Q1E - University Physics with Modern Physics

Question

A car travels in the +x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is $V_{av-x} = 6.25m/s$ . How far does the car travel in 4.00 s?

 

Step-by-Step Solution

Answer

The displacement done by the car in 4.00s is, $s=25m$

 

Step 1: Average velocity

Average velocity is the ratio of the rate of displacement over time.

 $v=\frac{d}{t}$………………(i)

Where, v= average velocity, s= total displacement, t= time travel

Step 2: Identification of the given data

The average velocity is, $v_{av-x}=6.25 m/s$

Time interval is, $t = 4.00s$ 

Step 3: Calculation of the total displacement by the car

Thus,using equation (i), we can write the displacement caused by the car will be,

 $d=v\times t$

Substituting the given values in the above expression, the displacement will be,

  $\begin{array}{rcl}d& =& 6.25m/s\times 4.00s\\ & =& 25m\end{array}$

Thus, the total displacement by the car is $=25m$