Conservation Biology and Global Change

Campbell Biology · 54 exercises

Q11TYU

Question: Phosphofructokinase is an enzyme that acts on fructose-6-phosphate at an early step in glucose breakdown. Regulation of this enzyme controls whether the sugar will continue on in the glycolytic pathway. Considering this graph, under which condition is phosphofructokinase more active? Given what you know about glycolysis and regulation of metabolism by this enzyme, explain the mechanism by which phosphofructokinase activity differs depending on ATP concentration. Explain why it makes sense that regulation of this enzyme has evolved so that its works this way.


4 step solution

Q27.5-1CC

Explain how prokaryotes, though small, can be considered giants in their collective impact on Earth and its life.

3 step solution

Q27.6-3ITD

The variation found in a set can be estimated by the standard deviation, s:

\({s_x}\, = \sqrt {\frac{1}{{n - 1}}} \sum {({x_i}}   - \,\overline x {)^2}\)

 

Calculate the standard deviation for each treatment.

Treatment

Dose (mg/kg)

Log of number of colonies

Mean (\(\overline x \,\))

\({x_i}\, - \,\overline x \)

Control

-

9.0,9.5,9.0,8.9

9.1

(-0.1), 0.4, (-0.1), (-0.2)

Vancomycin

1.0

8.5,8.4,8.2

8.36

0.14, 0.04, (-0.16)

 

5.0

5.3,5.9,4.7

5.3

0, 0.6, (-0.6)

Teixobactin

1.0

8.5,6.0,8.4,6.0

7.22

1.28, (-1.22), 1.18, (-1,22)

 

5.0

3.8,4.9,5.2,4.9

4.7

(-0.9), 0.2,0.5, 0.2 

5 step solution

Q42E

The graph of a function \(y = f\left( x \right)\) is shown. At which point(s) are the following true?

 

(a) \(\frac{{dy}}{{dx}}\) and \(\frac{{{d^2}y}}{{d{x^2}}}\) are both positive.

(b) \(\frac{{dy}}{{dx}}\) and \(\frac{{{d^2}y}}{{d{x^2}}}\) are both negative.

(c) \(\frac{{dy}}{{dx}}\) is negative but \(\frac{{{d^2}y}}{{d{x^2}}}\) is positive.



2 step solution

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