Q97E - Chemistry (OpenStax)

Question

Convert the boiling temperature of liquid ammonia, \( - 28.1^\circ F,\) into degrees Celsius and kelvin.

Step-by-Step Solution

Answer

The boiling temperature of liquid ammonia \( - 28.1^\circ F,\) to degrees Celsius and Kelvin are -33.4 ℃ and 239.8 K, respectively.

Step 1: Determine the temperature of the boiling temperature of liquid ammonia in Celsius.

The equation for converting Fahrenheit into Celsius temperature is:

\({T_{{}^ \circ C}} = \frac{5}{9} \times {T_{{}^ \circ F}} - 32\)

It is given that the boiling temperature of liquid ammonia is \( - 10^\circ F\).

\(\begin{aligned}{\underline{\phantom{xx}}}{T_{{}^ \circ C}} &= \frac{5}{9} \times  - 28.1{\rm{ }}^\circ F - 32\\{\rm{     }} &=  - {33.38^ \circ }C\end{aligned}\)

Hence the boiling temperature of liquid ammonia is \( =  - {33.38^ \circ }C\) _~  -33.4 ℃ ( round off to 3 significant figures).

Step 2: Determine the temperature of boiling temperature of liquid ammonia in Kelvin.

The equation for converting Celsius into Kelvin temperature is:

\({T_K} = {T_{{}^ \circ C}} + 273.15\)

From the above step, we know that the boiling temperature of liquid ammonia is \( - {33.38^ \circ }C\).

\(\begin{aligned}{\underline{\phantom{xx}}}{T_K}  &=  - {33.38^ \circ }C + 273.15\\{\rm{   }} &= 239.77K\end{aligned}\)

Hence the boiling temperature of liquid ammonia \( = 239.77K\)_~ 239.8 K