Q5B. - Algebra 1

Question

For $f\left(t\right)=2t^3$ find the value.

$3\left[f\right(t\left)\right]+2$

Step-by-Step Solution

Answer

The value of $3\left[f\right(t\left)\right]+2$ is 8.

Step 1. From question.

The given expression is $f\left(t\right)=2t^3,$

Step 2. To find.

Find the value of $3\left[f\right(t\left)\right]+2$ if $f\left(t\right)=2t^3,$

Step 3. Evaluation.

Putting $t=1$ in $f\left(t\right)=2t^3,$ we get,

$$\begin{gathered} f\left(1\right)=2\times 1^3 \\ =2\times 1 \\ =2 \end{gathered}$$

Now, putting $f\left(1\right)=2$ in $3\left[f\left(1\right)\right]+2$ we get,

$\begin{array}{c}3\left[f\left(1\right)\right]+2=3\left[2\right]+2\\ =6+2\\ =8\end{array}$

Hence, the value of $3\left[f\right(t\left)\right]+2$ if $f\left(t\right)=2t^3,$ is 8.