Q41P
Question
Two large metal plates (each of area ) are held a small distance
a part. Suppose we put a chargeon each plate; what is the electrostatic pressure on the plates?
Step-by-Step Solution
VerifiedThe electrostatic pressure on each plate of the parallel plate capacitor is
The electric field on either side of a charge-density conducting plate is as follows:
Here, is the permittivity for free space, is the electric field and charge density.
The magnitude of the electric force acting on a charge in an electric field is expressed as,
Here,is the amount of the charge.
Substitute for in above equation.
Write the expression for surface charge density on each plate of the capacitor is,
Here, is the area of the surface.
Substitute for in the equation
The following formula can be used to calculate the pressure acting on a surface due to a force :
Substitute for
Determine the electrostatic pressure on the parallel plate capacitor's individual plates.
Hence, the electrostatic pressure on each plate of the parallel plate capacitor is