Chapter 9
A Complete Resource Book in Chemistry for JEE Main · 166 exercises
Problem 186
The limiting molar conductivities \(\Lambda^{\circ}\) for \(\mathrm{NaCl}, \mathrm{KBr}\) and \(\mathrm{KCl}\) are 126,152 and \(150 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) respectively. The \(\Lambda^{\circ}\) for \(\mathrm{NaBr}\) is (a) \(278 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) (b) \(178 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) (c) \(128 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) (d) \(306 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\)
6 step solution
Problem 187
In a cell that utilizes the reaction \(\mathrm{Zn}(\mathrm{s})+2 \mathrm{H}^{+}(\mathrm{aq}) \longrightarrow \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g})\) Addition of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to cathode compartment, will (a) lower the \(E\) and shift equilibrium to the right (b) lower the \(E\) and shift the equilibrium to the left (c) increase the \(E\) and shift the equilibrium to the left (d) increase the \(E\) and shift the equilibrium to the right.
5 step solution
Problem 189
For a spontaneous reaction the \(\Delta \mathrm{G}\), equilibrium constant \((\mathrm{K})\) and \(E_{\text {cell }}^{\circ}\) will be respectively \([\mathbf{2 0 0 5}]\) (a) \(-\mathrm{ve},>1,+\mathrm{ve}\) (b) \(+\mathrm{ve},>1,-\mathrm{ve}\) (c) \(-\mathrm{ve},<1,-\mathrm{ve}\) (d) \(-\) ve, \(>1,-\) ve
4 step solution
Problem 190
Aluminium oxide may be electrolysed at \(1000^{\circ} \mathrm{C}\) to furnish aluminium metal (atomic mass \(=27 \mathrm{amu} ; 1\) faraday \(=965000\) coulombs). The cathode reaction is \(\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al}\) To prepare \(5.12 \mathrm{~kg}\) of aluminium metal by this method would require [2008] (a) \(5.49 \times 10^{7} \mathrm{C}\) of electricity (b) \(1.83 \times 10^{7} \mathrm{C}\) of electricity (c) \(5.49 \times 10^{4} \mathrm{C}\) of electricity (d) \(5.49 \times 10^{10} \mathrm{C}\) of electricity
4 step solution
Problem 192
The electrical conductivity of the flowing aqueous solutions is highest for (a) \(0.1 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}\) (b) \(0.1 \mathrm{M} \mathrm{CH}_{2} \mathrm{FCOOH}\) (c) \(0.1 \mathrm{M} \mathrm{CHF}_{2} \mathrm{COOH}\) (d) \(0.1 \mathrm{M} \mathrm{CH}_{2} \mathrm{ClCOOH}\)
5 step solution
Problem 193
Given the data at \(25^{\circ} \mathrm{C}\). [2006] \(\mathrm{Ag}+\mathrm{I} \stackrel{-}{\longrightarrow} \mathrm{AgI}+\mathrm{e} ; E^{\circ}=0.152 \mathrm{~V}\) \(\mathrm{Ag} \longrightarrow \mathrm{Ag}^{+}+\mathrm{e}^{-} ; E^{\circ}=-0.800 \mathrm{~V}\) What is the value of \(\log \mathrm{K}_{s p}\) for \(\mathrm{Ag}\) I? \((2.303 \mathrm{RT} / F=0.059 \mathrm{~V})\) (a) \(-8.12\) (b) \(+8.612\) (c) \(-37.83\) (d) \(-16.13\)
4 step solution
Problem 194
Resistance of a conductivity cell filled with a solution of an electrolyte of concentration \(0.1 \mathrm{M}\) is \(100 \Omega\). The conductivity of this solution is \(1.29 \mathrm{~S} \mathrm{~m}^{-1}\). Resistance of the same cell when filled with \(0.2 \mathrm{M}\) of the same solution is \(520 \Omega\). The molar conductivity of \(0.02 \mathrm{M}\) solution of the electrolyte will be (a) \(124 \times 10^{-4} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\) (b) \(1240 \times 10^{-4} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\) (c) \(1.24 \times 10^{-4} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\) (d) \(12.4 \times 10^{-4} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\)
4 step solution
Problem 195
The equivalent conductances of two strong electrolytes at infinite dilution in \(\mathrm{H}_{2} \mathrm{O}\) (where ions move freely through a solution) at \(25^{\circ} \mathrm{C}\) are given below: [2007] \(\Lambda^{\circ}\left(\mathrm{CH}_{3} \mathrm{COONa}\right)=91.0 \mathrm{~S} \mathrm{~cm}^{2} / \mathrm{equiv}\) \(\Lambda^{\circ}(\mathrm{HCl})=426.2 \mathrm{~S} \mathrm{~cm}^{2} / \mathrm{equiv}\) What additional information/quantity one needs to calculate \(\Lambda^{\circ}\) of an aqueous solution of acetic acid? (a) \(\Lambda^{\circ}\) of \(\mathrm{CH}_{3} \mathrm{COOK}\) (b) The limiting equivalent conductance of \(\mathrm{H}^{+}\left(\lambda^{\circ}\right)\) (c) \(\Lambda^{\circ}\) of chloroacetic acid \(\left(\mathrm{ClCH}_{2} \mathrm{COOH}\right)\) (d) \(\Lambda^{\circ}\) of \(\mathrm{NaCl}\)
4 step solution
Problem 196
The cell \(\mathrm{Zn}\left|\mathrm{Zn}^{2+}(1 \mathrm{M}) \| \mathrm{Cu}^{2+}(1 \mathrm{M})\right| \mathrm{Cu} \mathrm{E}_{\mathrm{cell}}^{\circ}=1.10\) V), was allowed to be completely discharged at 298 \(K\). The relative concentration of \(\mathrm{Zn}^{2+}\) and \(\mathrm{Cu}^{2+}\left(\left[\mathrm{Zn}^{2+}\right] /\right.\) \(\left.\left[\mathrm{Cu}^{2+}\right]\right)\) is [2007] (a) \(37.3\) (b) \(10^{37.3}\) (c) \(9.65 \times 10^{4}\) (d) antilog \((24.08)\)
6 step solution
Problem 197
Given \(\mathrm{E}^{\circ} \mathrm{Cr}^{3+} / \mathrm{Cr}=-0.72 \mathrm{~V}, \mathrm{E}^{\circ} \mathrm{Fe}^{2+} / \mathrm{Fe}=-0.42 \mathrm{~V}\). The potential for the cell \(\mathrm{Cr}\left|\mathrm{Cr}^{3+}(0.1 \mathrm{M}) \| \mathrm{Fe}^{2+}(0.01 \mathrm{M})\right| \mathrm{Fe}\) is (a) \(0.26 \mathrm{~V}\) (b) \(0.399 \mathrm{~V}\) (c) \(-0.339 \mathrm{~V}\) (d) \(-0.26 \mathrm{~V}\)
4 step solution
Problem 201
The reduction potential of hydrogen half-cell will be negative if: (a) \(\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}\) (b) \(\mathrm{p}\left(\mathrm{H}_{2}\right)=1 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=1.0 \mathrm{M}\) (c) \(\mathrm{p}\left(\mathrm{H}_{2}\right)=1 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}\) (d) \(\mathrm{p}\left(\mathrm{H}_{2}\right)=2 \mathrm{~atm}\) and \(\left[\mathrm{H}^{+}\right]=2.0 \mathrm{M}\)
1 step solution
Problem 202
The standard reduction potentials for \(\mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Ni}^{2+} / \mathrm{Ni}\), and \(\mathrm{Fe}^{2+} / \mathrm{Fe}\) are \(-0.76,-0.23\) and \(-0.44 \mathrm{~V}\) respectively. The reaction \(\mathrm{X}+\mathrm{Y}^{2+} \rightarrow \mathrm{X}^{2+}+\mathrm{Y}\) will be spontaneous when (a) \(\mathrm{X}=\mathrm{Fe}, \mathrm{Y}=\mathrm{Zn}\) (b) \(\mathrm{X}=\mathrm{Ni}, \mathrm{Y}=\mathrm{Zn}\) (c) \(\mathrm{X}=\mathrm{Ni}, \mathrm{Y}=\mathrm{Fe}\) (d) \(\mathrm{X}=\mathrm{Zn}, \mathrm{Y}=\mathrm{Ni}\)
6 step solution
Problem 204
Resistance of \(0.2 \mathrm{M}\) solution of an electrolyte is \(50 \Omega\) The specific conductance of the solution is \(1.4 \mathrm{~S} \mathrm{~m}^{-1}\). The resistance of \(0.5 \mathrm{M}\) solution of the same electrolyte is \(280 \Omega\) The molar conductivity of \(0.5 \mathrm{M}\) solution of the electrolyte in \(\mathrm{S} \mathrm{mt}^{2} \mathrm{~mol}^{-1}\) is: (a) \(5 \times 10^{3}\) (b) \(5 \times 10^{2}\) (c) \(5 \times 10^{-4}\) (d) \(5 \times 10^{-3}\)
8 step solution
Problem 205
The equivalent conductance of \(\mathrm{NaCl}\) at concentration \(\mathrm{C}\) and at infinite dilution are \(\lambda_{\mathrm{C}}\) and \(\lambda_{m}\), respectively. The correct relationship between \(\lambda_{\mathrm{C}}\) and \(\lambda_{\infty}\) is given as: (where the constant B is positive) (a) \(\lambda_{\mathrm{C}}=\lambda_{\infty}-(\mathrm{B}) \sqrt{\mathrm{C}}\) (b) \(\lambda_{\mathrm{c}}=\lambda_{\infty}+(\mathrm{B}) \sqrt{\mathrm{C}}\) (c) \(\lambda_{\mathrm{C}}=\lambda_{m}+(\mathrm{B}) \mathrm{C}\) (d) \(\lambda_{\mathrm{C}}=\lambda_{-\infty}-(\mathrm{B}) \mathrm{C}\)
4 step solution
Problem 206
Given below are the half-cell reactions: \(\mathrm{Mn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mn} ; \mathrm{E}^{0}=-1.18 \mathrm{~V}\) \(2\left(\mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2}+\right) ; \mathrm{E}^{\circ}=+1.51 \mathrm{~V}\) The \(\mathrm{E}^{0}\) for \(3 \mathrm{Mn}^{2+} \rightarrow \mathrm{Mn}+2 \mathrm{Mn}^{3+}\) will be: (a) \(-0.33 \mathrm{~V}\); the reaction will not occur (b) \(-0.33 \mathrm{~V}\); the reaction will occur (c) \(-2.69 \mathrm{~V}\); the reaction will not occur (d) \(-2.69 \mathrm{~V}\); the reaction will occur
5 step solution
Problem 207
Two faraday of electricity is passed through a solution of \(\mathrm{CuSO}_{4}\). The mass of copper deposited at the cathode is (at. mass of \(\mathrm{Cu}=63.5\) amu \()\) (a) \(0 \mathrm{~g}\) (b) \(63.5 \mathrm{~g}\) (c) \(2 \mathrm{~g}\) (d) \(127 \mathrm{~g}\)
3 step solution