Q25. - Algebra 2

Question

Find $p\left(4\right)\text{ and }p\left(-2\right)$ for the function $p\left(x\right)=x^5-x^2$.

Step-by-Step Solution

Answer

The value of $p\left(4\right)=1008\text{ and }p\left(-2\right)=-36$.

Step 1. Write down the given information.

The given function is $p\left(x\right)=x^5-x^2$.

Step 2. Calculation.

Evaluating $p\left(4\right)\text{ and }p\left(-2\right)$ by plugging $x=4\text{ and }x=-2$ in given function $p\left(x\right)=x^5-x^2$.

$\begin{array}{c}p\left(x\right)=x^5-x^2\mathrm{....}\left(\text{Given}\right)\\ p\left(4\right)={\left(4\right)}^5-{\left(4\right)}^2\\ =1008\\ \text{Now, }p\left(-2\right)={\left(-2\right)}^5-{\left(-2\right)}^2\\ =-36\end{array}$

Step 3. Conclusion.

The value of $p\left(4\right)=1008\text{ and }p\left(-2\right)=-36$.