Q65. - Algebra 1

Question

At a certain cheerleading competition, the maximum time per team, including the setup, is 3 minutes. The Ridgeview High School squad’s performance time is 2 minutes and 34 seconds. How much time does the squad have left for their setup?

Step-by-Step Solution

Answer

The total time left for their setup is 26 seconds.

Step 1. Given information.

Total minutes given = 3 minutes.

Performance time = 2 minutes and 34 seconds.

Step 2. Introduce the variable.

Consider the setup time of the squad be x.

Step 3. Write the equation.

1 minute $=60$ seconds

So,

3 minutes$=3\times 60$ seconds.

And

2 minutes 34 seconds $=\left(2\times 60+34\right)$ seconds

Since the maximum time per team is 3 minutes.

Therefore,

$$\begin{gathered} 3\times 60=\left(2\times 60+34\right)+x \\ 180=\left(120+34\right)+x \\ 180=154+x \end{gathered}$$

Step 4. Solve the equation.

Take the equation $180=154+x$.

 $$\begin{gathered} 180-154=154+x-154 \\ 180-154=x \end{gathered}$$

Subtract 154 from both sides of the above equation.

So,

$x=26\sec$