{Mg}^{+}+14 \% \mathrm{Mg}^{2+}\) (b) \(36 \% \mathrm{Mg}^{+}+64 \% \mathrm{Mg}^{2+}\) (c) \(69 \% \mathrm{Mg}^{+}+31 \% \mathrm{Mg}^{2+}\) (d) \(31 \% \mathrm{Mg}^{+}+69 \% \mathrm{Mg}^{2+}\)
5 step solution
Problem 124
A metal oxide has the formula \(\mathrm{Z}_{2} \mathrm{O}_{3} .\) It can be reduced by hydrogen to give free metal and water. \(0.1596 \mathrm{~g}\) of the metal oxide requires \(6 \mathrm{mg}\) of hydrogen for complete reduction. The atomic weight of the metal is (a) \(55.8\) (b) \(65.8\) (c) \(6.58\) (d) \(15.9\)
7 step solution
Problem 125
The volume of carbon dioxide gas evolved at STP by heating \(7.3 \mathrm{~g}\) of \(\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}\) will be (a) \(1100 \mathrm{~mL}\) (b) \(1120 \mathrm{~mL}\) (c) \(2230 \mathrm{~mL}\) (d) \(3240 \mathrm{~mL}\)
6 step solution
Problem 127
Assuming fully decomposed, the volume of \(\mathrm{CO}_{2}\) released at STP on heating \(9.85 \mathrm{~g}\) of \(\mathrm{BaCO}_{3}\) (atomic mass, \(\mathrm{Ba}=137\) ) will be (a) \(1.12 \mathrm{~L}\) (b) \(4.84 \mathrm{~L}\) (c) \(2.12 \mathrm{~L}\) (d) \(2.06 \mathrm{~L}\)
5 step solution
Problem 128
Specific volume of cylindrical virus particle is \(6.02 \times\) \(10^{-2} \mathrm{cc} / \mathrm{g}\). Whose radius and length are \(7 \AA\) and \(10 \AA\) respectively. If \(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23}\), find molecular weight of virus (a) \(15.4 \mathrm{~kg} / \mathrm{mol}\) (b) \(1.54 \times 10^{4} \mathrm{~kg} / \mathrm{mol}\) (c) \(4.68 \times 10^{4} \mathrm{~kg} / \mathrm{mol}\) (d) \(2.08 \times 10^{3} \mathrm{~kg} / \mathrm{mol}\)
4 step solution