Q5D. - Algebra 1

Question

For $f\left(t\right)=2t^3$ find the value.

$f(-3)–f\left(1\right)$.

Step-by-Step Solution

Answer

The value of $f(-3)-f\left(1\right)$ is $– 56$.

Step 1. From question.

The given expression is $f\left(t\right)=2t^3,$

Step 2. To find.

Find the value of $f(-3)-f\left(1\right)$ if width="68" style="max-width: none; vertical-align: -5px;" $f\left(t\right)=2t^3,$

Step 3. Evaluation.

Putting $t=-3$ in $f\left(t\right)=2t^3,$ we get,

$\begin{array}{c}f\left(-3\right)=2{\left(-3\right)}^3\\ =2\left(-27\right)\\ =-54\end{array}$

Again. putting $t=1$ in $f\left(t\right)=2t^3,$ we get,

$\begin{array}{c}f\left(1\right)=2{\left(1\right)}^3\\ =2\left(1\right)\\ =2\end{array}$

Substituting $f\left(-3\right)=-54$ and $f\left(1\right)=2$ in $f\left(-3\right)-f\left(1\right)$ we get,

$\begin{array}{c}f\left(-3\right)-f\left(1\right)=-54-2\\ =-56\end{array}$

 

Hence, the value of $f(-3)-f\left(1\right)$ if $f\left(t\right)=2t^3,$ is $–56$.