Chapter 8
Calculus for Biology and Medicine · 67 exercises
Problem 1
Suppose that $$\frac{d y}{d x}=y(2-y)$$ (a) Find the equilibria of this differential equation. (b) Graph \(d y / d x\) as a function of \(y\), and use your graph to discuss the stability of the equilibria. (c) Compute the eigenvalues associated with each equilibrium, and discuss the stability of the equilibria.
7 step solution
Problem 1
Solve each pure-time differential equation. \(\frac{d y}{d x}=x+\sin x\), where \(y_{0}=0\) for \(x_{0}=0\)
5 step solution
Problem 2
Solve each pure-time differential equation. \(\frac{d y}{d x}=e^{-3 x}\), where \(y_{0}=10\) for \(x_{0}=0\)
4 step solution
Problem 3
Solve each pure-time differential equation. \(\frac{d y}{d x}=\frac{1}{x}\), where \(y_{0}=0\) when \(x_{0}=1\)
5 step solution
Problem 4
Suppose that $$\frac{d y}{d x}=y(2-y)(y-3)$$ (a) Find the equilibria of this differential equation. (b) Graph \(d y / d x\) as a function of \(y\), and use your graph to discuss the stability of the equilibria. (c) Compute the eigenvalues associated with each equilibrium, and discuss the stability of the equilibria.
6 step solution
Problem 4
Solve each pure-time differential equation. \(\frac{d y}{d x}=\frac{1}{1+x^{2}}\), where \(y_{0}=1\) when \(x_{0}=0\)
4 step solution
Problem 5
Assume that the size of a population evolves according to the logistic equation with intrinsic rate of growth \(r=1.5\). Assume that the carrying capacity \(K=100\). (a) Find the differential equation that describes the rate of growth of this population. (b) Find all equilibria, and, using the graphical approach, discuss the stability of the equilibria. (c) Find the eigenvalues associated with the equilibria, and use the eigenvalues to determine the stability of the equilibria. Compare your answers with your results in (b).
4 step solution
Problem 5
Solve each pure-time differential equation. \(\frac{d x}{d t}=\frac{1}{1-t}\), where \(x(0)=2\)
4 step solution
Problem 6
Suppose that \(N(t)\) denotes the size of a population at time \(t .\) The population evolves according to the logistic equation, but, in addition, predation reduces the size of the population so that the rate of change is given by $$\frac{d N}{d t}=N\left(1-\frac{N}{50}\right)-\frac{9 N}{5+N}$$ The first term on the right-hand side describes the logistic growth; the second term describes the effect of predation. (a) Set $$g(N)=N\left(1-\frac{N}{50}\right)-\frac{9 N}{5+N}$$ and graph \(g(N)\). (b) Find all equilibria of \((8.65)\). (c) Use your graph in (a) to determine the stability of the equilibria you found in (b). (d) Use the method of eigenvalues to determine the stability of the equilibria you found in (b).
5 step solution
Problem 6
Solve each pure-time differential equation. \(\frac{d x}{d t}=\cos (2 \pi(t-3))\), where \(x(3)=1\)
5 step solution
Problem 7
Solve each pure-time differential equation. \(\frac{d s}{d t}=\sqrt{3 t+1}\), where \(s(0)=1\)
6 step solution
Problem 8
Solve each pure-time differential equation. \(\frac{d h}{d t}=5-16 t^{2}\), where \(h(3)=-11\)
4 step solution
Problem 9
Suppose that a fish population evolves according to the logistic equation and that a fixed number of fish per unit time are removed. That is, $$\frac{d N}{d t}=r N\left(1-\frac{N}{K}\right)-H$$ Assume that \(r=2\) and \(K=1000\). (a) Find possible equilibria, and discuss their stability when \(H=\) \(100 .\) (b) What is the maximal harvesting rate that maintains a positive population size?
5 step solution
Problem 9
Suppose that the volume \(V(t)\) of a cell at time \(t\) changes according to $$\frac{d V}{d t}=1+\cos t \quad \text { with } V(0)=5$$ Find \(V(t)\).
5 step solution
Problem 10
Suppose that a fish population evolves according to a logistic equation and
that fish are harvested at a rate proportional to the population size. If
\(N(t)\) denotes the population size at time \(t\), then
$$\frac{d N}{d t}=r N\left(1-\frac{N}{K}\right)-h N$$
Assume that \(r=2\) and \(K=1000\).
(a) Find possible equilibria, use the graphical approach to discuss their
stability when \(h=0.1\), and find the maximal harvesting rate that maintains a
positive population size.
(b) Show that if \(h
8 step solution
Problem 10
Suppose that the amount of phosphorus in a lake at time \(t\), denoted by \(P(t)\), follows the equation $$\frac{d P}{d t}=3 t+1 \quad \text { with } P(0)=0$$ Find the amount of phosphorus at time \(t=10\).
5 step solution
Problem 11
Solve the given autonomous differential equations. \(\frac{d y}{d x}=3 y\), where \(y_{0}=2\) for \(x_{0}=0\)
6 step solution
Problem 12
(Adapted from Crawley, 1997) Denote plant biomass by \(V\), and herbivore number by \(N .\) The plant-herbivore interaction is modeled as $$ \begin{array}{l} \frac{d V}{d t}=a V\left(1-\frac{V}{K}\right)-b V N \\ \frac{d N}{d t}=c V N-d N \end{array} $$ (a) Suppose the herbivore number is equal to \(0 .\) What differential equation describes the dynamics of the plant biomass? Can you explain the resulting equation? Determine the plant biomass equilibrium in the absence of herbivores. (b) Now assume that herbivores are present. Describe the effect of herbivores on plant biomass; that is, explain the term \(-b V N\) in the first equation. Describe the dynamics of the herbivoresthat is, how their population size increases and what contributes to decreases in their population size. (c) Determine the equilibria (1) by solving $$ \frac{d V}{d t}=0 \quad \text { and } \quad \frac{d N}{d t}=0 $$ and (2) graphically. Explain why this model implies that "plant abundance is determined solely by attributes of the herbivore," as stated in Crawley (1997).
6 step solution
Problem 12
Solve the given autonomous differential equations. \(\frac{d y}{d x}=2(1-y)\), where \(y_{0}=2\) for \(x_{0}=0\)
5 step solution
Problem 13
Solve the given autonomous differential equations. \(\frac{d x}{d t}=-2 x\), where \(x(1)=5\)
6 step solution
Problem 14
Suppose that a tank holds 1000 liters of water, and \(2 \mathrm{~kg}\) of salt is poured into the tank. (a) Compute the concentration of salt in g liter \(^{-1}\). (b) Assume now that you want to reduce the salt concentration. One method would be to remove a certain amount of the salt water from the tank and then replace it by pure water. How much salt water do you have to replace by pure water to obtain a salt concentration of \(1 \mathrm{~g}\) liter \(^{-1}\) ? (c) Another method for reducing the salt concentration would be to hook up an overflow pipe and pump pure water into the tank. That way, the salt concentration would be gradually reduced. Assume that you have two pumps, one that pumps water at a rate of 1 liter \(\mathrm{s}^{-1}\), the other at a rate of 2 liter \(\mathrm{s}^{-1} .\) For each pump, find out how long it would take to reduce the salt concentration from the original concentration to \(1 \mathrm{~g}\) liter \(^{-1}\) and how much pure water is needed in each case. (Note that the rate at which water enters the tank is equal to the rate at which water leaves the tank.) Compare the amount of water needed using the pumps with the amount of water needed in part (b).
5 step solution
Problem 15
Solve the given autonomous differential equations. \(\frac{d h}{d s}=2 h+1\), where \(h(0)=4\)
5 step solution
Problem 16
Solve the given autonomous differential equations. \(\frac{d N}{d t}=5-N\), where \(N(2)=3\)
6 step solution
Problem 17
Suppose that a population, whose size at time \(t\) is denoted by \(N(t)\), grows according to $$\frac{d N}{d t}=0.3 N(t) \quad \text { with } N(0)=20$$ Solve this differential equation, and find the size of the population at time \(t=5\).
7 step solution
Problem 18
Suppose that you follow the size of a population over time. When you plot the size of the population versus time on a semilog plot (i.e., the horizontal axis, representing time, is on a linear scale, whereas the vertical axis, representing the size of the population, is on a logarithmic scale), you find that your data fit a straight line which intercepts the vertical axis at 1 (on the log scale) and has slope \(-0.43 .\) Find a differential equation that relates the growth rate of the population at time \(t\) to the size of the population at time \(t\).
5 step solution
Problem 20
Assume that \(W(t)\) denotes the amount of radioactive material in a substance at time \(t\). Radioactive decay is then described by the differential equation $$\frac{d W}{d t}=-\lambda W(t) \quad \text { with } W(0)=W_{0} $$ where \(\lambda\) is a positive constant called the decay constant. (a) Solve \((8.42)\). (b) Assume that \(W(0)=123 \mathrm{gr}\) and \(W(5)=20 \mathrm{gr}\) and that time is measured in minutes. Find the decay constant \(\lambda\) and determine the half-life of the radioactive substance.
6 step solution
Problem 21
Denote by \(p=p(t)\) the fraction of occupied patches in a metapopulation model, and assume that $$\frac{d p}{d t}=0.5 p(1-p)-1.5 p \quad \text { for } t \geq 0$$ (a) Set \(g(p)=0.5 p(1-p)-1.5 p .\) Graph \(g(p)\) for \(p \in[0,1]\). (b) Find all equilibria of \((8.69)\) that are in \([0,1] .\) Use your graph in (a) to determine their stability. (c) Use the eigenvalue approach to analyze the stability of the equilibria that you found in (b).
5 step solution
Problem 21
Suppose that a population, whose size at time \(t\) is given by \(N(t)\), grows according to $$\frac{d N}{d t}=\frac{1}{100} N^{2}, \quad \text { with } N(0)=10$$ (a) Solve \((8.43)\). (b) Graph \(N(t)\) as a function of \(t\) for \(0 \leq t<10\). What happens as \(t \rightarrow 10 ?\) Explain in words what this means.
6 step solution
Problem 22
Denote by \(p=p(t)\) the fraction of occupied patches in a metapopulation model, and assume that $$\frac{d p}{d t}=c p(1-p)-p^{2} \quad \text { for } t \geq 0$$ where \(c>0 .\) The term \(p^{2}\) describes the density-dependent extinction of patches; that is, the per-patch extinction rate is \(p\), and a fraction \(p\) of patches are occupied, resulting in an extinction rate of \(p^{2}\). The colonization of vacant patches is the same as in the Levins model. (a) Set \(g(p)=c p(1-p)-p^{2}\) and sketch the graph of \(g(p)\). (b) Find all equilibria of \((8.70)\) in \([0,1]\), and determine their stability. (c) Is there a nontrivial equilibrium when \(c>0 ?\) Contrast your findings with the corresponding results in the Levins model.
7 step solution
Problem 22
Denote by \(L(t)\) the length of a fish at time \(t\), and assume that the fish grows according to the von Bertalanffy equation $$\frac{d L}{d t}=k(34-L(t)) \quad \text { with } L(0)=2$$ (a) Solve (8.44). (b) Use your solution in (a) to determine \(k\) under the assumption that \(L(4)=10\). Sketch the graph of \(L(t)\) for this value of \(k\). (c) Find the length of the fish when \(t=10\). (d) Find the asymptotic length of the fish; that is, find \(\lim _{t \rightarrow \infty} L(t)\)
5 step solution
Problem 23
Denote by \(L(t)\) the length of a certain fish at time \(t\), and assume that this fish grows according to the von Bertalanffy equation $$\frac{d L}{d t}=k\left(L_{\infty}-L(t)\right) \quad \text { with } L(0)=1$$ where \(k\) and \(L_{\infty}\) are positive constants. A study showed that the asymptotic length is equal to 123 in and that it takes this fish 27 months to reach half its asymptotic length. (a) Use this information to determine the constants \(k\) and \(L_{\infty}\) in (8.45). [Hint: Solve (8.45).] (b) Determine the length of the fish after 10 months. (c) How long will it take until the fish reaches \(90 \%\) of its asymptotic length?
4 step solution
Problem 24
Denote the size of a population at time \(t\) by \(N(t)\), and assume that $$\frac{d N}{d t}=2 N(N-10)\left(1-\frac{N}{100}\right) \quad \text { for } t \geq 0$$ (a) Find all equilibria of \((8.72)\). (b) Use the eigenvalue approach to determine the stability of the equilibria you found in (a). (c) Set $$g(N)=2 N(N-10)\left(1-\frac{N}{100}\right)$$ for \(N \geq 0\), and graph \(g(N) .\) Identify the equilibria of \((8.72)\) on your graph, and use the graph to determine the stability of the equilibria. Compare your results with your findings in (b). Use your graph to give a graphical interpretation of the eigenvalues associated with the equilibria.
3 step solution
Problem 24
Let \(N(t)\) denote the size of a population at time \(t .\) Assume that the population exhibits exponential growth. (a) If you plot \(\log N(t)\) versus \(t\), what kind of graph do you get? (b) Find a differential equation that describes the growth of this population and sketch possible solution curves.
4 step solution
Problem 25
Denote the size of a population at time \(t\) by \(N(t)\), and assume that $$\frac{d N}{d t}=0.3 N(N-17)\left(1-\frac{N}{200}\right) \quad \text { for } t \geq 0$$ (a) Find all equilibria of \((8.73)\). (b) Use the eigenvalue approach to determine the stability of the equilibria you found in (a). (c) Set $$g(N)=0.3 N(N-17)\left(1-\frac{N}{200}\right)$$ for \(N \geq 0\), and graph \(g(N)\). Identify the equilibria of \((8.73)\) on your graph, and use the graph to determine the stability of the equilibria. Compare your results with your findings in (b). Use your graph to give a graphical interpretation of the eigenvalues associated with the equilibria.
4 step solution
Problem 25
Use the partial-fraction method to solve $$\frac{d y}{d x}=y(1+y)$$ where \(y_{0}=2\) for \(x_{0}=0\).
7 step solution
Problem 26
Use the partial-fraction method to solve $$\frac{d y}{d x}=y(1-y)$$ where \(y_{0}=2\) for \(x_{0}=0\).
7 step solution
Problem 27
Use the partial-fraction method to solve $$\frac{d y}{d x}=y(y-5)$$ where \(y_{0}=1\) for \(x_{0}=0\).
5 step solution
Problem 28
Use the partial-fraction method to solve $$\frac{d y}{d x}=(y-1)(y-2)$$ where \(y_{0}=0\) for \(x_{0}=0\).
8 step solution
Problem 29
Use the partial-fraction method to solve $$\frac{d y}{d x}=2 y(3-y)$$ where \(y_{0}=5\) for \(x_{0}=1\).
5 step solution
Problem 30
Use the partial-fraction method to solve $$\frac{d y}{d t}=\frac{1}{2} y^{2}-2 y$$ where \(y_{0}=-3\) for \(t_{0}=0\).
7 step solution
Problem 31
Solve the given differential equations. $$ \frac{d y}{d x}=y(1+y) $$
7 step solution
Problem 32
Solve the given differential equations. $$ \frac{d y}{d x}=(1+y)^{2} $$
6 step solution
Problem 33
Solve the given differential equations. $$ \frac{d y}{d x}=(1+y)^{3} $$
5 step solution
Problem 34
Solve the given differential equations. $$ \frac{d y}{d x}=(3-y)(2+y) $$
5 step solution
Problem 35
(a) Use partial fractions to show that $$\int \frac{d u}{u^{2}-a^{2}}=\frac{1}{2 a} \ln \left|\frac{u-a}{u+a}\right|+C$$ (b) Use your result in (a) to find a solution of $$\frac{d y}{d x}=y^{2}-4$$ that passes through (i) \((0,0)\), (ii) \((0,2)\), and (iii) \((0,4)\).
8 step solution
Problem 36
Find a solution of $$\frac{d y}{d x}=y^{2}+4$$ that passes through \((0,2)\).
6 step solution
Problem 37
Suppose that the size of a population at time \(t\) is denoted by \(N(t)\) and that \(N(t)\) satisfies the differential equation $$\frac{d N}{d t}=0.34 N\left(1-\frac{N}{200}\right) \quad \text { with } N(0)=50$$ Solve this differential equation, and determine the size of the population in the long run; that is, find \(\lim _{t \rightarrow \infty} N(t)\).
6 step solution
Problem 38
Assume that the size of a population, denoted by \(N(t)\), evolves according to the logistic equation. Find the intrinsic rate of growth if the carrying capacity is \(100, N(0)=10\), and \(N(1)=20\).
5 step solution
Problem 39
Suppose that \(N(t)\) denotes the size of a population at time \(t\) and that $$\frac{d N}{d t}=1.5 N\left(1-\frac{N}{50}\right)$$ (a) Solve this differential equation when \(N(0)=10\). (b) Solve this differential equation when \(N(0)=90\). (c) Graph your solutions in (a) and (b) in the same coordinate system. (d) Find \(\lim _{t \rightarrow \infty} N(t)\) for your solutions in (a) and (b).
11 step solution
Problem 40
Suppose that the size of a population, denoted by \(N(t)\), satisfies $$\frac{d N}{d t}=0.7 N\left(1-\frac{N}{35}\right)$$ (a) Determine all equilibria by solving \(d N / d t=0\). (b) Solve \((8.46)\) for (i) \(N(0)=10\), (ii) \(N(0)=35\), (iii) \(N(0)=50\), and (iv) \(N(0)=0\). Find \(\lim _{t \rightarrow \infty} N(t)\) for each of the four initial conditions. (c) Compare your answer in (a) with the limiting values you found in (b).
3 step solution