Q95E - Chemistry (OpenStax)

Question

Convert the temperature of the coldest area in a freezer, \( - 10{\rm{ }}^\circ F,\)to degrees Celsius and kelvin.

Step-by-Step Solution

Answer

The temperature of the coldest area in a freezer \( - 10^\circ F,\) to degrees Celsius and Kelvin are -23  and 250 K, respectively.

Step 1: Determine the temperature of the coldest area in a freezer in Celsius.

The equation for converting Fahrenheit into Celsius temperature is:

\({T_{{}^ \circ C}} = \frac{5}{9} \times {T_{{}^ \circ F}} - 32\)

It is given that the temperature of the coldest area in a freezer is \( - 10^\circ F\).

\(\begin{aligned}{\underline{\phantom{xx}}}{T_{{}^ \circ C}} &= \frac{5}{9} \times  - 10{\rm{ }}^\circ F - 32\\{\rm{     }} &=  - {23.33^ \circ }C\end{aligned}\)

Hence the temperature of the coldest area in a freezer \( =  - {23.33^ \circ }C\)~ -23  ( 2 significant figures).

Step 2: Determine the temperature of the coldest area in a freezer in Kelvin.

The equation for converting Celsius into Kelvin temperature is:

\({T_K} = {T_{{}^ \circ C}} + 273.15\)

From the above step, we know that the temperature of the coldest area in a freezer is \( - {23.33^ \circ }C\).

\(\begin{aligned}{\underline{\phantom{xx}}}{T_K} &=  - {23.33^ \circ }C + 273.15\\{\rm{   }} &= 249.82K\end{aligned}\)

Hence the temperature of the coldest area in a freezer \( = 249.82K\)~ 250 K ( 2 significant figures).