Q69. - Algebra 1

Question

Find the perimeter and area of each figure.

 A rectangle with a length of 5 feet and width of 8 feet

Step-by-Step Solution

Answer

$\text{Perimeter}=26\text{ feet}$

$\text{Area}=40\text{ square feet}$

Step 1. Write the given information.

Given that,

The length of a rectangle is 5 feet.

Breadth is 8 feet.

Step 2. Formula used.

The perimeter of a rectangle is given as $2\left(L+B\right)$

Also, the area of a rectangle is given as $L\times B$

where L is length and B is the breadth of the rectangle.

Step 3. Description of the step.

To find the perimeter of a rectangle whose length and breadth are 5 and 8 feet respectively,

$\begin{array}{l}Perimeter=2\left(L+B\right)\\ =2\left(5+8\right)\\ =2\left(13\right)\\ =26\end{array}$

Step 4. Description of the step.

Now, the area of the given rectangle can be calculated as

$\begin{array}{l}Area=\left(L\times B\right)\\ =\left(5\times 8\right)\\ =40\end{array}$