Q.3.105 - An Introduction to General, Organic, and Biological Chemistry

Question

Metal is thought to be titanium or aluminium. When 4.7g of the metal absorbs 11J, its temperature rises by ${4.5}^{\circ }\mathrm{C}$.

a. What is the specific heat $\left(\mathrm{J}/{\mathrm{g}}^{\circ }\mathrm{C}\right)$ of the metal?

b. Would you identify the metal as titanium or aluminium

Step-by-Step Solution

Answer

a. the specific heat of the metal is $0.520\mathrm{J}/{\mathrm{g}}^{\circ }\mathrm{C}$

b. Titanium

Step 1: Given Information

The specific heat intensity limit of a substance is the intensity limit of an example of the substance isolated by the mass of the example, likewise at times alluded to as massic heat limit.

Step 2: Explanation Part (a)

Given,

mass =$4.7g$

Heat taken = $11J$

change in temperature $∆T={4.5}^{\circ }\mathrm{C}$

$\text{ Specific heat }=\frac{\text{ Heat }}{\text{ Mass }\times \mathrm{\Delta }T}$

$=\frac{11\mathrm{J}}{4.7\mathrm{g}\times {4.5}^{\circ }\mathrm{C}}=0.52 J/g^{o}C$

Step 3: Explanation Part (b)

The metal is titanium as the specific heat of titanium is $0.52\mathrm{J}/{\mathrm{g}}^{\circ }\mathrm{C}$