Q. 93 - An Introduction to General, Organic, and Biological Chemistry

Question

If you want to lose $1 lb$ of "body fat," which is $15\%$ water, how many kilocalories do you need to expend? 

Step-by-Step Solution

Answer

As a result, if a person wishes to shed $1$ pound of fat, which is $15$ percent water, he or she must lose $3500$kcal.

Step1: Given Information.

The Following are the given information as:

Body fat$= 1 lb$

water present in body$=15\%$

To find the Kilocalories found in body

Step2: Explanation

The proportion is calculated as follows: $15$ mass units of water contains $100$ mass units of fat.

As a result, $1 lb$ of body fat comprises $0.85 lb$ of fat, which is $15$ percent water. Then, $1 g$ of fat contains $9 Kcal$,

Hence the equation is same.

$1 g Fat=9 Kcal$

Step3: Find the Kilocalories.

We're given a weight in pounds, which we must convert to grammes. Egalitarianism exists.

$1\mathrm{lb}=454\mathrm{g}$

These are the factors of conversion

$\frac{1\mathrm{lb}}{454\mathrm{g}}\text{ and }\frac{454\mathrm{g}}{1\mathrm{lb}}$

As a result, using the relevant conversion factors, the number of kilocalories that must be lost can be computed.

$0.85\mathrm{tbfat}\times \frac{454\mathrm{gfat}}{1\mathrm{fbfat}}\times \frac{9\mathrm{kcal}}{1\mathrm{gfat}}=3500\mathrm{kcal}$