Chapter 25
A Complete Resource Book in Chemistry for JEE Main · 124 exercises
Problem 176
\(2-\) chlorobutane is treated with alcoholic \(\mathrm{KOH}\). Number of alkenes formed is
5 step solution
Problem 178
\(0-\) Xylene is methylated to get trimethyl benzene. The number of possible isomers is
5 step solution
Problem 179
Find the total number of monochlorinated products formed from the pure
reactant given below:
4 step solution
Problem 180
\(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3} \stackrel{\mathrm{HBr}}{\longrightarrow}\) product (s). Number of products possible in the above reaction is
5 step solution
Problem 183
Of the following reagents the number of them which will react with \(\mathrm{CH}_{3} \mathrm{MgBr}\) to give \(\mathrm{CH}_{4}\) is \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{SH}, \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{RC} \equiv \mathrm{CR}, \mathrm{HCHO}\) \(\mathrm{RC} \equiv \mathrm{CH}\)
3 step solution
Problem 184
Total number of monochlorination products that can be obtained on treating 1 - butene with \(\mathrm{Cl}_{2}\) in presence of light is
5 step solution
Problem 185
In an experimental determination of active hydrogens in an organic compound (Z), \(0.450 \mathrm{~g}\) of compound (Z) was treated with excess of \(\mathrm{CH}_{3} \mathrm{MgBr}\) when \(224 \mathrm{ml}\) of \(\mathrm{CH}_{4}\) was evolved at NTP. Compound (Z) has molar mass equal to \(90 \mathrm{~g}\) per mole. How many active hydrogens are present per molecule of the compound (Z)?
5 step solution
Problem 190
On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane. This alkane could be (a) propane (b) pentane (c) isopentane (d) neopentane
4 step solution
Problem 191
Which one of the following has the minimum boiling point? (a) \(\mathrm{n}\)-butane (b) 1-butyne (c) 1 -butene (d) iso-butene
5 step solution
Problem 192
Acid catalysed hydration of alkenes except ethene leads to the formation of (a) primary alcohol (b) secondary or tertiary alcohol (c) mixture of primary and secondary alcohols (d) mixture of secondary and tertiary alcohols
4 step solution
Problem 193
Elimination of bromine from 2-bromobutane results in the formation of (a) equimolar mixture of 1 and 2 -butene (b) predominantly 2 -butene (c) predominantly 1-butene (d) predominantly 2-butyne
5 step solution
Problem 194
Reaction of one molecule of HBr with one molecule of 1,3 -butadiene at \(40^{\circ} \mathrm{C}\) gives predominantly [2005] (a) 3-bromobutene under kinetically controlled conditions (b) 1-bromo-2-butene under thermodynamically controlled conditions(c) 3-bromobutene under thermodynamically controlled conditions (d) 1-bromo-2-butene under kinetically controlled conditions.
4 step solution
Problem 195
HBr reacts with \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OCH}_{3}\) under anhydrous conditions at room temperature to give (a) \(\mathrm{CH}_{3} \mathrm{CHO}\) and \(\mathrm{CH}_{3} \mathrm{Br}\) (b) \(\mathrm{BrCH}_{2} \mathrm{CHO}\) and \(\mathrm{CH}_{3} \mathrm{OH}\) (c) \(\mathrm{BrCH}_{2}-\mathrm{CH}_{2}-\mathrm{OCH}_{3}\) (d) \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CHBr}-\mathrm{OCH}_{3}\)
5 step solution
Problem 196
The structure of the compound that gives a tribromo derivative on treatment
with bromine water is [2006]\\}
(a)
4 step solution
Problem 198
The compound formed as a result of oxidation of ethyl benzene by \(\mathrm{KMnO}_{4}\) is: [2007] (a) acetophenone (b) benzoic acid (c) benzyl alcohol (d) benzophenone
4 step solution
Problem 200
The treatment of \(\mathrm{CH}_{3} \mathrm{MgX}\) with \(\mathrm{CH}_{3}
\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\) pro-
duces
(a) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\)
(b) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}\)
(c)
4 step solution
Problem 202
In the following sequence of reactions, the alkene affords the compound 'B' \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3} \stackrel{\mathrm{O}_{3}}{\longrightarrow}(\mathrm{A}) \stackrel{\mathrm{H}_{2} \mathrm{O}}{\longrightarrow}\) (B) \(\mathrm{Zn}\) The compound (B) is [2008] (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHO}\) (b) \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{3}\) (d) \(\mathrm{CH}_{3} \mathrm{CHO}\)
6 step solution
Problem 205
The alkene that exhibits geometrical isomerism is: [2009] (a) 2-methyl propene (b) 2 -butene (c) 2-methyl-2-butene (d) propene
6 step solution
Problem 206
vOne mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molcular mass of \(44 \mathrm{u}\). The alkene is (a) Propene (b) 1 -butene (c) 2 -butene (d) ethane
5 step solution
Problem 207
The main product of the following reaction is
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{OH})
\mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2} \stackrel{\text { conc. }
\mathrm{H}_{2} \mathrm{SO}_{4}}{\longrightarrow}\) ?
(a)
5 step solution
Problem 208
Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of (a) a vinyl group (b) an isopropyl group (c) an acetylenic triple bond (d) two ethylenic double bonds
4 step solution
Problem 209
2-Hexyne gives trans \(-2\) - Hexene on treatment with [2012] (a) \(\mathrm{Pd} / \mathrm{BaSO}_{4}\) (b) \(\mathrm{Li} / \mathrm{NH}_{3}\) (c) \(\mathrm{Pt} / \mathrm{H}_{2}\) (d) \(\mathrm{LiAlH}_{4}\)
3 step solution
Problem 210
Which branched chain isomer of the hydrocarbon with molecular mass \(72 \mathrm{u}\) gives only one isomer of mono substituted alkyl halide? [2012] (a) Isohexane (b) Neopentane (c) Tertiary butyl chloride
5 step solution
Problem 211
A gaseous hydrocarbon given upon combustion \(0.72 \mathrm{~g}\) of water and \(3.08 \mathrm{~g}\) of \(\mathrm{CO}_{2}\). The empirical formula of the hydrocarbon is (a) \(\mathrm{C}_{6} \mathrm{H}_{5}\) (b) \(\mathrm{C}_{7} \mathrm{H}_{8}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{4}\) (d) \(\mathrm{C}_{3} \mathrm{H}_{4}\)
6 step solution