Chapter 26

43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Chemistry · 70 exercises

Problem 3

An organic compound (A) (molecular formula \(\left.\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}\right)\) was hydrolysed with dil. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to give a carboxylic acid (B) and an alochol (C). 'C' gives white turbidity immediately when treated with anhydrous \(\mathrm{ZnCl}_{2}\) and conc. HCl. The organic compound (A) is :

5 step solution

Problem 4

The increasing order of the reactivity of the following compounds in nucleophilic addition reaction is: Propanal, Benzaldehyde, Propanone, Butanone [Main Sep. 03, 2020 (II)] (a) Benzaldehyde \(<\) Butanone \(<\) Propanone \(<\) Propanal (b) Butanone \(<\) Propanone \(<\) Benzaldehyde \(<\) Propanal (c) Propanal \(<\) Propanone \(<\) Butanone \(<\) Benzaldehyde (d) Benzaldehyde \(<\) Propanal \(<\) Propanone \(<\) Butanone

5 step solution

Problem 5

An organic compound [A], molecular formula \(\mathrm{C}_{10} \mathrm{H}_{20} \mathrm{O}_{2}\) was hydrolyzed with dilute sulphuric acid to give a carboxylic acid [B] and an alcohol \([\mathrm{C}]\). Oxidation of \([\mathrm{C}]\) with \(\mathrm{CrO}_{3}-\mathrm{H}_{2} \mathrm{SO}_{4}\) produced \([\mathrm{B}]\). Which of the following structures are not possible for [A]?

4 step solution

Problem 9

An unsaturated hydrocarbon \(X\) absorbs two hydrogen molecules on catalytic hydrogenation, and also gives following reaction: \(X \frac{\mathrm{O}_{3}}{\mathrm{Zn} / \mathrm{H}_{2} \mathrm{O}} \mathrm{A} \stackrel{\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}}{\longrightarrow}\) B(3-oxo-hexanedicarboxylic acid) \(\mathrm{X}\) will be :

5 step solution

Problem 10

What is the product of following reaction? Hex-3-ynal \(\frac{\text { (i) } \mathrm{NaBH}_{4}}{\text { (ii) } \mathrm{PBr}_{3} \text {, (iii) } \mathrm{Mg} / \text { ether, (iv) } \mathrm{CO}_{2} / \mathrm{H}_{3} \mathrm{O}^{\prime}} ? ?\)

4 step solution

Problem 14

In the following reaction [Main April 9, 2019 (II)] Carbonyl compound \(+\mathrm{MeOH} \stackrel{\mathrm{HCl}}{\rightleftharpoons}\) acetal Rate of the reaction is the highest for: (a) Acetone as substrate and methanol in excess. (b) Propanal as substrate and methanol in stoichiometric amount. (c) Propanal as substrate and methanol in excess. (d) Acetone as substrate and methanol in stoichiometric amount.

5 step solution

Problem 16

The correct decreasing order for acid strength is: (a) \(\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{FCH}_{2} \mathrm{COOH}>\) \(\mathrm{CNCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}\) (b) \(\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{CNCH}_{2} \mathrm{COOH}>\) \(\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}\) (c) \(\mathrm{CNCH}_{2} \mathrm{COOH}>\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\) \(\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}\) (d) \(\mathrm{NO}_{2} \mathrm{CH}_{2} \mathrm{COOH}>\mathrm{CNCH}_{2} \mathrm{COOH}>\) \(\mathrm{FCH}_{2} \mathrm{COOH}>\mathrm{ClCH}_{2} \mathrm{COOH}\)

4 step solution

Problem 20

The correct statement about the synthesis of erythritol \(\left(\mathrm{C}\left(\mathrm{CH}_{2} \mathrm{OH}\right)_{4}\right)\) used in the preparation of PETN is : [Main Online April 10, 2016] (a) Thy synthesis requires three aldol condensations and one Cannizzaro reaction. (b) Alpha hydrogens of ethanol and methanol are involved in this reaction. (c) The synthesis requires two aldol condensations and two Cannizzaro reactions. (d) The synthesis requires four aldol condensations between methanol and ethanol.

7 step solution

Problem 20

Sodium salt of an organic acid ' \(X\) ' produces effervescences with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\). \(' \mathrm{X}^{\prime}\) reacts with the acidified aqueous \(\mathrm{CaCl}_{2}\) solution to give a white precipitate which decolourises acidic solution of \(\mathrm{KMnO}_{4} .{ }^{\prime} \mathrm{X}^{\prime}\) is : (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COONa}\) (b) \(\mathrm{HCOONa}\) (c) \(\mathrm{CH}_{3} \mathrm{COONa}\) (d) \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\)

4 step solution

Problem 22

Bouveault-Blanc reduction reaction involves: (a) Reduction of an acyl halide with \(\mathrm{H}_{2} / \mathrm{Pd}\) (b) Reduction of an anhydride with \(\mathrm{LiAlH}_{4}\) (c) Reduction of an ester with \(\mathrm{Na} / \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (d) Reduction of a carbonyl compound with \(\mathrm{Na} / \mathrm{Hg}\) and \(\mathrm{HCl}\).

3 step solution

Problem 24

Which one of the following reactions will not result in the formation of carbon-carbon bond? [Main Online April 9, 2014] (a) Reimer-Tieman reaction (b) Friedel Craft's acylation (c) Wurtz reaction (d) Cannizzaro reaction

4 step solution

Problem 24

In the presence of a small amount of phosphorous, aliphatic carboxylic acids react with chlorine or bromine to yield a compound in which \(\alpha\)-hydrogen has been replaced by halogen. This reaction is known as : (a) Wolff - Kishner reaction (b) Rosenmund reaction (c) Etard reaction (d) Hell - Volhard - Zelinsky reaction

3 step solution

Problem 25

Tischenko reaction is a modification of: (a) Aldol condensation (b) Claisen condensation (c) Cannizzaro reaction (d) Pinacol-pinacolon reaction

4 step solution

Problem 26

An organic compound A upon reacting with \(\mathrm{NH}_{3}\) gives B. On heating B gives C. C in presence of \(\mathrm{KOH}\) reacts with \(\mathrm{Br}_{2}\) to give \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\). A is : (a) \(\mathrm{CH}_{3} \mathrm{COOH}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\)

5 step solution

Problem 27

Formaldehyde can be distinguished from acetaldehyde by the use of : (a) Schiff's reagent (b) Tollen's reagent (c) \(\mathrm{I}_{2} / \mathrm{Alkal}\) (d) Fehling's solution

6 step solution

Problem 27

Monocarboxylic acids are functional isomers of: (a) Ethers (b) Amines (c) Esters (d) Alcohols

6 step solution

Problem 28

Clemmensen reduction of a ketone is carried out in the presence of : (a) \(\mathrm{LiAlH}_{4}\) (b) \(\mathrm{Zn}-\mathrm{Hg}\) with \(\mathrm{HCl}\) (c) Glycol with \(\mathrm{KOH}\) (d) \(\mathrm{H}_{2}\) with Pt as catalyst

6 step solution

Problem 28

The compound that does NOT liberate \(\mathrm{CO}_{2}\), on treatment with aqueous sodium bicarbonate solution, is (a) Benzoic acid (b) Benzenesulphonic acid (c) Salicylic acid (d) Carbolic acid (Phenol)

4 step solution

Problem 30

The carboxyl functional group (- COOH) is present in (a) picric acid (b) barbituric acid (c) ascorbic acid (d) aspirin

6 step solution

Problem 32

How will you convert butan-2-one to propanoic acid? (a) Tollen's reagent (b) Fehling's solution (c) \(\mathrm{NaOH} / \mathrm{I}_{2} / \mathrm{H}^{+}\) (d) \(\mathrm{NaOH} / \mathrm{NaI} / \mathrm{H}^{+}\)

4 step solution

Problem 36

36\. A mixture of benzaldehyde and formaldehyde on heating with aqueous \(\mathrm{NaOH}\) solution gives (a) benzyl alcohol and sodium formate (b) sodium benzoate and methyl alcohol (c) sodium benzoate and sodium formate (d) benzyl alcohol and methyl alcohol

4 step solution

Problem 39

Benzoyl chloride is prepared from benzoic acid by (a) \(\mathrm{Cl}_{2}, h v\) (b) \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) (c) \(\mathrm{SOCl}_{2}\) (d) \(\mathrm{Cl}_{2}, \mathrm{H}_{2} \mathrm{O}\)

4 step solution

Problem 40

In the Cannizzaro reaction given below, $$ 2 \mathrm{PhCHO} \stackrel{\mathrm{OH}^{-}}{\longrightarrow} \mathrm{PhCH}_{2} \mathrm{OH}+\mathrm{PhCO}_{2}^{-}, $$ the slowest step is (a) the attack of \(-\mathrm{OH}\) at the carbonyl group, (b) the transfer of hydride to the carbonyl group, (c) the abstraction of proton from the carboxylic acid, (d) the deprotonation of \(\mathrm{PhCH}_{2} \mathrm{OH}\).

4 step solution

Problem 40

When propionic acid is treated with aqueous sodium bicarbonate, \(\mathrm{CO}_{2}\) is liberated. The ' \(\mathrm{C}\) ' of \(\mathrm{CO}_{2}\) comes from (a) methyl group (b) carboxylic acid group (c) methylene group (d) bicarbonate

4 step solution

Problem 41

\(m\)-Chlorobenzaldehyde on reaction with conc. \(\mathrm{KOH}\) at room temperature gives (a) potassium \(m\)-chlorobenzoate and \(m\)-hydroxybenzaldehyde (b) \(m\)-hydroxybenzaldehyde and \(m\)-chlorobenzyl alcohol (c) \(m\)-chlorobenzyl alcohol and \(m\)-hydroxybenzyl alcohol (d) potassium \(m\)-chlorobenzoate and \(m\)-chlorobenzyl alcohol.

4 step solution

Problem 42

The enolic form of acetone contains (a) 9 sigma bonds, 1 pi-bond and 2 lone pairs (b) 8 sigma bonds, 2 pi-bonds and 2 lone pairs (c) 10 sigma bonds, 1 pi-bond and 1 lone pair (d) 9 sigma bonds, 2 pi-bonds and 1 lone pair

6 step solution

Problem 44

The compound that will not give iodoform on treatment with alkali and iodine is : (a) acetone (b) ethanol (c) diethyl ketone (d) isopropyl alcohol

3 step solution

Problem 45

Formic acid when heated with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) produces

4 step solution

Problem 46

When acetaldehyde is heated with Fehling's solution it gives a precipitate of (a) \(\mathrm{Cu}\) (b) \(\mathrm{CuO}\) (c) \(\mathrm{Cu}_{2} \mathrm{O}\) (d) \(\mathrm{Cu}+\mathrm{Cu}_{2} \mathrm{O}+\mathrm{CuO}\)

3 step solution

Problem 46

The boiling point of propionic acid is less than that of \(n\)-butyl alcohol, an alcohol of comparable molecular weight.

4 step solution

Problem 47

A compound that gives a positive iodoform test is (a) 1-pentanol (b) 2 -pentanone (c) 3-pentanone (d) pentanal

6 step solution

Problem 48

The reagent with which both acetaldehyde and acetone react easily is [1981 - 1 Mark] (a) Fehling's reagent (b) Grignard reagent (c) Schiff's reagent (d) Tollen's reagent

4 step solution

Problem 52

Consider the following reactions \(\mathrm{A} \frac{(\mathrm{i}) \mathrm{CH}_{3} \mathrm{MgBr}}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}} \mathrm{B} \frac{\mathrm{Cu}}{573 \mathrm{~K}} \longrightarrow 2\)-methyl-2-butene The mass percentage of carbon in \(\mathrm{A}\) is

4 step solution

Problem 53

The structure of the enol form of \(\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{CH}_{2}-\mathrm{CO}-\mathrm{CH}_{3}\) with intramolecular hydrogen bonding is ......

4 step solution

Problem 54

Which of the following compounds will react with ethanolic \(\mathrm{KCN} ?\) (a) ethyl chloride (b) acetyl chloride (c) chlorobenzene (d) benzaldehyde

6 step solution

Problem 55

Which of the following compounds will give a yellow precipitate with iodine and alkali? (a) 2-Hydroxypropane (b) acetophenone (c) methyl acetate (d) acetamide

4 step solution

Problem 56

Each item from (i) to (x) given below indicates a reaction type, a process or a homologue. Match each of these items with the related phrase by writing the correct phrase in the corresponding vacant space given under each. The correct phrase must be picked only from those given below within brackets: (Bayer's process, Nucleophilic addition, Free radical substitution, Ostwald's process, Homologous pair, Cyanamide process, Electrophilic substitution, Homolytic addition, Thermite process, Nucleophilic substitution)

5 step solution

Problem 58

The yield of ketone when a secondary alcohol is oxidized is more than the yield of aldehyde when a primary alcohol is oxidized.

4 step solution

Problem 61

Compounds \(P\) and \(R\) upon ozonolysis produce \(Q\) and \(S\), respectively. The molecular formula of \(Q\) and \(S\) is \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O} . Q\) undergoes Cannizzaro reaction but not haloform reaction, whereas \(S\) undergoes haloform reaction but not Cannizzaro reaction

5 step solution

Problem 67

The smallest ketone and its next homologue are reacted with \(\mathrm{NH}_{2} \mathrm{OH}\) to form oxime $$ $$ (a) Two different oximes are formed (b) Three different oximes are formed (c) Two oximes formed are optically active (d) All oximes formed are optically active

5 step solution

Problem 69

Which of the following will undergo aldol condensation? (a) acetaldehyde (b) propanaldehyde (c) benzaldehyde (d) trideuteroacetaldehyde

3 step solution

Problem 70

Which of the following will react with water? (a) \(\mathrm{CHCl}_{3}\) (b) \(\mathrm{Cl}_{3} \mathrm{CCHO}\) (c) \(\mathrm{CCl}_{4}\) (d) \(\mathrm{CICH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\)

4 step solution

Problem 71

A new carbon-carbon bond formation is possible in (a) Cannizzaro reaction (b) Friedel-Craft alkylation (c) Clemmensen reduction (d) Reimer-Tiemann reaction

3 step solution

Problem 74

Base catalysed aldol condensation occurs with : (a) propionaldehyde (b) benzaldehyde (c) 2 -methylpropionaldehyde (d) 2,2 -dimethylpropionaldehyde

3 step solution

Problem 75

Statement-1 : Acetic acid does not undergo haloform reaction. Statement-2 : Acetic acid has no alpha hydrogens.

4 step solution

Problem 79

79\. Identify \((\mathrm{X}),(\mathrm{Y})\) and \((\mathrm{Z})\) in the following synthetic scheme and write their structures. \(\mathrm{Ba}^{*} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow(\mathrm{X})\) gas \(\left[\mathrm{C}^{*}\right.\) denotes \(\left.\mathrm{C}^{14}\right]\) $$ \begin{aligned} &\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{Br} \frac{\text { (i) } \mathrm{Mg} / \text { ether }}{\text { (ii) } \mathrm{X} \text { (iii) } \mathrm{H}_{3} \mathrm{O}^{\prime}}(\mathrm{Y}) \stackrel{\mathrm{LiAlH}_{4}}{\longrightarrow}(\mathrm{Z}) \\ &\text { [2001-5 Marks] } \end{aligned} $$ Explain the formation of labelled formaldehyde \(\left(\mathrm{H}_{2} \mathrm{C}^{*} \mathrm{O}\right)\) as one of the products when compound (Z) is treated with HBr and subsequently ozonolysed. Mark the \(C^{*}\) carbon in the entire scheme.

4 step solution

Problem 80

An organic compound A, \(\mathrm{C}_{8} \mathrm{H}_{4} \mathrm{O}_{3}\), in dry benzene in the presence of anhydrous \(\mathrm{AlCl}_{3}\) gives compound \(\mathbf{B}\). The compound \(\mathbf{B}\) on treatment with \(\mathrm{PCl}_{5}\), followed by reaction with \(\mathrm{H}_{2} / \mathrm{Pd}\left(\mathrm{BaSO}_{4}\right)\) gives compound \(\mathbf{C}\), which on reaction with hydrazine gives a cyclic compound \(\mathbf{D}\left(\mathrm{C}_{14} \mathrm{H}_{10} \mathrm{~N}_{2}\right)\). Identify A, B, C and D. Explain the formation of \(\mathbf{D}\) from \(\mathbf{C}\).

5 step solution

Problem 83

An ester \(A\left(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{2}\right)\), on treatment with excess methyl magnesium chloride followed by acidification, gives an alcohol \(B\) as the sole organic product. Alcohol \(B\), on oxidation with \(\mathrm{NaOCl}\) followed by acidification, gives acetic acid. Deduce the structures of \(A\) and \(B\). Show the reactions involved.

6 step solution

Problem 84

Give reasons for the following : (i) Although phenoxide ion has more number of resonating structures than benzoate ion, benzoic acid is a stronger acid than phenol. Why? (ii) Formic acid is a stronger acid than acetic acid; (iii) Acetic acid can be halogenated in the presence of red \(\mathrm{P}\) and \(\mathrm{Cl}_{2}\) but formic acid cannot be halogenated in the same way.

3 step solution

Problem 86

An organic compound \(A, \mathrm{C}_{8} \mathrm{H}_{6}\), on treatment with dilute sulphuric acid containing mercuric sulphate gives a compound \(B\), which can also be obtained from a reaction of benzene with an acid chloride in the presence of anhydrous aluminium chloride. The compound \(B\), when treated with iodine in aqueous \(\mathrm{KOH}\), yields \(C\) and a yellow compound \(D .\) Identify \(A, B, C\) and \(D\) with justification. Show how \(B\) is formed from \(A\).

6 step solution

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