Q61. - Algebra 1

Question

A deck is shaped like a rectangle with a width of 12 feet and a length of 15 feet. What is the area of the deck?

$\begin{array}{l}\mathbf{A}\mathbf{.}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{3}\mathbf{f}{\mathbf{t}}^{\mathbf{2}}\\ \mathbf{B}\mathbf{.}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{27}\mathbf{f}{\mathbf{t}}^{\mathbf{2}}\\ \mathbf{C}\mathbf{.}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{108}\mathbf{f}{\mathbf{t}}^{\mathbf{2}}\\ \mathbf{D}\mathbf{.}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{180}\mathbf{f}{\mathbf{t}}^{\mathbf{2}}\end{array}$

Step-by-Step Solution

Answer

Option D is correct.

Step 1. Area of the rectangle.

The area of the rectangle is given by:

$\text{area of rectangle}=\text{width}\times \text{length}$

Step 2. DESCRIPTION OF STEP.

Width of rectangle = 12 feet

Length of rectangle =15 feet

Thus, the area of a rectangle is calculated as:

$\begin{array}{l}\text{area of rectangle}=\text{12 feet}\times \text{15 feet}\\ {\text{ =180 ft}}^2\end{array}$

Thus, the area of the rectangle is 180 ft² i.e. option D is correct.