Chapter 27

43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Chemistry · 54 exercises

Problem 1

Aniline dissolved in dilute \(\mathrm{HCl}\) is reacted with sodium nitrate at \(0{ }^{\circ} \mathrm{C}\). This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:

4 step solution

Problem 2

A compound ' \(\mathrm{X}^{\prime}\) on treatment with \(\mathrm{Br}_{2} / \mathrm{NaOH}\), provided \(\mathrm{C}_{3} \mathrm{H}_{9} \mathrm{~N}\), which gives positive carbylamine test. Compound ' \(X\) ' is :

4 step solution

Problem 3

The most appropriate reagent for conversion of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{CN}\) into \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) is :(a) \(\mathrm{NaBH}_{4}\) (b) \(\mathrm{CaH}_{2}\)(c) \(\mathrm{LiAlH}_{4}\) (d) \(\mathrm{Na}(\mathrm{CN}) \mathrm{BH}_{3}\)

4 step solution

Problem 3

Conversion of benzene diazonium chloride to chlorobenzene is an example of which of the following reactions?(a) Claisen (b) Friedel-craft (c) Sandmeyer (d) Wurtz

4 step solution

Problem 4

Complete reduction of benzene-diazonium chloride with \(\mathrm{Zn} / \mathrm{HCl}\) gives:Complete reduction of benzene-diazonium chloride with \(\mathrm{Zn} / \mathrm{HCl}\) gives:

4 step solution

Problem 5

Fluorination of an aromatic ring is easily accomplished by treating a diazonium salt with \(\mathrm{HBF}_{4}\). Which of the following conditions is correct about this reaction?(a) \(\mathrm{NaF} / \mathrm{Cu}\) (b) \(\mathrm{Cu}_{2} \mathrm{O} / \mathrm{H}_{2} \mathrm{O}\) (c) Only heat (d) \(\mathrm{NaNO}_{2} / \mathrm{Cu}\)

4 step solution

Problem 7

In the following reaction,$$ \mathrm{CH}_{3} \mathrm{NH}_{2}+\mathrm{CHCl}_{3}+\mathrm{KOH} $$ \(\rightarrow\) Nitrogen containing compound \(+\mathrm{KCl}+\mathrm{H}_{2} \mathrm{O} .\) The nitrogen containing compound is (a) \(\mathrm{CH}_{3}-\mathrm{NH}-\mathrm{CH}_{3}\)(b) \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{N}\) (c) \(\mathrm{CH}_{3}-\mathrm{N} \equiv \overline{\mathrm{C}}^{+}\) (d) \(\mathrm{CH}_{3}-\overline{\mathrm{N}} \equiv \mathrm{C}^{-}+\mathrm{C}\)

3 step solution

Problem 8

When benzenesulfonic acid and \(p\)-nitrophenol are treated with \(\mathrm{NaHCO}_{3}\), the gases released respectively are(a) \(\mathrm{SO}_{2}, \mathrm{NO}\) (b) \(\mathrm{SO}_{2}, \mathrm{NO}_{2}\) (c) \(\mathrm{CO}_{2}, \mathrm{CO}_{2}\) (d) \(\mathrm{SO}_{2}, \mathrm{CO}_{2}\)

3 step solution

Problem 9

Benzamide on reaction with \(\mathrm{POCl}_{3}\) gives(a) aniline (b) chlorobenzene (c) benzylamine (d) benzonitrile

4 step solution

Problem 11

Benzenediazonium chloride on reaction with phenol in weakly basic medium gives(a) diphenyl ether(b) \(p\)-hydroxyazobenzene (c) chlorobenzene (d) benzene

5 step solution

Problem 12

Butanenitrile may be prepared by heating :(a) Propyl alcohol with \(\mathrm{KCN}\) (b) Butyl alcohol with \(\mathrm{KCN}\) (c) Butyl chloride with \(\mathrm{KCN}\)(d) Propyl chloride with \(\mathrm{KCN}\)

4 step solution

Problem 12

Hinsberg's reagent is:(a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}\) (b) \(\mathrm{SOCl}_{2}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\) (d) \((\mathrm{COCl})_{2}\)

3 step solution

Problem 13

The formation of cyanohydrin from a ketone is an example of :(a) Electrophilic addition (b) Nucleophilic addition (c) Nucleophilic substitution (d) Electrophilic substiution

4 step solution

Problem 13

Which of the following amines can be prepared by Gabriel phthalimide reaction? \(\quad[\) Main April 8, 2019 (I)](a) \(n\)-butylamine (b) triethylamine (c) \(t\)-butylamine (d) neo-pentylamine

3 step solution

Problem 14

The compound that is most reactive towards electrophilic nitration is(a) toluene (b) benzene (c) benzoic acid (d) nitrobenzene

4 step solution

Problem 14

How would you synthesise 4-methoxyphenol from bromobenzene in NOT more than five steps? State clearly the reagents used in each step and show the structures of the intermediate compounds in your synthetic scheme.

5 step solution

Problem 15

Amongst the three isomers of nitrophenol, the one that is least soluble in water is ...............

4 step solution

Problem 16

When nitrobenzene is treated with \(\mathrm{Br}_{2}\) in presence of \(\mathrm{FeBr}_{3}\), the major product formed is \(m\)-bromonitrobenzene. Statements which are related to obtain the \(m\)-isomer are(a) The electron density on meta carbon is more than that on ortho and para positions (b) The intermediate carbonium ion formed after initial attack of \(\mathrm{Br}^{+}\)at the meta position is least destabilised (c) Loss of aromaticity when \(\mathrm{Br}^{+}\)attacks at the ortho and para positions and not at meta position (d) Easier loss of \(\mathrm{H}^{+}\)to regain aromaticity from the meta position than from ortho and para positions.

5 step solution

Problem 17

The products of reaction of alcoholic silver nitrite with ethyl bromide are(a) ethane (b) ethene (c) nitroethane (d) ethyl alcohol (e) ethyl nitrite

5 step solution

Problem 18

Match each of the compounds in Column I with its characteristic reaction(s) in Column II.Column I Column II (A) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CN}\) (p) Reduction with \(\mathrm{Pd}-\mathrm{C} / \mathrm{H}_{2}\) (B) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCOCH}_{3}\) (q) Reduction with \(\mathrm{SnCl}_{2} / \mathrm{HCl}\) (C) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OH}\) (r) Development of foul smell on treatment with chloroform and alcoholic KOH (D) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (s) Reduction with diisobutylaluminium hydride(DIBAL-H) (t) Alkaline hydrolysis

5 step solution

Problem 20

Statement - 1: \(p\)-Nitrophenol is a stronger acid thano-nitrophenol. Statement - 2 : Intramolecular hydrogen bonding makes the o-isomer weaker than the \(p\)-isomer.

5 step solution

Problem 20

In the Hofmann bromamide degradation reaction, the number of moles of \(\mathrm{NaOH}\) and \(\mathrm{Br}_{2}\) used per mole of amine produced are :(a) Two moles of \(\mathrm{NaOH}\) and two moles of \(\mathrm{Br}_{2}\). (b) Four moles of \(\mathrm{NaOH}\) and one mole of \(\mathrm{Br}_{2}\). (c) One mole of \(\mathrm{NaOH}\) and one mole of \(\mathrm{Br}_{2}\). (d) Four moles of \(\mathrm{NaOH}\) and two moles of \(\mathrm{Br}_{2}\).

4 step solution

Problem 21

The test to distinguish primary, secondary and tertiary amines is :(a) Sandmeyer's reaction (b) Carbylamine reaction (c) Mustard oil test (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{2} \mathrm{Cl}\)

6 step solution

Problem 24

On heating an aliphatic primary amine with chloroform and ethanolic potassium hydroxide, the organic compound formed is:(a) an alkanol (b) an alkanediol (c) an alkyl cyanide (d) an alkyl isocyanide

4 step solution

Problem 25

The final product formed when methyl amine is treated with \(\mathrm{NaNO}_{2}\) and \(\mathrm{HCl}\) is:(a) Diazomethane (b) Methylalcohol (c) Methylcyanide (d) Nitromethane

4 step solution

Problem 26

Show with equations how the following compounds are prepared (equations need not be balanced):(i) 4 -nitrobenzaldehyde from benzene. (ii) \(p\)-bromonitrobenzene from benzene in two steps. (iii) toluene to \(m\)-nitrobenzoic acid?

5 step solution

Problem 26

A compound with molecular mass 180 is acylated with \(\mathrm{CH}_{3} \mathrm{COCl}\) to get a compound with molecular mass 390 . The number of amino groups present per molecule of the former compound is :(a) 2 (b) 5 (c) 4 (d) 6

5 step solution

Problem 27

The order of basicity of amines in gaseous state is :(a) \(1^{\circ}>2^{\circ}>3^{\circ}>\mathrm{NH}_{3}\) (b) \(3^{\circ}>2^{\circ}>\mathrm{NH}_{3}>1^{\circ}\) (c) \(3^{\circ}>2^{\circ}>1^{\circ}>\mathrm{NH}_{3}\) (d) \(\mathrm{NH}_{2}>1^{\circ}>2^{\circ}>3^{\circ}\)

4 step solution

Problem 32

\(\frac{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}}{\mathrm{DMF}, \Delta}(\mathrm{A}) \frac{\text { i) } \mathrm{NaNO}_{2} / \mathrm{HCl}}{0^{\circ}-5^{\circ} \mathrm{C}}{\longrightarrow}(\mathrm{B}) .\) (B) is: ii) \(\mathrm{H}_{2} / \mathrm{Ni}\)

5 step solution

Problem 35

Among the following, the strongest base is(a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (b) \(p-\mathrm{NO}_{2} \cdot \mathrm{C}_{6} \mathrm{H}_{4} \mathrm{NH}_{2}\) (c) \(m-\mathrm{NO}_{2} \cdot \mathrm{C}_{6} \mathrm{H}_{4} \cdot \mathrm{NH}_{2}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{NH}_{2}\)

4 step solution

Problem 36

In the reaction \(p\)-chlorotoluene with \(\mathrm{KNH}_{2}\) in liq. \(\mathrm{NH}_{3}\),the major product is:(a) \(o\)-toluidine (b) \(m\)-toluidine (c) \(p\)-toluidine (d) \(p\)-chloroaniline.

4 step solution

Problem 37

Amongst the following, the most basic compound is :(a) Benzylamine (b) Aniline (c) Acetanilide (d) \(p\)-Nitroaniline

6 step solution

Problem 38

Carbylamine test is performed in alcoholic \(\mathrm{KOH}\) by heating a mixture of :(a) chloroform and silver powder (b) trihalogenatedmethane and a primary amine (c) an alkyl halide and a primary amine (d) an alkyl cyanide and a primary amine

4 step solution

Problem 39

Acetamide is treated separately with the following reagents. Which one of these would give methylamine?(a) \(\mathrm{PCl}_{5}\) (b) \(\mathrm{NaOH}+\mathrm{Br}_{2}\) (c) soda lime(d) hot conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\)

4 step solution

Problem 40

The compound which on reaction with aqueous nitrous acid at low temperature produces an oily nitrosoamine is(a) methylamine (b) ethylamine (c) diethylamine (d) triethylamine

4 step solution

Problem 42

Consider the reaction sequence from \(\mathbf{P}\) to \(\mathbf{Q}\) shown below. The overall yield of the major product \(\mathbf{Q}\) from \(\mathbf{P}\) is \(75 \%\). What is the amount in grams of \(\mathbf{Q}\) obtained from \(9.3 \mathrm{~mL}\) of \(\mathbf{P} ?\) (Use density of \(\mathbf{P}=1.00 \mathrm{~g}\) \(\mathrm{mL}^{-1} ;\) Molar mass of \(\mathrm{C}=12.0, \mathrm{H}=1.0, \mathrm{O}=16.0\) and \(\mathrm{N}=14.0 \mathrm{~g} \mathrm{~mol}^{-}\) ')

4 step solution

Problem 45

In an acidic medium, ................. behaves as the strongest base. (nitrobenzene, aniline, phenol)

5 step solution

Problem 49

Hydrogen bonding plays a central role in the following phenomena(a) Ice floats in water (b) Higher Lewis basicity of primary amines than tertiary amines in aqueous solutions (c) Formic acid is more acidic than acetic acid (d) Dimerisation of acetic acid in benzene

4 step solution

Problem 51

A positive carbylamine test is given by(a) \(\mathrm{N}, \mathrm{N}-\) dimethylaniline (b) 2,4 -dimethylaniline (c) N-methyl-o-methylaniline (d) \(p\)-methylbenzylamine

5 step solution

Problem 52

Among the following compounds, which will react with acetone to give a product containing \(>\mathrm{C}=\mathrm{N}\)-bond ?(a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHC}_{6} \mathrm{H}_{5}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHNH}_{2}\).

5 step solution

Problem 53

\(p\)-Chloroaniline and anilinium hydrochloride can be distinguished by(a) Sandmeyer reaction (b) \(\mathrm{NaHCO}_{3}\) (c) \(\mathrm{AgNO}_{3}\) (d) Carbylamine test

3 step solution

Problem 62

Statement-1 : In strongly acidic solutions, aniline becomes more reactive towards electrophilic reagents. Statement-2 : The amino group being completely protonated in strongly acidic solution, the lone pair of electrons on the nitrogen isno longer available for resonance. [2001S] (a) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. (b) Statement- 1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement-1 is False, Statement-2 is True

5 step solution

Problem 64

There is a solution of \(p\)-hydroxybenzoic acid and \(p\)-aminobenzoic acid. Discuss one method by which we can separate them and also write down the confirmatory tests of the functional groups present.

4 step solution

Problem 66

Compound \(A\left(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}\right)\) on treatment with \(\mathrm{NH}_{2} \mathrm{OH} . \mathrm{HCl}\) gives \(B\) and \(C\). \(B\) and \(C\) rearrange to give \(D\) and \(E\), respectively, on treatment with acid \(B, C, D\) and \(E\) are all isomers of molecular formula \(\left(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}\right)\). When \(D\) is boiled with alcoholic \(\mathrm{KOH}\) an oil \(\mathrm{F}\left(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{~N}\right)\) separates out. \(\mathrm{F}\) reacts rapidly with \(\mathrm{CH}_{3} \mathrm{COCI}\) to give back \(D .\) On the other hand, \(E\)on boiling with alkali followed by acidification gives a white solid \(G\) \(\left(\mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}_{2}\right)\). Identify \(A\)-G. \(\quad\) [1999 - 7 Marks]

6 step solution

Problem 67

Complete the following with appropriate structures:(i) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2} \stackrel{\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}, \text { heat }}{\longrightarrow} 2\) products (ii) \(\mathrm{CH}_{3} \mathrm{CONHC}_{6} \mathrm{H}_{5} \stackrel{\mathrm{Br}_{2}, \mathrm{Fe}}{\longrightarrow} 2\) products (iii) \(\triangle \mathrm{NH}_{2}+\langle 0\rangle-\mathrm{COCl}\) base \(?\) Nc1ccccc1N

7 step solution

Problem 68

Give reasons for the following : (i) Dimethylamine is a stronger base than trimethylamine [19 (ii) Cyclohexylamine is a stronger base than aniline.

7 step solution

Problem 69

Acetophenone on reaction with hydroxylamine hydrochloride can produce two isomeric oximes. Write structures of the oximes.

6 step solution

Problem 70

Write the structure of the foul-smelling compound obtained when aniline is treated with chloroform in the presence of \(\mathrm{KOH}\).

4 step solution

Problem 72

A basic, volatile nitrogen compound gave a foul smelling gas when treated with chloroform and alcoholic potash. A \(0.295 \mathrm{~g}\) sample of the substance. dissolved in aq. HCl and treated with \(\mathrm{NaNO}_{2}\) solution at \(0^{\circ} \mathrm{C}\), liberated a colorless, odourless gas whose volume corresponded to \(112 \mathrm{~mL}\) at STP. After the evolution of the gas was complete, the aqueous solution was distilled to give an organic liquid which did not contain nitrogen and which on warming with alkali and iodine gave a yellow precipitate. Identify the original substance. Assume that it contains one \(\mathrm{N}\) atom per molecule.

5 step solution

Problem 73

A mixture of two aromatic compounds \(A\) and \(B\) was separated by dissolving a chloroform followed by extraction with aqueous \(\mathrm{KOH}\) solution. The organic layer containing compound \(A\), when heated with alcoholic solution of \(\mathrm{KOH}\) produced a compound \(\mathrm{C}\left(\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{~N}\right)\) associated with an unpleasant odour. The alkaline aqueous layer on the other hand, when heated with chloroform and then acidified gave a mixture of two isomeric compounds \(D\) and \(E\) of molecular formula \(\mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}_{2}\). Identify the compounds \(A, B, C, D, E\) and write their structures.

5 step solution

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