Q3E

Question

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip takes 1 h and 50 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 70 km/h (43 mi/h). How much longer does the trip take?

Step-by-Step Solution

Verified
Answer

The trip takes55 min longer in the heavy traffic as compared to the freeway.

1Step 1: Identification of given values
  • Your average speed on the freeway is, v1=105km/h
  • Time taken in the trip on the freeway is, t1=1h50min 
  • Your average speed after the heavy traffic is, v2=70km/h
2Step 2: Calculation of the average velocity

The expression for the average velocity can be given as, 

 v=dt

Where,v= average velocity, d= displacement, and t= travel time 

3Step 3: Calculation of thetotal covereddistance

So, for the freeway, your average speed will be,

 v1=dt1

Substituting the values in the above expression,

 d=105km/h×1.83h=192.5km

 Therefore, the total covered distance is,  d=192.5 km

4Step 4: Calculation of yourtravel time during heavy traffic

 For the traffic way

 v2=dt2

Substituting the values in the above expression,

 t2=192.5km70km/h=2.75h×60min1h=2h 45min

Thus, the travel time during the heavy traffic is,  t2=2h 45min

5Step 5: Calculation of the difference in the time taken during freeway and heavy traffic

Therefore, the difference in the travel time during the heavy traffic and on a freeway can be determined by,

 Δt=t2-t1

Substituting the values in expression will give,

Δt=2 hr 45 min-1 hr 50 min=55 min

Thus, you will take 55 min longer in the heavy traffic as compared to a freeway.